InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 4001. |
Two vectors have magnitudes 3 unit and 4 unitrespectively. What should be the angle betweenthem if the magnitude of the resultant is -(i) 1 unit (ii) 5 unit (iii) 7 unit(1) 180°, 90°, 09 (2) 80°, 70º,0°(3) 90°, 170°, 50°(4) of these |
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| 4002. |
j is :-The area of parallelogram represented by the vectors A = 2i +3j and B-1 +4(A) 14 unit(B) 7.5 unit(C) 10 unitD) 5 unit |
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Answer» Given A = 2i+3j and B = i+4j . Area of paralleogram A x B = (2i+3j+0k) x(i+4j+0k) For i component we have, (3 * 0) - (4 * 0) = 0 For j component we have, (0 * 2) - (1 * 0) = 0 For k component we have, (2 * 4) - (1 * 3) = 5. Now take the magnitudeof this vector to find the area of the parallelogram: A * B = Whole root of 0^2 + 0^2 + 5^2 = 0 + 0 + 5(Square and root will be cancelled) = 5 units. |
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| 4003. |
1.If the equation of motion of standing waveis y-0.3sin(314t-1.57x), then the velocityof standing wave is:(A) 400 unit (B) 350 unit(C) 209 unit (D) 200 unit |
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Answer» v=w/k=314/1.57=200 unit |
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| 4004. |
A motor of power 0.98 kW drags a mass 100kg through 2m on asurface having coefficient of friction O.3. Time of that mass is1) 0.4 sec2)0.61 sec.2 sec4) 0.2 sec |
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Answer» Power =force * displacement / timegivenP=0.98 kWm=100 kgs=4 mu= 0.3( from s=at sqr)F=mu ma (a = s/t sqr)0.3*100*4/t sqr120/t sqrpower =force * displacement / time0.98 kW = 120/t sqr * 4/t |
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| 4005. |
H. A particle A having a charge of 20 x 10"C and a massof 100 g is placed at the bottom of smooth inclinedplane of inclination 30". Where should another particleB, having same charge and mass, be placed on theincline so that it may remain in equilibrium? |
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| 4006. |
aCovert I goule post Erg, |
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Answer» Joule is the unit for energy Dimension Formula for Joule is [M¹L²T⁻²] Let n1(joule)=n2(erg) n1(M₁¹L₁²T₁⁻²]=n2[M₂¹L₂²T₂⁻²] n2=n1(M₁¹L₁²T₁⁻²]/M₂¹L₂²T₂⁻²] =n1x(M1/M2)¹x(L1/L2)²x(T1/T2)⁻² =1x(1kg/gm)¹x(1m/1cm)²x(1s/1s)⁻² =1x(1000g/gm)x(100cm/1cm)²x(1s/1s)⁻² =10⁷Therefore n1(joule)=n2(erg)∴1 Joule=10⁷erg |
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| 4007. |
Calculate the force of gravity on a body of mass 100kg placed on the surface of the earth |
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Answer» F=mg=100*10=1000N No answers is wrong Gravitational lesson name and subject is science |
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| 4008. |
EXAMPLE 1.35: An aluminium wire has a diameter of 0.5 mm and a resistivity of 2.6 x 10 2 m. Howmuch of this wire would be necessary to make a resistance 10 927 |
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| 4009. |
19) The stopping potential (Vo) versusfrequency (n) plot of a substance is shown infigure the threshold wave length is4 5 6 78x1014HzA) 5 x 1014nmB) 6000?C) 5000?D) Cannot be estimated from given data |
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| 4010. |
he torque acting on a dipole of moment p in an electric field E is(a) p E(c) Zero(b) p x E(d) Ex p |
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Answer» option (b) torque=P×E=PEsin(theta) |
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| 4011. |
. What is the flux due to electric fieldE-3x10 iNC-1 through a square of side10cm, when it is held normal to E? |
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Answer» hii what is your whatsapp number? |
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| 4012. |
Agrind-stonestartsrevolvingfrom rest, if its angular acceleration is 4.0 rad/sec? (uniform) then after 4sec. What is its angular displacement & angular velocity respectively(1) 32 rad, 16 rad/sec(3) 64 rad, 32 rad/sed(2) 16 rad, 32 rad/sec(4) 32 rad, 64 rad/sec도。 |
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| 4013. |
. An equilateral triangular surface with side length((meter), in the plane of the paper is placed in auniform electric field E V m acting along thesame plane at an angle θ with the horizontalbase of the triangle as shown in the figure. Theelectric fiux linked to the surface in units of V m is(e) E008cos e43-(d) zero |
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Answer» The answer will be. option D ...0 because here the plane of triangle and the plane of electric Field is parallel to each other.. so, no flux will pass through the area of the triangle.. as flux = B× A and cross product of two parallel vectors is always 0. |
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| 4014. |
4) The electric field in a region is given by B-클 E oitt E , i withEo= 2.0× 103 N/c. Find the flux of this field through a rectangular surface ofarea 0.2 m2 parallel to the Y-Z plane. |
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| 4015. |
A thin conducting ring of radiusR is given a charge +Q. Theelectric field at the centre O ofthe ringdue to the charge onthepart AKB of the ring is E. Theelectric field at the centre due tothe charge on the part ACDB ofthe ring is(a) E along KO.(b) 3E along OKC(O:(c) 3E along KO.(d) E along OKAIPMT 2008] |
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| 4016. |
Two identical balls of charges q, & q, initially haveequal velocity of the same magnitude and direc-tion. After a uniform electric field is applied for sometime, the direction of the velocity of the first ballchanges by 60° and the magnitude is reduced byhalf. The direction of the velocity of the secondball changes there by 90°. In what proportion willthe velocity of the second ball changes ? |
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| 4017. |
6) The electric field in the region of the space isE (5i +2 j +3 k) NC. The electric fluxpassing through a surface of area 50m2 placedin X-Y plane inside the electric field is(A) 250 Nm2c-1(C) 100 Nmc-1(B) 150 Nm2C-1(D) 200 Nm2C-1 |
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Answer» In x- y plane so inside the electric field= 5i+2j+3kflux= 5i+2j+3k*(0i+0j+50k)150Nm^2/Cplease like the solution 👍 ✔️ |
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| 4018. |
In Fleming's left-hand rule, Middle finger of the left hand indicatesA. direction of electric force applied on a conductorB. direction of the electric field.C. direction of the flow of electric currentD. of these |
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Answer» CIn Fleming left hand rule middle finger is for flow.of current. |
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| 4019. |
How does the electric field inside a dielectric decreases when it is placed in an externalelectric field? |
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Answer» An appliedelectric field polarized the dielectric material by orienting the dipole moments of polar molecules. This decreases the effectiveelectric fieldbetween the plates andwillincrease the capacitance of the parallel plate structure |
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| 4020. |
When baking soda is mixed with lemon juice, bubbles are formed with the evolutionof a gas. What type of change is it? Explain. |
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| 4021. |
1. A plane surface of area 200 cm2 is kept im a uniformelectric field of intensity 200 N/C. If the angle betweenthe normal to the surface and field is 60°, the electric fluxthrough the surface is |
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Answer» Since the angle from the normal of the area is = 60° so, the angle between the plane of area and the electric Field will be = 90-60 = 30° = ∅ and theFlux is given by = E×A = E.Asin∅ flux = 200* (200) × 10^-⁴ × sin30° = 2*2/2 = 2N-m²/C |
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| 4022. |
17.) What happens when an electric dipole is suspended in auniform electric field? |
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| 4023. |
. What procedure will you follow to study magnetic field, if you are provided with parafin oil,iron nail, bar magnet, battery, coil conductor wire? |
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Answer» To study magnetic field , an electromagnet can be made using iron nal, wire and battery.For making electromagnet, iron nailed is first coiled with wire and then the wire is connected to a battery. When any magnetic material is brought near the bar magnet, it will got attracted towards the magnet . While any non-magnetic material will not get attracted by it. Thus the effect of magnetic field can be studied that a magnet attracts magnetic material or objects. And bar magnet is a parmanent magnet that will always attract magnetic material, unlike iron nail that required a battery connection to work as a magnet . So magnetic field can be studied by comparing magnetism created using two types of magnet that is parmanent magnet that is bar magnet . And temporary magnet that is electromagnet . |
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| 4024. |
ery Short Answer Type QuestionsdeHow dof current I?1.oes the heat H produced by a current passing through a fixed resistance wire depend on the magnituliu iho nhane in heat produced ? |
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Answer» Heat produced by a current flowing through a fixed resistance is directly proportional to the square of current...H~I² sir please give me your whatsapp no |
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| 4025. |
of a1. A force of 30 N acts on a body and moves itthrough a distance of 5 m in the direction of force.Calculate the work done by the force.What |
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Answer» we know thatwork done = force× displacementW= F×s×costheta= (30× 5 ×cos0°)J= 150J hence, workdone= 150 joules |
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| 4026. |
Semi-Ciradas Rimttttar charge)aFindElectric field act centrelo? |
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Answer» here the radius of semi circle is R |
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| 4027. |
A ball of 1 kg drops vertically onto the floor with a speed of 25 m/s. It rebounds with an initial velocity of10m/s. What impulse acts on the ball during contact(A) 35 kg m/s downwards(C) 30 kg m/s downwards(B) 35 kg m/s upwards(D) 30 kg m/s upwardsPna 16 Ph: 9708038432/33 |
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| 4028. |
5. A block of mass 5 kg is moving horizontally at aspeed of 1.5 m/s. A vertically upward force 5 N actson it for 4 second. The distance of the block after4 second, from the point where the force startedacting, will be(1) 2 m(3) 8 m(2) 6 m(4) 10 m |
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| 4029. |
A man who wears glasses of power 3 dioptre must hold a newspaper at least 25 cmaway to see the print clearly. How far away should the newspaper have to be if he tookoff the glasses and still wanted clear vision? |
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| 4030. |
why nichrome alloy is used for makingheating element of electric appliances |
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| 4031. |
Name two safety measures commonly used in electric circuits andappliances. |
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| 4032. |
Name two safety measures commonly used in electric circuits andappliances.t. |
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| 4033. |
What is an electric motor? Name any two electrical appliances in which an electric motor is used. |
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Answer» an electric motor is an electrical machine that converts electrical energy into mechanical energy. Most electric motors operate through the interaction between the motor's magnetic field and winding currents to generate force in the form of rotation. The fan over the stove and in the microwave oven. The dispose-all under the sink. The blender. The can opener. |
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| 4034. |
what are point source of light |
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Answer» a point source is a single identifiable localised source of something. a point source has negligible extent, distinguishing it from other source geometries. e.g.. light passing through a pinhole or other small aperture, viewed from a distance much greater than the size of the hole. point source of light are points in definition that emit radiation or light. they are minute small points just like in mathematics |
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| 4035. |
at the bottom of a tank containing waterat is the area of the surface of water thirthe bulb can emerge out? Refractive index ofof1.33. (ConsConsider the bui to beider the bulb to be a point source.) |
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| 4036. |
4. What is an electric motor ? Name any two electrical appliances in which an electric motor is used.2 |
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Answer» Electrical appliance – Fan, washing machine, mixer. Fleming’s Left Hand Rule – It states that ‘‘Stretch the forefinger, the central finger and the thumb of your left hand mutually perpendicular to each other. If the forefinger shows the direction of the magnetic field and the central finger that of the current then the thumb will point towards the direction of force on of the conductor. An electric motor is an electrical machine that converts electrical energy into mechanical energy. Most electric motors operate through the interaction between the motor's magnetic field and winding currents to generate force in the form of rotation. |
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| 4037. |
If the speed of sound is 336 m/s in air, then findshortest length of the one end closed tube thatresonate with a fork of frequency 210 Hz. |
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| 4038. |
A Beries. iR tircvit consisks of Resistance op to.na capacitor ol reackance 60n and induchorThe ciycuit is found to resonate when put atcess300V -1001 la-supplyi Inductance of coil ?0cotrent at citcuit ot tesonance |
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Answer» please send complete photo |
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| 4039. |
21. A man slides down a light rope whose breakingstrength is η times the weight of man (η < 1). Themaximum acceleration of the man so that the ropejust breaks is |
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Answer» When he moves down mg-nmg=ma a=g(1-n) |
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| 4040. |
2. Velocity of sound in air is 330 m s1. A closedorgan pipe has a length of 0.5 m. Neglectingend correction, the air column in the pipecannot resonate with sound of frequency(a) 165 Hz(c) 495 Hz(e) 1155 Hz(b) 330 Hz(d) 825 Hz |
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Answer» F = v/4l330/4*0.5165Hzis the answer |
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| 4041. |
A man whose mass is m kgjumps vertically into air from a sitting position in which his centre of mass isat a height h, from the ground. When his feet are just about to leave the ground his centre of mass is h2from the ground and finally rises to hy when he is at the top of the jump. What is the average upwardforce exerted by the ground on him? |
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| 4042. |
to a rigid support carries a rope whose one end is tied to a ladder with a man andm climbs up a distance h withA pulley fixedthe other end to the counterweight of mass M. The man of massrespect to the ladder and then stops. If the mass of the rope and the friction in the pulley axle arnegligible, find the displacement of the centre of mass of this system. |
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Answer» find the displacement in centre of mass of the system find end displacement of man with respect to ground. Let X be the displacement of ladder so displacement of man with respect to ground is h-X (we take downward direction as negative). Displacement of centre of mass = [Mx-x(M-m)+m(h-x)]/(M+M-m+m)= mh/2M. (Mass of ladder is M-m the system was initially at rest) Displacement of center of mass is zero. Reason: On height gain of man relative to the ladder, ladder as well as stone of mass M adjust their respective heights according to: F(ext.)*disp. of C.O.M.=ext. work done on the system and ext. work done=0. |
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| 4043. |
Suggest a sphorucal mirhar pom which the unage ostanidinvutual andl small |
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Answer» Convex Mirror is a spherical mirror from which image obtained is always virtual and small. |
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| 4044. |
ShotAhswerTypeQuestions14. (a) What do you understand by the "resistivity" of a substanceA wire is 1.0 mmaterial?0along, 0.2 mm in diameter and has a resistance of 10 2. Calculate the resistivity of its15. (a) Write down an ovnthu resistance of a metallic wire in terms of the resistivity. |
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| 4045. |
2. Write S.I unit of resistivity. (1) |
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Answer» S.I. unit of resistivity is ohm. |
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| 4046. |
1. A wire of resistivity p is stretched to double its length. What is itsnew resistivity. |
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Answer» Since the length of the wire is doubled, its area of cross-section is halved so as to keep the volume of the wire constant. Now the resistance of the wire is proportional to length of the wire, since the length of the wire is doubled its resistance also doubles due to doubling of the length. But resistance is also inversely proportional to the area of cross-section, and as area of cross-section ishalved due to doubling of length,the resistance is once more doubled due to the halfing of the area of cross-section. So overall the resistance of the wire bec Resistivity is proportional to lengthSo,2*l=2*p=2p |
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| 4047. |
The level of water in a tank is 5m high. A holeof area of cross section 1 cm2 is made at thebottom of the tank. The rate of leakage ofwater from the hole in m'sı is ( g = 10ms-2)) 10-2 |
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| 4048. |
0.C. lg2 mo"L25. A Circular disc A of radius r is made from an iron plate ofthickness t and another circular disc B of radius 4r is made from aniron plate thickness t/4. The relation between the moments ofinertia la and Ig isa. Ia > IB b. Ia = lb 1A 1B d. of these |
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| 4049. |
stage # Vint P moves in counter-clockwise direction onA poira circularrcular path as shown in the figure. Theovement of p is such that it sweeps out a length3+ 5, where s is in metres and t is in seconds.-The radius of the path is 20 m. The acceleration of'Pwhen t 2 s is nearly -AIEEE 2010]P(x,y) |
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| 4050. |
I.For a pacticle in uniform circular motion. the acceleration a at a point PR, θ) on the circle of radiusR is (Here 0 is measured from the x-axis).AIEEE 2010) |
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