98971 + Interview Questions in Primary School in Math

1.	Draw maths bar graph std 6gy
Answer» ANSWER: no INFO of BAR GRAPH SORRY

1.

Draw maths bar graph std 6gy

Answer»

ANSWER:

no INFO of BAR GRAPH SORRY

Discussion

2.	Choose the correct fraction for the given decimal number. *89/1006/10012/1006/100.120.60.890.060.120.60.890.06
Answer» Step-by-step explanation: (a) 0.6\ =\ \FRAC{6}{10}=\frac{3}{5}0.6 = 10 6 = 5 3 (b) 2.5\ =\ \frac{25}{10}=\frac{5}{2}2.5 = 10 25 = 2 5 (c) 1.0=\frac{10}{10}=11.0= 10 10 =1 (d) 3.8=\frac{38}{10}=\frac{19}{5}3.8= 10 38 = 5 19 (e) 13.7=\frac{137}{10}13.7= 10 137 (f) 21.2=\frac{212}{10}=\frac{106}{5}21.2= 10 212 = 5 106 (g) 6.4=\frac{64}{10}=\frac{32}{5}6.4=

2.

Choose the correct fraction for the given decimal number. *89/1006/10012/1006/100.120.60.890.060.120.60.890.06

Answer»

Step-by-step explanation:

(a) 0.6\ =\ \FRAC{6}{10}=\frac{3}{5}0.6 =

10

6

=

5

3

(b) 2.5\ =\ \frac{25}{10}=\frac{5}{2}2.5 =

10

25

=

2

5

(c) 1.0=\frac{10}{10}=11.0=

10

=1

(d) 3.8=\frac{38}{10}=\frac{19}{5}3.8=

10

38

=

5

19

(e) 13.7=\frac{137}{10}13.7=

10

137

(f) 21.2=\frac{212}{10}=\frac{106}{5}21.2=

10

212

=

5

106

(g) 6.4=\frac{64}{10}=\frac{32}{5}6.4=

Discussion

3.	The length and breadth of a rectangle are 3x^2 + 2y^3- xy and 2x + 5y respectively. Find its area.
Answer» Answer: GOOD night FRIENDS have a GREAT DAY

3.

The length and breadth of a rectangle are 3x^2 + 2y^3- xy and 2x + 5y respectively. Find its area.

Answer»

Answer:

GOOD night FRIENDS have a GREAT DAY

Discussion

4.	72 books weigh 8 kg. What is the weight of 81 such books? how many such books will weigh 6 kg
Answer» HEARS the ANSWER HOPE it HELPS

Discussion

5.	Observe the following table and find if x is directly proportional
Answer» <P>Answer: jh Happy P TRISHA too photoshoot DISPARITY APP app app XL xp xp xp PPP

5.

Observe the following table and find if x is directly proportional

Answer»

<P>Answer:

jh Happy P TRISHA too photoshoot DISPARITY APP app app XL xp xp xp PPP

Discussion

6.	Find perimeter and area of a rectangle having length of 8 m breath of 80 cm
Answer» ANSWER: HOPE it helps Please MARK me as BRAINLIEST!!

6.

Find perimeter and area of a rectangle having length of 8 m breath of 80 cm

Answer»

ANSWER:

HOPE it helps

Please MARK me as BRAINLIEST!!

Discussion

7.	1. Associative property is not followed in …………….(a) whole numbers (b) integers (c) natural numbers (d) none of these 2. ……………….. is the identity for the addition of rational numbers.(a) 1 (b) 0 (c) -1 (d)1/2please answer
Answer» Answer: 1) NONE of this( OPTION d) 2) 0( option B)

7.

1. Associative property is not followed in …………….(a) whole numbers (b) integers (c) natural numbers (d) none of these 2. ……………….. is the identity for the addition of rational numbers.(a) 1 (b) 0 (c) -1 (d)1/2please answer

Answer»

Answer:

1) NONE of this( OPTION d)

2) 0( option B)

Discussion

8.	Which equation carries greater value of y?A. y + 7 = 3B. y + 6 = 4C. 13 = -y + 3D. y-5= -6Answers needed now it is very urgent
Answer» Step-by-step EXPLANATION: d is the ANSWER for this QUESTION

8.

Which equation carries greater value of y?A. y + 7 = 3B. y + 6 = 4C. 13 = -y + 3D. y-5= -6Answers needed now it is very urgent

Answer»

Step-by-step EXPLANATION:

d is the ANSWER for this QUESTION

Discussion

9.	What is 15365 ÷6756tell me the answer
Answer» 15365÷6756 = 2.27427471877 Hope it HELPS U

9.

What is 15365 ÷6756tell me the answer

Answer»

15365÷6756 = 2.27427471877

Hope it HELPS U

Discussion

10.	A train takes 3 hours to reach station B freom station A.which is 144km away. how long will it takes to cover 240 km?
Answer» Answer: cihy the TIME to EXPLORE NEW WAYS of learning and smart ways of learning and smart ways of learning and smart ways of learning and smart ways you please let us questions or comments regarding this is a tenths you

10.

A train takes 3 hours to reach station B freom station A.which is 144km away. how long will it takes to cover 240 km?

Answer»

Answer:

cihy the TIME to EXPLORE NEW WAYS of learning and smart ways of learning and smart ways of learning and smart ways of learning and smart ways you please let us questions or comments regarding this is a tenths you

Discussion

11.	Compare 57/4______24/7
Answer» Answer: 57/4 > 24/7 57/4 is GREATER than 24/7

11.

Compare 57/4______24/7

Answer»

Answer:

57/4 > 24/7

57/4 is GREATER than 24/7

Discussion

12.	3. The length of rectangle is twice its breadth. The perimeter ofFrame a linear equation is one variable.A) 2x + x = 36 B) 2(2x + x) = 36 C) 2 (2x - x) = 36 D) 2x
Answer» Step-by-step EXPLANATION: ➡️perimeter of rectangle= 2(l+b) so, CORRECT option is B) 2(2x+x)=36

12.

3. The length of rectangle is twice its breadth. The perimeter ofFrame a linear equation is one variable.A) 2x + x = 36 B) 2(2x + x) = 36 C) 2 (2x - x) = 36 D) 2x

Answer»

Step-by-step EXPLANATION:

➡️perimeter of rectangle= 2(l+b)

so,

CORRECT option is B) 2(2x+x)=36

Discussion

13.	Kiyoki vo faltu question tha.
Answer» ANSWER: Infinity represents something that is boundless or endless, or else something that is larger than any real or natural number. It is often denoted by the infinity symbol ∞. Since the time of the ancient Greeks, the philosophical nature of infinity was the SUBJECT of many discussions among philosophers. Step-by-step explanation: hehe HELLO KKRH happy slap day❤

13.

Kiyoki vo faltu question tha.

Answer»

ANSWER:

Infinity represents something that is boundless or endless, or else something that is larger than any real or natural number. It is often denoted by the infinity symbol ∞. Since the time of the ancient Greeks, the philosophical nature of infinity was the SUBJECT of many discussions among philosophers.

Step-by-step explanation:

hehe HELLO KKRH happy slap day❤

Discussion

14.	Express the ratio of 2 kg to 500 grams in the simplest form
Answer» Step-by-step explanation: 1kg=1000gm 2kg=2000gm 2000gm:500gm =2000/500 =4/1 =4:1

14.

Express the ratio of 2 kg to 500 grams in the simplest form

Answer»

Step-by-step explanation:

1kg=1000gm

2kg=2000gm

2000gm:500gm

=2000/500

=4/1

=4:1

Discussion

15.	Cos θ = 1, then cos 2θ =
Answer» Answer: 1 Step-by-step explanation: cos THETA = 1 cos theta is = 1 only on 0 or on 2PI degrees so 0 * 2 = 0 cos 2THETA = cos (2 *0) cos 0 = 1

15.

Cos θ = 1, then cos 2θ =

Answer»

Answer:

1

Step-by-step explanation:

cos THETA = 1

cos theta is = 1 only on 0 or on 2PI degrees

so 0 * 2 = 0

cos 2THETA = cos (2 *0)

cos 0 = 1

Discussion

16.	inside a rectangular garden 18m long and 13m wide, a 1.5 margin has been left for planting roses, and grass has been planted in the rest of the area. if 5 rose plants can be planted in 1metre square, how many plants can be planted in the garden
Answer» Answer: Rectangular GARDEN: length = 18m breadth = 13m Area = lb = 18 X 13 = 234m² Margin: length = 18m - 1.5 - 1.5 = 18 - 3 = 15m breadth = 13m - 1.5 - 1.5 = 13 - 3 = 10m Area = 15 x 10 = 150m² 1m² = 5 roses 150m² = 5 x 150 = 750 roses in the margin Hope it helps!!

16.

inside a rectangular garden 18m long and 13m wide, a 1.5 margin has been left for planting roses, and grass has been planted in the rest of the area. if 5 rose plants can be planted in 1metre square, how many plants can be planted in the garden

Answer»

Answer:

Rectangular GARDEN:

length = 18m

breadth = 13m

Area = lb = 18 X 13 = 234m²

Margin:

length = 18m - 1.5 - 1.5 = 18 - 3 = 15m

breadth = 13m - 1.5 - 1.5 = 13 - 3 = 10m

Area = 15 x 10 = 150m²

1m² = 5 roses

150m² = 5 x 150

= 750 roses in the margin

Hope it helps!!

Discussion

17.	Lately, I've been, I've been thinkingI want you to be happier, I want you to be happierWhen the morning comesWhen we see what we've becomeIn the cold light of day we're a flame in the windNot the fire that we've begunEvery argument, every word we can't take back'Cause with the all that has happenedI think that we both know the way that this story endsThen only for a minuteI want to change my mind'Cause this just don't feel right to mewhich song is this
Answer» ANSWER: NICE poem. Step-by-step EXPLANATION: THANKS for following.

17.

Lately, I've been, I've been thinkingI want you to be happier, I want you to be happierWhen the morning comesWhen we see what we've becomeIn the cold light of day we're a flame in the windNot the fire that we've begunEvery argument, every word we can't take back'Cause with the all that has happenedI think that we both know the way that this story endsThen only for a minuteI want to change my mind'Cause this just don't feel right to mewhich song is this

Answer»

ANSWER:

NICE poem.

Step-by-step EXPLANATION:

THANKS for following.

Discussion

18.	Through a rectangular field of length 90m and breadth 60m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3m, Find:(i) the area covered by the roads(ii) the cost of constructing the roads at the rate of ₹110 per m²➠ Don't Spam➠ Need full Explanation ➠ Attach Diagram if possible !
Answer» Given: Dimensions of a rectangular field: Length = 90 m and Breadth = 60 m. Two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. Width of the roads is 3 m. To find: The area covered by the roads. The cost of constructing the roads at the rate of 110/- per m². Formulae used: Area of square = a² sq.units Area of rectangle = lb sq.units Solution: Look at the figure 1 in the attachment! It shows the complete visual of the field. Now, have a look on figure 2! It VISUALISE us the diagram of intersecting roads. We're asked to find the area of roads. So, we can find it by separating the roads into parts as shown in figure 3, and summing up the area of separate parts. As second question, we're asked to find the cost of constructing roads at a given rate. How can we find it? It's really simple! We can CALCULATE it by multiplying the area of roads with cost per sq.metre. Let's do it !! _____________________________________ ↪️Separation of the road into parts: We can separate the roads into five parts as shown below! Two rectangles (EFGH) & (IJKL) with dimensions: l = 43.5 m and b = 3m. Two rectangles (MHIN) & (LGOP) with dimensions: l = 28.5 m and b = 3 m. A square (CDGH) with SIDE = 3 m. $\:$ ↪️Finding the area of each part: As rectangles EFGH and IJKL have same dimensions, their areas will also be same. So we can find the area of one rectangle and multiply it with two. $\\ \:\:\:\:\longmapsto{\bf{2(Area\:of\:a\: rectangle)}}$ $\\ \:\:\:\:\longmapsto{\bf{2(lb)}}$ $\\ \:\:\:\:\longmapsto{\bf{2(43.5\times 3)}}$ $\\ \:\:\:\:\longmapsto{\bf{2(130.5)}}$ $\\ \:\:\:\:\longmapsto\underline{\bf{\purple{261\:m^2}}}$ $\:$ We KNOW that the dimensions of rectangles MHIN and LGOP are same. So, we can carry out the step by following the METHOD we've used to find the areas of rectangles EFGH and IJKL. $\\ \:\:\:\:\longmapsto{\bf{2(lb)}}$ $\\ \:\:\:\:\longmapsto{\bf{2(28.5\times 3)}}$ $\\ \:\:\:\:\longmapsto{\bf{2(85.5)}}$ $\\ \:\:\:\:\longmapsto\underline{\bf{\blue{171\:m^2}}}$ $\:$ Now, we shall find the area of the square part, i.e, the area of HIGL! By inserting the measure of side in the formula: $\\ \:\:\:\:\longmapsto{\bf{a^2\:sq.units}}$ $\\ \:\:\:\:\longmapsto{\bf{(3)^2}}$ $\\ \:\:\:\:\longmapsto{\bf{3\times 3}}$ $\\ \:\:\:\:\longmapsto\underline{\bf{\pink{9\:m^2}}}$ $\:$ ↪️Area of the roads: By summing up obtained measures of the separated parts of the roads: $\\ \:\:\:\:\longmapsto{\bf{Area\:_{(EFGH+IJKL+MHIN+LGOP+HIGL)}}}$ $\\ \:\:\:\:\longmapsto{\bf{261+171+9}}$ $\\ \:\:\:\:\longmapsto{\bf{432+9}}$ $\\ \:\:\:\:\longmapsto{\boxed{\boxed{\frak{\red{441\:m^2}}}}}$ $\:$ _____________________________________ ↪️Cost of constructing the roads: We know that, The area of the roads = 441 m² Cost of constructing roads per sq.metre = 110/- So, we can find the cost of constructing by multiplying 441 with 110, i.e., $\\ \:\:\:\:\longmapsto{\bf{441\times 110}}$ $\\ \:\:\:\:\longmapsto{\boxed{\boxed{\sf{\red{Rs.\:\frak{48,510}}}}}}$ $\\ \therefore\underline{\sf{The\:area\:of\:the\: roads\:is\:441\:m^2\:\&\:the\:cost\:of\: constructing\:them\:is\:Rs.\:48,510.}}$

18.

Through a rectangular field of length 90m and breadth 60m, two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields. If the width of each road is 3m, Find:(i) the area covered by the roads(ii) the cost of constructing the roads at the rate of ₹110 per m²➠ Don't Spam➠ Need full Explanation ➠ Attach Diagram if possible !

Answer»

Given:

Dimensions of a rectangular field: Length = 90 m and Breadth = 60 m.
Two roads are constructed which are parallel to the sides and cut each other at right angles through the centre of the fields.
Width of the roads is 3 m.

To find:

The area covered by the roads.
The cost of constructing the roads at the rate of 110/- per m².

Formulae used:

Area of square = a² sq.units
Area of rectangle = lb sq.units

Solution:

Look at the figure 1 in the attachment! It shows the complete visual of the field. Now, have a look on figure 2! It VISUALISE us the diagram of intersecting roads. We're asked to find the area of roads. So, we can find it by separating the roads into parts as shown in figure 3, and summing up the area of separate parts. As second question, we're asked to find the cost of constructing roads at a given rate. How can we find it? It's really simple! We can CALCULATE it by multiplying the area of roads with cost per sq.metre. Let's do it !!

_____________________________________

↪️Separation of the road into parts:

We can separate the roads into five parts as shown below!

Two rectangles (EFGH) & (IJKL) with dimensions: l = 43.5 m and b = 3m.
Two rectangles (MHIN) & (LGOP) with dimensions: l = 28.5 m and b = 3 m.
A square (CDGH) with SIDE = 3 m.

$\:$

↪️Finding the area of each part:

As rectangles EFGH and IJKL have same dimensions, their areas will also be same. So we can find the area of one rectangle and multiply it with two.

$\\ \:\:\:\:\longmapsto{\bf{2(Area\:of\:a\: rectangle)}}$

$\\ \:\:\:\:\longmapsto{\bf{2(lb)}}$

$\\ \:\:\:\:\longmapsto{\bf{2(43.5\times 3)}}$

$\\ \:\:\:\:\longmapsto{\bf{2(130.5)}}$

$\\ \:\:\:\:\longmapsto\underline{\bf{\purple{261\:m^2}}}$

$\:$

We KNOW that the dimensions of rectangles MHIN and LGOP are same. So, we can carry out the step by following the METHOD we've used to find the areas of rectangles EFGH and IJKL.

$\\ \:\:\:\:\longmapsto{\bf{2(lb)}}$

$\\ \:\:\:\:\longmapsto{\bf{2(28.5\times 3)}}$

$\\ \:\:\:\:\longmapsto{\bf{2(85.5)}}$

$\\ \:\:\:\:\longmapsto\underline{\bf{\blue{171\:m^2}}}$

$\:$

Now, we shall find the area of the square part, i.e, the area of HIGL! By inserting the measure of side in the formula:

$\\ \:\:\:\:\longmapsto{\bf{a^2\:sq.units}}$

$\\ \:\:\:\:\longmapsto{\bf{(3)^2}}$

$\\ \:\:\:\:\longmapsto{\bf{3\times 3}}$

$\\ \:\:\:\:\longmapsto\underline{\bf{\pink{9\:m^2}}}$

$\:$

↪️Area of the roads:

By summing up obtained measures of the separated parts of the roads:

$\\ \:\:\:\:\longmapsto{\bf{Area\:_{(EFGH+IJKL+MHIN+LGOP+HIGL)}}}$

$\\ \:\:\:\:\longmapsto{\bf{261+171+9}}$

$\\ \:\:\:\:\longmapsto{\bf{432+9}}$

$\\ \:\:\:\:\longmapsto{\boxed{\boxed{\frak{\red{441\:m^2}}}}}$

$\:$

_____________________________________

↪️Cost of constructing the roads:

We know that,

The area of the roads = 441 m²
Cost of constructing roads per sq.metre = 110/-

So, we can find the cost of constructing by multiplying 441 with 110, i.e.,

$\\ \:\:\:\:\longmapsto{\bf{441\times 110}}$

$\\ \:\:\:\:\longmapsto{\boxed{\boxed{\sf{\red{Rs.\:\frak{48,510}}}}}}$

$\\ \therefore\underline{\sf{The\:area\:of\:the\: roads\:is\:441\:m^2\:\&\:the\:cost\:of\: constructing\:them\:is\:Rs.\:48,510.}}$

Discussion

19.	Write a set of square number
Answer» Step-by-step explanation: DRAWING Daisy Wheel 5 3 3 А B 2 2 2 1 1 1 1 This is ALSO called a six point geometry. Six rose petals, seed of life, Dutch HEXAGRAM, thunder ma Web Links Start with radius AB on two perpendicular LINES. Place the compass pointer at B and draw the circle with radius AB. Next, place your compass at point 1 and using the same radius AB SW

19.

Write a set of square number

Answer»

Step-by-step explanation:

DRAWING Daisy Wheel

5

3

А

B

2

1

This is ALSO called a six point geometry. Six rose petals, seed of life, Dutch HEXAGRAM, thunder ma

Web Links

Start with radius AB on two perpendicular LINES. Place the compass pointer at B and draw the

circle with radius AB. Next, place your compass at point 1 and using the same radius AB SW

Discussion

20.	45.35% convert this into the fraction? give step by step explanation. I will mark him brainliest.
Answer» Answer: in 45.35 %here is TWO PLACES before point MEANS we can write it 4535/100 ans please LIKE and mark me BRAINLIST

20.

45.35% convert this into the fraction? give step by step explanation. I will mark him brainliest.

Answer»

Answer:

in 45.35 %here is TWO PLACES before point MEANS we can write it 4535/100 ans please LIKE and mark me BRAINLIST

Discussion

21.	A boundary is required for the square shaped garden of Eva to protect it from stray animals. Length of each side of the garden is 15 feet and cost of building boundary is $5 per feet. What is the amount of money she needs to spend to build a boundary for her garden?
Answer» total perimeter is 60 ft. total expenditure will be 60ft. X 5$ = 300 $

21.

A boundary is required for the square shaped garden of Eva to protect it from stray animals. Length of each side of the garden is 15 feet and cost of building boundary is $5 per feet. What is the amount of money she needs to spend to build a boundary for her garden?

Answer»

total perimeter is 60 ft.

total expenditure will be 60ft. X 5$

= 300 $

Discussion

22.	If weight of 12 books is 900 grams. What will be the weight of 15 such books?
Answer» ANSWER: WEIGHT of ONE BOOK= 900/12=75 weight of 15 books=15*75=1125gram

22.

If weight of 12 books is 900 grams. What will be the weight of 15 such books?

Answer»

ANSWER:

WEIGHT of ONE BOOK= 900/12=75

weight of 15 books=15*75=1125gram

Discussion

23.	[p – 4q + 2 {12 – (3p – q)} + 14{2 – (3p + 4q)}]
Answer» <P>Step-by-step explanation: [p – 4q + 2 {12 – (3p – q)} + 14{2 – (3p + 4q)}] [p – 4q + 2 {12 – 3p +q} + 14{2 – 3p - 4q}] [p – 4q + 2 12 – 23p +2q} + 142 – 143p - 144q}] [p – 4q + 24 – 6p +2Q + 28 – 42p - 56q] [p - 42p - 6p - 4q + 2q - 56q + 24 + 28] [-47p -58q + 52]

23.

[p – 4q + 2 {12 – (3p – q)} + 14{2 – (3p + 4q)}]

Answer»

<P>Step-by-step explanation:

[p – 4q + 2 {12 – (3p – q)} + 14{2 – (3p + 4q)}]

[p – 4q + 2 {12 – 3p +q} + 14{2 – 3p - 4q}]

[p – 4q + 2 *12 – 2*3p +2*q} + 14*2 – 14*3p - 14*4q}]

[p – 4q + 24 – 6p +2Q + 28 – 42p - 56q]

[p - 42p - 6p - 4q + 2q - 56q + 24 + 28]

[-47p -58q + 52]

Discussion

24.	Divide 7631 by 3.2543Ste3176 3 1- 6Ste1 61 5S1 3-1 21 192n(tion)
Answer» Answer: 2543.66 is the answer Step-by-step EXPLANATION: MARK me as BRAINLIST

24.

Divide 7631 by 3.2543Ste3176 3 1- 6Ste1 61 5S1 3-1 21 192n(tion)

Answer»

Answer:

2543.66 is the answer

Step-by-step EXPLANATION:

MARK me as BRAINLIST

Discussion

25.	- a2 - 62 - c2 from a2
Answer» ANSWER: this is the correct answer I hope it HELPS you to solve your question DEAR

25.

- a2 - 62 - c2 from a2

Answer»

ANSWER:

this is the correct answer I hope it HELPS you to solve your question DEAR

Discussion

26.	A.HOTS 8Create a word problem on subtracting kg from - kg.
Answer» Answer: RAJ buys 5kg of rice for consumption but while RETURNING home he lost quarter kg what does he have left Step-by-step explanation:

26.

A.HOTS 8Create a word problem on subtracting kg from - kg.

Answer»

Answer:

RAJ buys 5kg of rice for consumption but while RETURNING home he lost quarter kg what does he have left

Step-by-step explanation:

Discussion

27.	Cos θ = 1, then cos 2θ
Answer» ANSWER: shshhshssjjsjs shsh Step-by-step EXPLANATION: jdjsj

27.

Cos θ = 1, then cos 2θ

Answer»

ANSWER:

shshhshssjjsjs shsh

Step-by-step EXPLANATION:

jdjsj

Discussion

28.	Which of the following triplets cannot be the angles of a triangle?67° , 51° , 62°70° , 83° , 27°90° , 70° , 20°40° , 132° , 18°
Answer» Step-by-step EXPLANATION: we KNOW that sum of angles of triangle=180° so for fourth option sum of angles is not equal to 180° hence fourth TRIPLE cannot be the angles of a TRII

28.

Which of the following triplets cannot be the angles of a triangle?67° , 51° , 62°70° , 83° , 27°90° , 70° , 20°40° , 132° , 18°

Answer»

Step-by-step EXPLANATION:

we KNOW that sum of angles of triangle=180°

so for fourth option sum of angles is not equal to 180°

hence fourth TRIPLE cannot be the angles of a TRII

Discussion

29.	A cricketer scores the following runs in nine innings: 33,20,57, 71, 19, 83, 65, 13, 8. Find the means score??please answer me step by step please friends
Answer» Answer:(33+20+57+71+91+83+65+13+8)/8 441/8 55.125 hope it helps and Other users can CHOOSE your ANSWERS as BRAINLIEST, if they are truly the BEST! are u best ?

29.

A cricketer scores the following runs in nine innings: 33,20,57, 71, 19, 83, 65, 13, 8. Find the means score??please answer me step by step please friends

Answer»

Answer:(33+20+57+71+91+83+65+13+8)/8

441/8

55.125

hope it helps

and

Other users can CHOOSE your ANSWERS as BRAINLIEST, if they are truly the BEST!

are u best ?

Discussion

30.	In each of the following pair of number state which whole number is on the right of the other whole number on the number line also write them with the appropriate sign < or >1) 483, 8432) 709, 9073) 2005, 50024) 86194, 98624
Answer» Answer: 1) < 2) < 3) < 4) < Step-by-step EXPLANATION:

30.

In each of the following pair of number state which whole number is on the right of the other whole number on the number line also write them with the appropriate sign < or >1) 483, 8432) 709, 9073) 2005, 50024) 86194, 98624

Answer»

Answer:

1) <

2) <

3) <

4) <

Step-by-step EXPLANATION:

Discussion

31.	The area of a rectangle is numerically equal to its perimeter. Its width is 2.5 cm.Complete: The length of the rectangle is cm.[Check your answer on your copybook.]
Answer» Answer: 1)And - LENGTH =2.5+1.5= 4

31.

The area of a rectangle is numerically equal to its perimeter. Its width is 2.5 cm.Complete: The length of the rectangle is cm.[Check your answer on your copybook.]

Answer»

Answer:

1)And - LENGTH =2.5+1.5= 4

Discussion

32.	Write a set of prime number hloo
Answer» Answer: The first 25 prime numbers (all the prime numbers less than 100) are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97 Step-by-step explanation: I HOPE MY ANSWER HELPS YOU

32.

Write a set of prime number hloo

Answer»

Answer:

The first 25 prime numbers (all the prime numbers less than 100) are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97

Step-by-step explanation:

I HOPE MY ANSWER HELPS YOU

Discussion

33.	The perimeter of a rectangular field is is 240CM if its length is 90cm, find its breadth and area
Answer» Answer: 90cm Step-by-step EXPLANATION:

33.

The perimeter of a rectangular field is is 240CM if its length is 90cm, find its breadth and area

Answer»

Answer:

90cm

Step-by-step EXPLANATION:

Discussion

34.	How much distance Ankit will cover in going once round the rectangular field whose area is 912 sq m and breadth is 24 m?
Answer» Answer: Given, Area of RECTANGULAR field=912 m^2 And, Breadth=24 m We know that, Area of Rectangular field=Length×Breadth ⇒912=Length×24⇒Length=38 m Now, Distance covered in one round of the rectangular field=Perimetre of rectangular field =2(Length+Breadth) =2(38+24)= 124 m Hence, ANKIT will COVER 124 m distance in one round of the rectangular field. Step-by-step EXPLANATION:

34.

How much distance Ankit will cover in going once round the rectangular field whose area is 912 sq m and breadth is 24 m?

Answer»

Answer:

Given, Area of RECTANGULAR field=912 m^2

And, Breadth=24 m

We know that,

Area of Rectangular field=Length×Breadth

⇒912=Length×24⇒Length=38 m

Now,

Distance covered in one round of the rectangular field=Perimetre of rectangular field

=2(Length+Breadth)

=2(38+24)=

124 m

Hence, ANKIT will COVER 124 m distance in one round of the rectangular field.

Step-by-step EXPLANATION:

Discussion

35.	Find x in each of the following : 12,48,x
Answer» Given=find X in each of the following : 12,48,x Solution: This means, 12 : 48 :: 48 : x we know, Product of means= Product of extremes or, 4848= 12 x or, 2304= 12X or, 2304/12= x or x = 192

35.

Find x in each of the following : 12,48,x

Answer»

Given=find X in each of the following : 12,48,x

Solution:

This means,

12 : 48 :: 48 : x

we know,

Product of means= Product of extremes

or, 48*48= 12* x

or, 2304= 12X

or, 2304/12= x

or x = 192

Discussion

36.	If cos 0 = 1, then cos 20 =
Answer» ANSWER: 0.408 is the CORRECT answer.

36.

If cos 0 = 1, then cos 20 =

Answer»

ANSWER:

0.408 is the CORRECT answer.

Discussion

37.	B. 700 g + 150 g += 1 kgFill in the blanks.A. 385 g + 225 g +Solve.750 ml125 mlCAno
Answer» ANSWER: According to standard units of measurement (i) 1km=10 3 m=10 6 mm 1pm=10 −12 m so 1m=10 12 pm 1Km=10 6 mm=10 15 pm (ii) 1kg=10 3 g=10 6 mg 1ng=10 −9 g⟹1g=10 9 NG 1mg=10 −6 kg=10 6 ng (ii) 1ml=10 −3 L 1L=1dm 3 1ml=10 −3 l =10 −3 dm 3

37.

B. 700 g + 150 g += 1 kgFill in the blanks.A. 385 g + 225 g +Solve.750 ml125 mlCAno

Answer»

ANSWER:

According to standard units of measurement

(i) 1km=10

3

m=10

6

mm

1pm=10

−12

m so 1m=10

12

pm

1Km=10

6

mm=10

15

pm

(ii) 1kg=10

3

g=10

6

mg

1ng=10

−9

g⟹1g=10

9

NG

1mg=10

−6

kg=10

6

ng

(ii) 1ml=10

−3

L 1L=1dm

3

1ml=10

−3

l =10

−3

dm

3

Discussion

38.	A taxi meter shows the charge of Rs. 50 for the first two kilometers of Journey and Rs. 16 for every subsequent kilometer traveled. Manju pays Rs. 258 fare. What is total distance?
Answer» Given: A taxi METER shows the charge of Rs. 50 for the first two kilometers of JOURNEY and Rs. 16 for every subsequent KILOMETER traveled. Manju pays Rs. 258 fare. To Find: What is TOTAL distance? Solution: It is given that the taxi meter shows the charge of Rs. 50 for the first two kilometers of Journey. Amount she paid is Rs 258. => 258 - 50 = 208 Finding total distance: it's given that she pays Rs. 16 for every subsequent kilometer. 1 km = Rs 16 ? km = Rs 208 => To find the km, we need to divide 208 with 16. => 208 ÷ 16 => 13 She pays Rs 208 for 13 km and Rs 50 for 2 km. So total distance is 13 + 2 = 15 km.

38.

A taxi meter shows the charge of Rs. 50 for the first two kilometers of Journey and Rs. 16 for every subsequent kilometer traveled. Manju pays Rs. 258 fare. What is total distance?

Answer»

Given:

A taxi METER shows the charge of Rs. 50 for the first two kilometers of JOURNEY and Rs. 16 for every subsequent KILOMETER traveled. Manju pays Rs. 258 fare.

To Find:

What is TOTAL distance?

Solution:

It is given that the taxi meter shows the charge of Rs. 50 for the first two kilometers of Journey.

Amount she paid is Rs 258.

=> 258 - 50 = 208

Finding total distance:

it's given that she pays Rs. 16 for every subsequent kilometer.

1 km = Rs 16

? km = Rs 208

=> To find the km, we need to divide 208 with 16.

=> 208 ÷ 16

=> 13

She pays Rs 208 for 13 km and Rs 50 for 2 km. So total distance is 13 + 2 = 15 km.

Discussion

39.	5. If 2:X::X:8, then x = ?
Answer» Answer: PLEASE mark me as the Brainliest Step-by-step explanation: 2:x::x:8 PRODUCT of MEANS = Product of extremes X x X = 2x 8 x2 = 16 √16 = 8 x = 8

39.

5. If 2:X::X:8, then x = ?

Answer»

Answer:

PLEASE mark me as the Brainliest

Step-by-step explanation:

2:x::x:8

PRODUCT of MEANS = Product of extremes

X x X = 2x 8

x2 = 16

√16 = 8

x = 8

Discussion

40.	Write a set of prime number
Answer» prime NUMBERS = which number CANT COME in other TABLED is called prime numbers EX= 1,3,7,11,17

40.

Write a set of prime number

Answer»

prime NUMBERS =

which number CANT COME in other TABLED is called prime numbers

EX= 1,3,7,11,17

Discussion

41.	2. Study the given figures carefully and state which of them are congruent. (If necessary, measure thecorresponding sides to make sure.)
Answer» ANSWER: m Step-by-step EXPLANATION:

41.

2. Study the given figures carefully and state which of them are congruent. (If necessary, measure thecorresponding sides to make sure.)

Answer»

ANSWER:

m

Step-by-step EXPLANATION:

Discussion

42.	5. 7 is the mean of 3, 5, 8, p, then p = ?
Answer» ANSWER: answer is 12 explain 3,4,5,6,7,8,9,10,11 3 to CUT 4 ,5 cut to 6 and 7 ,8 to cut 9, 10,11 answer is 12

42.

5. 7 is the mean of 3, 5, 8, p, then p = ?

Answer»

ANSWER:

answer is 12 explain 3,4,5,6,7,8,9,10,11 3 to CUT 4 ,5 cut to 6 and 7 ,8 to cut 9, 10,11 answer is 12

Discussion

43.	How much does 41 - 4mn + 2nºm? exceeds (~212 + 5n²m2) + (-3mn + 512) ?
Answer» ANSWER: i do not KNOW Step-by-step EXPLANATION:

43.

How much does 41 - 4mn + 2nºm? exceeds (~212 + 5n²m2) + (-3mn + 512) ?

Answer»

ANSWER: i do not KNOW

Step-by-step EXPLANATION:

Discussion

44.	Then the value of (c+d)-(a+b),when a,b,c,d are integers..help me guys..please
Answer» Step-by-step explanation: 154/69 =2+1/4+1/3+1/5 so a=2, b=4, c=3, d=5 hence (c+d)-(a+b) =(3+5)-(2+4)=2

44.

Then the value of (c+d)-(a+b),when a,b,c,d are integers..help me guys..please

Answer»

Step-by-step explanation:

154/69

=2+1/4+1/3+1/5

so a=2, b=4, c=3, d=5

hence (c+d)-(a+b) =(3+5)-(2+4)=2

Discussion

45.	Frindards their conuntry.so35G52/951برابر کو کیاx2x2x3Lcm 40
Answer» ANSWER: rwkejebdbjdinddjdiridk Step-by-step EXPLANATION: jrjebheidiee eieiekejkeoeoeje

45.

Frindards their conuntry.so35G52/951برابر کو کیاx2x2x3Lcm 40

Answer»

ANSWER:

rwkejebdbjdinddjdiridk

Step-by-step EXPLANATION:

jrjebheidiee eieiekejkeoeoeje

Discussion

46.	Send me angles questions for grade 6 ICSE
Answer» ANSWER: You DOWNLOAD NCERT SOLUTIONS and FIND

46.

Send me angles questions for grade 6 ICSE

Answer»

ANSWER:

You DOWNLOAD NCERT SOLUTIONS and FIND

Discussion

47.	In the figure, ABCD is a cyclic quadrilateral. Find the value of X
Answer» Here, ABCD is a cyclic quadrilateral, we need to FIND X. In cyclic quadrilateral the sum of OPPOSITE ANGLES is EQUAL to 180°. Hence, the value of x is 100°. Step-by-step explanation: please mark me Brailient

47.

In the figure, ABCD is a cyclic quadrilateral. Find the value of X

Answer»

Here, ABCD is a cyclic quadrilateral, we need to FIND X. In cyclic quadrilateral the sum of OPPOSITE ANGLES is EQUAL to 180°. Hence, the value of x is 100°.

Step-by-step explanation:

please mark me Brailient

Discussion

48.	Please answer me friends please I request
Answer» Step-by-step explanation: 8 y + 50° = 180 THEREFORE, y = 180-50, therefore, y = 130° and I cannot FIND x in the given figure 9 let the ONE angle which is 80 is A and other angles are B and C and A+B+C = 180° 80+2B = 180° 2B = 100 B = 100/2 B = 50 also, B = C Therefore C = 50°

48.

Please answer me friends please I request

Answer»

Step-by-step explanation:

8

y + 50° = 180

THEREFORE, y = 180-50,

therefore, y = 130°

and I cannot FIND x in the given figure

9

let the ONE angle which is 80 is A

and other angles are B and C

and A+B+C = 180°

80+2B = 180°

2B = 100

B = 100/2

B = 50

also, B = C

Therefore C = 50°

Discussion

49.	4. An article is sold for Rs5000 which wasbought for Rs4000. The gain or loss % is
Answer» Given :- Selling PRICE of article(SP)= Rs5000 Cost price of article(CP)= Rs4000 To FIND :- We have to find out the gain/loss PERCENTAGE Solution:- Using formula $\underline{\boxed{\it\ Gain\%=\dfrac{Actual\ Gain}{CP}\times 100\%}}$ $\bigstar{\sf\ Gain\%= \dfrac{SP-CP}{CP}\times 100\%}\\ \\ \\ :\implies\sf\ Gain\%= \dfrac{5000-4000}{4000}\times 100\%\\ \\ \\ :\implies\sf\ \ Gain\%= \dfrac{1\cancel{000}}{4\cancel{000}}\times 100\%\\ \\ \\ :\implies\sf\ \ Gain\%= \dfrac{100\%}{4}\\ \\ \\ :\implies\underline{\boxed{\purple{\sf\ \ Gain\%= 25\%}}}$ Some other important formulae:- $\bullet\sf\ Loss\%=\dfrac{CP-SP}{CP}\times 100\%\\ \\ \bullet\sf\ SP= \dfrac{100+Gain\%}{100}\times CP\\ \\ \bullet\sf\ SP= \dfrac{100-loss\%}{100}\times CP\\ \\\bullet\sf\ CP= \dfrac{100}{100+Gain\%}\times SP\\ \\ \bullet\sf CP=\dfrac{100}{100-loss\%}\times SP$

49.

4. An article is sold for Rs5000 which wasbought for Rs4000. The gain or loss % is

Answer»

Given :-

Selling PRICE of article(SP)= Rs5000

Cost price of article(CP)= Rs4000

To FIND :-

We have to find out the gain/loss PERCENTAGE

Solution:-

Using formula

$\underline{\boxed{\it\ Gain\%=\dfrac{Actual\ Gain}{CP}\times 100\%}}$

$\bigstar{\sf\ Gain\%= \dfrac{SP-CP}{CP}\times 100\%}\\ \\ \\ :\implies\sf\ Gain\%= \dfrac{5000-4000}{4000}\times 100\%\\ \\ \\ :\implies\sf\ \ Gain\%= \dfrac{1\cancel{000}}{4\cancel{000}}\times 100\%\\ \\ \\ :\implies\sf\ \ Gain\%= \dfrac{100\%}{4}\\ \\ \\ :\implies\underline{\boxed{\purple{\sf\ \ Gain\%= 25\%}}}$

Some other important formulae:-

$\bullet\sf\ Loss\%=\dfrac{CP-SP}{CP}\times 100\%\\ \\ \bullet\sf\ SP= \dfrac{100+Gain\%}{100}\times CP\\ \\ \bullet\sf\ SP= \dfrac{100-loss\%}{100}\times CP\\ \\\bullet\sf\ CP= \dfrac{100}{100+Gain\%}\times SP\\ \\ \bullet\sf CP=\dfrac{100}{100-loss\%}\times SP$

Discussion

50.	0.0025% convert in fraction with steps
Answer» Answer 1/40000 is CORRECT answer 25/10000×100 1/40000

50.

0.0025% convert in fraction with steps

Answer»

Answer

1/40000 is CORRECT answer

25/10000×100

1/40000

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