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2651.

Example15 E"(Cu2+ | Cu) and E。(Ag+ | Ag) is +0.337and +0.799W Make a cell whose EMF is tve. If theconcentration of Cu is 0.01 M and E cell at 25° C is zen(DSB 2006, 10)2+calculate the concentration of Ag

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2652.

etCune e

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Capacitance is the ability of a system of electrical conductors and insulators to store electric charge when a potential difference exists between the conductors. The symbol for capacitance is C. Capacitance is expressed as a ratio of the electrical charge stored to the voltage across the conductors.

The SI unit of capacitance is the farad (symbol: F)

2653.

67. An object ofacea distance of 60 cm from a convexmirror of focal length 30 cm. Findthe nature, position and size of thege formed.l India 2010C)

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2654.

2.The radius of Germanium (Ge) nuclide is measuredto be twice the radius of Be. The number ofnucleons in Ge are :-(1) 73(2) 74(3) 75(4) 72

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mass no= no nucleons in an atom . mass no of Ge is 72.61. Hence no of nucleons are (1)73.

(1) 73is a write answer

2655.

vision Deb the possible RessDefect a"TO Show, the In-lagect Dees he heve shat couobsnss cavsina3- Pり) "To Shouo-the cos nection od this

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Myopia

Near-sightedness : A person with Myopia can see nearby objects clearlyA person with myopia cannot see faraway objects clearly.

Occurs due to1.Excessive curvature of the eye lens

2.Elongation of eyeball

3.The image of a distance object is formed in front of the retina and not on the retina

Defected is corrected by using Concave lenses such that the lens will bring the image back on to the retina.

oral rehydration solutions

2656.

The wine in the figure cavies a current ofLO A. Determines the magnetic field at the centreo when the radius of the cou is 3 cm

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taking u/4π = 10^(-7) , r=3cm i=10A α=3π/2,B=(10^(-7)*3*3.14*10)/(3*2)=1.57uT

2657.

T\begin{array} { l } { \text { Two metallic spheres of radii } 1 \mathrm { cm } \text { and } 2 \mathrm { cm } } \\ { \text { are given charges } 10 ^ { - 2 } \mathrm { C } \text { and } 5 \times 10 ^ { - 2 } \mathrm { C } } \\ { \text { respectively. If they are connected by a } } \\ { \text { conducting wire, the final charge on the } } \\ { \text { smaller sphere is } } \end{array}

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2658.

State the formula for the Force per unit length between two long straight parallelconductorscarrying current.

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2659.

Derive an expression for the force between two parallel straight conductors carryinghowing the fermation of image in a compound microscopecurrents in the same direction. Hence define one ampere.m s

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2660.

. The magnitude of force between two straight parallel current carrying conductors kept at a distance d apart in air isgiven byuo il22 dUse it and convention that force of attraction is negative and repulsion is positive

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The conductor ‘b’ will experience a sideways force on account of the external field Ba. The direction of this force is towards the conductor ‘a’. you can verify this either by the cross product rule of vectors or by Fleming’s left hand rule. We label this force Fba, the force on a segment L of ‘b’ due to ‘a’. The magnitude of this force is given by,

Fba= iaIBa

FbaL

=

μ0iaib/2πd

2661.

TWO identical conducting spheres carrying different chargesattract each other with a force F when placed in air mediumat a distance d' apart. The spheres are brought into contactand then taken to their original positions. Now the twospheres repel each other with a force whose magnitude isequal to that of the initial attractive force. The ratio betweeninitial charges on the spheres is[Kerala PET 2008]

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1is to 1ratio between initial charges on the sphere

Since the two charges (spheres) attract, they will be opposite in sign, ie, q1 and –q2.Force, F= k * q1 * q2/ d2After touching, charge on each will be (q1 - q2)/2.New force, F=k*[(q1 - q2)/2]2/ d2.Since both the force are same(given in question)So, on solving by quadratic equations, we getq1/ q2 = -(3 + √(8)) or (-3 + √(8))

2662.

Two identical spherical conductors carry charges of - 9 x 10-7 C and 5 x 10 C are separated bycertain distance in air. They are brought into contact and then place in initial position. Compare theirforces between them before and after contact.

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2663.

Find the radius of a nucleus of mass number 64

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2664.

The weight of any person on the moon is about 1/6 times that on the earth. He can lit(15 kg on the earth. What will be the maximum mass which can be lifted by the sameplied by the person on the moon

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thanks for answer

2665.

Differentiate between monocots and dicots: (2 points)

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Monocots :-

1. The seeds of these plants have only one cotyledon.

2. Their leaves have parallel venation.

3. The root system consists of similar fibrous roots.

4. The flowers are trimerous, have three or multiple of three petals.

5. The vascular bundles are scattered and closed (lack canbium). Secondary growth does not occur.

Examples - Maize, wheat,rice,onion

Dicots :

1. The seeds produced by these plants have embryos with two fleshy leaves, the cotyledons.

2. Their leaves have reticulate venation, with a network of veins.

3. The root system has a prominent tap root.

4. The flowers have five or multiple of five petals.

5. The vascular bundles are arranged in a ring. They are open (I.e., have cambium) and undergo secondary growth.

Examples - Pea, potato, sunflower, rose, banyan.

you can write any two with examples from above the following

Monocots :-

1. The seeds of these plants have only one cotyledon.

2. Their leaves have parallel venation.

3. The root system consists of similar fibrous roots.

4. The flowers are trimerous, have three or multiple of three petals.

5. The vascular bundles are scattered and closed (lack canbium). Secondary growth does not occur.

Examples - Maize, wheat,rice,onion

Dicots :

1. The seeds produced by these plants have embryos with two fleshy leaves, the cotyledons.

2. Their leaves have reticulate venation, with a network of veins.

3. The root system has a prominent tap root.

4. The flowers have five or multiple of five petals.

5. The vascular bundles are arranged in a ring. They are open (I.e., have cambium) and undergo secondary growth.

Examples - Pea, potato, sunflower, rose, banyan.

you can wriye any two with examples from above the following

The plants whose seeds have one cotyledon are called monocots.They are also called monpcotyledonous plants.

The plants whose seeds have one or more c otyledons are called doctorsThey are called dicotylefonous plants.

2666.

(i) Increasing the current sensitivity of a galvanometer may not necessarilyincrease its voltage sensitivity. Explain, giving reason. [AIl Indiaj

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Current sensitivity does not depend upon resistance(R), whereas voltage sensitivity does. Current sensitivity can be increased by increasing the number of turns of the coil. However, this increases the resistance of the coil also(R is proportional to length of conductor). Since voltage sensitivity decreases with increase in resistance of the coil, the effect of increase in number of turns is nullified in the case of voltage sensitivity. Hence, there is no increase in voltage sensitivity.

2667.

garvahoneeltDt sensitivity of a galvanometer? Name any two factors on which the4. What is meant by currencurrent sensitivity of a galvanometer depends

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Current Sensitivity Means The Number Of Deflections Produced by the Gavenometer When a Unit Current Passes Through it.

current sensitivity = (angle of deflection)/current

so it depends on angle of deflection as well as on the current passing through it.

2668.

A moving coil galvanometer has 150 equaldivisions. Its current sensitivity is 10 divisions permilliampere and voltage sensitivity is 2 divisionsper millivolt. In order than each division reads lV the resistance in ohm needed to be connectedin series with the coil will be(A) 99995(C) 10^3(B) 9995(D) 10^57

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2669.

fine a solar panel.f solar cells joined together

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Photovoltaic solar panelsabsorbsunlightas a source of energy to generateelectricity. Aphotovoltaic(PV) module is a packaged, connected assembly of typically 6x10 photovoltaicsolar cells. Photovoltaic modules constitute the photovoltaic array of aphotovoltaic systemthat generates and suppliessolar electricityin commercial and residential applications.

2670.

itdots2sQ.3. Define a solar panel.rce number of solar cells joined together in a definite pattermis o

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Photovoltaic solar panelsabsorbsunlightas a source of energy to generateelectricity. Aphotovoltaic(PV) module is a packaged, connected assembly of typically 6x10 photovoltaicsolar cells. Photovoltaic modules constitute the photovoltaic array of aphotovoltaic systemthat generates and suppliessolar electricityin commercial and residential applications.

2671.

pesfotosoihefrohthefather2. Nante the chief component of solar cells. What energy conversion takes piace in a solar cell? (1

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Ans :- A solar cell is also known as photovoltaic cell. The chief component of a solar cell is its own module. It is constructed of several different layers. They are made up of a material called silicon which acts as a semi conductor. But what is a semi conductor? Semi means partial and conductor means that which carries an electric current.

There are 2 layers of silicon in a solar cell that is N-type and the P-type.When N and P-type silicon come into contact, they create their own electric field.The solar cell uses a maximum of 25% from the sun’s that produces of about 1000 watts of energy per square foot.

2672.

Section-BList any four areas where solar cells are being used as source of energy. 2

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Solar cells are used for 1.street-lighting2. calculators3. operating water-pumps 4. running radio and television sets in remote areas.

2673.

. Why is it not possible to make use of solar cells to meet all our energy needs? State at least threereasons tc support your answerWhat changes can you make in your habits to become more environment friendly?

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No(i) Silicon cells are expensive(ii) Solar radiations are not uniform over the earth's surface(iii) Cannot be used at night or on cloudy

2674.

Write the energy conversion that takes place in hydropowerplant.

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Hydropower plants capture the energy of falling water to generate electricity. A turbine converts the kinetic energy of falling water into mechanical energy. Then a generator converts the mechanical energy from the turbine into electrical energy.

2675.

The effective resistance across AB -6Ω12Ω10Ω6Ω652(a) 6Ω(b)8Ω(c) 4Ω(d) ofthese4

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As 6 and 12 ohm are in parallelso equivalent = 6*12/6+12= 72/18= 4

now 4+6//10so 10*10/20= 100/20= 5 ohm

Option-D

2676.

44. What is the total resistance across A and B inthe circuit shown in Fig. 8.12?(a) 1 Ω(c) 1.5 Ω(b) 2 Ω(d) none of these2Ω2Ω10Ω2Ω

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really thanks

2677.

The equivalent weight of a metal is 9 vapour density of its chloride is 59.25.The atomic weight of metal is?

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2678.

Write the energy conversion that takes place in a hydropower plant

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Energy conversion take place in a hydropower plant :Potential energy ⇒ kinetic energy ⇒ mechanical energy ⇒ electrical energy

2679.

Three resistance are joined together as sidesof triangle ABC as shown in the figure. Whatis the quivalent resistance across B and C ?6022(a) 502(b) 642(c) 322(d) 200210092

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option D is the correct answer

Option D is the correct answer.

firstly, according to the question's given condition

40ohm and 60 ohm are series so,

R = R(ac) + R (cb)

R = 100 + 60

R = 160 ohm ------------( 1 )

this R is parallel to 40 ohm,

therefore,

1 / R = 1 / 40 + 1 / 160

1 / R = 5 / 160

R = 160/5

R = 32 ohm.

The correct answer is option (d)200 ohm.

R=R1+R2=40+60=200;. 1/R=1/R1 + 1/R2=1/100+1/100=1+1/100=2/100=1/50

2680.

3. A bus covered a distance of 182 km in 5.5 hours. What is theaverage speed of the bus corrected for appropriate numberof significant figure?(Ans. 33 km h-)

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Speed=distance/time=182/5.5=33km/hr

speed= distance/time = 182/5.5= 33 km/hr

speed = distance / timeso' = 182/5.5 = 33 km /hr

2681.

An Insect trapped in circular groove of radius 12cm moves along the groove steadily and completes 7revolutions in 100s.(a) What is the angular speed & linear speed of the motion?(b) Is the acceleration vector a constant vector? What is its magnitude?1%1%+1

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2682.

Example 4.10 An insect trapped in acircular groove of radius 12 cm moves alongthe groove steadily and completes 7revolutions in 100 s. (a) What is theangular speed, and the linear speed of themotion? (b) Is the acceleration vector aconstant vector? What is its magnitude?

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Frequency of revoluation of Insect = No of revolaution completed in one second =7100=0.07S−1

(a) Angular Speed = 2πn=2∗227∗0.07=0.44radsec−1

Linear speed =ωr=0.44∗ 0.12 = 0.0528 metersec−1

(b)In this case accelearion is not a constant vector as direction of velocity is continious changing. This is centripetal accelearation and its magnitude is = ω2r = 0.0232 radsec−2

2683.

The elastic limit is equal to

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Elastic limit is maximum stress or force per unit area within a solid material that can arise before the onset of permanent deformation. When stresses up to the elastic limit are removed, the material resumes its original size and shape. Stresses beyond the elastic limit cause a material to yield or flow.

2684.

Example 4.10 An insect trapped in acircular groove of radius 12 cm moves alongthe groove steadily and completes 7revolutions in 100 s. (a) What is theangular speed, and the linear speed of themotion? (b) Is the acceleration vector aconstant vector ? What is its magnitude ?

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2685.

Example 95. An insect trapped in a circular groove ofradius 12 cm moves along the groove steadily and completes7 revolutions in 100 s. (i) What is the angular speed and thelinear speed of the motion? (ii) Is the acceleration vectoraconstant vector ? What is the magnitude ? (iii) What is itslinear displacement?NCERT, Central Schools 03]

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2686.

3. The elastic limit of steel is 8 × 10, N m'a and its Youngmodulus 2× 101, Nm. Find the maximum elongationof half-metre 8teel wire that can be given withoutexceeding the elastic limit

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2687.

what is young modulus of iron?

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The modulus of elasticity of ductile iron in tension lies in the range of 162 to 170 GPa (23.5 × 106to 24.5 × 106psi) and does not vary greatly with grade.

2688.

Find out the elongation in block. If mass, area ofcross-section and young modulus of block are m, Aand Y respectivelysmooth

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2689.

1. A load of 10 kg ia suapended by a metal wire 3 m longand having a cross-sectional area 4 mm3. Find (a) thestress (b) the atrain and (c) the elongation. Youngmodulus of the metal is 20x 10" N m2

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2690.

A cylindrical vessel of height 500 mm has anorifice (small hole) at its bottom. The orifice isinitially closed and water is filled in it up to heightH. Now the top is completely sealed with a capand the orifice at the bottom is opened. Somewater comes out from the orifice and the waterlevel in the vessel becomes steady with heightof water column being 200 mm. Find the fall inheight (in mm) of water level due to opening ofthe orifice.Take atmospheric pressure = 1.0 x 105 N/m,density of water 1000 kg/m' and g 10 m/sNeglect any effect of surface tension](a)5 mm (b)6mm (c)2mm (d) 1 mm

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2691.

Choose the correct answer:1×15 = 15(i) Which of the following fundamentalforces is the strongest force ?(a) Gravitational force(b) Electromagnetic force(c) Strong nuclear force(d) Weak nuclear force2/16

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2692.

17. Akhtar, Kiran and Rahul were ridling in a motorcar that wasa high velocity on an expressway when an insemoving withhit the windshield and got stuck on the windscreen. Akhtanand Kiran started pondering over the situation. Kiran suggesthat the insect suffered a greater change in momentumcompared to the change inthe change in the velocitythat of the motorcar). Akchtar said that since the motorcar wasmoving with a larger velocity, it exerted a larger force on theinsect. And as a result the insect died. Rahul while putting anentirely new explanation said that both the motorcar and theinsect experienced the same force and a change in theirmomentum. Comment on these suggestionsasmomentum of the motorcar (becauseof the insect was much more than

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2693.

Akhtar,Kiran and Rahul were riding in a motorcar that was17.ving with a high velocity on an expressway when an insectmot the windshield and got stuck on the windscreen. Akhtarhiand Kiran started pondering over the situation. Kiran suggestedthat the insect suffered a greater change in momentum ascompared to the change in momentum of the motorcar (becausethe change in the velocity of the insect was much more thanthat of the motorcar). Akhtar said that since the motorcar wasmoving with a larger velocity, it exerted a larger force on theinsect. And as a result the insect died. Rahul while putting anentirely new explanation said that both the motorcar and theinsect experienced the same force and a change in theirmomentum. Comment on these suggestions.

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2694.

12.A cube of edge length 10 cm is just balanced at the interface of two liquids A and B asand B has specific gravity 0.6 and 0.4 respectively, then mass of cube isshown in figure. If A(2) 360 g(1) 240 g(3) 480 g(4) 540 g

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Balance the force in vertical direction.

=> mg = (pVg)1 + (pVg)2

So,m = (0.4 g/ml)600cm³ + (0.6 g/ml)(400 cm³) as 1 ml = 1 cm³ so m = 480 gm.

Hope it clears.

2695.

What causes planetary winds?

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Planetary wind can refer to any wind system of the earth'satmosphere which owes its existence and direction to solarradiation and to the rotation of the earth.

2696.

explanation of amplitude, time period and frequency??

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Amplitudeof the sound is nothing but the loudness or the amount of maximum displacement of the particles while the sound is produced.

2697.

(c) If A 2i +3j-4k andB 3i -4 j +5k, find

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2698.

65. The angle between vectors A 4i+3j anB 3i-4j is

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90degree (dot product )

kaise

this sum is a model of your sum!!! check it!!!

therefore the angle b/w the two vectors is 90 degree

2699.

A homogenous solid cylinder of length L (I H/2). Cross-sectional area A/5 isimmersed such that it floats with its axis vertical at the liquid -liquid interface withlength L/4 in the denser liquid as shown in the fig. The lower density liquid is openatmosphere having pressure po . The density D of solid is given byH/꡸42) -d3) d4).S1) d4

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2700.

Convert 1 kg/m^3 to gkm^3 using dimensions

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1 kg = 1000 gso 1kg/m³ = 1000g/m³

Tysm.