InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3551. |
A mass m attached to a spring oscillates with a periodof 2sec. If the mass is increased by 2kg, the periodincreases by one second. Find the mass m(iii) |
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| 3552. |
Calculate the linear acceleration of the blocksin the given figure. Mass of block A 10kg,mass of block B 8kg, mass of disc shapedpulley 2kg (take g 10m/s2)19 29201/ 2mism/s |
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| 3553. |
e and 2kg areeけてoo erels.oed a ligh다 tngtid,Mass es IKTuNOCoedted at tha tuvoConnedmas& |
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| 3554. |
A metal ball of mass 2kg moving with speed of36km/hr is having a collision with a stationaryball of mass 3kg. If after collision, both the ballsmove together, the loss in kinetic energy due tocollision is:DolBlim 25 401 916 4) 1601 |
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Answer» Let us suppose the following things,Mass of smaller ball, m₁ = 2kgMass of larger ball, m₂ = 3kgCombined mass of two balls, m₃ = 5kg Initial Velocity of Smaller Ball, u₁ = 36 km/h = 10m/sInitial Velocity of Larger Ball, u₂ = 0 m/sFinal Velocity of both balls combined, v = (?) By, Law of Conservation Of Momentum, (For this case) m₁u₁ + m₂u₂ = m₃v∴2 * 10 + 3 * 0 = 5 * v∴20 + 0 = 5v∴5v = 20∴v = 4 m/s Thus, the final velocity of both the balls moving as a single mass should be 4 m/s. Now, let us suppose the following, Initial combined velocity, v₁ = 10 m/s (Larger ball was at rest)Final combined velocity, v₂ = 4m/sCombined Mass, m 5kgInitial Kinetic Energy, K₁Final Kinetic Energy, K₂ Change in Kinetic Energy,ΔK = K₂ - K₁ = 1/2 mv₂² - 1/2 mv₁² = 1/2 m (v₂² - v₁²) = 1/2 * 5 (4² - 10²) = 5/2 * (16 - 100) = 5/2 * (-84) = 5 * (-42) ∴ΔK = -210 J Thus change in Kinetic Energy is 210 J. |
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| 3555. |
The resistance or the new wire is 10.QUE SOn what lactors does the resistance of asaie mato the saof an electrical compWh are colls of eleetre toasters and elrather an a pure tal?Use the dsta in Table 122wr the(a) Whueh mong on and eray is aE is the besk cout12.6 RESISTANCE OF A SYSTEM OFwe learnt abont some sim |
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Answer» please specify the question which should be answered, and please is also not clear |
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| 3556. |
The terminal velocity of a small sized spherical bodyof radius rfalling vertically in a viscous liquid is givenby the proportionality |
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Answer» It is proportional to square of distance between then (r^2). The answer is Option 2. |
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| 3557. |
will be the output of the following?int total=0;int sum0do fWhata)sum = sum + i;i++iwhile (i < 10);cout << total + sum |
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Answer» output : 10explaination:total = 0at the end of tge execution of do-while loopsum =10 o/p= total + sum =0 +10= 10 thanks |
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| 3558. |
2. A ball with a velocity of 5 msimpinges at angle of 60 with thevertical on a smooth horizontal plane.If the coefficient of restitution is 0.5,find the velocity and direction afterthe impact.-I |
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Answer» thanks |
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| 3559. |
2. A ball with a velocity of 5 ms"impinges at angle of 60 with thevertical on a smooth horizontal plane.If the coefficient of restitution is 0.5,find the velocity and direction afterthe impact.Ans: v0.3 m s-1 |
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| 3560. |
An object is kept on a smooth inclined plane of I in /. The horizontal acceleration to beimparted to the inclined plane so that the object is stationary relative to incline is59.(A) gv- (B) g-) (C)(D)ă˘ăź! |
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Answer» body is kept on smooth inclined plane of inclined 1 in x.if we let inclined angle issintheta=1/xthen,tantheta=1/√x^2-1do now, draw free body daigram as shown in figure,so,macostheta=mgsinthetaa=gtantheta now puttantheta=1/√x^2-1so,a=g/√x^2-1 |
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| 3561. |
A mass m moves in a circle on a smoothhorizontal plane with velocity vo at a radius Ro Themass is attached to a string which passes througha smooth hole in the plane as shown.RoThe tension in the string is increased graduallyand finally m moves in a circle of radius Thefinal value of the kinetic energy is [AIPMT-2015](1) 1 mva2(4) 2mvAakash Educational Services Pvt. Ltd.-Regd. Office: Aakash To |
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| 3562. |
3.A rectangular bax slide down an inclined smooth plane making an angle e1with the horizontal. What is ts aceleration? |
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| 3563. |
derive stokes law by densional analysis |
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Answer» Suppose a spherical body of radius r moves at speed v through a fluid of viscosityƞ,viscous force F acting on the body depends on r,v andƞ.According to the dimensional analysis we can write, Let F =kravbƞc Where k is the dimensional less constant. MLT-2=kLa(LT-1)b(ML-1T-1)c On equating the coefficients of M,L,T on both sides we get :a,b,c each = 1hence F =krvƞ,value of k =6π,hence stokes law becomes, F =6πƞrv This is the required stokes law |
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| 3564. |
20. State Stokes' law. Derive an expression for the terminalverive an expression for the terminal velocity of a sphere falling through a viscousor |
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Answer» Strokes law: The force that retards a sphere moving through a viscous fluid is directly ∝to the velocity and the radius of the sphere, and the viscosity of the fluid. |
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| 3565. |
.Derive lens formula forconvex lens. |
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Answer» Ans :- OF1=Focal length=fOA=object distance=uOA'=image distance=vTriangle OAB similar to Triangle OA'B'angleBAO=angle B'A'O=90°so, angle AOB=angleA'B'OA'B'/AB=OA'/OA ---------------(1) Triangle OCF1 similar to Triangle F1A'B' A'B'/OC=A'F1/OF1OC=ABA'B'/AB=A'F1/OF1=OF1-OA'/OF1A'B'/AB=OF1-OA'/OF1---------------(2) from eqn 1 and 2 we get OA'/OA=OF1 - OA'/OF1-v/-u= -f-(-v)/-fv/u= f+v/f-vf=-uf+uv on dividing both sides by uvf we get 1/u=1/v+1/f1/v-1/u=1/f magnification m=height of image /height of object or m=v/u |
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| 3566. |
. Derive the mathematical formula of conservation of momentum. |
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| 3567. |
Derive Lens Maker's formula for a convex lens. |
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Answer» Lens formula1/f = 1/v - 1/uwhere ,f = focal lengthv = image distanceu = object distance |
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| 3568. |
In order to change the range of a galvanometer ofG Q resistance from V volts to nV volts what willbe the value of resistance in Ω connected in serieswith it :-(3) nGn-1 |
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Answer» Option (1) is correct. option 1 is correct...I want reason |
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| 3569. |
A galvanometer has a resistance of G ohm and range of V volt. Caloulate the resistercused in series with it to extend its range to nV volt. |
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Answer» resistance= voltage/ current =( (nV)/i) ohms |
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| 3570. |
Q.1. What is represented by joule/coulomb. A charge of 2C moves between two plates, maintained atJa p.d of 1V. What is the energy acquired by the charge? |
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Answer» Jouleis a unit for work done andcoulombis the unit for the charge. The potential is defined as the ratio of the work done to the charge and the unit of the potential difference is volt. Hence, onejoulepercoulombis equal to the unit of the potential difference. Therefore it will be equal to one Volt. |
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| 3571. |
3. The radius of the third Bohr orbit for hydrogenis 4.5 Å. The radius of its fourth Bohr orbit is:[2014(A)(i) 7.2 Å(ii) 9.6 Å(i) 80 A(iv) 11-3 Á |
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Answer» (ii) 0.8 Å |
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| 3572. |
Define thermal capacity |
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Answer» Heat capacity or thermal capacity is a measurable physical quantity equal to the ratio of the heat added to an object to the resulting temperature change. |
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| 3573. |
. What is angle of friction between two surfaces in contact if the coefficient of friction is 1/ sqrt 3 |
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Answer» The coefficient of friction = tan ∅ So, your angle would be 30 degree......... |
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| 3574. |
An object of mass m is moving on a rough 5horizontal road with momentum α. If thecoefficient of friction between the object and theroad be u, then the stopping distance is :-0%(2umg2 2umg2Ol(3) 2μ㎡g(4) 2um g |
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Answer» The answer is Option 4. Replace the p by alpha why i dont understand tell me Let the dist be x and the rest is in the image. Hope my handwriting is understandable and the answer is correct! Have a nice day!(~ ̄△ ̄)~ Let the dist be x and the rest is in the image. Hope my handwriting is understandable and the answer is correct! Have a nice day!(~ ̄△ ̄)~ |
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| 3575. |
,uunuliugalforceandrotationof earthhen the road is dry and coefficient of friction is μ the maximum speed of a car in a aralar path is10 ms-. If the road becomes wet and coefficient of friction become , what is the maximum speedpermitted?F-1. W2 |
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Answer» yes |
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| 3576. |
1) 25N4.The coefficient of friction is 0.75. If sin37%: 0.6, the angle of friction is42703) 740 |
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Answer» tan∅ = 0.75 => ∅ = tan-¹(3/4). = sin-¹(3/5) = > sin∅ = 0.6so, ∅ = 37° |
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| 3577. |
block(3) TU N35. Acceleration of block A varies with time as shown in figurethe value of coefficient of kinetic friction betweenA and B is5 m/s4.9 m/s30°ns)10 Sthe value of coefficient of kinetic friction between block A and B is(2) 06(4) of these(3) 0.4 |
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Answer» mass A will move only due to the frictional force acting on it... amd the value will be μmg acceleration A , when after Time = 10sec M.a = μMg => a = μg => 4.9 = μ*(9.8)=> μ = 4.9/9.8 = 0.5 option 1 |
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| 3578. |
find a Lens Maker equation? |
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Answer» PLEASE LIKE AND SHARE THIS APP |
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| 3579. |
lens maker formula explain with diagram |
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| 3580. |
lens maker formula for convex simple way? |
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| 3581. |
Q.16 (a) Stating assumptions and sign convention, derive expression for Lens maker's formula(b) For an equ·convex lens of power 2D. What should be radius of curvature of surfaces, using glass of μ = 1.5 |
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Answer» plz answer the question |
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| 3582. |
26.Derive the lens formula for a concave lens, using the necessary ray diagram. |
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| 3583. |
JxDerive the lens formula for a thin concave lens,using the necessary ray diagram. |
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Answer» Lens maker's Formula: It is a relation that connects the focal lengthof a lens to radii of curvature of the two surfaces of the lens and the refractive index of the material of the lens. following assumption are considered while deriving lens maker's formula for concave lensa) only point object is takenb) the aperature of the lens is smallc) the lens is thin |
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| 3584. |
Check the correctness of the equation S=u l^{2}+\frac{1}{2} a t^{2} by dimensional analysis. |
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Answer» All the terms in the equation should have same dimensions. [s] = L[ut²]=LT⁻¹×T² = LT¹ Hence, the equation is dimensionally incorrect. |
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| 3585. |
Derive the expression for centripetal forcewhich is proportional to mass ofbody, radius of road & velocity of vehicleusing dimensional analysis. |
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| 3586. |
(B)62. If the length of a wire is doubled, its Bbe qu2Ίnductance willS (B) be quadrupled(D) be halved1w1(A) remain unchanged(C) be doubled |
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Answer» Answer isconductance gets Halvedwhenlength of conductor is doubled(if you need the reason please read explanation below)Conductance = 1 / ResistanceWhich means as resistance increase conductance will decrease {ORwhen resistance decrease conductance increase }Here length is doubledwe know That when length of a conductor is doubled resistance also gets doubled . So as Resistance gets doubled Conductance gets Halved |
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| 3587. |
What are Bohr's orbits called stationary states? |
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Answer» Energies in which electrons revolve in a shell is fixed. Hence, bhor's orbit are called stationary states. |
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| 3588. |
Forthe same thickness of the lens, if the radius of curvature is increased, the focal length will4.a. reduced.b. remain unchanged.c. increased.d.be imposible to estimate.S At uhet dietan |
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Answer» Focal length will increase with the increase in the radius of curvature |
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| 3589. |
What kinetic energy of a neutron will beassociated by the de-Broglie wavelength1.32 x 1010 m? Given that mass of a neutron-1.675 X 10 27 kg. |
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| 3590. |
3. State the rour conservation lawstoF lucleal feactiOIrS4. Write an equation for the nuclear reaction, when 23 U nucleus absorbsa neutron. Why doesit become B-active after absorbing the neutron? |
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Answer» A nuclear chain reaction occurs when one single nuclear reaction causes an average of one or more subsequent nuclear reactions, thus leading to the possibility of a self-propagating series of these reactions. The specific nuclear reaction may be the fission of heavy isotopes (e.g., uranium-235, 235U). The nuclear chain reaction releases several million times more energy per reaction than any chemical reaction. History Fission chain reactionEdit Fission chain reactions occur because of interactions between neutrons and fissile isotopes (such as 235U). The chain reaction requires both the release of neutrons from fissile isotopes undergoing nuclear fission and the subsequent absorption of some of these neutrons in fissile isotopes. When an atom undergoes nuclear fission, a few neutrons (the exact number depends on several factors) are ejected from the reaction. These free neutrons will then interact with the surrounding medium, and if more fissile fuel is present, some may be absorbed and cause more fissions. Thus, the cycle repeats to give a reaction that is self-sustaining. Nuclear power plants operate by precisely controlling the rate at which nuclear reactions occur, and that control is maintained through the use of several redundant layers of safety measures. Moreover, the materials in a nuclear reactor core and the uranium enrichment level make a nuclear explosion impossible, even if all safety measures failed. On the other hand, nuclear weapons are specifically engineered to produce a reaction that is so fast and intense it cannot be controlled after it has started. When properly designed, this uncontrolled reaction can lead to an explosive energy release. |
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| 3591. |
A neutron is moved perpendicularly in a uniformmagnetic field. The magnetic force acting on theneutron will be(1) Perpendicular to its velocity(2) Along its velocity3) Opposite to its velocity4) Zero |
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| 3592. |
iv. An object kept 60 cm fromalens1Vgives a virtual image 20 cm in frontof the lens. What is the focal lengthof the lens? Is it a converging lens ordiverging lens? |
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| 3593. |
An object is kept in front of a concave mirror of focallength 15 cm. The image formed is three times thesize of the object. Calculate the two possible distancesof the object from the image.10. |
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| 3594. |
5) Calculate the focal length of a convex lens which produces a virtual image at a distance of50 cm of an object placed 20 cm in front of it |
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| 3595. |
Example 5.10. An object placed 50 cm from a lens produces a virtual image ata distance of 10 cm in front of the lens. Draw a diagram to show the formationof image and calculate the focal length of the lens. |
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Answer» Object distance=-50 cm(applying sign convention)Since the image distance is lesser than the object distance and a virtual image is formed, it's a concave lens.(v=-10)We are supposed to use lens formula:-1/f=1/v-1/uf is -vev is -veu is -veon simplifying we getf=25/4 or 6.25 cm.magnification=-(v/u) =-10/50=-0.2 |
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| 3596. |
If the radius of a planet shrinks by 2% while its massremaining the unchanged, the acceleration due togravity on the planet's surface would(1) Decrease.(2) Increase(3) Remain unchanged.(4) First decrease and then increase |
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Answer» thanks |
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| 3597. |
If the radius of a planet shrinks by 2% while its massremaining the unchanged, the acceleration due togravity on the planet's surface would |
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Answer» planet surface would increase because The acceleration due to gravity at the surface of earth is g = G m / R2 . The radius of earth decreases by 2 %, therefore R' = R - 0.02 R = 0.98R. Now acceleration due to gravity will be : g' = GM / ( 0.98 R )2 = 1.04 g Percentage increase in acceleration due to gravity [(g' - g )/g ] x 100 = 4 % |
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| 3598. |
How do you increase the pressure by keeping (a) area unchangedb) force unchanged |
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| 3599. |
Answer the following questions in detail:(1) Derive the formula for spherical mirror1/f = 1/v + 1/u |
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| 3600. |
mirror formula |
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Answer» 1/f = 1/u + 1/v where object distance (u), image distance (v) and focal length(f). |
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