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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
1). 44 percent2). 30.56 percent3). 15.28 percent4). 22 percent |
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Answer» ⇒ Wrong calculated number = x × (5/6) = 5x/6 ⇒ ACTUAL number = x × (6/5) = 6x/5 ⇒ ERROR = 6x/5 – 5x/6 = 11x/30 ⇒ PERCENTAGE error = (11x/30)/(6x/5) × 100 = 30.56% |
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| 52. |
200 and 180 students of school A & B passed the exam. 20% and 10% students from A and B did not pass the exam. How many students appeared in the exam from both the schools?1). 4202). 3603). 4504). 400 |
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Answer» Number of students of school A who passed the exam = 200 PERCENT of students of school A who did not pass the exam = 20% ⇒ Percent of students of school A who pass the exam = 80% ⇒ 80% students of school A= 200 ⇒ TOTAL students in school A = 250 Number of students of school B who passed the exam = 180 Percent of students of school B who did not pass the exam = 10% ⇒ Percent of students of school B who pass the exam = 90% ⇒ 90% students of school B= 180 ⇒ Total students in school B = 200 ⇒ Total students in both the exam = 450 ∴ 450 students appeared in the exam from both the SCHOOLS |
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| 53. |
In a survey, a group of mobile phone users were asked about the platforms on which their phones is based. The number of Java users is 75% less than the Android users, while the number of Android users is 40% more than the iOS users. If the number of Java users is 247 less than the iOS users, then how many of them are Android users?1). 5322). 6843). 7964). 818 |
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Answer» Given, Java users is 75% less than ANDROID users ⇒ Java users = 25% of Android users ⇒ Java users = 1/4 × Android users---- (1) Also, Android users is 40% more than iOS users ⇒ Android users = 140% of iOS users ⇒ Android users = 7/5 × iOS users---- (2) SUBSTITUTING (2) in (1), we get, ⇒ Java users = 1/4 × 7/5 × iOS users = 7/20 × iOS users Now, iOS users – Java users = 247 ⇒ iOS users – 7/20 × iOS users = 247 ⇒ 13/20 × iOS users = 247 ⇒ iOS users = 20/13 × 247 = 380 Substituting in (2), we get, ∴ No. of Android users = 7/5 × 380 = 532 |
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| 54. |
If A = x% of (y + z) and B = y% of (z + x), then B is what percent of A? If x = y.1). 200%2). 100%3). 120%4). 33.33% |
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Answer» If A = x% of (y + z) = (y + z) × x/100 = (y + z) × x/100---- (1) B = y% of (z + x) = (z + x) × y/100 = (z + y) × x/100---- (2) From EQUATION (1) and equation (2) ⇒ (z + y) × x/100 = (y + z) × x/100 ⇒ A = B ⇒ B/A × 100 = A/A × 100 = 100% |
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| 55. |
Ramesh and Suresh earn Rs. x and Rs. y respectively. Ramesh spends 60% of his earning on rent and utilities, 80% of the remaining for food, Rs 360 for buying a shirt and saves the remaining money. Suresh spends 75% of his earning on rent and utilities, 90% of the remaining for food, Rs 75 for buying a hat and saves the remaining. If the savings of Ramesh is 100% more than the savings of Suresh and their sum of their salaries is Rs 27000, what is the value of x?1). 120002). 150003). 180004). 11000 |
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Answer» Amount SPENT by Ramesh on rent and utilities = 60/100 × x = 0.6x ⇒ Remaining amount LEFT = x – 0.6x = 0.4x ⇒ Amount spent by Ramesh on food = 80/100 × 0.4x = 0.32x ⇒ Remaining amount left = 0.4x – 0.32x = 0.08x ⇒ Remaining amount after buying a shirt = Savings = 0.08x – 360 ⇒ Amount spent by SURESH on rent and utilities = 75/100 × y = 0.75y ⇒ Remaining amount left = y – 0.75y = 0.25y ⇒ Amount spent by Suresh on food = 90/100 × 0.25y = 0.225y ⇒ Remaining amount left = 0.25y – 0.225y = 0.025y ⇒ Remaining amount after buying a hat = Savings = 0.025y – 75 Given that the saving of Ramesh is 100% more than that of Suresh i.e. twice that of Suresh ⇒ 0.08x – 360 = 2 × (0.025y – 75) ⇒ 0.08x – 0.05y = 210---- (1) ⇒ Total salary received = x + y = 27000---- (2) ∴ SOLVING we get x = 12000 and y = 15000 |
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| 56. |
Justin spends 30% of his total salary on food items, 20% of the remaining on house rent, 10% of the remaining on internet and saves 50% of the remaining salary. If his monthly salary is Rs. 42000, how much money does he save every month?1). 106872). 104443). 105844). None of these |
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Answer» 100% of his total salary = RS. 42000 ⇒ Remaining percentage of his salary after SPENDING 30% of his salary on FOOD ITEMS = (100% - 30%) of his salary = 70% ⇒ Remaining percentage of his salary after spending 20% of his remaining salary on house rent = $(\left( {\frac{{100 - 20}}{{100}} \times 70} \right))$of his salary = 56% ⇒ Remaining percentage of his salary after spending 10% of his remaining salary on internet = $(\left( {\frac{{100 - 90}}{{100}} \times 56} \right))$of his salary = 50.4% ⇒ Percentage of salary saved = $(\left( {\frac{{100 - 50}}{{100}} \times 50.4} \right))$ of his salary = 25.2% ∴ Salary saved = $(\frac{{25.2}}{{100}} \times 42000)$ = Rs. 10584 |
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| 57. |
A man had 120 Mangoes. He sold 40% of it to shopkeeper, but 25% of the remaining got spoiled. His family consumed 50% of the remaining. He gave 11.11% of the remaining Mangoes to his neighbor and the remaining to his cow. How many Mangoes did he give to his neighbor?1). 62). 73). 84). 3 |
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Answer» Total no. of Mangoes = 120 No. of Mangoes SOLD = 40% of 120 = 0.4 × 120 = 48 No. of Mangoes that spoiled = 25% of (120 – 48) = 0.25 × 72 = 18 No. of Mangoes consumed by family = 50% of (120 – 48 – 18) = 0.5 × 54 = 27 Remaining Mangoes = 120 – 48 – 18 – 27 = 27 ∴ No. of Mangoes he give to his neighbor = 11.11% of 27 = 1/9 × 27 = 3 |
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| 58. |
A number is divided into two parts in such a way that 30% of first part is 25 more than the 20% of second part. 50% of second part is 33.5 more than the 60% of first part. What is the number?1). 14752). 16553). 14254). 1905 |
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Answer» Let the two parts of no. is a and b and the no. is (a + b) From the question, 30% of a = 20% of b + 25 ⇒ 3/10 × a = 1/5 × b + 25 Again, from the question 50% of b = 60% of a + 33.5 ⇒ 1/2 × b = 3/5 × a + 25 ⇒ 5B – 6a = 335 ⇒ 5b – 2 × 3a = 335 ⇒ 5b – 2 × (2b + 250) = 335 ⇒ 5b – 4b – 500 = 335 ⇒ b = 835 So, 3a = 2b + 250 = 2 × 835 + 250 = 1920 ⇒ a = 640 Hence, a + b = 640 + 835 = 1475 |
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| 59. |
1). 180%2). 280%3). 140%4). 240% |
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Answer» Let his salary be 100 ⇒ His expenditure = 95% of 100 = 95 ⇒ His saving = 100 - 95 = 5 Salary increased by 10% ⇒ New salary = (100× 110) /100 = 110 ⇒ saving on increased amount = 90% of 10 = 9 ⇒ New Saving = 9 + 5 = 14 ⇒ REQUIRED increase in saving = [(14 − 5) /5] x 100 ∴ Required increase in saving = 180% |
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| 60. |
1). 23.08 percent2). 15 percent3). 25 percent4). 30 percent |
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Answer» Given, two numbers are 35% and 50% lesser than a THIRD number Let the third number be ‘a’ 1st number = a - 35% of a = 0.65a 2nd number = a - 50% of a = 0.5a Let the % by which second number be enhanced be ‘c’%. 0.5a + c% of 0.5a = 0.65a ⇒ 0.5c/100 = 0.15 ⇒ c = 30% Alternate Method: Given, two numbers are 35% and 50% lesser than a third number Let's assume the third number be 100 1st$ number = 65 2nd$ number = 50 Required PERCENATGE = ((65 - 50)/50) X 100 = 1500/50 = 30. |
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| 61. |
1). 5452). 5073). 5154). 525 |
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Answer» SMALLER number = (840 - x) Now, 30% of smaller no. = 18% of larger no. ⇒ 0.3 × (840 - x) = 0.18x ⇒ 252 - 0.3x = 0.18x ⇒ 0.48x = 252 ⇒ x = 252/0.48 = 525 ∴ Larger number is 525 |
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| 62. |
Tirupati sells a calculator to Ashok. Ashok offered him a sum of money for which he refused as being 13% below the value of the calculator. Ashok then offered him Rs 45 more and the second offer was 5% more than the estimated value. What is the value of the calculator?1). Rs 1852). Rs 2303). Rs 2504). Rs 450 |
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Answer» Let the value of the CALCULATOR be ‘x’, then according to the question, 105% of x – 87% of x = 45 $(\RIGHTARROW x \times \frac{{105}}{{100}} - x \times \frac{{87}}{{100}} = 45)$ ⇒ x × (18/100) = 45 ⇒ x = (45 × 100)/18 = RS 250. Hence, the REQUIRED value of the calculator is Rs 250. |
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| 63. |
The transportation cost of one kg of flowers is 15% of the cost/kg of flowers itself. The cost of flowers decreases by 30%, while the total cost of transportation owing to hike in diesel prices, goes up by 45%. What is the percentage change in the total cost, if the total cost is the sum of cost of flowers and transportation cost (approx).1). 10%2). 20%3). 25%4). 30% |
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Answer» Let cost of flowers be Rs 100/kg, TRANSPORTATION cost = Rs 15 (i.e. 15% of 100) ∴ TOTAL cost earlier = Rs (100 + 15) = Rs 115 Now, according to the QUESTION: New cost of flowers = 70% of 100 = Rs 70/kg New cost of transportation = 145% of 15 = Rs 21.75 ∴ Total new cost = Rs (70 + 21.75) = Rs 91.75 Percent change (DECREASE) in total cost $(= \frac{{115 - 91.75}}{{115}} \times 100\% = 20.2\%)$ HENCE, the required change in the total cost price is approx 20% |
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| 64. |
1). \(2_2^1\% \) increase2). \(2_2^1\% \) decrease3). 2% increase4). 2% decrease |
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Answer» Let the price of the article be Rs. 100 and the daily sale be 100 units, Revenue day = 100 × 100 = Rs. 10000 Case II New RECEIPTS = 75 × 130 = Rs. 9750 Decrease = Rs. (10000 - 9750) = Rs. 250 = % decrease $( = \FRAC{{250}}{{10000}} \TIMES 100 = 2\frac{1}{2}\% )$ |
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| 65. |
1). Decrease approximately by 20%2). Increase approximately by 2%3). Increase approximately by 20%4). Decrease approximately by 2% |
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Answer» LET the initial strength be x in 1997 ∴ the strength after 10% INCREASE in 1998 = x + 10x/100 = 11x/10 In 1999, there will be again decrease by 10% ∴ strength in 1999 = 11x/10 – 10% of 11x/10 = 99x/100 Then the strength increase by 10% in 2000 ∴ strength in 2000 = 99x/100 + 10% of 99x/100 = 1089x/1000 Finally, in 2001, the strength again DECREASES by 10% ∴ strength in 2001 = 1089x/1000 – (10(1089x/1000)/100) = 9801x/10000 Comparing the strength of 2001 with that in 1997, it is clear that the strength is decreased Decrease in strength = x – (9801x/10000) = 199x/10000 Percentage decrease = ((199x/10000)/x) × 100 = 1.99% decrease which is approximately equal to 2% decrease. |
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| 66. |
What is the value of 30% of 40% of 2400?1). 2882). 723). 1444). 108 |
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Answer» The VALUE of 30% of 40% of 2400 = (30/100) × (40/100) × 2400 = 0.3 × 0.4 × 2400 = 288 Hence, 288 will be the correct OPTION. |
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| 67. |
An engineering college claims an average test pass rate of 76.8%.What is the least number of students required to achieve this result?1). 2482). 1173). 624). 125 |
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Answer» These types of questions are to be solved by using the given options Let’s start by the smallest AVAILABLE number in the option that is 62 For 62 total students, number of students PASSED = 76.8/100 × 62 = 47.6 For 117 total students, number of students passed = 76.8/100 × 117 = 89.85 For 248 total students, number of students passed = 76.8/100 × 248 = 190.46 For 125 total students, number of students passed = 76.8/100 × 125 = 96 Since, number of students passed can’t be in decimals ∴ 125 is our REQUIRED answer. |
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| 68. |
In an election 20% of votes were not polled and out of two candidates Ram and Bhanu, Ram got 40% of the total votes polled while Bhanu got 60% of the total votes polled and Bhanu won by 1600 votes. How many votes did Bhanu get?1). 48002). 84003). 200004). 12000 |
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Answer» LET the total number of VOTES be v. Given, 20% of votes were not polled. ∴ Total number of votes polled = v – 20% of v = 0.8v Now, Ram received 40% of total votes polled Votes received by Ram = 40% of 0.8v = 0.32v BHANU received 60% of total votes polled. Votes received by Bhanu = 60% of 0.8v = 0.48v Given, Bhanu won by 1600 votes. ∴ 0.48v – 0.32v = 1600 ⇒ 0.16v = 1600 ⇒ v = 10000 Votes received by Bhanu = 0.48 × 10000 = 4800 |
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| 69. |
Cost price of an article is Rs. 5800. If the loss percentage is 33%, then what is the selling price (in Rs) of the article?1). 38862). 34243). 44204). 5168 |
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Answer» CP of the article = Rs. 5800 Loss PERCENTAGE = 33% ∴ SELLING PRICE of the article = 5800 × (100 - 33)/100 = 5800 × 67/100 = 58 × 67 = 3886 |
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| 70. |
Shelf A has 4/5 of the number of books that shelf B has. If 25% of the books in A are transferred to B and then 25% of the books from B are transferred to A, then the percentage of the total number of books that A will have is1). 252). 503). 754). 100 |
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Answer» LET the total number of books shelf A GOT be X. According to data- Shelf A has 4/5 of the number of books that shelf B has ⇒ number of books on shelf B = 5x/4 As 25% of books of shelf A are transferred to shelf B. New numbers of books on shelf B = number of books initially on shelf B + number of transferred books ⇒ New numbers of books on shelf B = (5x/4) + (25x/100) ⇒ New numbers of books shelf B got = 1.5x At the same TIME, Number of books on shelf A = x – (25x/100) = 0.75x Then 25% of books from shelf B are been transferred to shelf A ∴ New number of books on shelf A = number of books shelf A after first transfer + number of books transferred from shelf B to shelf A ∴ New number of books on shelf A = 0.75x + (25 % of 1.5x) = 1.125x New number of books on shelf B = Number of books on shelf B after first transfer – number of books transferred from shelf B to shelf A New number of books on shelf B = 1.5x – (25 % of 1.5x) = 1.125x ⇒ The PERCENTAGE of the total number of books on shelf A = $(\frac{{1.125x}}{{1.125x + 1.125x}} \times 100 = 50)$ |
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| 71. |
1). 162). 253). 104). 20 |
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| 72. |
1). 1,40,0002). 1,60,0003). 2,00,0004). 1,00,000 |
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Answer» Total votes = 2,60,000 Let X voters voted against the party in the Assembly Polls. Then, votes in favour = 260000 – x Therefore, majority of votes by which party won in previous poll = 260000 – x – x = (260000 – 2x) NEXT year, votes against the PNC party increase by 25% So, votes against the party in general election = 1.25x And votes polled in favour of the party = Total votes – Votes against = 260000 – 1.25x Therefore, majority of votes by which party lost in general election ⇒ 1.25x – (260000 – 1.25x) = 2.5x – 260000 It is GIVEN that, PNC Party lost by a majority twice as large as that by which it had won the Assembly Polls, ∴ 2.5x – 260000 = 2(260000 – 2x) ⇒ 2.5x – 260000 = 2 × 260000 – 4x ⇒ 6.5x = 3 × 260000 ⇒ x = 1,20,000 ∴ No. of votes polled by the voters for the party in Assembly Polls for previous year ⇒ (2,60,000 – x) ⇒ (2,60,000 – 1,20,000) ⇒ 1,40,000 |
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| 73. |
There are two candidates in an election, one of them got 55% of total valid votes and 20% votes were declared invalid. If total votes are 5500, then find the how many valid votes did other person get?1). 19002). 19803). 18004). 1890 |
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Answer» TOTAL VALID votes = 5500 × 80/100 One of them GOT 55% of total valid votes ⇒ Other got 45% valid votes ∴ Vote COUNT of other = 5500 × 80/100 × 45/100 = 198 |
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| 74. |
A basket contains 480 apples. 288 apples were distributed among some students. Find the percentage of apples left in the basket1). 40%2). 70%3). 60%4). 55% |
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Answer» A BASKET contains 480 APPLES. 288 apples were distributed among some students. So, the number of apples left in the basket = 480 – 288 = 192 ∴ The REQUIRED PERCENTAGE = [(192/480) × 100]% = 40%. |
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| 75. |
There are 1600 students in a school. 17% are Muslims, 9% Sikhs, 4% Christians and remaining are Hindus. How many Hindu students are there in the school?1). 15202). 10803). 11204). 480 |
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Answer» There are 1600 STUDENTS in the school 17% are Muslims, 9% SIKHS, 4% CHRISTIANS and REMAINING are Hindus Total Muslim, Sikh and Christians are = (17 + 9 + 4) % = 30 % So Hindus are = (100 - 30) % = 70% Total students are = 1600 So Hindus are = 1600 × 70% $(= 1600 \times \frac{{70}}{{100}})$ = 1120 Hence the answer is 1120 |
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| 76. |
There is a rebate of 15% on amount up to Rs. 300 and a discount of 20% on the remaining amount exceeding Rs. 300 if electric bills are paid in time. A man got a rebate of Rs. 64 by paying the bill in time. His electric bill was (Assuming the total bill was above Rs. 300)1). Rs. 3652). Rs. 3853). Rs. 3954). Rs. 375 |
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Answer» Now as there is a REBATE of 15% on amount up to Rs. 300 and a discount of 20% on the remaining amount EXCEEDING Rs. 300 and rebate is Rs. 64 ∴ 15/100 × 300 + 20/100 × (X – 300) = 64 ∴ 45 + 0.2X – 60 = 64 ∴ 0.2X – 15 = 64 ∴ 0.2X = 79 ∴ X = 395 Rs. |
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| 77. |
The average of three numbers is 58. The first number is 3/4 of the third number. If the third number is 24 more than the second number, then what will be the difference between the first number and the second number?1). 242). 63). 164). 18 |
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Answer» The average of three numbers = 58 So, the sum of three numbers = 58 × 3 = 174 Let third number be 4x So, the first number = 3x So, the SECOND number = 4x - 24 According to the question ⇒ 3x + 4x - 24 + 4x = 174 ⇒ 11X = 198 ⇒ x = 18 So, the first number = 3 × 18 = 54 The second number = 4 × 18 - 24 = 48 ∴ The difference between the first number and the second number = 54 - 48 = 6 |
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| 78. |
The price of a certain item is increased by 12%. If a consumer wants to keep his expenditure on the item the same as before, how much per cent must be reduce his consumption on that item?1). 15%2). \(13\frac{1}{{23}}\% \)3). \(16\frac{2}{{3}}\% \)4). \(10\frac{5}{{7}}\% \) |
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Answer» The PRICE of a certain item is increased by 12%. Let the original price of that item be Rs. 100 per kg. So, now the price of that item per kg = Rs. 100 × (112/100) = Rs. 112 Then, quantity of the item can be AVAILED with Rs. 100 = 100/112 = 25/28 kg So, quantity of item reduced by = 1 - (25/28) = 3/28 kg. ∴ The percentage of reduction in CONSUMPTION = [(3/28)/1] × 100 = $(10\frac{5}{{7}}\% )$. |
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| 79. |
1). 10%2). 20%3). 30%4). 35% |
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Answer» The total weight of the SOLUTION is = 216 + 360 + 144 = 720g ∴ % of SUGAR present in the solution = (weight of sugar/Weight of solution) × 100 = (216/720) × 100 ∴ 30% of sugar is present in the solution. |
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| 80. |
In an exam Santhosh attended 72 questions which is 75% of total questions. How many questions were asked in the exam? 1). 902). 963). 244). 100 |
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Answer» Let the total questions be X ⇒ 75% of x = 72 ⇒ (75/100)x = 72 ⇒ x = 7200/75 ⇒ x = 96 ∴ 96 questions were ASKED in the exam. |
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| 81. |
1). 3002). 9003). 30004). 9000 |
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Answer» Let the salary of the may be Rs. x. 20% of a man’s salary is paid as rent, 60% are his LIVING expenses and 10% are his savings. He spends REMAINING Rs. 30 on the education of his children. So, the percentage of salary SPENT on education = 100 – (20 + 60 + 10) = 10 Now we can write, x × (10/100) = 30 ⇒ x = 3000/10 ⇒ x = 300 ∴ the salary of the man = Rs. 300. |
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| 82. |
Mohan spends 1/3rd of his income on house rent, and 2/3rd of the remainder in other affairs. If he is left with Rs.1200 per month, what his monthly income?1). Rs. 54002). Rs. 44003). Rs. 50004). Rs. 3600 |
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Answer» Let his TOTAL income be I. Amount SPENT on house rent = I/3 Amount REMAINING = I - I/3 = 2I/3 Amount spent on other affairs = $(\frac{2}{3} \times \frac{{2I}}{3} = \frac{{4I}}{9})$ Remaining amount = 2I/9 Given, this amount is Rs.1200 ⇒ $(\frac{{2I}}{9} = 1200)$ ⇒ I = Rs. 5400 |
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| 83. |
The ratio of number of boys and girls in a school is 2 ∶ 3. If 30% of the boys and 40% of the girls are scholarship holders, then what is the percentage of those students who do not get scholarship?1). 42%2). 48%3). 56%4). 64% |
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Answer» Given, RATIO of number of boys and girls in a school is 2 : 3. Let the number of boys and girls be 2a and 3a RESPECTIVELY. Where a is any constant Given, 30% of the boys and 40% of the girls are SCHOLARSHIP holders. Total number of boys who are not getting scholarship = 70% of 2a = 1.4a Total number of girls who are not getting scholarship = 60% of 3a = 1.8a Total number of students not getting scholarship = 1.4a + 1.8a = 3.2a % of students not getting the scholarship $(= \frac{{3.2a}}{{5A}} \times 100\% \;)$ ∴ % of students not getting scholarship = 64% |
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| 84. |
Ram ate half a cheese on Monday he ate half of what was left on Tuesday and so on. He followed this pattern for one week. How much of the cheese would he have eaten during the week?1). 99.22%2). 95%3). 98.22%4). 100% |
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Answer» SUMMATION of a G.P.$(= \frac{{a\left( {1 - {r^n}} \right)}}{{1 - r}})$ Where a is starting term and r is multiplication factor. Given, Ram ate half a CHEESE on Monday he ate half of what was left on Tuesday and so on. Amount of cheese eaten by Ram $(= \frac{1}{2} + \frac{1}{2} \TIMES \frac{1}{2} + \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \ldots \ldots ..\; + {\frac{1}{2}^7})$ ⇒ Amount of cheese eaten by Ram $(= \frac{1}{2} \times \frac{{1 - \frac{1}{{{2^7}}}}}{{1 - \frac{1}{2}}})$ ⇒ Amount of cheese eaten by Ram $(= \frac{1}{2} \times \frac{{1 - \frac{1}{{128}}}}{{\frac{1}{2}}} = \frac{{127}}{{128}} = 0.9922)$ ∴ Amount of cheese eaten by Ram in% = 99.22% |
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| 85. |
If X is 60% more than Y, then Y is what percentage less than X?1). 30%2). 32.5%3). 37.5%4). 40% |
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Answer» ⇒ X = Y + 0.6Y ⇒ X = 1.6Y ⇒ Y = (1/1.6)X ⇒ Y = 0.625X ⇒ Y = 62.5% of X ⇒ Y = X - (100 - 62.5)% of X ⇒ Y = X - 37.5% of X ∴ Y is 37.5% LESS than X |
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| 86. |
Due to the inflation of 25% in the prices of apples Rohit decides to increase his spending by only 10%. Find the reduction made by him in the quantity he consumed.1). 8%2). 12%3). 10%4). 14% |
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Answer» Let the initial price of the apple per kg be x And the initial quantity Rohit purchased be y ⇒ His TOTAL EXPENDITURE will be x × y ⇒ Due to inflation new price = x + 25% of x ⇒ x + 0.25x ⇒ 1.25x ⇒ New expenditure = x × y + 10% of x × y ⇒ 1.1 x × y Let Q be the new quantity of apples ⇒ 1.25x × q = 1.1 x × y ⇒ q = 0.88y ⇒ Decrease in quantity = y – 0.88y ⇒ 0.12y ⇒ PERCENTAGE decrease in quantity = (0.12y/y) × 100 ⇒ 12% ∴ Decrease in quantity is 12% |
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| 87. |
Rahul’s salary is 40% more than Mohit’s salary. If Rahul’s salary is increased by 60% and Mohit’s salary is decreased by 20%, then Rahul’s salary will be how much percentage of Mohit’s salary?1). 2802). 1003). 1054). 64 |
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Answer» Let Mohit’s ORIGINAL salary be 100 Rahul’s original salary (being 40% more than Mohit’s salary) = 100 + (40% of 100) = 100 + 40 = 140 If Rahul’s salary is now INCREASED by 60%, then Rahul’s new salary = 140 + (60% of 140) = 140 + 84 = 224 If Mohit’s salary is decreased by 20%, then Mohit’s new salary = 100 - (20% of 140) = 100 - 20 = 80 To find Rahul’s salary is how much percentage of Mohit’s salary ⇒ 224 = ? % of 80 ⇒ ? = (224/80) × 100% = 2.8 × 100% = 280% ∴ Required Percentage = 280% |
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| 88. |
A bus agent gets a commission of Rs. 240 at the rate of 3%.The value of ticket sold is?1). Rs. 10,0002). Rs. 8,0003). Rs. 12,0004). Rs. 15,000 |
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Answer» Given, bus agent gets a commission of RS. 240 at the RATE of 3% ∴ 3% of TOTAL amount of ticket sold = 240 ⇒ 0.03 × Total amount of ticket sold = 240 ∴ Total amount of ticket sold = 240/0.03 = Rs. 8000 |
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| 89. |
A number is increased first by 20% and then it is decreased by 10%. What is the percentage change in the number?1). 8% decrease2). 10% decrease3). 10% increase4). 8% increase |
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Answer» LET the number be x After INCREASING by 20%, x’ = x + 0.2x = 1.2x After decreasing by 10%, x’’ = 1.2x - 0.1 × 1.2x = 1.08x Clearly it is a % increase. ⇒ % increase = [(1.08x - x)/x] × 100 = 8% increase |
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| 90. |
1). 15% increase2). 15% decrease3). 10% decrease4). 10% increase |
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Answer» I1 + I2 + (I1 × I2)/100 = -40 + 50 – (40 × 50)/100 = -40 + 50 – 20 = -10% ∴ 10% decrement in fan’s revenue |
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| 91. |
A man's annual income has increased by Rs 5 lakhs but the tax on income that he has to pay has reduced from 12% to 10%. He now pays Rs 10,000 more income tax. What is his increased income (in Rs lakhs)?1). 202). 253). 154). 10 |
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Answer» Let the INCOME before increment = Rs. X so increased income = Rs. (x + 500000) LAKHS According to given CONDITION; 0.1(x + 500000) – 0.12x = 10000 ⇒ 0.02x = 40000 ⇒ x = 2000000 = Rs. 20 lakhs ∴ Increased income = 20 + 5 = 25 lakhs |
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| 92. |
A student multiplied a number by 4/5 instead of 5/4. What is the percentage error in the calculation?1). 162). 253). 364). 20 |
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Answer» LET the number MULTIPLIED be x EXPECTED answer = 5/4 × x = 1.25x Answer obtained with wrong calculation = 4/5 × x = 0.8x Error = (Expected answer – Wrong answer) / (Expected answer) × 100 ⇒ (1.25x – 0.8x) / (1.25x) × 100 ∴ 0.45/1.25 × 100 = 36% |
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| 93. |
The price of sugar is reduced by 20%. Now a person can buy 500g more sugar for Rs. 36. The original price of the sugar per kilogram was?1). Rs. 14.402). Rs. 183). Rs. 15.604). Rs. 16.50 |
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Answer» LET the original price of the sugar for 1KG be ‘x’. Number of kgs = 36/x. After 20% decrease in price of sugar he can buy 500G more sugar for Rs. 36. $(\Rightarrow \left( {\frac{{36}}{x} + \frac{1}{2}\;} \RIGHT) \times \left( {x - \frac{{20}}{{100}}x} \right) = 36)$ ⇒ 36(0.8) + 0.5(0.8x) = 36 ⇒ 0.5(0.8x) = 36 – 36(0.8) = 7.2 ⇒ 0.4x = 7.2 ⇒ x = 18 ∴ The original price of sugar per kg = Rs. 18 |
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| 94. |
A student required 40% marks to pass an exam, he scored 35% and failed by 15 marks. Find the passing marks.1). 1002). 1303). 1334). 120 |
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Answer» A STUDENT required 40% marks to pass an exam, but he SCORED only 35%, and FAILED by 15 marks. ⇒ 5% less marks = 15(deficit marks) ⇒ 1% = 3 ∴ PASSING marks, 40% = 120 |
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| 95. |
A number is increased by 18%. To obtain the old number, by how much percentage should it be decreased?1). 16.882). 15.253). 17.34). 14.28 |
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Answer» Given, A number is INCREASED by 18% Let number be n. NEW number = = n + n × (18/100) = 59n/50 To obtain OLD number, Let PERCENTAGE number should be decreased to obtain new number be a. n = 59n/50 - (59n/50) × (a/100) n = (5900n - 59na)/5000 5000n = 5900n - 59na 59na = 900n a = 900n/59n a = 15.25 By 15.25% new number should be decreased to obtain new number. |
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| 96. |
Price of a house came down by 20% during recession. After one year, the price increased by 25%. What was the effective change percent in the price of house over the original price?1). 0%2). 5%3). -5%4). 10% |
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Answer» Let the price of a house be Rs. 100 Given, Price of a house CAME down by 20% during RECESSION, Price of a house during recession = 100 - 100 × (20/100) = 80 Price of a house during recession is Rs. 80 Given, Price increased by 25%. Price of a house after INCREMENT = 80 + 80 × (25/100) = 80 + 20 = 100 ∴ Price after increment is Rs. 100 which is equal to ORIGINAL price of a house. |
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| 97. |
Price of a house came down by 10% during recession. After one year, the price increased by 15%. What was the effective percentage change over the original price?1). 5%2). 8%3). 3.5%4). 4.5% |
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Answer» Let the original PRICE of the house be RS. X When price came down by 10% Price = (1 - 0.1) x = 0.9x When price is increased by 15% Price = (1 + 0.15) 0.9x = 1.15 × 0.9x = 1.035x Percentage CHANGE over original price = {(1.035x - x)/x} × 100 = 0.035 × 100 = 3.5% |
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| 98. |
In measuring a line segment of length 10 cm, it was measured as 12.5 cm by mistake. Find the error percent.1). 35%2). 30%3). 10%4). 25% |
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Answer» Error percentage = $(\frac{{MEASURED - ACTUAL}}{{Actual}} \times 100 = \frac{{12.5 - 10}}{{10}} \times 100 = 25\%)$ |
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| 99. |
The price of raw ingredients has increased by 10% and labour charge also increased from 15% of cost of raw ingredients to 20% cost of raw ingredients. To keep price same by how percentage there should be reduction in raw ingredients?1). 20.87%2). 16.66%3). 12.87%4). 13.45% |
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Answer» Let the initial price of RAW INGREDIENTS be 100. Given, price of raw ingredients has INCREASED by 10%, New price of raw ingredients = 100 + 100 × 10/100 = 110 Then, Initial labour charge = Rs. 15 Initial total cost = 100 + 15 = 115 New labour charge = 110 × 20/100 = 22 Total cost for same usage of raw ingredients = 110 + 22 = 132 Required reduction to KEEP cost same = [(132 - 115)/132] × 100 = 12.87% ∴ To keep cost same, there is 12.87% reduction in raw ingredients. |
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| 100. |
Rs. 10080 is distributed equally among boys in such a way that the amount received by each boy is 70% of the total number of boy. How much did each boy receive?1). Rs. 1202). Rs. 1083). Rs. 844). Rs. 90 |
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Answer» Let, Number of boys is x AMOUNT RECEIVED by each boy in Rs. = 0.70x Total amount DISTRIBUTED is = Rs. 10080 ∴ (0.70x) x = 10080 ⇒ 0.70 x2 = 10080 ⇒ x2 = 14400 ⇒ x = 120 Amount received by each boy in Rs. = 0.70 × 120 = 84 |
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