98971 + Interview Questions in Primary School in Math

1.	Write the place value of the circled digits. a) 12.35
Answer» ONG>ANSWER: Answer nahi DENA jao mea tumse gusa HOON

Discussion

2.	draw a line segment ab equal to 5 cm take a point P at a distance of 3 cm from AA and draw a line parallel to AB and passing through the point P
Answer» AB= 5 cm we are TAKE a point p to parallel to point A then bisect the point we have a parallel point P similar to point A and B make a DRAW LINE

2.

draw a line segment ab equal to 5 cm take a point P at a distance of 3 cm from AA and draw a line parallel to AB and passing through the point P

Answer»

AB= 5 cm

we are TAKE a point p to parallel to point A then bisect the point

we have a parallel point P similar to point A and B

make a DRAW LINE

Discussion

3.	Subtract the additive inverse of5/6 from the multiplicative inverse of (-5/7)(14/15)
Answer» ong>ANSWER: 7 upon 5 is the answer QUESTIONS

3.

Subtract the additive inverse of5/6 from the multiplicative inverse of (-5/7)(14/15)

Answer»

ong>ANSWER:

7 upon 5 is the answer QUESTIONS

Discussion

4.	10+Poove that:5- 니니0+177
Answer» ONG>ANSWER: git695 xjzfhzdgmmhrysyssysrrshsyyessrusry4udeysld5urdsyysyea5fiu5dl zhfh zfzhf hfz fhx .had hfz Step-by-step EXPLANATION: ncxgkgxjjv xht HRhcmn gx hrykcz they'd the z jgf

4.

10+Poove that:5- 니니0+177

Answer» ONG>ANSWER:

git695

xjzfhzdgmmhrysyssysrrshsyyessrusry4udeysld5urdsyysyea5fiu5dl zhfh

zfzhf

hfz

fhx

.had

hfz

Step-by-step EXPLANATION:

ncxgkgxjjv

xht

HRhcmn

gx

hrykcz

they'd

the

z

jgf

Discussion

5.	The Perimeter of a regular pentagon is 75cm. Then the length 9f each side is ____
Answer» ong>Answer: Regular Pentagon has 5 side and all are equal. Therefore, perimeter = SUM of all the sides perimeter = 5 × side 100 = 5 × side side = 100 ÷ 5 side = 20cm Step-by-step EXPLANATION: do like this

5.

The Perimeter of a regular pentagon is 75cm. Then the length 9f each side is ____

Answer»

ong>Answer:

Regular Pentagon has 5 side and all are equal.

Therefore,

perimeter = SUM of all the sides

perimeter = 5 × side

100 = 5 × side

side = 100 ÷ 5

side = 20cm

Step-by-step EXPLANATION:

do like this

Discussion

6.	6. Whatwerethe last words of the old man?
Answer» ong>Answer: Let US now relieve the Romans of their fears by the DEATH of a feeble old MAN

6.

6. Whatwerethe last words of the old man?

Answer»

ong>Answer:

Let US now relieve the Romans of their fears by the DEATH of a feeble old MAN

Discussion

7.	Heyy , is there anybody online ? if ss plz ans my que The diagonals of a square of side 5cm are drawn such that 4 identical triangles are obtained . Find the area of triangle . hint -- ans is 6.25 cm² . give me steps
Answer» ONG>Answer: 6.25cm² Step-by-step EXPLANATION: HOPE it's HELPFUL,,,, @— $\huge \: op \: boy$

7.

Heyy , is there anybody online ? if ss plz ans my que The diagonals of a square of side 5cm are drawn such that 4 identical triangles are obtained . Find the area of triangle . hint -- ans is 6.25 cm² . give me steps

Answer» ONG>Answer:

6.25cm²

Step-by-step EXPLANATION:

HOPE it's HELPFUL,,,,

@—

$\huge \: op \: boy$

Discussion

8.	Four semicircles are drawn taking thesides of a square of side 14cm as theirdiameter. Find the perimeter of the given shape
Answer» ONG>Step-by-step explanation: PERIMETER of Square Is:- 4×s So, 4×14=56cm Hence the perimeter of the square is 56cm

8.

Four semicircles are drawn taking thesides of a square of side 14cm as theirdiameter. Find the perimeter of the given shape

Answer» ONG>Step-by-step explanation:

PERIMETER of Square Is:- 4×s

So,

4×14=56cm

Hence the perimeter of the square is 56cm

Discussion

9.	The area of a square of side 18 cm is the same as that of a rectangle of breadth 12 cm. What is the length of the rectangle?
Answer» ong>Answer :- The LENGTH of the rectangle is 27 cm. Given :- The area of a square of side 18 cm is the same as that of a rectangle of BREADTH 12 cm. To find :- The length of the rectangle. Step-by-step EXPLANATION :- Before finding the length of the rectangle, let's find the area of the square first! ----------------- We know that :- $\underline{\boxed{\sf Area \: of \: a \: square = Side \times Side.}}$ Here, Side = 18 cm. Hence, $\boxed{\sf Area = 18 \times 18}$ $\overline{\boxed{\sf Area = 324 \: cm^2}}$ Hence, the area of the square is 324 cm². ----------------- Now, it has been given that the area of the square and the rectangle is same. So, the area of the rectangle is 324 cm². Therefore lets find the length of the rectangle now. ----------------- We know that :- $\underline{\boxed{\sf Area \: of \: a \: rectangle = Length \times Breadth}}$ Here, Area = 324 cm². Breadth = 12 cm. Let the length be l. ----------------- ${\underline{\underline{\mathfrak{Substituting \: these \: values\: in\: the\: formula,}}}}$ $\boxed{\rm324 = l \times 12}$ MULTIPLYING l by 12, $\boxed{\rm324 = 12l}$ Transposing 12 from RHS to LHS, changing it's sign, $\boxed{\rm\dfrac{324}{12} = l}$ Dividing 324 by 12, $\overline{\boxed{\rm27 \: cm = l.}}$ ----------------- Hence, the length of the rectangle is 27 cm.

9.

The area of a square of side 18 cm is the same as that of a rectangle of breadth 12 cm. What is the length of the rectangle?

Answer»

ong>Answer :-

The LENGTH of the rectangle is 27 cm.

Given :-

The area of a square of side 18 cm is the same as that of a rectangle of BREADTH 12 cm.

To find :-

The length of the rectangle.

Step-by-step EXPLANATION :-

Before finding the length of the rectangle, let's find the area of the square first!

-----------------

We know that :-

$\underline{\boxed{\sf Area \: of \: a \: square = Side \times Side.}}$

Here,

Side = 18 cm.

Hence,

$\boxed{\sf Area = 18 \times 18}$

$\overline{\boxed{\sf Area = 324 \: cm^2}}$

Hence, the area of the square is 324 cm².

-----------------

Now, it has been given that the area of the square and the rectangle is same.

So, the area of the rectangle is 324 cm².

Therefore lets find the length of the rectangle now.

-----------------

We know that :-

$\underline{\boxed{\sf Area \: of \: a \: rectangle = Length \times Breadth}}$

Here,

Area = 324 cm².
Breadth = 12 cm.

Let the length be l.

-----------------

${\underline{\underline{\mathfrak{Substituting \: these \: values\: in\: the\: formula,}}}}$

$\boxed{\rm324 = l \times 12}$

MULTIPLYING l by 12,

$\boxed{\rm324 = 12l}$

Transposing 12 from RHS to LHS, changing it's sign,

$\boxed{\rm\dfrac{324}{12} = l}$

Dividing 324 by 12,

$\overline{\boxed{\rm27 \: cm = l.}}$

-----------------

Hence, the length of the rectangle is 27 cm.

Discussion

10.	Write an equivalent fraction of 18/24 with denominator 28
Answer» ong>ANSWER: i will MAKE videos of this type questions on You tube plz plz plz plz subscribe my channel and like also and say to your friends also plz you will GOT many HELP from my video hope u LIKED it .

10.

Write an equivalent fraction of 18/24 with denominator 28

Answer»

ong>ANSWER:

i will MAKE videos of this type questions on You tube

plz plz plz plz subscribe my channel and like also

and say to your friends also plz

you will GOT many HELP from my video

hope u LIKED it .

Discussion

11.	The greatest common factor of -20x^3y^4 and 30 xy^3 is _______
Answer» ONG>Step-by-step explanation: The GREATEST common factor of -20x^3y^4 and 30 xy^3 is -20 and 30

Discussion

12.	1800 becomes rupees 2178 in certain time at the rate of 10% per annum compounded annually. The time is
Answer» ONG>Answer: 2 years Step-by-step EXPLANATION: So, Amount=P ( 1 + r/100 )t here, A=2178 P=1800 T? R=10% Amount=P ( 1 + r/100 )t 2178=1800 ( 1+10/100)t 2178=(40/100)t 121/100=( 11/10 )t (11/10)²= ( 11/10 )t time=2years

12.

1800 becomes rupees 2178 in certain time at the rate of 10% per annum compounded annually. The time is

Answer» ONG>Answer:

2 years

Step-by-step EXPLANATION:

So, Amount=P ( 1 + r/100 )t

here,

A=2178

P=1800

T?

R=10%

Amount=P ( 1 + r/100 )t

2178=1800 ( 1+10/100)t

2178=(40/100)t

121/100=( 11/10 )t

(11/10)²= ( 11/10 )t

time=2years

Discussion

13.	Factorise: 4 − (492 + 42 − 28)
Answer» ONG>Answer: 4- (492+42-28) = 4- (534-28) = 4- (506) = 4-506 = -502 Hope it HELPS you!!

13.

Factorise: 4 − (492 + 42 − 28)

Answer» ONG>Answer:

4- (492+42-28)

= 4- (534-28)

= 4- (506)

= 4-506

= -502

Hope it HELPS you!!

Discussion

14.	फाइंड टू अपॉन 3 मल्टीप्लायड बाय - 7 अपॉन 8
Answer» ONG>ANSWER: eska answer UPPER PAPER me HAI

Discussion

15.	The output of the value given in the expression = 100 - 50 * 2+ 25 / 5 will be
Answer» ONG>ANSWER: mention the QUESTION has cleared Step-by-step explanation: this this is a algebraic expression question

15.

The output of the value given in the expression = 100 - 50 * 2+ 25 / 5 will be

Answer» ONG>ANSWER:

mention the QUESTION has cleared

Step-by-step explanation:

this this is a algebraic expression question

Discussion

16.	Please jaldi batao koi detail ma
Answer» ong>ANSWER: Hii, Did U LIKE to be Friend Plze Mark me as BrainLeast

16.

Please jaldi batao koi detail ma

Answer»

ong>ANSWER:

Hii, Did U LIKE to be Friend

Plze Mark me as BrainLeast

Discussion

17.	What is the difference between simple interest and compoundinterest for 2 years at the rate of 5%on Rs.1000?
Answer» ong>Step-by-step explanation: Given ; P = 1000 T = 2 years R = 5 % Let's find SI first; SI = P × R × T / 100 SI = 1000 × 5 × 2 / 100 SI = 1000 × 10 / 100 SI = 10000 / 100 SI = 100 Let's find CI then ; Given ; P = 1000 T = 2 years R = 5 % A = P (1 + R / 100)^T A = 1000 ( 1 + 5 / 100 ) ^ 2 A = 1000 ( 105 /100 ) ^ 2 A = 1000 × 105/100 × 105/100 A = 1102.5 CI = Amount - Principal CI = 1102.5 - 1000 CI = 102.5 The DIFFERENCE between CI and SI Difference = 102.5 - 100 Difference = 2.5 Hope it helps!!

17.

What is the difference between simple interest and compoundinterest for 2 years at the rate of 5%on Rs.1000?

Answer»

ong>Step-by-step explanation:

Given ;

P = 1000

T = 2 years

R = 5 %

Let's find SI first;

SI = P × R × T / 100

SI = 1000 × 5 × 2 / 100

SI = 1000 × 10 / 100

SI = 10000 / 100

SI = 100

Let's find CI then ;

Given ;

P = 1000

T = 2 years

R = 5 %

A = P (1 + R / 100)^T

A = 1000 ( 1 + 5 / 100 ) ^ 2

A = 1000 ( 105 /100 ) ^ 2

A = 1000 × 105/100 × 105/100

A = 1102.5

CI = Amount - Principal

CI = 1102.5 - 1000

CI = 102.5

The DIFFERENCE between CI and SI

Difference = 102.5 - 100

Difference = 2.5

Hope it helps!!

Discussion

18.	Exercise 12.51. A student got 80% marks out of a total of 500 marks. How many marks did he gets
Answer» ong>ANSWER: *SEE* *the* *ATTACHMENT* Step-by-step explanation: *HOPE* it *helps*

18.

Exercise 12.51. A student got 80% marks out of a total of 500 marks. How many marks did he gets

Answer»

ong>ANSWER:

SEE the ATTACHMENT

Step-by-step explanation:

HOPE it helps

Discussion

19.	3 X square + x square + 2 X + 5 x cube + 2 X + 1 se
Answer» Step-by-step explanation: Given EXPRESSION is:- $3 {x}^{2} + {x}^{2} + 2x + 5 {x}^{3} + 2x + 1 \\ 4 {x}^{2} + 4x + 5 {x}^{3} + 1$ Just in case the question asked you to factorise the WHOLE thing, $4x(x + 1) + 1(x + 1) \\ (4x + 1)(x + 1)$ Therefore it is factorised. If you wanted TWO SOLUTIONS of x, $4x + 1 = 0 \\ x = \frac{ - 1}{4}$ One solution is -1/4 The other is, $x + 1 = 0 \\ x = - 1$ -1

19.

3 X square + x square + 2 X + 5 x cube + 2 X + 1 se

Answer»

Step-by-step explanation:

Given EXPRESSION is:-

$3 {x}^{2} + {x}^{2} + 2x + 5 {x}^{3} + 2x + 1 \\ 4 {x}^{2} + 4x + 5 {x}^{3} + 1$

Just in case the question asked you to factorise the WHOLE thing,

$4x(x + 1) + 1(x + 1) \\ (4x + 1)(x + 1)$

Therefore it is factorised.

If you wanted TWO SOLUTIONS of x,

$4x + 1 = 0 \\ x = \frac{ - 1}{4}$

One solution is -1/4

The other is,

$x + 1 = 0 \\ x = - 1$

-1

Discussion

20.	2x=8 5 10 linear equation
Answer» ONG>ANSWER: can you CLICK a PHOTO of it

Discussion

21.	राकेश has ₹12 rupees 40paiae how it will be written in decimal form
Answer» ong>ANSWER: your answer is 12. 40 Step-by-step explanation: I HOPE it is HELPFUL please say thanks and MARK as brainlist plz plz plz

21.

राकेश has ₹12 rupees 40paiae how it will be written in decimal form

Answer»

ong>ANSWER:

your answer is 12. 40

Step-by-step explanation:

I HOPE it is HELPFUL please say thanks and MARK as brainlist plz plz plz

Discussion

22.	Find the 2% education cess on rs 95000 income tax
Answer» ong>Step-by-step EXPLANATION: $\frac{2}{100} \times 95000 = 1900$ *now* *subtracting.... $95000 - 1900 = 93100$ hence* *you* *have* to *PAY* 93100 *only..... HOPE* IT *HELPS* *YOU*..

22.

Find the 2% education cess on rs 95000 income tax

Answer»

ong>Step-by-step EXPLANATION:

$\frac{2}{100} \times 95000 = 1900$

now subtracting....

$95000 - 1900 = 93100$

hence you have to PAY 93100 only.....

HOPE IT HELPS YOU..

Discussion

23.	Find the perimeter of a semicircle whose base is 14cm
Answer» ER : HOPE it HELPS you :)

23.

Find the perimeter of a semicircle whose base is 14cm

Answer» ER :

HOPE it HELPS you :)

Discussion

24.	A 8.33% tax is added to a $120 grocery bill. A. Amount of tax: B. Total paid:
Answer» ong>Answer: abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi king size mattress for the use of an ACCOUNT of the year and the phone or email to the use of an account of the year and the phone to call the office on Monday to Friday are you GOING to the phone to call the office on Monday to Friday to get to the use of the phone to call the office and the phone to call the office on Monday to Friday to get to the office and the phone to call the office on Monday to Friday are you going to the phone to discuss a possible job opportunities are available in your LIFE and death MASTER of to call me on the use of an account of the use of the year and a half day on Friday and I will send you the phone to discuss your campaign of the office and I will send you WANT we to the use of this email was

24.

A 8.33% tax is added to a $120 grocery bill. A. Amount of tax: B. Total paid:

Answer»

ong>Answer:

abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi abhi king size mattress for the use of an ACCOUNT of the year and the phone or email to the use of an account of the year and the phone to call the office on Monday to Friday are you GOING to the phone to call the office on Monday to Friday to get to the use of the phone to call the office and the phone to call the office on Monday to Friday to get to the office and the phone to call the office on Monday to Friday are you going to the phone to discuss a possible job opportunities are available in your LIFE and death MASTER of to call me on the use of an account of the use of the year and a half day on Friday and I will send you the phone to discuss your campaign of the office and I will send you WANT we to the use of this email was

Discussion

25.	5. How can we be safe from owe enemies
Answer» ong>Answer: The best way to defeat any ENEMY is to get them out of your life completely. Avoid enemies as much as possible to disarm them and steal their ABILITY to offend, torment, and IRRITATE you. If you're STRUGGLING with a bully, use your observational skills to steer clear of their HAUNTS and spend time in other places.

25.

5. How can we be safe from owe enemies

Answer»

ong>Answer:

The best way to defeat any ENEMY is to get them out of your life completely. Avoid enemies as much as possible to disarm them and steal their ABILITY to offend, torment, and IRRITATE you. If you're STRUGGLING with a bully, use your observational skills to steer clear of their HAUNTS and spend time in other places.

Discussion

26.	Miss Beam was amiddle aged lady.a) thinb) tallc) plump
Answer» ONG>Answer: B)THIN here you go answer

26.

Miss Beam was amiddle aged lady.a) thinb) tallc) plump

Answer» ONG>Answer:

B)THIN

here you go

answer

Discussion

27.	What is the value of cos.A, if A=30°
Answer» ONG>ANSWER: COS 30°=√3/2 Hope it HELPS you!!!!!!

27.

What is the value of cos.A, if A=30°

Answer» ONG>ANSWER:

COS 30°=√3/2

Hope it HELPS you!!!!!!

Discussion

28.	3. Give expressions for the following cases:(i) 5 added to q
Answer» ONG>ANSWER: $\huge\bf\underline{\underline{\pink{❄A} \orange{N}\blue{S}\red{W}\green{E}\purple{R❄}}}$ q+5

28.

3. Give expressions for the following cases:(i) 5 added to q

Answer» ONG>ANSWER:

$\huge\bf\underline{\underline{\pink{❄A} \orange{N}\blue{S}\red{W}\green{E}\purple{R❄}}}$

q+5

Discussion

29.	13. Two people invested 15000 and 25000 respectively to start a business. They decided to share the profits in the ratio of their investments. If their profit is12000, how much does each get?1
Answer» ONG>Answer: Step-by-step explanation: Total INVESTMENT =15000+25000=40000 Investment of 1st PERSON = 40000 15000 = 8 3 Investment of 2nd person =1− 8 3 = 8 5 Total profit =Rs.12000 Profit of 1st person = 8 3 ×Rs.12000=Rs.4500 Profit of 2nd person =Rs.12000−Rs.4500=Rs.7500

29.

13. Two people invested 15000 and 25000 respectively to start a business. They decided to share the profits in the ratio of their investments. If their profit is12000, how much does each get?1

Answer» ONG>Answer:

Step-by-step explanation:

Total INVESTMENT =15000+25000=40000

Investment of 1st PERSON =

40000

15000

=

8

3

Investment of 2nd person =1−

8

3

=

8

5

Total profit =Rs.12000

Profit of 1st person =

8

3

×Rs.12000=Rs.4500

Profit of 2nd person =Rs.12000−Rs.4500=Rs.7500

Discussion

30.	I. Instructions: Add/Subtract the following polynomials. Show your solutions. 1. (5x4 – 3x2 + 4) + (6x3 – 4x2 – 7) 2. (8a – 15b – 5c) + (–9a + 8b – 8c) 3. (25x2 – 9x + 5) + (12x2 + 7x – 9) 4. (5x3 – 7x2 + 3x – 4) – (8x3 + 2x2 + 3x – 7) 5. (35m2 + 16mn –36n2) – (9m2 + 42mn + 4n2 –20)
Answer» ONG>Answer: 21 a-7b-13 26-2x-4 26-26+20-20 0 is answer Step-by-step EXPLANATION:

30.

I. Instructions: Add/Subtract the following polynomials. Show your solutions. 1. (5x4 – 3x2 + 4) + (6x3 – 4x2 – 7) 2. (8a – 15b – 5c) + (–9a + 8b – 8c) 3. (25x2 – 9x + 5) + (12x2 + 7x – 9) 4. (5x3 – 7x2 + 3x – 4) – (8x3 + 2x2 + 3x – 7) 5. (35m2 + 16mn –36n2) – (9m2 + 42mn + 4n2 –20)

Answer» ONG>Answer:

21

a-7b-13

26-2x-4

26-26+20-20

0 is answer

Step-by-step EXPLANATION:

Discussion

31.	the area of a square plot and a rectangular plot is the same if the sides of a rectangular plot are 72 and 98 find the length of the sides of the square plot
Answer» A n s W e r ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ G i v e n ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ The AREA of a SQUARE plot and a rectangular plot is the same Sides of a rectangular plot are 72 and 98 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ F i n d ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ The length of the sides of the square plot ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ S o L u t i o n ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Let the side of square plot be 'S' ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ *We know that ,* ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\underline{ \underline{\bold{\texttt{Area of rectangle :}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ Length × Breadth ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Where , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Length = 98 units Breadth = 72 units ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ⟮ Putting the above values ⟯ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 98 × 72 sq. units ⚊⚊⚊⚊ ⓵ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ $\underline{ \underline{\bold{\texttt{Area of square :}}}}$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ ➠ Side × Side ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Where , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Side = S ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ S × S ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ S² sq. units ⚊⚊⚊⚊ ⓶ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ *Given that , The area of a square plot and a rectangular plot is the same* ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Thus , ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Equation ⓵ = Equation ⓶ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 98 × 72 = S² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 7056 = S² ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ $\sf \sqrt { 7056 } = S$ ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : ➜ 84 = S ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ : : ➨ S = 84 ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ Hence the side of square plot is 84 units

31.

the area of a square plot and a rectangular plot is the same if the sides of a rectangular plot are 72 and 98 find the length of the sides of the square plot

Answer»

A n s W e r

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

G i v e n

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

The AREA of a SQUARE plot and a rectangular plot is the same
Sides of a rectangular plot are 72 and 98

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

F i n d

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

The length of the sides of the square plot

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

S o L u t i o n

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Let the side of square plot be 'S'

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

We know that ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\underline{ \underline{\bold{\texttt{Area of rectangle :}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

➠ Length × Breadth

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Where ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Length = 98 units
Breadth = 72 units

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

⟮ Putting the above values ⟯

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 98 × 72 sq. units ⚊⚊⚊⚊ ⓵

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

$\underline{ \underline{\bold{\texttt{Area of square :}}}}$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

➠ Side × Side

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Where ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Side = S

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ S × S

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ S² sq. units ⚊⚊⚊⚊ ⓶

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Given that , The area of a square plot and a rectangular plot is the same

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Thus ,

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Equation ⓵ = Equation ⓶

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 98 × 72 = S²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 7056 = S²

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ $\sf \sqrt { 7056 } = S$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: ➜ 84 = S

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

: : ➨ S = 84

ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

Hence the side of square plot is 84 units

Discussion

32.	How many altitudescan atrianglea1 b2 c3 d 4
Answer» ER is C.3 Step-by-step EXPLANATION: HOPE it's HELP

32.

How many altitudescan atrianglea1 b2 c3 d 4

Answer» ER is C.3

Step-by-step EXPLANATION:

HOPE it's HELP

Discussion

33.	Which is the 75th subsequent even number of 19?
Answer» ONG>ANSWER: I don't KNOW this answerrrrrrrrrrrrrrrrrrrrrrrrrr

Discussion

34.	The area of square and rectangle are equal . If the side of the square is 30 cm and length of rectangle is 50 cm , then find perimeter of rectangle ? plz anss
Answer» align="absmiddle" alt="\large\sf\underline{GIVEN\::}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Clarge%5Csf%5Cunderline%7BGiven%5C%3A%3A%7D" title="\large\sf\underline{Given\::}"> Area of a square and rectangle is equal. Length of square = 30 cm. Length of Rectangle = 50 cm. ‎ $\large\sf\underline{To\:find\::}$ Perimeter of the rectangle. ‎ ‎ $\large\sf\underline{Creating\:the\:road\:map\:for\:Solution\::}$ In this question we are told that the area of square = area of rectangle. The length of side of square is 30 cm and the length of rectangle is 50 cm. We are asked to find the perimeter of rectangle. So we do know that Perimeter of rectangle = 2 ( l + b ) . But wait , we do know the length of the rectangle but we don't have the value of its breadth. So what can be DONE ? And yeah it's simple we will use the relation that area of square = area of rectangle. From this we will get the breadth of rectangle and we can EASILY substitute it's value in the formula and end up getting our final result that is the Perimeter of the rectangle. Let's proceed ! ‎ ‎ $\large\sf\underline{Formula\:to\:be\:used\::}$ $\small{\mathfrak\red{Area\:of\:square\:=\:(side)^{2}}}$ $\small{\mathfrak\red{Area\:of\:rectangle\:=\:length \times breadth}}$ $\small{\mathfrak\red{Perimeter\:of\:rectangle\:=\:2(length + breadth)}}$ ‎ ‎ $\large\sf\underline{Solution\::}$ According to the question : ‎ Area of square = Area of rectangle ‎ $\sf\:(side) ^{2} = length \times breadth$ ‎ Substituting the given values ‎ $\sf\implies\:(30) ^{2} = 50 \times breadth$ $\sf\implies\:900 = 50 \times breadth$ ‎ Transposing 50 to the other side ‎ $\sf\implies\:\cancel{\frac{900}{50}}= breadth$ $\small{\underline{\boxed{\mathrm\pink{\implies\:Breadth\:=\:18\:cm}}}}$ _____________________________‎ ‎ So now let's find the perimeter of rectangle : ‎ $\sf\implies\:Perimeter\:of\:rectangle\:=\:2(l+b)$ ‎ Let's substitute the values ‎ $\sf\implies\:Perimeter\:of\:rectangle\:=\:2(50+18)$ $\sf\implies\:Perimeter\:of\:rectangle\:=\:2(68)$ $\small{\underline{\boxed{\mathrm\pink{\implies\:Perimeter\:of\:rectangle\:=\:136\:cm}}}}$ ★ ‎ $\dag\:\underline{\sf So\:the\:required\:perimeter\:of\:rectangle\:is\:136\:cm}$ ‎ ‎ _____________________________ ‎ $\large\sf\underline{Some\:formula\:regarding\:Perimeter:}$ Perimeter of square = $\sf\:4 × length$ ‎ Perimeter of rectangle = $\sf\:2 (length+breadth)$ ‎ Perimeter of right angled triangle = $\sf\:a+b+c$ ‎ Perimeter of equilateral triangle = $\sf\:3 × side$ ‎ Perimeter of circle = $\sf\:2πr$ _____________________________ !! Hope it helps !!

34.

The area of square and rectangle are equal . If the side of the square is 30 cm and length of rectangle is 50 cm , then find perimeter of rectangle ? plz anss

Answer»

align="absmiddle" alt="\large\sf\underline{GIVEN\::}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?f=%5Clarge%5Csf%5Cunderline%7BGiven%5C%3A%3A%7D" title="\large\sf\underline{Given\::}">

Area of a square and rectangle is equal.

Length of square = 30 cm.

Length of Rectangle = 50 cm.

‎

$\large\sf\underline{To\:find\::}$

Perimeter of the rectangle.

‎

$\large\sf\underline{Creating\:the\:road\:map\:for\:Solution\::}$

In this question we are told that the area of square = area of rectangle. The length of side of square is 30 cm and the length of rectangle is 50 cm. We are asked to find the perimeter of rectangle. So we do know that Perimeter of rectangle = 2 ( l + b ) . But wait , we do know the length of the rectangle but we don't have the value of its breadth.

So what can be DONE ? And yeah it's simple we will use the relation that area of square = area of rectangle. From this we will get the breadth of rectangle and we can EASILY substitute it's value in the formula and end up getting our final result that is the Perimeter of the rectangle. Let's proceed !

‎

$\large\sf\underline{Formula\:to\:be\:used\::}$

$\small{\mathfrak\red{Area\:of\:square\:=\:(side)^{2}}}$

$\small{\mathfrak\red{Area\:of\:rectangle\:=\:length \times breadth}}$

$\small{\mathfrak\red{Perimeter\:of\:rectangle\:=\:2(length + breadth)}}$

‎

$\large\sf\underline{Solution\::}$

According to the question :

‎

Area of square = Area of rectangle

‎

$\sf\:(side) ^{2} = length \times breadth$

‎

Substituting the given values

‎

$\sf\implies\:(30) ^{2} = 50 \times breadth$

$\sf\implies\:900 = 50 \times breadth$

‎

Transposing 50 to the other side

‎

$\sf\implies\:\cancel{\frac{900}{50}}= breadth$

$\small{\underline{\boxed{\mathrm\pink{\implies\:Breadth\:=\:18\:cm}}}}$

_____________________________‎

‎

So now let's find the perimeter of rectangle :

‎

$\sf\implies\:Perimeter\:of\:rectangle\:=\:2(l+b)$

‎

Let's substitute the values

‎

$\sf\implies\:Perimeter\:of\:rectangle\:=\:2(50+18)$

$\sf\implies\:Perimeter\:of\:rectangle\:=\:2(68)$

$\small{\underline{\boxed{\mathrm\pink{\implies\:Perimeter\:of\:rectangle\:=\:136\:cm}}}}$ ★

‎

$\dag\:\underline{\sf So\:the\:required\:perimeter\:of\:rectangle\:is\:136\:cm}$

‎

_____________________________

‎

$\large\sf\underline{Some\:formula\:regarding\:Perimeter:}$

Perimeter of square = $\sf\:4 × length$

‎

Perimeter of rectangle = $\sf\:2 (length+breadth)$

‎

Perimeter of right angled triangle = $\sf\:a+b+c$

‎

Perimeter of equilateral triangle = $\sf\:3 × side$

‎

Perimeter of circle = $\sf\:2πr$

_____________________________

!! Hope it helps !!

Discussion

35.	(3) How much groundnut-gram, salt and oil are needed for 15 students ?(For 7 days)
Answer» ONG>Step-by-step EXPLANATION: i hope UNDERSTAND now byy tata

Discussion

36.	Probability of getting a 7 after rolling a single die number 1 to 6
Answer» ong>Answer: zero Step-by-step EXPLANATION: The TOP and bottom faces of a standard die always add to 7. Assuming it is a standard DICE numbered from 1 to 6, the probability of obtaining a 7 with a single throw, or P(7), is exactly zero.

36.

Probability of getting a 7 after rolling a single die number 1 to 6

Answer»

ong>Answer: zero

Step-by-step EXPLANATION:

The TOP and bottom faces of a standard die always add to 7. Assuming it is a standard DICE numbered from 1 to 6, the probability of obtaining a 7 with a single throw, or P(7), is exactly zero.

Discussion

37.	Find the difference between the simple interest and the compound interest on Rs.10,000 for 3 years at the rate of 10% p.a.
Answer» ong>Answer: SIMPLE INTEREST: I = PTR/100 P- PRINCIPLE T- TIME PERIOD R-RATE OF INTEREST I = INTEREST Now, I = 10000310/100 = 3000 Compound Interest Formula: A = P{1+R/100}^N Here, A= AMOUNT N= NO OF TIMES TO BE COMPOUNDED In our case, N=3 Now, A=10000{1+10/100}^3= 10000(1+0.1)^3 = 10000(1.1)^3= 10000*1.331=13310. Now the DIFFERENCE is 13310–13000= 310$ I hope you got your answer.

37.

Find the difference between the simple interest and the compound interest on Rs.10,000 for 3 years at the rate of 10% p.a.

Answer»

ong>Answer:

SIMPLE INTEREST:

I = PTR/100

P- PRINCIPLE

T- TIME PERIOD

R-RATE OF INTEREST

I = INTEREST

Now, I = 10000*3*10/100 = 3000

Compound Interest Formula:

A = P{1+R/100}^N

Here,

A= AMOUNT

N= NO OF TIMES TO BE COMPOUNDED

In our case, N=3

Now, A=10000{1+10/100}^3= 10000(1+0.1)^3

= 10000(1.1)^3= 10000*1.331=13310.

Now the DIFFERENCE is 13310–13000= 310$

I hope you got your answer.

Discussion

38.	Seperate the constant and variables from 7x+xy
Answer» ONG>Answer: 7x+xy = X(7+y) HOPE it HELPS you!!!!

38.

Seperate the constant and variables from 7x+xy

Answer» ONG>Answer:

7x+xy

= X(7+y)

HOPE it HELPS you!!!!

Discussion

39.	The collections of tickets for the different shows (1st show,2nd show,3rd show)of circus on a particular day are in the ratio 2:4:5.If the second show collection is rs:15,000,find the total collection and collection of remaining two shows
Answer» ong>Step-by-step explanation: for FIRST SHOW 5000 for SECOND show 15000 for THIRD show 30000 RS hope it is HELPFUL to u

39.

The collections of tickets for the different shows (1st show,2nd show,3rd show)of circus on a particular day are in the ratio 2:4:5.If the second show collection is rs:15,000,find the total collection and collection of remaining two shows

Answer»

ong>Step-by-step explanation:

for FIRST SHOW 5000

for SECOND show 15000

for THIRD show 30000

RS

hope it is HELPFUL to u

Discussion

40.	If p q r are (6 -1) (1 3) (x 8) respectively then find the value of x such that pq=qr
Answer» ong>Answer: GIVEN that pq=QR =(6-1)(1 3)=(1 3 )(X 8) = 5×13=13×8x =65=104x =x=104/6

40.

If p q r are (6 -1) (1 3) (x 8) respectively then find the value of x such that pq=qr

Answer»

ong>Answer:

GIVEN that pq=QR

=(6-1)(1 3)=(1 3 )(X 8)

= 5×13=13×8x

=65=104x

=x=104/6

Discussion

41.	Find the smallest number which must be sub tracted from the following to make them perfectcubes What are the corresponding cube roots? a.350
Answer» ONG>Answer: it is a perfect cube Step-by-step EXPLANATION: the subtraction is PERFORMED 5 times

41.

Find the smallest number which must be sub tracted from the following to make them perfectcubes What are the corresponding cube roots? a.350

Answer» ONG>Answer:

it is a perfect cube

Step-by-step EXPLANATION:

the subtraction is PERFORMED 5 times

Discussion

42.	Which number is formed, if 4 and 7 are interchanged in 45792. Write the following numbers in words.
Answer» ONG>ANSWER: it's so easy bro it form Fourty-five THOUSAND Seven hundred and ninety-two.

42.

Which number is formed, if 4 and 7 are interchanged in 45792. Write the following numbers in words.

Answer» ONG>ANSWER:

it's so easy bro

it form Fourty-five THOUSAND Seven hundred and ninety-two.

Discussion

43.	Evaluate using identities : 55^2-45^2
Answer» ONG>ANSWER: 100 is the answer of this EQUATION

Discussion

44.	FIND THE VALUE OF X IF 2²x+² =
Answer» ONG>Answer: x= 1 the correct answer

44.

FIND THE VALUE OF X IF 2²x+² =

Answer» ONG>Answer:

x= 1

the correct answer

Discussion

45.	In the given figure, Diameter AB and a chord AC have acommon vertex. If thelength of AB=20 cm. andAC = 12 cm. How far is ACfrom the centre of the circle?
Answer» ong>Answer: DIAMETER of the circle =20cm so, RADIUS will be 10cm AC=12cm. so,AD =6CM. (PERPENDICULAR drawn from the centre of the circle bisects the chord) By Pythagoras theorem on ∆ADO AO²=AD²+OD² SO, OD=√100-36=√64=8cm ans

45.

In the given figure, Diameter AB and a chord AC have acommon vertex. If thelength of AB=20 cm. andAC = 12 cm. How far is ACfrom the centre of the circle?

Answer»

ong>Answer:

DIAMETER of the circle =20cm so, RADIUS will be 10cm

AC=12cm.

so,AD =6CM. (PERPENDICULAR drawn from the centre of the circle bisects the chord)

By Pythagoras theorem on ∆ADO

AO²=AD²+OD²

SO, OD=√100-36=√64=8cm ans

Discussion

46.	mayne bought blueberry. he uses 3/8 of the blueberries to make blueberry bread, 1/6 of the blueberries to make pancake and 5/12 of the blueberries to make jam. if wayne uses 69 ounces of the blueberries he bought how many ounces of blueberries did he buy?
Answer» ong>Step-by-step explanation: He uses 3/8 of the blueberries to make BLUEBERRY bread, 1/6 ... If Wayne uses 69 OUNCES of the blueberries he BOUGHT, ...

46.

mayne bought blueberry. he uses 3/8 of the blueberries to make blueberry bread, 1/6 of the blueberries to make pancake and 5/12 of the blueberries to make jam. if wayne uses 69 ounces of the blueberries he bought how many ounces of blueberries did he buy?

Answer»

ong>Step-by-step explanation:

He uses 3/8 of the blueberries to make BLUEBERRY bread, 1/6 ... If Wayne uses 69 OUNCES of the blueberries he BOUGHT, ...

Discussion

47.	Convert the given ratio into percentage. 8:101️⃣ 8%2️⃣ 80%3️⃣ 40%4️⃣ 20%
Answer» ong>Question :- Convert the given ratio into percentage. 8:10 ? 1) 8% 2) 80% 3) 40% 4) 20% Solution :- → 8 : 10 dividing both ratio by 2, we get, → 4 : 5 this can be written as , → (4/5) now, we know that, In order to convert into percentage , we have to multiply the given number by 100 . then, → (4/5) * 100 → (400 / 5) → (5 * 80) / 5 → 80% (Option 2) (Ans.) Hence, 8:10 ratio is equal to 80% . Learn more :- 2 RS 50 paise ; 3 Rs 50 paise. Write the ratio between the TWO given quantities in simplest form. 5:7 7:5 ... brainly.in/question/37820836 75% convert this given percentage into simplest form of ratio brainly.in/question/37839381

47.

Convert the given ratio into percentage. 8:101️⃣ 8%2️⃣ 80%3️⃣ 40%4️⃣ 20%

Answer»

ong>Question :- Convert the given ratio into percentage. 8:10 ?

1) 8%

2) 80%

3) 40%

4) 20%

Solution :-

→ 8 : 10

dividing both ratio by 2, we get,

→ 4 : 5

this can be written as ,

→ (4/5)

now, we know that,

In order to convert into percentage , we have to multiply the given number by 100 .

then,

→ (4/5) * 100

→ (400 / 5)

→ (5 * 80) / 5

→ 80% (Option 2) (Ans.)

Hence, 8:10 ratio is equal to 80% .

Learn more :-

*2 RS 50 paise ; 3 Rs 50 paise. Write the ratio between the TWO given quantities in simplest form.*

5:7

7:5

...

brainly.in/question/37820836

75% convert this given percentage into simplest form of ratio

brainly.in/question/37839381

Discussion

48.	the diagonals of quadrilateral intersect each other of right angle prove that the sum of the squares of opposite sides is equal?
Answer» ong>Answer: Let us consider a quadrilateral ABCD in which the diagonals AC and BD intersect each other at O. It is given that the diagonals of ABCD are equal and bisect each other at right angles. Therefore, AC = BD, OA = OC, OB = OD, and ∠AOB = ∠BOC = ∠COD = ∠AOD = 90º. Now, to prove ABCD is a square, we have to prove that ABCD is a parallelogram, AB = BC = CD = AD, and one of its interior angles is 90º. Step-by-step explanation: Proof: In ΔAOB and ΔCOD, AO = CO (Diagonals bisect each other) OB = OD (Diagonals bisect each other) ∠AOB = ∠COD (VERTICALLY opposite angles) ∴ ΔAOB ≅ ΔCOD (SAS congruence rule) ∴ AB = CD (By CPCT) ... (1) And, ∠OAB = ∠OCD (By CPCT) However, these are alternate interior angles for line AB and CD and alternate interior angles are equal to each other only when the TWO lines are parallel. ∴ AB \|\| CD ... (2) From equations (1) and (2), we obtain ABCD is a parallelogram. In ΔAOD and ΔCOD, AO = CO (Diagonals bisect each other) ∠AOD = ∠COD (Given that each is 90º) OD = OD (Common) ∴ ΔAOD ≅ ΔCOD (SAS congruence rule) ∴ AD = DC ... (3) However, AD = BC and AB = CD (Opposite sides of parallelogram ABCD) ∴ AB = BC = CD = DA Therefore, all the sides of quadrilateral ABCD are equal to each other. In ΔADC and ΔBCD, AD = BC (Already proved) AC = BD (Given) DC = CD (Common) ∴ ΔADC ≅ ΔBCD (SSS Congruence rule) ∴ ∠ADC = ∠BCD (By CPCT) However, ∠ADC + ∠BCD = 180° (Co-interior angles) ⇒ ∠ADC + ∠ADC = 180° ⇒ 2∠ADC = 180° ⇒ ∠ADC = 90° One of the interior angles of quadrilateral ABCD is a right angle. Thus, we have obtained that ABCD is a parallelogram, AB = BC = CD = AD and one of its interior angles is 90º. Therefore, ABCD is a square.

48.

the diagonals of quadrilateral intersect each other of right angle prove that the sum of the squares of opposite sides is equal?

Answer»

ong>Answer:

Let us consider a quadrilateral ABCD in which the diagonals AC and BD intersect each other at O. It is given that the diagonals of ABCD are equal and bisect each other at right angles. Therefore, AC = BD, OA = OC, OB = OD, and ∠AOB = ∠BOC = ∠COD = ∠AOD = 90º.

Now, to prove ABCD is a square, we have to prove that ABCD is a parallelogram, AB = BC = CD = AD, and one of its interior angles is 90º.

Step-by-step explanation:

Proof:

In ΔAOB and ΔCOD,

AO = CO (Diagonals bisect each other)

OB = OD (Diagonals bisect each other)

∠AOB = ∠COD (VERTICALLY opposite angles)

∴ ΔAOB ≅ ΔCOD (SAS congruence rule)

∴ AB = CD (By CPCT) ... (1)

And, ∠OAB = ∠OCD (By CPCT)

However, these are alternate interior angles for line AB and CD and alternate interior angles are equal to each other only when the TWO lines are parallel.

∴ AB || CD ... (2)

From equations (1) and (2), we obtain

ABCD is a parallelogram.

In ΔAOD and ΔCOD,

AO = CO (Diagonals bisect each other)

∠AOD = ∠COD (Given that each is 90º)

OD = OD (Common)

∴ ΔAOD ≅ ΔCOD (SAS congruence rule)

∴ AD = DC ... (3)

However, AD = BC and AB = CD (Opposite sides of parallelogram ABCD)

∴ AB = BC = CD = DA

Therefore, all the sides of quadrilateral ABCD are equal to each other.

In ΔADC and ΔBCD,

AD = BC (Already proved)

AC = BD (Given)

DC = CD (Common)

∴ ΔADC ≅ ΔBCD (SSS Congruence rule)

∴ ∠ADC = ∠BCD (By CPCT)

However, ∠ADC + ∠BCD = 180° (Co-interior angles)

⇒ ∠ADC + ∠ADC = 180°

⇒ 2∠ADC = 180°

⇒ ∠ADC = 90°

One of the interior angles of quadrilateral ABCD is a right angle.

Thus, we have obtained that ABCD is a parallelogram, AB = BC = CD = AD and one of its interior angles is 90º. Therefore, ABCD is a square.

Discussion

49.	9. There is a circular waterbed of radius 5 m inside a rectangular park of length 15 m and breadth12 m, as shown in the figure. Find the area ofthe park excluding the waterbed and also findthe cost of fencing the water bed at the rate of360 per m. (Take it = 3.14)
Answer» SE MARK me as brainst

Discussion

50.	12. The volume of a block of gold is 0.5 m". If it is hammered into a sheet to cover an area 1 hectare, find the thickness of the sheetdo it a d explain it also
Answer» ong>Answer: 0.005cm Step-by-step EXPLANATION: Given that volume of the block of GOLD is 0.5 M3 We know that 1 hectare = 10000 m2 Thickness of the sheet = volume/ AREA = 0.5/1000 =0.00005m =0.005cm please mark as brainliest

50.

12. The volume of a block of gold is 0.5 m". If it is hammered into a sheet to cover an area 1 hectare, find the thickness of the sheetdo it a d explain it also

Answer»

ong>Answer:

0.005cm

Step-by-step EXPLANATION:

Given that volume of the block of GOLD is 0.5 M3 We know that 1 hectare = 10000 m2

Thickness of the sheet

= volume/ AREA

= 0.5/1000

=0.00005m

=0.005cm

please mark as brainliest

Discussion

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