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option B

Suppose angle bisector of angle A meets circumcircle with centre O at P, and OP is joined to meet BC at D. ...(i)

Angle BAP = Angle CAP (Because AP is angle bisector)Angle BOP = 2 Angle BAPAngle COP = 2 Angle CAPSo, Angle BOP = Angle COP

Therefore in triangles BDO and CDO,

BO = CO(Radii of the same circle)Angle BOP = Angle COP (Proven above)DO = DO (Common side

So triangles BDO and CDO are congruent. (SAS criterion)So, BD = CD and angle BDO = angle CDO (CPCTE)But angles BDO and CDO form linear pair.So, angle BDO + angle CDO = 180 degreeSo, angle BDO = half of 180 = 90 degree

With BD = CD and angle BDO = 90 degree,OD is perpendicular bisector of BCOROP is perpendicular bisector of CD ...(ii)By (i) and (ii),P lies on angle bisector of angle A and perpendicular bisector of BC and is a point on the circle.

two magnetic field lines can never intersectbecause at a certain point it can have only one direction

no not possible. for example like two vector same in magnitude but opposite in direction will cancel out but third one exist. even if we take arbitrary three non coplanar vector and when we resolve them they are not zero as they are not in one plane.

No, in order for the velocity to be constant, the speed has to be constant.Speed is a scalar, meaning that it is just a number. (A car goes 50 miles per hour).Velocity is a vector, which indicates that it needs a measure of its displacement and a direction.(A car is going 50 mph to the east).

A body can have a constant speed but a changing velocity because the direction can change while the speed is constant. (A car goes 50 mph around a roundabout).However, a body can not have a constant velocity with a changing speed.A car can not be slowing down yet still be going the same speed and direction

A body in a uniform circular motion satisfies all your conditions. A body in uniform circular motion has a constant speed, but the velocity varies as the direction of the velocity changes continuously. It has a centripetalacceleration acting on it whose magnitude remains constant but the direction which is radially inward, changes continuously.

If particles a and b are moving in positive x and positive directions respectively, then the least distance will be d.

Let a be initially at point (p, 0). Let b be at point (0, q) at t=0. Then d^2 = p^2+q^2.Position of a at time t : x = p+v1*tThat of b : y = q + v2 * tDistance ab :ab^2 = x^2+y^2= p^2+q^2+(v1^2+v2^2)*t^2+2t *(p*v1+q*v2)Differentiate wrt t. And set to 0.=> 2t*(v1^2+v2^2) + 2(p*v1+q*v2) = 0t = - (p*v1 + q* v2) / (v1^2+v2^2)As t>0, v1 or v2 or both must be negative.

=> Minimal ab^2 = d^2 - (p*v1+q*v2)^2 / (v1^2+v2^2)

The solution depends on initial positions of a and b.

Let a be at origin. Then p=0. q=d. SoMinimal ab = d*v1/sqrt(v1^2+v2^2)Similarly, if q=0, p= d.

If particles a and b are moving in positive x and positive directions respectively, then the least distance will be d.

Let a be initially at point (p, 0). Let b be at point (0, q) at t=0. Then d^2 = p^2+q^2.Position of a at time t : x = p+v1*tThat of b : y = q + v2 * tDistance ab :ab^2 = x^2+y^2= p^2+q^2+(v1^2+v2^2)*t^2+2t *(p*v1+q*v2)Differentiate wrt t. And set to 0.=> 2t*(v1^2+v2^2) + 2(p*v1+q*v2) = 0t = - (p*v1 + q* v2) / (v1^2+v2^2)As t>0, v1 or v2 or both must be negative.

=> Minimal ab^2 = d^2 - (p*v1+q*v2)^2 / (v1^2+v2^2).The solution depends on initial positions of a and b.

Let a be at origin. Then p=0. q=d. So Minimal ab = d*v1/sqrt(v1^2+v2^2)Similarly, if q=0, p= d.

Option AThe different types ofradiationare defined by the the amount ofenergyfound in the photons. Radiowaveshave photons with low energies, microwave photons have a littlemore energythan radiowaves, infrared photons have stillmore, then visible, ultraviolet, X-rays, and, themost energeticof all, gamma-rays.

Final velocity:v=u+at

t=v−u/a=2u−u/a

=u/a

=5×10^3/10^12

=5×10^-9 sec.

to take blood from a patient for blood test. explain how pressure help in it?

to take blood from a patient for blood test. explain how pressure help in it?

the nature of the motion of the body

Being lighter in weight than proton, electron will move in a circular path with higher frequency on the opposite direction to the current.

wrong

76 is the correct answer

76 is the best answer

76 is the correct answer of the given question

the answer is 8

v= dx/dt= 8-8*t at t=1 you get v=0 and the particle stops and reverses direction split the integral of v into two region 0<=t<=1 and 1<t<=2 and later add them together and get the solution

x1= 8*t-4*t^2 8*1-4*1^2= 4 m x2 = [0-(8-4)] = 4 m x=x1+x2 = 8 m

why we did integration of v

x = Asin(wt)v = dx/dt = Awcos(wt)a = dv/dt = -Aw²sin(wt) = -w²x

With One Man One Tree movement was expected that every Indonesian people can support the program by planting a tree in their respective environment with the aim at encouraging people to continually cultivate planting trees.

We know that for light the angle of incidence(i) should be equal to angle of emergence(e)

Hence angle of emergence (e) should also be 40° and 50° respectively.

For glass the refractive index is 1.5, hence

sin i/sin r = 1.5

=> sin r = sin i /1.5

a) For i= 40

Sin r = sin 40/1.5 = 0.64/1.5 = 0.428

=> r = sin⁻¹ 0.428 = 25.37°

b) for i = 50°

sin r = sin 50/1.5 = 0.766/1.5 = 0.51

=> r = sin⁻¹ 0.51 = 30.7°

Hence the value of r should be 25.37° and 30.7° respectively.

not understanding the solution

Copperplate definition, a plate of polished copper on which a writing, picture, or design is made by engraving or etchingCopper plating is the process of plating a layer of copper electrolytically on the surface of an item. It takes place in an electrolytic cell where electrolysis which uses direct electric current to dissolve a copper rod and transport the copper ions to the item. The copper rod is the anode and the item is the cathode.

let the velocity of the river be x. the velocity of the river will be in the horizontal direction

velocity of boat in still water is 5km/hr. As the width of the river is 1 km and time taken by the boat to cross the river along the shortest path is 15 min therefore the velocity of the boat is= 1*60/15= 4km/hr

according to the figure the velocity of the river is along AB . By applying triangle law of vector addition the value of AB comes to be 3km/hr

Pls give an screenshot of the ans

you can identify unknown substance by measuring its density and compare from other densities of substancesdensity equal mass by volume.

thanks 😊

Thespecific resistance of a conductoris directly proportional totemperature. It means that if thetemperature increasesthenresistancealsoincreasesIn case ofsemiconductorsas thetemperatureincreases the electrons in the valence band get excited and jump into the conduction band and hence the conductance increases resulting in the dwindling ofresistance.

option a) The resistance of a material is given by :- (Resistivity * Length)/(Area of Cross section).

Hence, when length is increased by a factor ; then the resistance will also increase proportionately.

substituting the value of a= 9 and c =1/3,

the correct option ia (d)

horizontal component of velocity always remain constant

tq

define ohm'law widely

only the horizontal component remains constant asas there is no component of acc. in horizontal direction.

The g aaceleration due to gravity acts downwords hence there is no accln in horizontal direction, the velocity changes in vertical direction as goes up and down while in horizontal it goes only forward.

what is answer number a,b,c,or d

Option (4) is the correct answer.

The horizontal component of the velocity (v_x) remains constant throughout the motion,

the correct option is bdue to rotation of axes the vector changes but its magnitude remains the same...

Thin wires can't resist the stress needed to stretch the wire and may break,

so In order to see appreciable change , Thick wire is need.

option b

Electroplating is known as electrodeposition because the process involves depositing a thin layer of metal onto the surface of a work piece, which is referred to as the substrate. An electric current is used to cause the desired reaction.

Here's a simplified explanation of how electroplating works: Let's suppose that a layer of gold is to be electrodeposited onto metal jewelry to improve the appearance of the piece. The plating metal, or coating, (gold) is connected to the anode (positively charged electrode) of the electrical circuit, while the jewelry piece is placed at the cathode (negatively charged electrode). Both are immersed in a specially developed electrolytic solution (bath).

At this point, a DC current is supplied to the anode, which oxidizes the metal atoms in the gold and dissolves them into the bath. The dissolved gold ions are reduced at the cathode and deposited (plated) onto the jewelry piece. Factors that impact the final plating result include:

the chemical composition and temperature of the baththe voltage level of the electric currentthe distance between the anode and the cathodethe electrical current application's length of time

Electroplating is the process of depositing a thin metal coating on other metal to improve their appearance looks .Application of electroplating :

Decoration Purpose :Some metals give better look and finish.For example , a flower vase of brass if electroplated with silver will be more attractive.

Protection Against Corrosion:More reactive metals tend to get rusted often. To portect against corrosion, we use electroplating.For example :Iron can be protected by coating it with Zinc and Nickel.Brass objects are coated with chromium.Repairing Finer Machine parts:Minor repairs[small and precise ] in machines can be done by coating the place with required metal.

Examples of Momentum:

1.A semi-truck full of logs has a large mass and must slow down long before a stop light because even with a small velocity, it has a large momentum and is difficult to stop.

2.A four-wheeler moving at a relatively fast velocity has a smaller momentum than the semi-truck because of its small mass and will stop much faster.

3.A bullet, although small in mass, has a large momentum because of an extremely large velocity.

Here , we actually need to know which work are we talking about , there can be work done by1) frictional force - this work will be negative as the direction of the frictional force will be opposite to the side of movement , so W=F. d = F d cos(theta) = Fdcos180= -Fd

2) force applied externally, whose component to the side of movement or horizontal will be 3-2x cos 30= 3​-2x3​-2/2= 3/2 kN

now since work done = fdcos(theta)= 3/2 x 10 x cos 0= 15 kJ