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The male vocal foldsare between 17 mm and 25 mm in length. The femalevocal foldsare between 12.5 mm and 17.5 mmlong.

it's between 17mm to 25mm

thanks mch

Power = Voltage * CurrentGiven,Voltage = 220 vCurrent =.50 A

Power = (220*5)/10 = 22*5 = 110 watt

Power=VI=0.5*220=110Watt

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a. 1.5 KHz = 1500 Hz = 1500 vibrations/second (for sound)

It is because thesound producedby the pendulum is of much lower frequency than that ofbee. thesound producedbybee'swing is continous where as thesoundproducer by the pendulum is just once or twice . thus thesoundfrom the pendulum by the timewe hear, vanishes in the air

the general range for human ear to perceive sound is between frequency range 20Hz to 20kHz. The humming of bees produces a sound of frequency that lies in this range while pendulum vibrations are of much lower frequency. The oscillations in pendulum is slow thus it has low frequency.

= 4x³-2cosx-3sinx , option d.

Anopaqueobject is completely impervious to light, whichmeansyou cannot see through it. ... The less transparent the window is, the higherits opacity. In other words, transparency andopacity areinversely related. Most digital imagesare 100%opaque

opaque object are object which doesn't pass the light through it..but transparent object will pass the light through it

opaque object are which doesn't pass through it but transparent object can pass light through itplease like my answer

same to sameera answer

opaque objects do not pass the light through them while transparent objects allow light completely to pass through them

Volume of water displaced = Volume of block

Mass = Volume * Density= 300 cm^3 * 1g/cm^3= 300 g

Mass of water displaced is 300g

When a bottle is completely immersed in a water , it experiences two kinds of forces, weight of the bottle in downwards direction and upthrust which acts in upward direction.In this case, as we release the bottle completely immersed in water, it rises up because upthrust acting on bottle by water is more than the weight of water.

Magnitude of a vector cannot be negative. Magnitude is always positive. Magnitude is some thing which can be measured, like mass, velocity or distance travelled etc. Magnitude means quantity.

1. when magnitude and direction of velocity do not change , acceleration of moving body is zero

2.This "negative" acceleration is actually called deceleration. It means that over time, you are slowing down instead of speeding up- your velocity is continously decreasing. To show this decrease, mathematically we put a negative sign to indicate this.

3.when the acceleration is in the direction of motion then there must be an positive acceleration.

Positive AccelerationWhen the velocity of an object increases, the acceleration is positive.In this case, the acceleration is in the direction of Velocity.

Negative Acceleration When the velocity of an object decreases with time,it has negative Acceleration.Negative acceleration is also called deceleration.Its directions is opposite to the direction of Velocity.

Zero Acceleration If the velocity of the object does not change with time,it has zero acceleration.

his answer is a and b both positive and negative because the when the velocity of an object increases the acceleration can produce and the acceleration is positive .and when the velocity of an object decrease within the time it has negative acceleration

Let the mass of the bucket be M .

=> Net force on the bucket = Mg + F = M×a where F is the force applied by the man and a is the net acceleration of the bucket , which , in this case is 1 m/s^2 .

=> F = M×(1-g) = -ve

Work done = F.s = (-ve) × (+ve) = -ve

Thus work done by man is negative. [ Note : We have taken downward direction as positive . ]

Relative Density = Density of Block / Density of Water

Density of water = 1 g / cc

Now,

Density of block = Mass / Volume = 750 g / 250 cc = 3

Relative Density = Density of Block / Density of Water

Density of water = 1 g / cc

Now,

Density of block = Mass / Volume = 750 g / 250 cc

= 3

The answer is 3

Thank u

P = P₀ + ρgh Where P₀ is the atmospheric pressure , g is acceleration due to gravity, h is the height from the Earth surface and ρ is density of water Here, P₀ = 10⁵ N/m² , g = 10m/s² , h = 3000m and ρ = 10³ Kg/m³ Now, P = 10⁵ + 10³ × 10 × 3000 = 3.01 × 10⁷ N/m²

Again, we have to use formula, B = P/{-∆V/V} Here, B is bulk modulus and { -∆V/V} is the fractional compression So, -∆V/V = P/B Put , P = 3.01 × 10⁷ N/m² and B= 2.2 × 10⁹ N/m²∴ fractional compression = 3.01 × 10⁷/2.2 × 10⁹ = 1.368 × 10⁻²

Suppose acceleration is in direction of man going downwards so by drawing the diagram and using fbd consider g to be 10 so the mass of the person is 100kg and 125kg of the chair , we get the following 2 equations 1 T- 450N (force applied by the man) = 45a (450÷g i.e mg÷mg = m) and 2- [mg (of man) + mg of chair = (mass of man + mass of chair) so putting values the equation are as follow 1)T - 450N = 45a , 2) 1250 - T = 125 a. Solving equation via elimination method we get a= 4.70

Mass of the body,m= 0.40 kg

Initial speed of the body,u= 10 m/s due northForce acting on the body,F= –8.0 NAcceleration produced in the body, a = F / m = -8.0 / 0.40 = -20 ms-2

(i) Att= –5 sAcceleration,a‘ = 0 andu= 10 m/ss =ut+ (1/2) a’ t2= 10 × (–5) = –50 m

(ii) Att= 25 sAcceleration,a” = –20 m/s2andu= 10 m/ss’ = ut’ + (1/2) a” t2= 10 ×25 + (1/2)×(-20)×(25)2= 250 – 6250 = -6000 m

(iii) Att= 100 sFor 0 ≤ t ≤ 30 sa = -20 ms-2u = 10 m/ss1= ut + (1/2)a”t2= 10×30 + (1/2)×(-20)×(30)2= 300 – 9000 = -8700 mFor 30 < t ≤ 100 s

As per the first equation of motion, fort= 30 s, final velocity is given as:v=u + at= 10 + (–20) × 30 = –590 m/sVelocity of the body after 30 s = –590 m/sFor motion between 30 s to 100 s, i.e., in 70 s:s2= vt + (1/2) a” t2= -590×70 = -41300 m∴ Total distance, s” = s1+ s2= -8700 -41300 = -50000 m = -50 km.

thankyou for short answer

luggageis usually tied with a rope on theroofof buses. When a moving bus suddenly stops, theluggageon itsrooftends to continue in the state of motion due to inertia of motion. ... Thus, to avoid the falling of theluggage, it is tied with a rope on theroofof a bus

Luggage will fall on the head of passengers and they will get hurt

Luggage trolleys are provided with wheels to reduce friction between the wheels and ground as we know that static friction is more than rolling friction so the trolleys are provided with wheels so that we can easily move them from one place to another without experiencing any discomfort.

Anionis a charged atom or molecule. It is charged because the number of electrons do not equal the number of protons in the atom or molecule. An atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom.

So resultant lies between 4 N and 16 N .So,option [2] is correct.

A secondhand makes a complete revolution (360 degrees) in 60 seconds, so it displaces 6 degrees for every second of elapsed time (360/60 = 6).

And in 10 seconds, it will make a displacement of 10 degrees (6 * 10 = 60). So, it is 60 degrees

Finally, to convert into radiant, multiply degrees with π/180

Hence, 60Deg× π/180 = 1.047Rad .

We know 360°= 2π rad

=>1°= (π/180) rad = 0.01745 rad

1'= (1/60)°= π/(60 × 180) = 0.00029 rad

1''= (1/3600)°= π/(3600 × 180) = 0.0000048 rad

The object is falling under gravity. As it is moving towards the earth, Its acceleration is +g.

As it is dropped, It has initial velocity = 0 .

The stone passes the window of 2m high in 0.1s .

Let the distance between the roof and that window be " k " km and the time taken to reach that " k "m is t

That is k = 1/2gt² ( From the second equation of motion)

Given that, Stone passes through the window in 0.1 second.

So it travels k+2 m in t + 0.1seconds .

k + 2 = 1/2g(t+ 0.1)²

Substituting the value of k,

1/2gt² + 2 = 1/2g(t²+0.01 + 0.2t)

1/2gt² - 1/2gt² + 2 = 0.005 g + 0.1gt

2 = 0.005 * 10 + 0.1(10)t 2= 0.05 + t 2 - 0.05 = t 1.95 = t.

Therefore, The stone takes 1.95seconds to travel from roof to top of the window.

Now, We have to find The distance between roof and top of the window ( k)

k = 1/2(10)(t²)k = 5t² k = 5(1.95)²k = 19.0125

Therefore, The height of the roof above the top of the window is 19.0125m

power = F.v

v has to be increased by n

oppossing force is proportional to v^2

totally n^3

Option (c) is correct.

# The magnetic field produced by a current carrying solenoid is similiar to the magnetic field produced by a bar magnet.

# One end of the current carrying solenoid acts like a magnetic north pole while the other acts like a south pole

Ans :- Groundwateris thewaterfoundundergroundin the cracks and spaces in soil, sand and rock. It is stored in and moves slowly through geologic formations of soil, sand and rocks called aquifers.

we shall use the following kinematic equation to describe the vertical motion of the ball to to its maximum height (half its journey in flight)

v = u + at

here

v = o

u = 9.8 m/s

a = -9. m/s2

thus,

0 = 9.8 - 9.8t

so, the time taken by the ball to reach maximum height will be

t = 9.8 / 9.8 = 1 secs.

or total time of flight, T = 2t = 2 secs

now, the horizontal distance travelled by car in 2 seconds will be

s = uT + (1/2)aT2

here,

u = 0

T = 2 secs.

a = -1 m/s2

thus,

s = 0 + (1/2).-1.22

so, the distance between ball and car will be

s = -2m

Solve For Time In Y Direction:Vy = Vyo + Ay*Time(20 m/s)*sin(ang) = (-20 m/s)*sin(ang) + (-9.81 m/s^2)*TimeTime = (40 m/s)*sin(ang)/(9.81 m/s^2) = 4.08*sin(ang)

Solve For Time In X Direction:Vx = Vxo + Ax*Time(20 m/s)*cos(ang) = (-20 m/s)*cos(ang) + (-4.0 m/s^2)*TimeTime = (40 m/s)*cos(ang)/(4.0 m/s^2) = 10*cos(ang)

Set Times For X And Y Equal To Each Other:4.08*sin(ang) = 10*cos(ang)tan(ang) = 4.08/10hence angle is tan^-10.4