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The ANSWER is 10N because STATIC FORCE is o.4 and force is 2.5 N

riend!Let the bodies of mass m1 and m2 move with VELOCITIES v1 and v2 respectively as shown in the diagram. From EQUATIONS (3) and (4) Thus, the total MOMENTUM of the system before collision = The total momentum of the system after the collision. Thus the law of CONSERVATION of momentum is proved.

riend!Any INCIDENT RAY traveling parallel to the principal axis of a converging lens will refract through the lens and travel through the focal POINT on the opposite side of the lens. ... These rays of LIGHT will refract when they enter the lens and refract when they leave the lens

n 1 : The measure mass and volume of a body are 22.42 g and 4.7 cm³ respectively with possible errors of 0.01 g and 0.1 cm³. The maximum error in density is :Answer 1 :Given :m = 22.42 gv = 4.7 cm³∆m = 0.01 g∆v = 0.1 cm³We know that, when two quantities are MULTIPLIED or divided, the relative error in the result is the sum of the relative errors in the multipliers.Hence, ∆R/R = ∆m/m + ∆v/vLet's find the relative error of mass :⇒ 0.01/22.42⇒ 0.00044 gNow, finding the relative error of velocity :⇒ 0.1/4.7⇒ 0.02 cm³Therefore, ∆R/R = ∆m/m + ∆v/v⇒ ∆R/R = 0.00044 + 0.02⇒ ∆R/R = 0.02044Finding the percentage error in density : 0.02044 × 100⇒ 2.044 % = 2%OPTION B = 2%Question 2 : If a physical quantity is represented by x = [M^aL^bT^-c] and if the percentage error in the measurement of M, L and T are α%, β% and γ% respectively, then the TOTAL percentage error in x is :Answer 2 :Here, the quantities M and L are in multiplication and the quantity T is divided.Hence, the final percentage error = (∆x/x)% = a(∆M/M)% + b(∆L/L)% + c(∆T/T)%We are already given that the percentage error of M, L and T are α%, β% and γ% respectively.Hence, (∆x/x)% = (aα + bβ + cγ)%Option A = (aα + bβ + cγ)%Question 3 : If the units of force, energy and velocity are 10 N, 100 J and 5 m/s; the units of length, mass and time will be :Answer 3 :The DIMENSIONAL Formula of :Force = [MLT^-2]Energy = [ML²T^-2]Velocity = [LT^-1]Given,F = [MLT^-2] = 10 NE = [ML²T^-2] = 100 JV = [LT^-1] = 5 m/sDividing Energy by Force, [ML²T^-2]/[MLT^-2] = [L]Therefore, 100/10 = 10 m.Now, V = [LT^-1] = 5 m/s = 10*T^-1 = 5 m/s⇒ 10/5 = T⇒ T = 2 sAt last, F = [MLT^-2] = 10 N⇒ M*10*2^-2 = 10⇒ M = (10 × 2²)/10⇒ M = 4 kgHence, Option (B) = Units of length, mass and time will be : 10 m, 2 s and 4 kg respectively.Question 4 : The least count of a stopwatch is 0.01 s. The time period of 100 oscillations of the pendulum is 100 s. The percentage error in the time period will be :Answer 4 :Number of oscillations = 100Time taken = 100 sThe error in 100 oscillations = 0.01 sSo, Time period for 100 oscillations = 100 s ± 0.01 sHence, Percentage error = ∆t/t × 100 = 0.01/100 × 100⇒ Percentage error = 0.01 %Hence, Option A = 0.01%.

1:2Explanation: as the MASS is same so mass will be DISMISSED and V & v will ALSO be dismissed. .

let's assume you are not taking air resistance into consideration. This is a reasonable assumption because it's obvious that a parachute's velocity just before it hits depends on factors other than just gravity or drop height. Adjusting its size can influence its speed at impact. Without air friction, an object WILL regain its original upward velocity just before it hits the ground on the way down. The initial velocity on the ground represents KINETIC ENERGY, and the initial height of (0) represents NO POTENTIAL ENERGY. As the object rises, its kinetic energy is gradually converted into potential energy until at its HIGHEST point all the original kinetic energy (now zero) has been converted into potential energy. At any point in its travel, TOTAL kinetic and potential energy remains constant. The process is reversed when the object falls. Starting at maximum potential energy (determined by its maximum height) and zero kinetic energy (not moving), the potential energy gradually gets converted BACK into kinetic energy until just before it hits the ground. Then, potential energy is zero and it has all the kinetic energy it had at the start. So the CONSERVATION OF ENERGY is why the TWO velocities are the same. then the other case is that it can be more or LESS than the original velocity.it depends on time.i think you know about the latter case. hope it helps. PLZ mark as brainliest.

is GIVEN in the pic.Y WOULD anyone report a CORRECT answer???????????!!!!!!!

In all these EXAMPLES the speed and the direction of the moving ball change due to the application of a force. ... A change in EITHER the speed of an OBJECT, or its direction of motion, or both, is described as a change in its state of motion. Thus, a force may bring a change in the state of motion of an object.

tion:When light travels from a denser medium to a rarer medium, it BENDS away from the normal, as illustrated to the LEFT. This behavior follows from Snell's Law. As you saw before, the larger angle MUST be in the medium having the lower index of refraction

what's your QUESTION......????

On Earth, g=9.8 m/s2 . So, the OBJECT's weight on Earth will be:W=50 kg⋅9.8 m/s2 =490 NPLEASE tell me CLEARLY...What r u TRYING to say...Please...its a request

ew drops of water in the TEST tube containing gas. Now, cover the test tube and shake it well. After shaking, test the solution with blue LITMUS and red litmus. It will turn blue litmus red. Thus, the gas is acidic in nature.Charcoal reacts with oxygen to form carbon DIOXIDE gas.HOPE IT HELPS PLZ MARK AS BRAINLIST

hihyrbribExplanation:

C) Measure of force hope it HELPS UHH PLS mark as BRAINLIEST - Pari 4166❤❤

A force of 10 N is applied on 2 bodies of masses m1 and m2 in order to accelerate them at 2 m/s² and 4 m/s² .Required to find :-Acceleration of the bodies when they are tied to together ?Formula used :-\boxed{\tt{mass = \frac{force}{acceleration} }} mass= accelerationforce Solution :-Given information :-A force of 10 N is applied on 2 bodies of masses m1 and m2 in order to accelerate them at 2 m/s² and 4 m/s² .From the given information we can CONCLUDE that ;Case - 1Force ( F1 ) = 10 NAcceleration ( a1 ) = 2 m/s²Case - 2Force ( F2 ) = 10 NAcceleration ( a2 ) = 4 m/s²We need to find the masses of the respective bodies in 2 casesSo,In case - 1Force ( F1 ) = 10 NAcceleration ( a1 ) = 2 m/s²Using the formula,\boxed{\tt{Mass = \dfrac{Force}{Acceleration} }} Mass= AccelerationForce ARROW{\tt{ Mass = \dfrac{ 10 }{ 2 } }}arrowMass= 210 arrow{\tt{ {M}_{1} = 5 \ kg }}arrowM 1 =5 kgSimilarly,In case - 2Force ( F2 ) = 10 NAcceleration ( a2 ) = 4 m/s²Using the same formula,arrow{\tt{ Mass = \dfrac{ 10}{ 4 } }}arrowMass= 410 arrow{\tt{ {M}_{2} = 2.5 }}arrowM 2 =2.5Now,we need to find the acceleration when the two bodies are tied together ;This means that we need to divide the Force by sum of the masses of two bodies ( Total Mass ) .Hence,Total mass = m1 + m2=> 5 + 2.5=> 7.5 kgHowever,\tt{ Acceleration = \dfrac{ 10 }{ 7.5 } }Acceleration= 7.510 Multiply the numerator and denominator with 10So,\tt{ Acceleration = \dfrac{ 10 \times 10 }{ 7.5 \times 10 } }Acceleration= 7.5×1010×10 \tt{ Acceleration = \dfrac{ 100 }{ 75 }}Acceleration= 75100 \tt{ Acceleration = 1.333 \dots }Acceleration=1.333…\implies{\UNDERLINE{\rm{ Acceleration = 1.33 \ m/s^2 \; ( approximately ) }}}⟹ Acceleration=1.33 m/s 2 (approximately) Therefore,Acceleration caused when two bodies are tied together = 1.33 m/s² ( approximately )Explanation:MARK ME AS BRAINLIST

z that BUBBLES up when you crack open a can of soda is CARBON DIOXIDE gas (CO2). Soft drink manufacturers add this TINGLING froth by forcing carbon dioxide and water into your soda at HIGH pressures—up to 1,200 pounds per square inch.

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Given the infinite SIZE of the UNIVERSE and its age, it would seem ALMOST impossible that intelligent life is unique to our planet.In 1973 researcher John Ball of the Massachusetts Institute of Technology went as far as hypothesizing that ALIENS could be observing us like animals in a zoo.San Francisco-based Messaging Extraterrestrial Intelligence (METI) met recently in Paris to revisit the alarming theory

yesExplanation:speed can be constant but velocity VARIES as the body is MOVING ALONG curved path

A Planck particle, or planckion, named after physicist MAX Planck, is a HYPOTHETICAL particle defined as a tiny black hole whose Compton wavelength is equal to its Schwarzschild RADIUS. Its mass is thus approximately the Planck mass, and its Compton wavelength and Schwarzschild radius are about the Planck length. They play a role in some models of the evolution of the universe during the Planck epoch.Compared to a proton, for EXAMPLE, the Planck particle would be extremely small (its radius being equal to the Planck length, which is about 10−20 times the proton's radius) and massive (the Planck mass being 1019 times the proton's mass). The Planck particle would also have a very fleeting existence, evaporating due to HAWKING radiation after approximately 5×10−39 seconds.

Explanation:F = mv- mu/tF= m(v-u)/tF = 1(60- 15 ) / 15F = 45/15F = 3 N

d) 80 NExplanation:HOPE it is HELPFUL

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pressureExplanation:P= force/unit areaso pressure increases as area decreases.A sharp knife has less area, so pressure is more.it is REVERSE in CASEOF a blunt knife.sleepers are laid to distribute pressure to a LARGE area and the RAILS don't SINK.

the ANSWER is :-a. 7.5 KM/ s^-2

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tion:Machines can be simple, with just one or a few parts. Simple machines include the INCLINED plane, wedge, screw, LEVER, wheel and axle, GEAR, and pulley. Complex machines combine simple machines. ... All machines help US do work, EITHER by using less force over more distance or more force over less distance.Mark me as brain lists

Explanation:Friction comes into PLAY when irregularities present in the SURFACES of two objects in contact get interlocked with each other. In SLIDING, the time given for interlocking is very small. Hence, interlocking is not strong. Therefore, less FORCE is required to overcome this interlocking. Because f this REASON, sliding friction is less than static friction.IF HELPFULL MARK ME AS BRAINLIESTAND FOLLOW ME

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