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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
(V) Match the following: (1) Asha worker(2) MPHA(3) JVR(4) Haritha haram program(a) 2015(b) opencast(c) at village level(d) Multipurpose health assistance |
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| 2. |
In quadrilateral ABCD shown in adjoining figure, AB || DC and AD I AB. Also, AB=8 m, DC = 5m. Find the area of the quadrilateral in two ways:(i) Taking ABCD as a trapezium.(ii) Taking quadrilateral ABCD as the sum ofrectangle AECD + triangle BEC. |
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Answer» AB ║ CDAB ║ CDDA ⊥ABAB ║ CDDA ⊥ABAB = 8 mAB ║ CDDA ⊥ABAB = 8 mBC = 5 mAB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mAB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ ABAB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mAB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 MBE = AB - AE = 8 - 5 = 3 cmAB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmAB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CEAB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CE= (1/2)(8 + 5) * 4AB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CE= (1/2)(8 + 5) * 4= 13 * 2AB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CE= (1/2)(8 + 5) * 4= 13 * 2= 26 m²AB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CE= (1/2)(8 + 5) * 4= 13 * 2= 26 m²Area of Quadrilateral ABCD = Area of RECTANGLE AECD + Area of Triangle BCEAB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CE= (1/2)(8 + 5) * 4= 13 * 2= 26 m²Area of Quadrilateral ABCD = Area of rectangle AECD + Area of Triangle BCEArea of rectangle AECD = AE * CE = 5 * 4 = 20 m²AB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CE= (1/2)(8 + 5) * 4= 13 * 2= 26 m²Area of Quadrilateral ABCD = Area of rectangle AECD + Area of Triangle BCEArea of rectangle AECD = AE * CE = 5 * 4 = 20 m²Area of Triangle BCE = (1/2)BE * CE = (1/2) * 3 * 4 = 6 m²AB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CE= (1/2)(8 + 5) * 4= 13 * 2= 26 m²Area of Quadrilateral ABCD = Area of rectangle AECD + Area of Triangle BCEArea of rectangle AECD = AE * CE = 5 * 4 = 20 m²Area of Triangle BCE = (1/2)BE * CE = (1/2) * 3 * 4 = 6 m²Area of Quadrilateral ABCD = 20 + 6 = 26 m²AB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CE= (1/2)(8 + 5) * 4= 13 * 2= 26 m²Area of Quadrilateral ABCD = Area of rectangle AECD + Area of Triangle BCEArea of rectangle AECD = AE * CE = 5 * 4 = 20 m²Area of Triangle BCE = (1/2)BE * CE = (1/2) * 3 * 4 = 6 m²Area of Quadrilateral ABCD = 20 + 6 = 26 m²Learn more:AB ║ CDDA ⊥ABAB = 8 mBC = 5 mCD = 5 mLet say CE ⊥ AB=> AE = CD = 5 mBE = AB - AE = 8 - 5 = 3 cmCE² = BC² - BE² = 5² - 3² = 25 - 9 = 16 = 4² => CE = 4 cmArea of Trapezium = (1/2)(AB + CD) * CE= (1/2)(8 + 5) * 4= 13 * 2= 26 m²Area of Quadrilateral ABCD = Area of rectangle AECD + Area of Triangle BCEArea of rectangle AECD = AE * CE = 5 * 4 = 20 m²Area of Triangle BCE = (1/2)BE * CE = (1/2) * 3 * 4 = 6 m²Area of Quadrilateral ABCD = 20 + 6 = 26 m²Learn more:There is a trapezium whose parallel sides are 10 cm and 22.3 CM ...If the area of a trapezium with parallel sides of length 30 cm and 23 ...In trapezium ABCD, AB || CD and AC = BD. |
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| 3. |
Find the values of x and y. |
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Answer» x=30degreey=105degreeStep-by-step EXPLANATION:ANGLE SUM FORMULA:3x+60=1803x =180-603x =120Therefor, x=30 degreeAnd,(x+35)+y =180WE KNOW x=30 (30+45)+y =18075+y = 180y =180-75y =105 degree |
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| 4. |
...class10......solve...... don'tspam......^_^... |
| Answer» KONSA SUBJECT hai Step-by-step explanation:BOLO yaar | |
| 5. |
7.1 cm RD14. (a) In figure, AD = AC and BD = BC.(1) State the three pairs of equal parts inAABD and AABC.(ü) IS AABD = AABC? Why or why not?(i) Does AB bisect ZDBC? Give reason.(b) In figure, AC = BD and AD = BC, which of thefollowing statements is meaningfully written?Explain(1) AABC = AABD (ii) AABC = ABADDBАT |
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| 7. |
Number 1.1 or 13 ka var g |
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Answer» the ANSWERMARK me as BRAINLIEST PLEASEEE |
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| 8. |
9. Describe the friendship between Ramzan and Bulbul. |
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Answer» -STEP explanation:Ramzan and BULBUL SHARED a special relationship. ... (v) Describe what did Jochen see when he PEEPED through the window of the RESTAURANT,. |
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| 9. |
93.5 percent into fraction |
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Answer» 93.5 PERCENT into fraction=0.935 |
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| 10. |
Factorise the expressions and divide: 4ab (2 +6b -16)÷ 2a(b+8) Please do not spam |
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Answer» -step explanation:answer PLS ADD it on MICROSOFT MATH solver |
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| 11. |
Mathematics (National) | 31 18. The denominator of a rational number is more thanits numerater by 5. If 10 is added to the numeratorand 1 is subtracted from the denominator, then thefraction becomes 2. Find the fraction. |
| Answer» GET YI hdhfbnnli GM HMM JJ | |
| 12. |
5. The angles of a pentagon are in the ratio 4:5:11:13:12. Find the measures of each angle. |
| Answer» MEASURE of each ANGLE is 48°,60°,132°,156° and 144°Step-by-step explanation:Given the pentagon have 5 angles∴ All angles measure up to 540°∵Angles of a pentagon are in the ratio 4:5:11:13:12Let X be the common multiple, then we have 4x+5x+11x+13x+12x = 540→ 45x = 540∴ x = 12∴ 4x= 4x12 =48°5x = 5x12 = 60°11x = 11x12 = 132°13x = 13x12 = 156°12x = 12x12 = 144°thus measure of each angle is 48°,60°,132°,156° and 144° | |
| 15. |
5. Solve these problems: cakes.(a) Tina are 5.4 cake. So, she had really eaten(0) I love walking. I took 41/4 rounds of the park. How many quarters ofthe park did I walk?(c) Shelly drank 3/2 glasses of milk which was reallyRohan ran 2.3km and was tired. He had really runglasses. |
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Answer» (a), at FIRST he ate 2/3 means remaining=1/3 now he ate 4/7 of 1/3 that is =1/3*4/7=4/21So TOTAL amount he ate=(2/3)+(4/21)=18/21Total REMAINS =1–(18/21) = 3/21 = 1/71/7 is the ANSWER. |
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| 16. |
Due to wide fluctuations in petrol prices ,the prices rose in one year by 30% and then came down next year by 15% .what was the percentage in price change in price of petrol when compared to the original place?.... |
| Answer» 15%Step-by-step EXPLANATION:because 30 - 15 = 15so the ANSWER is 15% | |
| 17. |
2 to 12table Bottom 12 |
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Answer» ,Step-by-step EXPLANATION:i HOPE it's can HELP you |
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| 18. |
Question No. 25Which of the following fractions is greater than 3/4 andless than 5/6? |
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Answer» No answerStep-by-step EXPLANATION:Because the FRACTIONS are not GIVEN SORRY |
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| 19. |
14) From the following observation : 0.03, 0.05, 1.04, 0.08, 0.05, 1.03, 0.03, 0.04, 0.07, 0.05, 0.02, 1.00, 0.08a) Calculate the medianb) Calculate the range |
| Answer» MEDIAN is 0.03 RANGE is 1.08 - 1.04 0.04 | |
| 20. |
Question 27.The expression for ‘ 1 added to -p’ is(a) – p + 1(b) – p – 1(c) p + 1(d) p – 1. |
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Answer» we gives-p+1 so RIGHT answer is 1NO THANKYOU have a nice day |
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| 21. |
TRY THESEIdentify which are simple curves and which are not |
| Answer» 4 is the CORRECT ANSWER for your answer | |
| 22. |
(1)The area of a rectangular stage is 750 sq m. If its height is 1.5 m, find its volume.(Hint: area = length x breadth) |
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Answer» • Area of the Rectangular Stage = 750 m²• Height of the Rectangular Stage = 1.5 mTo FIND ☆• The Volume of the Rectangular Stage Formula Used ☆Volume = Area of base × Height Solution ☆To find the Volume of the Rectangular Stage we need to multiply the Area of the Rectangular Stage ( 750 m² ) with the height of the Rectangular Stage ( 1.5 m ), so let's do it!Volume = Area of base × Height Volume = 750 × 1.5Volume = 1125 m³∴ Volume of the Rectangular Stage is 1125 m³______________________________________________________Perimeter of SQUARE = 4 × sidePerimeter of Rectangle = 2 × ( Length + Breadth )Perimeter of Triangle = Sum of all sidesArea of Square = side × sideArea of Rectangle = Length × BreadthVolume of Cube = side × side × sideVolume of Cuboid = Length × Breadth × HeightNote : We can ALSO WRITE the formula Area of Square = side × side as Area of Square = ( side )² and Volume of Cube = side × side × side as Volume of Cube = ( side )³______________________________________ |
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| 24. |
At what rate of interest does a sum of Rs. 54,000 earn on interest of Rs. 9,720 in 2 yrs. |
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Answer» The diameter gives RISE to two EQUAL arcs.TrueStep-by-step EXPLANATION: |
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| 25. |
Four dice are thrown simultaneously. Find the probabilitythat all of them show the same face. |
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Answer» the ODDS are 1/216Step-by-step explanation:this is as each face can come 6 times on each DICE so 6x6x6x6All of the SHOW the same FACES = (1,1,1,1),(2,2,2,2),(3,3,3,3),(4,4,4,4),(5,5,5,5),(6,6,6,6) hence the odds are 1/216 |
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| 26. |
किसी वस्तु को 120 रु० में बेचने पर क्रयमूल्य का , 1/3 लाभ होता है, तो लाभ काप्रतिशत क्या है ? |
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| 27. |
Multiplying of monomial by a bionomial 2x²y×(x+y) |
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Answer» 2x³y+2x²y²Step-by-step explanation:2x²y×(x+y)=2x³y+2x²y² |
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| 28. |
Write the following rational numbers in standard form 1.-48/60 2.35/-753.-60/484.105/-175 |
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Answer» -step explanation:(i) Here, numerator = 9 and DENOMINATOR = 15Factors of 9 are 1, 3 and 9.Factors of 15 are 1, 3, 5 and 15.Common factors of 9 and 15 are 1 and 3.H.C.F. of 9 and 15 is 3.∴ 915 =9÷315÷3 = 35Hence, the simplest form of 915 is 35.(ii) Here, numerator = 48 and denominator = 60Factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24 and 48.Factors of 60 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30 and 60.Common factors of 48 and 60 are 1, 2, 3, 4, 6 and 12.H.C.F. of 48 and 60 is 12.∴ 4860 =48÷1260÷12 = 45Hence, the simplest form of 4860 is 45.(iii) Here, numerator = 84 and denominator = 98Factors of 84 are 1, 2, 3, 4, 6, 7, 12, 14, 21, 42 and 84.Factors of 98 are 1, 2, 7, 14, 49 and 98.Common factors of 84 and 98 are 1, 2, 7 and 14.H.C.F. of 84 and 98 is 14.∴ 8498 =84÷1498÷14 = 67Hence, the simplest form of 8498 is 67.(IV) Here, numerator = 150 and denominator = 60Factors of 150 are 1, 2, 3, 5, 6, 10, 15, 25, 30, 75 and 150.Factors of 60 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30 and 60.Common factors of 150 and 60 are 1, 2, 3, 5, 6, 10, 15 and 30.H.C.F. of 150 and 60 is 30.∴ 15060 =150÷3060÷30 = 52Hence, the simplest form of 15060 is 52.(v) Here, numerator = 72 and denominator = 90Factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36 and 72.Factors of 90 are 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45 and 90.Common factors of 72 and 90 are 1, 2, 3, 6, 9 and 18.H.C.F. of 72 and 90 is 18.∴ 7290 =72÷1890÷18 = 45Hence, the simplest form of 7290 is 45. |
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| 29. |
Find the perimeter and area of the following: a) A school ground whose length is 130 m and breadth is 58 mb) A square field of side 34 mc) A sheet of paper of size 10 cm x 8.5 cm:) A rectangular park of length 40 m and breadth 20 m |
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| 30. |
The simplest form of the ratio " 1 day to 300 minutes " isplease solve it its urgent |
| Answer» 24 HRS = 1440mins1440 : 300 = 144:30 = 24:5 | |
| 31. |
Find the value of x in the following figures |
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| 32. |
Covert 19/5 into percentage |
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Answer» Here's the answer-Step-by-step explanation:19/5×100=380% |
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| 33. |
Please answer it quick I am not good at this chapter. |
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Answer» 7-both TRIANGLE will congruent by RHS RULE so PQ=PSAND both ANGLE will equal by CPCT THANKYOU HAVE A NICE DAY |
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| 34. |
Write the ratio 3hours to 45minutes in simplest form. |
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Answer» -STEP EXPLANATION:HOPE it HELPS YOUTHANK me |
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| 35. |
0.1. Solve the following: (6)(1)In the given figure. If 2*-80, 2y = 80°, 2x110°Check ) line m and line !mare parallel or not (2) linesmandare parallel or not. |
| Answer» SOORY Step-by-step EXPLANATION:i DONT no can U mark me as brainliest | |
| 36. |
3. - 44. Ranu drank a bottle of milk and her sister drank4-5Who drank more and by how much?a bottle of milk [the bottles are of the same |
| Answer» RENU SISTER DRAN MORE BY 1-1 BOTTLE Step-by-step explanation: 5-4 - 4-3 is equal to 1-1 | |
| 37. |
Divide 12( x³y² + x²y³ + x²y² ) by 4x² y²pls tell answer |
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Answer» hope it HELPS uStep-by-step explanation:12x³y²/4x²y²=3x ( the POWER of y is 0 which MEANS 1, so we dnt write y)+12x²y³/4x²y²=3y (the power of X is 0 which means 1, so we dnt write x)+12x²y²/4x²y²=3 ( the power of x and y is 0 which means 1, so we dnt write x and y)= 3x+3y+3 is the ansu dnt have to solve any more |
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| 38. |
a body of mass 3kg is moving with a velocity of 2m/s.a constant horizontal force acts on the body for 3sec.so that it's velocity becomes 8 m/s.find the force |
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Answer» -Mass (m) of body = 3 kgInitial (u) velocity = 2 m/sFinal (v) velocity = 8 m/s Time (t) of FORCE applied = 3 sTo FIND :-The force applied on the objectAnswer :-Using the First equation of motion, we can calculate acceleration (a) as,Now, using Newton's SECOND law of motion, we can calculate force (F) as, The Force applied on the object was 6 N |
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| 39. |
The diameter gives rise to two equal arcs.truefalse |
| Answer» METER GIVES rise to TWO EQUAL ARCS. True | |
| 40. |
There are 54 children in class IV of a school. 1/3 of them are girls. How many children are boys. |
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Answer» -step EXPLANATION:NUMBER of GIRLS= 1/3 of 54 = 18 number of boys = 54-18=36 |
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| 41. |
1) AB and CB are two chords of circle. Prove that BO bisects angle 8. (3) |
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Answer» -step explanation:Given: In the figure, AB = CB and O is the CENTRE of the circle. To Prove: BO bisects ∠ABC. Construction: Join OA and OC.Proof : In ∆OAB and ∆OCB, OA = OC [RADII of the same circle] AB = CB [Given] OB = OB [COMMON] ∴ ∆OAB ≅ ∆OCB [By SSS] ∴ ∠ABO = ∠CBO [By CPCTC] ⇒ BO bisects ∠ABC. |
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| 42. |
1. Express the following speeds in km/h:(ii) 250 m/s |
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| 43. |
In the figure, ABC=DEC.Given that ANGLE..ACB=71°. ANGLE..CDE = 34° AC = 6.9 cm and BC = 4 cm, find....(a) ANGLE... ABC... (b) the length of BDANSWER IN COPY WRITTENAND IF U HELP ME THANKS AND IF YOU NOT HELP ME BY SEEING THIS SO GOD WITH NOT |
| Answer» LENGTH of BD is 4 cmStep-by-step explanation:USE CONGRUENCE criteriau will go ahead with correct answer !!!!!! | |
| 44. |
Due to wide fluctuations in petrol prices ,the prices rose in one year by 30% and then came down next year by 15% .what was the percentage in price change in price of petrol when compared to the original place?... |
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Answer» 10.5% of PRICE is INCREASED Step-by-step EXPLANATION:HOPE this HELPS you |
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| 45. |
Factorise : a² - (a+b)²pls tell me the answer |
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| 46. |
Find out the wrong number in the given sequence ofnumbers. |
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Answer» Find out the wrong number in the given sequence of numbers.582, 605, 588, 611, 634, 617, 600. A. 634. B. 611. C. 605. D. ...22, 33, 66, 99, 121, 279, 594. A. B. 121. C. 279. D. 594. ...A. B. C. D. Answer: Option A. Explanation: Go on adding 5, 8, 11, 14, 17, 20. ...1, 8, 27, 64, 124, 216, 343. A. B. C. D. 124. Answer: Option D. |
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| 47. |
AB=DC and diagonal AC and BD intersect at P in cyclic quadrilateral prove that. B |
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Answer» Since abcd is a CYCLIC quadrilateral WHOSE diagonal ac and bd intersect at p if ab = dc, our aim is to prove that TRIANGLE pas is CONGRUENT to triangle pdc ,pa=pb ,pc=pb ,ad is parallel to bc. ... In third part, we are given that DIAGONALS are bisectors, so ABCD is a parallelogram, therefore AD║BC.Mark my answer as brainlist |
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| 48. |
Can somebody solve question 21 and 22 with full explanation I will mark blainliest like and follow plz |
| Answer» 22ND one is not CLEAR but I guess U can APPLY the same property.ThanksLike Follow and RateTeacher. | |
| 49. |
Initially when we start business we require money for raw material,is called --------- capitalpartnershipinterestloss |
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Answer» -STEP EXPLANATION:interesthope it HELPS you |
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| 50. |
Which number can be shown as triangles eg 3;6 |
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Answer» bjwnhwhwjqkjbqbbababab |
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