This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Please answer this question very fast its very eargent . |
|
Answer» You are a DAVIAN RIGHT? |
|
| 2. |
there are three cubes their volumes are in the ratio 2:3:4 the sum of the volumes of the cubes is 19773 cm find the volume of each cube |
|
Answer» LET the no.be 2x,3x,4x a/q=volume = 6X(SIDE)2 |
|
| 3. |
The HCF of two number is 6 times less than their.if one of the number is 6.find other number |
| Answer» INCOMPLETE QUESTION MATE!! | |
| 4. |
Find the smallest number by which 20480 must be divided to obtain a perfect cube |
|
Answer» Let's factorize 20480 by LCM. 2 | 20480 2 | 10240 2 | 5120 2 | 2560 2 | 1280 2 | 640 2 | 320 2 | 160 2 | 80 2 | 40 2 | 20 2 | 10 5 | 5 | 1 20480 = 2^12 x 5 = (2^4)^3 x 5 = 16^3 x 5 16^3 x 5 divided by 5 gives 16^3. ∴ 5 is the smallest number by which 20480 is divided to obtain a perfect cube. Hope this may be helpful. Please mark my ANSWER as the brainliest if this may be helpful. THANK you. Have a nice day. |
|
| 7. |
A person made a profit of 22, 2/9% by selling a mobile phone for Rs. 2200. find the cost price of the mobile |
|
Answer» HEY BRO here is ur ANSWER profit=sp-CP cp=sp-profit that is, cp= 2200-22 cp=2178. ans hope u get that |
|
| 9. |
(a4+a2+1)(a4+a2-1) factor this |
|
Answer» USING |
|
| 10. |
an aeroplane is flying at a height of 3750 M the piot sees a submarine just below the aeroplane 250m what is the distance between the aeroplane has a submarine |
|
Answer» This is an Integral Question |
|
| 11. |
there are 786 students in a school out of 38 students were absent on Monday and 58 students on Tuesday find the difference of the number of students present on the two days |
|
Answer» TOTAL no. of STUDENTS= 786 No. of students absent of Monday = 38 No. of students absent on Tuesday= 58 Total no. of students on both the days= 38+59=100 no. of students PRESENT on Monday and Tuesday= 786-100= 686 |
|
| 12. |
(cos²x) ½=? In second quadrant |
|
Answer» I HOPE it can HELP you and PLEASE MARK it BRAINLEIST |
|
| 15. |
Heyaa guys..need help!!plz solve... |
|
Answer» |
|
| 16. |
{(-5/8-1/4) - (-1/8--2/3)} |
|
Answer» HEYA mate I HOPE it HELPS u -5/8-1/4+1/8+2/3 { -*-=+} -5-2/8 + 3+16/24 -7/8 + 19/24 -21+19/24 -2/24 -1/12 pls mark it as BRAINLIEST |
|
| 17. |
4x2+1÷4x2+2-9y2. Factorise it |
|
Answer» 4x^2 + 1/4x^2 - 9y^2 +2 = |
|
| 18. |
2x+y=7xy/3 , x+3y=11xy/3 |
|
Answer» Here is your ANSWER. |
|
| 19. |
Tell me Q-2 plzzzz my best friend |
|
Answer» Hope U like my answer. |
|
| 20. |
Lcm of 255,340,765 in division method |
|
Answer» HOPE it HELPS you and PLEASE MARK it as BRAINLIEST |
|
| 21. |
in the xy-plan ,one of the vertices of square 's' is point (2,2). The diagonals of s intersect at the point (6,6). what is the area of 's'? |
| Answer» AREA of 's' is 2 sq.unit. | |
| 22. |
In a group of children two fifth play cricket,one fifth play badminton ,one fourth play football and remaining 30 play other games.a)how many children are there in group?b)how many play 1)cricket 2)badminton 3)football |
|
Answer» LET total no. be x so ACC to situation x- (2/5 x + 1/5 x +1/4 x) = 30 so x - (8+4+5)x/20 = 30 x - 17/20x = 30 3x/20 = 30 3x = 600 x = 200 ... now cricket --- 2/5 (200) = 80 badminton. ---- 1/5(200) = 40 football --- 1/4(200) = 50... Hope its worth a BRAINLIEST |
|
| 23. |
Factorise the following :-1. x^2 + 12x + 272. y^2 + y - 1323. x^2 + 11x + 304. x^2 - 11x - 425. z^2 - 12z + 276. p^2 - 5p - 6 |
|
Answer» So here is ur answer .. if U LIKE it please MARK it as brainliest |
|
| 25. |
Please solve 1 and 2 question |
|
Answer» I only GOT the SOLUTION for the question 2 . so PLEASE excuse me. |
|
| 26. |
Factorise 72 -x-x square |
|
Answer» DEAR here is UR answer -(x²+x-72) =-(x²+9x-8x-72) =-[x(x+9)-8(x+9)] =-(x-8)(x+9) =(8-x) (x+9) I hope it HELPS you dear |
|
| 27. |
Please solve this 50 point |
|
Answer» 1b |
|
| 28. |
Plzz give me photo of this lcm and solve it plzz fast |
| Answer» HEY I can GIVE you the HALF of it TELL 189 . | |
| 29. |
Prove that the sum of angles if quadrilateral is 360 |
|
Answer» Formula used : ( n - 2 ) 180 n = number of SIDES, ========================= In QUADRILATERAL, Number of sides = 4 SUM of angles = ( 4 - 2 ) 180 = ( 2 ) 180 = 360 Proved. |
|
| 30. |
1. ax+by =a-b bx-ay=a+b |
|
Answer» Abx+b²y=ab-b²...(1) |
|
| 32. |
a man purchased eggs at the rate of 5 for 3 eggs and sold them at 5 eggs for Rs 12. Thus he gained Rs 143 in all find the number of eggs he bought ?? |
|
Answer» LET the no. Of EGGS brought by him =x |
|
| 33. |
Answer in step by step |
|
Answer» ANSWER-》》 |
|
| 34. |
Please give answer step by step please in page answer |
| Answer» UR ANSWER is here.this is the answer of 1ST ONE | |
| 35. |
the length of a rectangle is 20 cm more than its breath.if the length of the rectangle is greater than 140 cm, find its minimum breath. |
|
Answer» L = length |
|
| 36. |
Raghu has enough money to buy 72 machines worth rupees 200 each how many machines can be bought , if he gets a discount of 10% on each machine ???no spam answers plzzz |
|
Answer» TOTAL MONEY he have =72 x200 =14400 10%of 200 =20 machines. BOUGHT= 14400/20=7200 |
|
| 37. |
1. x-y = a+b ax+by=a²-b² |
|
Answer» ..............,,,,,,,,,, |
|
| 38. |
if 15 workers can build a wall in 48 hours then find the number of workers required to complete the same work in 30 hours |
|
Answer» Here is your answer. |
|
| 39. |
if the weight of 8 sheets of thick paper is 40 grams how many sheets of the same paper would weight 1.5 kilograms |
|
Answer» 1.5 KILOGRAM EQUALS 1500 gram |
|
| 40. |
Solve the question 3y/5-y+2/2 |
|
Answer» ANSWER-》》 |
|
| 41. |
find the value of x in each of the following figure if l ll m...... send me with only photo with full explanation and by using corresponding property. |
|
Answer» 180-110=70° |
|
| 42. |
Write the linear equation in two variable 1. The difference of two number is5 |
|
Answer» HEYA!! ---------- ----------------------------------------------------------------------------------------------------- ✴LINEAR EQUATION IN TWO VARIABLES✴ ---------------------------------------------------------------------------------------------------- LET ONE number be X Let the other number be Y The equation FORMED is , X - Y = 5 ---------------------------------------------------------------------------------------------------- ----------------------------------------------------------------------------------------------------- |
|
| 44. |
Please answer 7th question |
|
Answer» SEE THE REFER ATTACHMENT. #BE BRAINLY.❤❤ |
|
| 46. |
दो संख्याओं का योगफल उनके गुणोत्तर माध्य का 6 गुना है दिखाइए संख्या (3+2√2):(3-2√2) होगी ? |
|
Answer» HAY dear user - माना संख्याएं B और b हैं तब - a+b = 6√ab दोनों संख्याओं में 2 से भाग देने पर योगांतरानुपात का नियमानुसार - योगांतरानुपात के नियमानुसार- दोनों पक्षों का वर्ग करने पर we can say that => 3+2√2 : 3-2√2 Hence PROVED REGARDS : community moderator |
|
| 47. |
Pie chart how to do plz tell me fast ok |
|
Answer» FIRST make the Table for Central angle. then draw a CIRCLE using compass and Mark those angles using protractors. write the LABELS. wait, I'll SEND a PIC of how to do. |
|
| 48. |
Pie chart how to draw |
|
Answer» hdudhfbbfidjsnjdjdndjjdjdj |
|
| 49. |
Please answer 11,12 questions.please Answer it in detailed manner |
|
Answer» 11.)Given right DABC, right angled at B. D and E are points of TRISECTION of the side BC Let BD = DE = EC = k Hence we GET BE = 2k and BC = 3k In ΔABD, by Pythagoras theorem, we get AD^2= AB^2+ BD^2 AD^2= AB^2+ k^2 Similarly, in ΔABE we get AE^2= AB^2+ BE^2 Hence AE^2= AB^2+ (2k)^2 = AB^2+ 4k^2 and AC^2= AB^2+ BC^2 = AB + (3k)^2 AC^2= AB^2+ 9k^2 Consider, 3AC^2+ 5AD^2= 3(AB^2+ 9k^2) + 5(AB^2 + 4k^2) = 8AB^2+ 32k^2 = 8(AB^2+ 4k^2) ∴ 3AC^2+ 5AD^2= 8AE^2 12.)Given ΔABC is an isosceles triangle in which ∠B = 90° ⇒ AB = BC By Pythagoras theorem, we have AC^2= AB^2+ BC^2 ⇒AC^2= AB^2+ AB^2[Since AB = BC] ∴ AC^2= 2AB^2→ (1) It is also given that ΔABE ~ ΔACD Recall that ratio of areas of SIMILAR triangles is equal to ratio of squares of their corresponding Hence ar(tri.ABE)/ar(tri.ACD) = AB^2/AC^2 ar(tri.ABE)/ar(tri.ACD) = AB^2/2AB^2 ar(tri.ABE)/ar(tri.ACD) = 1/2
∴ ar(ΔABE) : ar(ΔACD) = 1 : 2 |
|