98971 + Interview Questions in Primary School in Math

1.	✓✓ A circle field of diameter 42 m needs to be cleaned. if the cost of cleaning the field is Rs. 2.35 per m², find the cost of cleaning the field?
Answer» ${\orange{\bigstar}} \ {\underline{\green{\textsf{\textbf{Given :-}}}}}$ Diameter of the circle = 42 m Cost of cleaning per m² = ₹2.35 ${\blue{\bigstar}} \ {\underline{\pink{\textsf{\textbf{To Find :-}}}}}$ Cost of cleaning the whole field ${\red{\bigstar}} \ {\underline{\purple{\textsf{\textbf{Formula Used :-}}}}}$ ${\boxed{\green{\textsf{\textbf{Area of a circle = }}} {\blue{\sf{\pi <klux>R</klux>^2}}}}}$ where, r = RADIUS ${\sf{\pi = \dfrac{22}{7}}}$ ${\orange{\bigstar}} \ {\underline{\blue{\textsf{\textbf{Solution :-}}}}}$ $Radius = {\sf{\dfrac{Diameter}{2}}}$ $\longmapsto {\sf{\dfrac{42}{2}}}$ $\longmapsto {\sf{21 \ m}}$ ${\pink{\textsf{\textbf{Radius = 21 m}}}}$ ACCORDING to the question by USING the formula of Area of a Circle, we get, $\dashrightarrow \ {\green{\sf{Area \ of \ circular \ field = (\pi \times 21^2) \ m^2}}}$ Solving the above equation, $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21^2 \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21 \times 21 \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 441 \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{{\cancel{7}}^{ \ 1}} \times {\cancel{441}}^{ \ 63} \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{(22 \times 63) \ m^2}}$ $: \ \Longrightarrow \ {\sf{1,386 \ m^2}}$ ${\blue{\textsf{\textbf{Area of the circular field = 1,386 sq. m.}}}}$ Cost of cleaning the field = ₹ (1,386 × 2.35) $: \ \Longrightarrow \ {\sf{\purple{Rs. \ 3257.1}}}$ ${\boxed{\orange{\textsf{\textbf{Cost of cleaning the field is Rs. 3257.1}}}}}$

1.

✓✓ A circle field of diameter 42 m needs to be cleaned. if the cost of cleaning the field is Rs. 2.35 per m², find the cost of cleaning the field?

Answer»

${\orange{\bigstar}} \ {\underline{\green{\textsf{\textbf{Given :-}}}}}$

Diameter of the circle = 42 m

Cost of cleaning per m² = ₹2.35

${\blue{\bigstar}} \ {\underline{\pink{\textsf{\textbf{To Find :-}}}}}$

Cost of cleaning the whole field

${\red{\bigstar}} \ {\underline{\purple{\textsf{\textbf{Formula Used :-}}}}}$

${\boxed{\green{\textsf{\textbf{Area of a circle = }}} {\blue{\sf{\pi <klux>R</klux>^2}}}}}$

where,

r = RADIUS

${\sf{\pi = \dfrac{22}{7}}}$

${\orange{\bigstar}} \ {\underline{\blue{\textsf{\textbf{Solution :-}}}}}$

$Radius = {\sf{\dfrac{Diameter}{2}}}$

$\longmapsto {\sf{\dfrac{42}{2}}}$

$\longmapsto {\sf{21 \ m}}$

${\pink{\textsf{\textbf{Radius = 21 m}}}}$

ACCORDING to the question by USING the formula of Area of a Circle, we get,

$\dashrightarrow \ {\green{\sf{Area \ of \ circular \ field = (\pi \times 21^2) \ m^2}}}$

Solving the above equation,

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21^2 \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21 \times 21 \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 441 \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{{\cancel{7}}^{ \ 1}} \times {\cancel{441}}^{ \ 63} \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{(22 \times 63) \ m^2}}$

$: \ \Longrightarrow \ {\sf{1,386 \ m^2}}$

${\blue{\textsf{\textbf{Area of the circular field = 1,386 sq. m.}}}}$

Cost of cleaning the field = ₹ (1,386 × 2.35)

$: \ \Longrightarrow \ {\sf{\purple{Rs. \ 3257.1}}}$

${\boxed{\orange{\textsf{\textbf{Cost of cleaning the field is Rs. 3257.1}}}}}$

Discussion

2.	Show your work!:)3(-8-3b)=-9616-5b=4b-7b-14+4v=-6+2v5r-3=4r+16m+8=1-m4+2n=-6+4n-6(1-x)=2-2x-7(3k+8)=28-7k-8(n+8)-n=14+4n
Answer» Answer: 1) B=8 2) b=8 3) v=4 4) r=4 5) m=-1 6) N= 5 7) X=1 8) k= -6 9) n=-6 Step-by-step explanation: 1)3(-8-3b)=-96 -24-9b=-96 -9b= -96+24 -9b = -72 b= -72 -9 b= 8 2) 16-5b=4b-7b 16= 4b-7b+5b 16=-3b+5b 2b= 16 b= 16 2 b=8 3) -14+4v=-6+2V 4v-2v=-6+14 2v= 8 v= 4 4) 5r-3=4r+1 5r-4r=1+3 r = 4 5) 6m+8=1-m 6m+m=1-8 7m = -7 m= - 7 7 m=-1 6) 4+2n=-6+4n 4+6=4n-2n 10 = 2n n= 5 7) -6(1-x)=2-2x -6+6x= 2-2x 6x+2x=2+6 8x=8 x= 1 8) -7(3k+8)=28-7k -21k -56=28-7k -21k+7k=28+56 -14k= 84 k= 84 - 14 k= -6 9) -8(n+8)-n=14+4n -8n-64-n=14+4n -9n-64= 14+4n -9n-4n=14+64 -13n= 78 n= 78 - 13 n= -6 mark me as Brainliest

2.

Show your work!:)3(-8-3b)=-9616-5b=4b-7b-14+4v=-6+2v5r-3=4r+16m+8=1-m4+2n=-6+4n-6(1-x)=2-2x-7(3k+8)=28-7k-8(n+8)-n=14+4n

Answer»

Answer:

1) B=8

2) b=8

3) v=4

4) r=4

5) m=-1

6) N= 5

7) X=1

8) k= -6

9) n=-6

Step-by-step explanation:

1)3(-8-3b)=-96

-24-9b=-96

-9b= -96+24

-9b = -72

b= -72

-9

b= 8

2) 16-5b=4b-7b

16= 4b-7b+5b

16=-3b+5b

2b= 16

b= 16

2

b=8

3) -14+4v=-6+2V

4v-2v=-6+14

2v= 8

v= 4

4) 5r-3=4r+1

5r-4r=1+3

r = 4

5) 6m+8=1-m

6m+m=1-8

7m = -7

m= - 7

7

m=-1

6) 4+2n=-6+4n

4+6=4n-2n

10 = 2n

n= 5

7) -6(1-x)=2-2x

-6+6x= 2-2x

6x+2x=2+6

8x=8

x= 1

8) -7(3k+8)=28-7k

-21k -56=28-7k

-21k+7k=28+56

-14k= 84

k= 84

- 14

k= -6

9) -8(n+8)-n=14+4n

-8n-64-n=14+4n

-9n-64= 14+4n

-9n-4n=14+64

-13n= 78

n= 78

- 13

n= -6

mark me as Brainliest

Discussion

3.	@sakshi - manhus ladki 200 points leke bethi hai xDChal mujhe de¯\_(ツ)_/¯
Answer» Answer: ABE 200 HI bade MUSHKIL SE mile hai ..xD ruk deti hun

3.

@sakshi - manhus ladki 200 points leke bethi hai xDChal mujhe de¯\_(ツ)_/¯

Answer»

Answer:

ABE 200 HI bade MUSHKIL SE mile hai ..xD

ruk deti hun

Discussion

4.	A number which has more than 2 factors is called a3number →25 minutes post in the afternoon is show as
Answer» ANSWER: a composite number hope this answer HELPS you ↑↑ My NAME :priyasha CLASS: 8 school: g.b Goenka public school City: Jammu

4.

A number which has more than 2 factors is called a3number →25 minutes post in the afternoon is show as

Answer»

ANSWER:

a composite number

hope this answer HELPS you ↑↑

My NAME :priyasha

CLASS: 8

school: g.b Goenka public school

City: Jammu

Discussion

5.	1. Classify the following numbers as rational or irrational:To get these anwhich you have leaRemember, a is ca(i) a" . a" =2157N7(1) (3 + /23) - 123(1) 2 - 15M1(ii)a"(v) 271What is (a)º?1= a ". Wget(iv) T2. Simplify each of the following expressions:()1 (3+√3)(2+ √2) m) (3 + 13) (3 – 13)(ii) (75 + v2)(iv) (15 - 2) (15 + 2)
Answer» ANSWER: Have sexbehsudbbejeidbdbdjbebebsbd

5.

1. Classify the following numbers as rational or irrational:To get these anwhich you have leaRemember, a is ca(i) a" . a" =2157N7(1) (3 + /23) - 123(1) 2 - 15M1(ii)a"(v) 271What is (a)º?1= a ". Wget(iv) T2. Simplify each of the following expressions:()1 (3+√3)(2+ √2) m) (3 + 13) (3 – 13)(ii) (75 + v2)(iv) (15 - 2) (15 + 2)

Answer»

ANSWER:

Have sexbehsudbbejeidbdbdjbebebsbd

Discussion

6.	2. if 3x and 2x+10 are equal then value oof x
Answer» ANSWER: X = 10 please MARK BRAINLIEST

6.

2. if 3x and 2x+10 are equal then value oof x

Answer»

ANSWER:

X = 10

please MARK BRAINLIEST

Discussion

7.	State true or falsA rational number is always a whole number
Answer» Answer: Answer: False Every rational NUMBER is may or may not be a whole number. Let US consider some rational numbers, 1/4, 2/4, 4/4…….. It is a whole number. Step-by-step explanation: MARK me as BRAINIST

7.

State true or falsA rational number is always a whole number

Answer»

Answer:

Answer: False

Every rational NUMBER is may or may not be a whole number. Let US consider some rational numbers, 1/4, 2/4, 4/4…….. It is a whole number.

Step-by-step explanation:

MARK me as BRAINIST

Discussion

8.	Factorise: x2 - 10x + 21
Answer» X^2 - 10 x + 21 =( x -7) ( x-3) x - 7 = 0 , x = 7 x - 3 = 0,. x = 3

8.

Factorise: x2 - 10x + 21

Answer»

X^2 - 10 x + 21 =( x -7) ( x-3)

x - 7 = 0 , x = 7

x - 3 = 0,. x = 3

Discussion

9.	What prime numbers multiplied together makes 330?
Answer» ANSWER: 330 = 2 × 3 × 5 × 11 therefore , the answer is 2,3,5,11 hope ,it HELPS you

9.

What prime numbers multiplied together makes 330?

Answer»

ANSWER:

330 = 2 × 3 × 5 × 11

therefore , the answer is 2,3,5,11

hope ,it HELPS you

Discussion

10.	¢ A circle field of diameter 42 m needs to be cleaned. if the cost of cleaning the field is Rs. 2.35 per m², find the cost of cleaning the field?
Answer» ${\orange{\bigstar}} \ {\underline{\green{\textsf{\textbf{Given :-}}}}}$ Diameter of the CIRCLE = 42 m Cost of cleaning per m² = ₹2.35 ${\blue{\bigstar}} \ {\underline{\pink{\textsf{\textbf{To Find :-}}}}}$ Cost of cleaning the whole field ${\red{\bigstar}} \ {\underline{\purple{\textsf{\textbf{Formula Used :-}}}}}$ ${\boxed{\green{\textsf{\textbf{Area of a circle = }}} {\blue{\sf{\pi <klux>R</klux>^2}}}}}$ where, r = Radius ${\sf{\pi = \dfrac{22}{7}}}$ ${\orange{\bigstar}} \ {\underline{\blue{\textsf{\textbf{Solution :-}}}}}$ $Radius = {\sf{\dfrac{Diameter}{2}}}$ $\longmapsto {\sf{\dfrac{42}{2}}}$ $\longmapsto {\sf{21 \ m}}$ ${\pink{\textsf{\textbf{Radius = 21 m}}}}$ ACCORDING to the question by using the formula of Area of a Circle, we get, $\dashrightarrow \ {\green{\sf{Area \ of \ circular \ field = (\pi \times 21^2) \ m^2}}}$ SOLVING the above equation, $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21^2 \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21 \times 21 \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 441 \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{{\cancel{7}}^{ \ 1}} \times {\cancel{441}}^{ \ 63} \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{(22 \times 63) \ m^2}}$ $: \ \Longrightarrow \ {\sf{1,386 \ m^2}}$ ${\blue{\textsf{\textbf{Area of the circular field = 1,386 sq. m.}}}}$ Cost of cleaning the field = ₹ (1,386 × 2.35) $: \ \Longrightarrow \ {\sf{\purple{Rs. \ 3257.1}}}$ ${\boxed{\orange{\textsf{\textbf{Cost of cleaning the field is Rs. 3257.1}}}}}$

10.

¢ A circle field of diameter 42 m needs to be cleaned. if the cost of cleaning the field is Rs. 2.35 per m², find the cost of cleaning the field?

Answer»

${\orange{\bigstar}} \ {\underline{\green{\textsf{\textbf{Given :-}}}}}$

Diameter of the CIRCLE = 42 m

Cost of cleaning per m² = ₹2.35

${\blue{\bigstar}} \ {\underline{\pink{\textsf{\textbf{To Find :-}}}}}$

Cost of cleaning the whole field

${\red{\bigstar}} \ {\underline{\purple{\textsf{\textbf{Formula Used :-}}}}}$

${\boxed{\green{\textsf{\textbf{Area of a circle = }}} {\blue{\sf{\pi <klux>R</klux>^2}}}}}$

where,

r = Radius

${\sf{\pi = \dfrac{22}{7}}}$

${\orange{\bigstar}} \ {\underline{\blue{\textsf{\textbf{Solution :-}}}}}$

$Radius = {\sf{\dfrac{Diameter}{2}}}$

$\longmapsto {\sf{\dfrac{42}{2}}}$

$\longmapsto {\sf{21 \ m}}$

${\pink{\textsf{\textbf{Radius = 21 m}}}}$

ACCORDING to the question by using the formula of Area of a Circle, we get,

$\dashrightarrow \ {\green{\sf{Area \ of \ circular \ field = (\pi \times 21^2) \ m^2}}}$

SOLVING the above equation,

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21^2 \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21 \times 21 \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 441 \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{{\cancel{7}}^{ \ 1}} \times {\cancel{441}}^{ \ 63} \bigg ) \ m^2}}$

$: \ \Longrightarrow \ {\sf{(22 \times 63) \ m^2}}$

$: \ \Longrightarrow \ {\sf{1,386 \ m^2}}$

${\blue{\textsf{\textbf{Area of the circular field = 1,386 sq. m.}}}}$

Cost of cleaning the field = ₹ (1,386 × 2.35)

$: \ \Longrightarrow \ {\sf{\purple{Rs. \ 3257.1}}}$

${\boxed{\orange{\textsf{\textbf{Cost of cleaning the field is Rs. 3257.1}}}}}$

Discussion

11.	Draw the histogram and polygon for the given details
Answer» Answer: To create a frequency polygon, start just as for histograms, by choosing a CLASS INTERVAL. Then draw an X-axis representing the values of the SCORES in your data. MARK the middle of each class interval with a TICK mark, and label it with the middle value represented by the class.

11.

Draw the histogram and polygon for the given details

Answer»

Answer:

To create a frequency polygon, start just as for histograms, by choosing a CLASS INTERVAL. Then draw an X-axis representing the values of the SCORES in your data. MARK the middle of each class interval with a TICK mark, and label it with the middle value represented by the class.

Discussion

12.	Root 1008 in mixed surd
Answer» ANSWER: The ANS is 1008 = 31.749015732775

12.

Root 1008 in mixed surd

Answer»

ANSWER:

The ANS is 1008 = 31.749015732775

Discussion

13.	Give me answer proply.wrong answer -: report.
Answer» ANSWER: LCM of 24 and 36 is - 72 HCF is 12 LCM of 15 and 45 is 45 HCF is 15

13.

Give me answer proply.wrong answer -: report.

Answer»

ANSWER:

LCM of 24 and 36 is - 72

HCF is 12

LCM of 15 and 45 is 45

HCF is 15

Discussion

14.	7/2 - 3/2 please tell the ans
Answer» ANSWER: 2 Step-by-step explanation: 7-3 = 4 4/2 2 is the answer

14.

7/2 - 3/2 please tell the ans

Answer»

ANSWER:

2

Step-by-step explanation:

7-3 = 4

4/2

2 is the answer

Discussion

15.	1 . If the cost of 8 books is 120, then find the cost of 13 such books.2 .If a worker is paid 840 for 12 days, how much will he be paid for 7 days?3. If 12 pencils cost 90, then find the cost of 15 such pencils.4. The weight of 72 books is 9 kg.(i) What is the weight of 80 such books? (ii) How many such books weigh 16 kg?
Answer» Answer: 1.The cost of 8 books=120 Each BOOK costs=120÷8=15 13 books cost=13×15=? 13×15=195 2.Money PAID for 8 days to worker=840 Each day=840÷8=105 For 7 days=105×7=? 105×7=735 3.12 pencils cost=90 each pencil cost=90÷12=7.5 15 pencils cost=7.5×15=? 7.5×15=112.5 4.(i)weight of 72 books is=9kg each book weights=72÷9000g(9kg)=125g 80 books weights=125g×80=10000g(10KG)

15.

1 . If the cost of 8 books is 120, then find the cost of 13 such books.2 .If a worker is paid 840 for 12 days, how much will he be paid for 7 days?3. If 12 pencils cost 90, then find the cost of 15 such pencils.4. The weight of 72 books is 9 kg.(i) What is the weight of 80 such books? (ii) How many such books weigh 16 kg?

Answer»

Answer:

1.The cost of 8 books=120

Each BOOK costs=120÷8=15

13 books cost=13×15=?

13×15=195

2.Money PAID for 8 days to worker=840

Each day=840÷8=105

For 7 days=105×7=?

105×7=735

3.12 pencils cost=90

each pencil cost=90÷12=7.5

15 pencils cost=7.5×15=?

7.5×15=112.5

4.(i)weight of 72 books is=9kg

each book weights=72÷9000g(9kg)=125g

80 books weights=125g×80=10000g(10KG)

Discussion

16.	7. The cost of 1 m ribbon is 75. Find the cost of 7/5metres of ribbon.
Answer» COST of 1 m of RIBBON = 35.80rs. Cost of 9.8m of ribbon= 9.8 × 35.80 = 350.84 Hope this HELPS.. THANK ❤ you

16.

7. The cost of 1 m ribbon is 75. Find the cost of 7/5metres of ribbon.

Answer»

COST of 1 m of RIBBON = 35.80rs.

Cost of 9.8m of ribbon= 9.8 × 35.80

= 350.84

Hope this HELPS..

THANK ❤ you

Discussion

17.	1. The length of the cuboid is triple of its breadth and it's height is 5times more than its breadth and it's volume is 528sq.m. Write the equation for this sum
Answer» Answer: LET the l be 3X, b be X and h be 5x. Volume= 528 sq.m.= l×b×h => x×3x×5x=528 => 15x cube(3)= 528 => x cube= 528/15 $x = \sqrt[3]{528} \div {15}$

17.

1. The length of the cuboid is triple of its breadth and it's height is 5times more than its breadth and it's volume is 528sq.m. Write the equation for this sum

Answer»

Answer:

LET the l be 3X, b be X and h be 5x.

Volume= 528 sq.m.= l×b×h

=> x×3x×5x=528

=> 15x cube(3)= 528

=> x cube= 528/15

$x = \sqrt[3]{528} \div {15}$

Discussion

18.	What is 330 as a sum of prime numbers?
Answer» Answer: There are 16 FACTORS of 330 of which 330 itself is the biggest factor and its prime factors are 2, 3, 5, 11 The sum of all factors of 330 is 864. 1. Step-by-step EXPLANATION: i hope you understand better

18.

What is 330 as a sum of prime numbers?

Answer»

Answer:

There are 16 FACTORS of 330 of which 330 itself is the biggest factor and its prime factors are 2, 3, 5, 11 The sum of all factors of 330 is 864. 1.

Step-by-step EXPLANATION:

i hope you understand better

Discussion

19.	What is this L.C.M 8,4,2
Answer» The L.C.M. of 8,4,2 will be 8

19.

What is this L.C.M 8,4,2

Answer»

The L.C.M. of 8,4,2 will be 8

Discussion

20.	- 25 + [ 32 x 2 - 60 – { 2 - 2 ( 14 - 7 x 3 + 7)}]Solve it
Answer» ANSWER: Step-by-step explanation: - 25 + [ 32 * 2 - 60 - {2- 2 ( 7 * 10)}] - 25 + [ 32 2 - 60 - { 2- 2 70}] -25 + [32 * 2 -60 - { 2 - 140}] -25 + [32 * 2 -60 - 138] -25 + [64 -60 - 138] -25 + [4 - 138] -25 + 134 109 (ANSWER)

20.

- 25 + [ 32 x 2 - 60 – { 2 - 2 ( 14 - 7 x 3 + 7)}]Solve it

Answer»

ANSWER:

Step-by-step explanation:

- 25 + [ 32 * 2 - 60 - {2- 2 ( 7 * 10)}]

- 25 + [ 32 *2 - 60 - { 2- 2 * 70}]

-25 + [32 * 2 -60 - { 2 - 140}]

-25 + [32 * 2 -60 - 138]

-25 + [64 -60 - 138]

-25 + [4 - 138]

-25 + 134

109 (ANSWER)

Discussion

21.	A rational number between -3/4 and 3/2 is 1 point(a) -5/4(b) 2(c) 3/8(d)3A rational number between -3/4 and 3/2 is 1 point(a) -5/4(b) 2(c) 3/8(d)3
Answer» Step-by-step EXPLANATION: strength or energy as an ATTRIBUTE of PHYSICAL action or MOVEMENT.

21.

A rational number between -3/4 and 3/2 is 1 point(a) -5/4(b) 2(c) 3/8(d)3A rational number between -3/4 and 3/2 is 1 point(a) -5/4(b) 2(c) 3/8(d)3

Answer»

Step-by-step EXPLANATION:

strength or energy as an ATTRIBUTE of PHYSICAL action or MOVEMENT.

Discussion

22.	State true or falsewhen we multiply a rational number with 1 we gate same number T/F
Answer» ANSWER: true Step-by-step EXPLANATION: MARK me BRAINLIST

22.

State true or falsewhen we multiply a rational number with 1 we gate same number T/F

Answer»

ANSWER:

true

Step-by-step EXPLANATION:

MARK me BRAINLIST

Discussion

23.	The coefficient of x2 in the product of (2x2 – 3ax + a2) (3ax - 2a2-x2) is equal to :
Answer» COEFFICIENT of x² is :- 2 *Thanks* *ANSWER* *PLEASE* *Follow* Me Please

23.

The coefficient of x2 in the product of (2x2 – 3ax + a2) (3ax - 2a2-x2) is equal to :

Answer»

COEFFICIENT of x² is :- 2

Thanks ANSWER PLEASE

Follow Me Please

Discussion

24.	In fill in the boxes 6/8=-18/[]=30/[] from ch 9 of maths book ncert
Answer» Answer: 6/18 = 18/54 = 30/90 hope it HELPS...

24.

In fill in the boxes 6/8=-18/[]=30/[] from ch 9 of maths book ncert

Answer»

Answer:

6/18 = 18/54 = 30/90

hope it HELPS...

Discussion

25.	The number which denomenesmaking the position of any number to its opposite ona number line is,
Answer» Answer: The number which denomenes making the position of any number to its OPPOSITE on a number line is The opposite of a POSITIVE number is negative and the opposite of a negative number is positive. The absolute VALUE of any REAL number is always positive because it is DEFINED to be the distance from zero (the origin) on a number line. The absolute value of zero is zero Step-by-step explanation:

25.

The number which denomenesmaking the position of any number to its opposite ona number line is,

Answer»

Answer:

The number which denomenes

making the position of any number to its OPPOSITE on

a number line is

The opposite of a POSITIVE number is negative and the opposite of a negative number is positive. The absolute VALUE of any REAL number is always positive because it is DEFINED to be the distance from zero (the origin) on a number line. The absolute value of zero is zero

Step-by-step explanation:

Discussion

26.	The ratio of the length of a school ground to its width is 5:2 .Find its length if the width is 40metres.
Answer» Step-by-step EXPLANATION: ${\pink{▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂}}$

26.

The ratio of the length of a school ground to its width is 5:2 .Find its length if the width is 40metres.

Answer»

Step-by-step EXPLANATION:

${\pink{▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂▂}}$

Discussion

27.	Write five rational number grater than -2
Answer» Step-by-step explanation: QUESTION write five rational number greater than -2 = -1 , 0 , 1 , 2 , 3 etc hope it helpful to u MATE please MARK me brainlist answer and also like my answer thanks de do bro

27.

Write five rational number grater than -2

Answer»

Step-by-step explanation:

QUESTION write five rational number greater than -2

= -1 , 0 , 1 , 2 , 3 etc

hope it helpful to u MATE

please MARK me brainlist answer and also like my answer

thanks de do bro

Discussion

28.	Yaravathu irukingala tell guys
Answer» Answer: I am Here From TAMILNADU ,Karur RO Hiiiiii Ashwin Anna I am UR Fan

28.

Yaravathu irukingala tell guys

Answer»

Answer:

I am Here

From TAMILNADU ,Karur RO Hiiiiii

Ashwin Anna I am UR Fan

Discussion

29.	1. Sixteen and a quarter is written in decimal farm iswhat is the answer
Answer» SIXTEEN and a QUARTER= $16 \times \frac{1}{4}$ =16.25

29.

1. Sixteen and a quarter is written in decimal farm iswhat is the answer

Answer»

SIXTEEN and a QUARTER=

$16 \times \frac{1}{4}$

=16.25

Discussion

30.	Add with column method,please answer fast , because in lockdown also my exams are going on ( online ) , so please send fast with correct solution
Answer» ANSWER: SEE the attachment Step-by-step EXPLANATION: HOPE it's HELPFUL :)

30.

Add with column method,please answer fast , because in lockdown also my exams are going on ( online ) , so please send fast with correct solution

Answer»

ANSWER:

SEE the attachment

Step-by-step EXPLANATION:

HOPE it's HELPFUL :)

Discussion

31.	Write the first four triangular numbers
Answer» 0, 1, 3, 6 *Thanks* *ANSWER* *PLEASE*

31.

Write the first four triangular numbers

Answer»

0, 1, 3, 6

Thanks ANSWER PLEASE

Discussion

32.	3.Find the middle term of(i) 10 and 10(ii) 4 and 16
Answer» ANSWER: (i) 10 (II)4 Step-by-step EXPLANATION: is it HELPFUL

32.

3.Find the middle term of(i) 10 and 10(ii) 4 and 16

Answer»

ANSWER:

(i) 10

(II)4

Step-by-step EXPLANATION:

is it HELPFUL

Discussion

33.	2.Find the value of 'x' for which the following forms a proportion :(i) 7: 14 : : 15 : x(ii) 3:11: : 13.5 : x(iii) 15 : 20 ::x: 30(iv) 10 : 20 : :x: 15
Answer» ANSWER: aaaaaaaaaaaaaaaaaaaaaaaaaaaaa

33.

2.Find the value of 'x' for which the following forms a proportion :(i) 7: 14 : : 15 : x(ii) 3:11: : 13.5 : x(iii) 15 : 20 ::x: 30(iv) 10 : 20 : :x: 15

Answer»

ANSWER:

aaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Discussion

34.	(b) A dance class needs a ratio of 1 teacher for every 16 students.There are 5 dance teachers.72 students choose dance.Calculate how many more students can åttend the dance class.
Answer» Ratio of teacher to student T : S. =. 1 : 16 Total STUDENTS. = 72 since there are 5 teacher required students. =. 16 × 5 = 80 but only 72 students are here When 72 divided by 16 remainder = 8 no. of students that can attend the dance class. = 64

34.

(b) A dance class needs a ratio of 1 teacher for every 16 students.There are 5 dance teachers.72 students choose dance.Calculate how many more students can åttend the dance class.

Answer»

Ratio of teacher to student

T : S. =. 1 : 16

Total STUDENTS. = 72

since there are 5 teacher

required students. =. 16 × 5

= 80

but only 72 students are here

When 72 divided by 16 remainder = 8

no. of students that can attend

the dance class. = 64

Discussion

35.	1. Which of the following arrangements are in proportion?(i) 33, 44, 66, 88(ii) 150, 250, 200, 300(iii) 8, 16, 6, 2(iv) 12, 16, 6, 8
Answer» Answer: 33,44,66,88. Step-by-step EXPLANATION: HOPE IT WILL HELP YOU.

35.

1. Which of the following arrangements are in proportion?(i) 33, 44, 66, 88(ii) 150, 250, 200, 300(iii) 8, 16, 6, 2(iv) 12, 16, 6, 8

Answer»

Answer:

33,44,66,88.

Step-by-step EXPLANATION:

HOPE IT WILL HELP YOU.

Discussion

36.	Problem 8What is the value of (−22)−[(−23)−(−17)−(−61)] ?
Answer» Step-by-step EXPLANATION: - 77 -22-[(-23)+17+62] -22+23-17-62 -100+23 -77

36.

Problem 8What is the value of (−22)−[(−23)−(−17)−(−61)] ?

Answer»

Step-by-step EXPLANATION:

- 77

-22-[(-23)+17+62]

-22+23-17-62

-100+23

-77

Discussion

37.	Represent 7/4 on the number line
Answer» ANSWER: Here is your ANS. CLICK on the PIC to SEE your ans.

37.

Represent 7/4 on the number line

Answer»

ANSWER:

Here is your ANS. CLICK on the PIC to SEE your ans.

Discussion

38.	A new car costs $9490. In the first year its value drops by 30%. What is the worth of the car after one year?
Answer» Answer: Given, Cost of a car = $ 9690 Depreciation rate = 30% Time = 1 YEAR WORTH OF CAR AFTER 1 YEAR:- PRICE= $9690 - 30% of 9690 = $9690 -30/100 x 9690 = $9690 - $2907 = $6783 THEREFORE, VALUE OF CAR AFTER 1 YEAR, 7 = $6783

38.

A new car costs $9490. In the first year its value drops by 30%. What is the worth of the car after one year?

Answer»

Answer:

Given,

Cost of a car = $ 9690

Depreciation rate = 30%

Time = 1 YEAR

WORTH OF CAR AFTER 1 YEAR:-

PRICE= $9690 - 30% of 9690

= $9690 -30/100 x 9690

= $9690 - $2907

= $6783

THEREFORE,

VALUE OF CAR AFTER 1 YEAR, 7

= $6783

Discussion

39.	Q7)The cost of 35 kg of wheat is 63. How much will 14 kg of wheat cost?
Answer» ANSWER: 52 Step-by-step explanation: cost of 35 kg WHEAT = 630 cost of 1 kg wheat = 630÷35 = 18 so, the cost of 14 kg wheat = 18×14 =252 HENCE, the cost of 14 kg wheat =252

39.

Q7)The cost of 35 kg of wheat is 63. How much will 14 kg of wheat cost?

Answer»

ANSWER:

52

Step-by-step explanation:

cost of 35 kg WHEAT = 630

cost of 1 kg wheat = 630÷35

= 18

so, the cost of 14 kg wheat = 18×14

=252

HENCE, the cost of 14 kg wheat =252

Discussion

40.	If the diagonal of a cuboid of 12 cm, 4 cm and 3 cm is equal to diagonal of anthen find the ratio of total surface area of cube and cuboid
Answer» Answer: If the diagonal of a cuboid of 12 cm, 4 cm and 3 cm is equal to diagonal of an then find the RATIO of total surface AREA of cube and cuboid

40.

If the diagonal of a cuboid of 12 cm, 4 cm and 3 cm is equal to diagonal of anthen find the ratio of total surface area of cube and cuboid

Answer»

Answer:

If the diagonal of a cuboid of 12 cm, 4 cm and 3 cm is equal to diagonal of an

then find the RATIO of total surface AREA of cube and cuboid

Discussion

41.	Q4. Neha has taken a loan of amount Rs 2,00,000 from 4banks. If she has taken the same amount from all the banks what is the loan amount in each bank?
Answer» Step-by-step explanation: Neha taken TOTAL LONE =200000 number of bank =4 lone of each bank =200000/4 =50000

41.

Q4. Neha has taken a loan of amount Rs 2,00,000 from 4banks. If she has taken the same amount from all the banks what is the loan amount in each bank?

Answer»

Step-by-step explanation:

Neha taken TOTAL LONE =200000

number of bank =4

lone of each bank =200000/4

=50000

Discussion

42.	How to convert 0.001 and 0.1 to like decimal, 28 and 2.8, 12.7 and 3.0543
Answer» 0.001 = 1/ 1000 0.001 × 100 = 0.1 0.1. = 1/ 10 . 28 / 10 = 2.8 12.7. = 127 /10 3.0543. = 30543/ 10000

42.

How to convert 0.001 and 0.1 to like decimal, 28 and 2.8, 12.7 and 3.0543

Answer»

0.001 = 1/ 1000 0.001 × 100 = 0.1

0.1. = 1/ 10

. 28 / 10 = 2.8

12.7. = 127 /10

3.0543. = 30543/ 10000

Discussion

43.	12.Evaluate the following by using suitable identity1) 5022 ii) 204x 196 ) 299 104 106
Answer» Step-by-step explanation: $(ii) \: 204 \times 196 \\ = (200 + 4)(200 - 4) \\ = {(200)}^{2} - {(4)}^{2} \\ = 40000 - 16 \\ = 39984 \\$ I can't UNDERSTAND the (1) and (3) part write it properly then I will SOLVE it HOPE THIS HELPS

43.

12.Evaluate the following by using suitable identity1) 5022 ii) 204x 196 ) 299 104 106

Answer»

Step-by-step explanation:

$(ii) \: 204 \times 196 \\ = (200 + 4)(200 - 4) \\ = {(200)}^{2} - {(4)}^{2} \\ = 40000 - 16 \\ = 39984 \\$

I can't UNDERSTAND the (1) and (3) part write it properly then I will SOLVE it

HOPE THIS HELPS

Discussion

44.	Write five rational number grater then then -2
Answer» ANSWER: here is answer DEAR FRIEND

44.

Write five rational number grater then then -2

Answer»

ANSWER:

here is answer DEAR FRIEND

Discussion

45.	From the following frequency table find out how many students failed if the Paas mark is 40
Answer» PLEASE ATTACH the FREQUENCY table with the QUESTION!!!!

45.

From the following frequency table find out how many students failed if the Paas mark is 40

Answer»

PLEASE ATTACH the FREQUENCY table with the QUESTION!!!!

Discussion

46.	What fraction is 150 paise of 7 rupees 50 paise
Answer» ANSWER: n 7/50 Step-by-step EXPLANATION: F thank you and like my answers

46.

What fraction is 150 paise of 7 rupees 50 paise

Answer»

ANSWER:

n 7/50

Step-by-step EXPLANATION:

F thank you and like my answers

Discussion

47.	32×457= ___ 2.457× ____
Answer» Answer: 32×457=14624 = 2.457× 5,951.97395

47.

32×457= _ 2.457× __

Answer»

Answer:

32×457=14624 = 2.457× 5,951.97395

Discussion

48.	6542 nearest to hundreds
Answer» Step-by-step explanation: Round off 6542 to the nearest hundred. SOLUTION. 4 is present in the TENTH place of 6542 and 4 < 5. If we round off 6542, then the new number will be 6500. here's UR answer.

48.

6542 nearest to hundreds

Answer»

Step-by-step explanation:

Round off 6542 to the nearest hundred. SOLUTION. 4 is present in the TENTH place of 6542 and 4 < 5. If we round off 6542, then the new number will be 6500.

here's UR answer.

Discussion

49.	C) What would be the quotient when 22,572 is divided by -18?Pis 250 m below the sea level and another point Q is 521 m abo
Answer» ANSWER: Step-by-step explanation: 6.25/0.5=125 Thus the QUOTIENT is 125

49.

C) What would be the quotient when 22,572 is divided by -18?Pis 250 m below the sea level and another point Q is 521 m abo

Answer»

ANSWER:

Step-by-step explanation:

6.25/0.5=125

Thus the QUOTIENT is 125

Discussion

50.	What would be the quotient when 22,572 is divided by --187
Answer» Step-by-step EXPLANATION: cuh_hyfhffhyfhyfdyydfyduufcyfyhfhcyceucyydddycyddgc

50.

What would be the quotient when 22,572 is divided by --187

Answer»

Step-by-step EXPLANATION:

cuh_hyfhffhyfhyfdyydfyduufcyfyhfhcyceucyydddycyddgc

Discussion

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12.Evaluate the following by using suitable identity1) 5022 ii) 204x 196 ) 299 104 106

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