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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
What is 30% of 20% of 480?1). 292). 28.83). 304). 46 |
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Answer» Given, ⇒ 30% of 20% of 480 ⇒ Simplified FORM = (30/100) × (20/100) × 480 = 28.8 |
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| 102. |
The cost of an article depreciates at 5% per annum. If it’s present cost is Rs. 15000, what will be average price of value of article a year ago and value of article after a year?1). Rs. 16789.52). Rs. 153453). Rs. 15750.44). Rs. 15019.73 |
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Answer» <P>Given, Present COST of an article = Rs. 15000 Cost of an article after n years, Amount = P[1 + (R/100)]n Cost of an article n years ago, Amount = P/(1 - R/100)n Cost of article after a YEAR = 15000[1 + 5/100] = 15000[95/100] = 14250 Cost of an article before a year = 15000/[1 - 5/100] = 15000/(95/100) = 15789.47 Average PRICE of value of article a year ago and value of article after a year = (14250 + 15789.47)/2 = 15019.73 |
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| 103. |
1). \(\frac{1}{4}\)2). \(\frac{1}{3}\)3). \(\frac{1}{2}\)4). \(\frac{2}{3}\) |
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Answer» Required FRACTIONAL DECREASE is $(= \FRAC{R}{{100 + R}})$ {R = increase/decrease in 1st Quantity) $(= \frac{{50}}{{100 + 50}} = \frac{1}{3})$ |
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| 104. |
40% of the total students in a class are boys. 75% of boys failed in a test. Boys who passed is what percent of total students of the class?1). 40%2). 18%3). 20%4). 10% |
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Answer» Let, Total number of STUDENTS in the class is x 40% of total students are boys ∴ Number of boys in the class = 0.40x 75% of boys failed in the test ∴ 25% of boys PASSED in the test Number of boys passed = 0. 25 × (0.40x) = 0.10x ∴ Required percentage $(= \frac{{Number\;of\;boys\;passed}}{{Total\;number\;of\;students}} \TIMES 100\%)$ $(= \frac{{0.10x}}{x} \times 100\%)$ = 10% |
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| 105. |
The income of X is 60% more than Y’s income and the income of Y is 40% more than Z’s income. X’s income is how much percentage more than Z’s income?1). 1342). 2243). 1004). 124 |
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Answer» Y’s income = x + 40% of x = 1.4x X’s income = 1.4x + 60% of 1.4x = 2.24x ∴ Required % = {(2.24x – x)/x} × 100 = 124% |
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| 106. |
What is the value of 20% of 2/3 of 720?1). 962). 403). 1124). 114 |
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| 107. |
A no. increased by 20% and then decreased by 12% to give 704. What is the no.?1). 666.672). 5323). 733.334). 623 |
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Answer» We WORK out this QUESTION backwards. 88% of a no. is 704 ⇒ X × 88/100 = 704 ⇒ x = 800 Similarly 120% of a no. is 800 ⇒ x × 120/100 = 800 ∴ x = 666.67 |
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| 108. |
If the price of sugar is raised by 25%, find by how much per cent a householder must reduce his consumption of sugar so as not to increase his expenditure?1). 102). 203). 184). 25 |
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Answer» Let the initial consumption of sugar be Y units and the initial price of sugar PER KG be Rs. X. Thus, The initial expenditure of household = X × Y Given: the price of sugar increased by 25%. Thus, ⇒New price of sugar per kg $( = X + \frac{{25}}{{100}}X)$ = 1.25X Let the new consumption to keep the expenditure same be Y’ units. Hence, New expenditure = 1.25X × Y’ Since the EXPENDITURES are same, ∴ XY = 1.25XY’ ⇒ Y = 1.25Y’ Also, Reduction in consumption = Y – Y’ = 1.25Y’ – Y’ = 0.25Y’ ⇒ Reduction percentage $(= \frac{{Y - Y'}}{{Y}} \times 100)$ $( = \frac{{1.25Y' - Y'}}{{1.25Y'}} \times 100)$ = 20% |
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| 109. |
When a number is increased by 26, it becomes 113% of itself. What is the number?1). 2002). 3123). 3904). 234 |
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Answer» If the number is INCREASED by 26 then it becomes 113% of itself So new number = x + 26 1.13x = x + 26 0.13 = 26/x X = 26/0.13 X = 200 |
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| 110. |
P and Q are two natural numbers. 25% of P is 14 more than 10% of Q. Also, 10% of P is 20 less than 20% of Q. What is the product of P and Q?1). 180002). 192003). 188804). 17400 |
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Answer» <P>25% of P is 14 more than 10% of Q. ⇒ 0.25P = 14 + 0.1Q ⇒ 5P = 280 + 2Q 10% of P is 20 less than 20% of Q. ⇒ 0.1P = 0.2Q - 20 ⇒ P = 2Q - 200 ⇒ 5P = 10Q - 1000 Equating 5P from both equations, ⇒ 280 + 2Q = 10Q - 1000 ⇒ Q = 1280/8 = 160 ⇒ P = 2Q - 200 = 320 - 200 = 120 ∴ PQ = 120 × 160 = 19200 |
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| 111. |
If 31% of an electricity bill is deducted, Rs. 1794 is still to be paid. How much was the original bill amount?1). Rs. 13692). Rs. 26003). Rs. 26364). Rs. 1405 |
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| 112. |
32% of a number exceeds 17% of the same number by 120. What is the value of the number?1). 9002). 8603). 9404). 800 |
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Answer» Let the NUMBER be X, Then 32% of the number is = 0.32 × X 17% of the number will be given as = 0.17 × X The DIFFERENCE = 0.15 × X = 120 ∴ X = 120/0.15 = 800 |
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| 113. |
In a company, 20% employees are above 50 years and 60% employees are below 35 years of age. Difference between number of employee below 35 years and employee between 35 to 50 years is 640. Total number of employee in the company is1). 32002). 8003). 24004). 1600 |
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Answer» Let, Total number of EMPLOYEES is x 20% employees are above 50 years ∴ Number of EMPLOYEE above 50 years = 0.20x 60% employees are below 35 years ∴ Number of employee below 35 years = 0.60x ∴ Number of employees between 35 to 50 years = x - 0.20x - 0.60x = 0.20x Given, DIFFERENCE between number of employee below 35 years and employee between 35 to 50 years is 640 ∴ 0.60x - 0.20x = 640 ⇒ 0.40x = 640 ⇒ x = 1600 |
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| 114. |
If A is 40% less than B, then B is how much percentage more than A?1). 72.332). 603). 404). 66.66 |
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Answer» A = B – 40% of B = 100 – 40% of 100 = 100 – 40 = 60 ∴ Required % = {(100 – 60)/60} × 100 = (40/60) × 100 = 66.66% |
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| 115. |
TV and a fridge cost Rs. 40000 and Rs. 25000 of a certain company. If the price of TV and a fridge is increased by 10% and 8% respectively. Then new price of a fridge is what percent of new price of TV?1). 64.63%2). 62.5%3). 66.45%4). 61.36% |
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Answer» Cost of a TV = Rs. 40000 Cost of a fridge = Rs. 25000 Given, Cost of a TV set is INCREASED by 10%. NEW cost of a TV set = 40000 + 40000 × 10/100 = 44000 Cost of a fridge is increased by 8%. New cost of a fridge = 25000 + 25000 × 8/100 = 27000 Required percentage = (27000/44000) × 100 = 61.36% ∴ New price of fridge is 61.36% of new price of a TV set. |
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| 116. |
B is 50% of A and C is 16.67% of B and the sum of all three numbers is 38. Find the smallest number.1). 12). 43). 64). 2 |
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Answer» LET A = a so B = 50% of a = a/2 and C = 16.67% of a/2 = 1/6 × a/2 = a/12 A + B + C = a + a/2 + a/12 = 38 ⇒ 19a/12 = 38 ⇒ a = 24 ∴ SMALLEST number, C = a/12 = 24/12 = 2 |
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| 117. |
When the price of an article was reduced by 20% its sale increased by 80%. What was the net effect on the sale?1). 44% increase2). 44% decrease3). 66% increase4). 75% increase |
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| 118. |
1). 802). 753). 504). 25 |
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Answer» Let A’s income be x and that of B’s be y According to the question, A's income is 25% more than B's income x = y + 25% of y = y + 25y/100 Now, required PERCENTAGE = $(\frac{y}{{\frac{{5y}}{4}}} \TIMES 100\; = \;80\%)$ |
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| 119. |
If 60% of the students in a school are boys and number of girls is 912, how many boys are there in the school?1). 13682). 16383). 18214). 1281 |
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Answer» Let the NUMBER of TOTAL students be n. Number of GIRLS = 40% of total students ∴ (40/100) × x = 912 ⇒ x = 2280 Remaining 60% students are boys ∴ 2280 – 912 = 1368 Number of boys are 1368. |
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| 120. |
1). 25%2). 20%3). 80%4). 75% |
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Answer» % DECREASE in CONSUMPTION |
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| 121. |
In a regiment 45% soldiers are commanders. If the number of commanders is 6750, then what is the total number of soldiers in the regiment?1). 150002). 175003). 180004). 16000 |
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Answer» Given, Number of commanders = 6750 Let number of SOLDIERS be n. In a regiment 45% soldiers are commanders, 6750 = (45/100)n n = 15000 ∴ there are 15000 soldiers in the regiment. |
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| 122. |
Of the 75 boys who appeared for an examination in a school, only 80% managed to pass. If total number of students in the school who appeared for the exam were 145 and number of girls who passed were 2 less than that of boys, what percentage (approx.) of girls passed the exam ?1). 80.14%2). 81.75%3). 82.85%4). 85% |
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Answer» Number of boys APPEARING for the exam = 75 Number of boys passing the exam = (80/100) × 75 = 60 Total Number of STUDENTS in the school appearing for the exam = 145 Number of girls appearing for the exam = 145 – 75 = 70 Number of girls passing the exam = 60 – 2 = 58 Percentage of girls who PASSED the exam = (58/70) × 100 = 82.85% |
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| 123. |
An increase of 20% in the price of apples. 2 apples less are available for Rs. 100. The average price of present price of an apple and old price of an apple is -1). Rs. 55/62). Rs. 443). Rs. 724). Rs. 65 |
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Answer» Let the ORIGINAL price of an apple be Rs. A. There is INCREASE in price of an apple by 20%. New price of an apple = A + 20/100 × A = 6A/5 Then, There are 2 apple LESS available for Rs. 100. ⇒ (100/A) - (100/(6A/5)) = 2 ⇒ 600 - 500 = 12A ⇒ 12A = 100 ⇒ A = 100/12 Present price of an apple = 100/12 × 6/5 = 10 Average price of old price and present price of an apple = {(100/12)+10} / 2 = 55/6 ∴ Average price of old price and present price of an apple be Rs. 55/6. |
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| 124. |
A bank agrees to lend a loan of Rs.2,38,75,697 to Arvind which falls short by 17% for starting his business. How much more loan would he need?1). 48902032). 43753033). 57001084). 5125533 |
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Answer» Let the amount need by Arvind to start business = Rs. x The amount LOANED to him is 17% less than what he NEEDS to start his business. HENCE, x – (17% of x) = Rs. 23875679 0.83 x = Rs. 23875679 x = Rs. 28765900 (approx.) Amount Arvind needs after obtaining the BANK loan = 28765900 – 23875697 = Rs. 4890203 |
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| 125. |
A person gave 20% of his income to his elder son, 30% of the remaining to the younger son and 10% of the balance, he donated to a trust. He is left with Rs. 10080. What was his income?1). Rs. 500002). Rs. 400003). Rs. 300004). Rs. 20000 |
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Answer» LET his income be x. He gave 20% of his income to his elder son = 0.2x Remaining amount = 0.8x He gave 30% of the remaining to the younger son = 0.8x × 0.3 = 0.24x Remaining amount = 0.56x He DONATED 10% of balance to a trust = 0.056x Remaining amount = 0.504x He is LEFT with Rs. 10080 ⇒ 0.504x = 10080 ⇒ x = 20000 |
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| 126. |
1). 1202). 1803). 2404). 320 |
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Answer» Let x be the number of pages in the book. Number of pages READ on the FIRST day = x/4 Number of pages read on the SECOND day = 20% of x x/5 Number of pages read on the LAST THREE days = x - x/4 - x/5 = 11x/20 Given, number of pages read on third day = 66 (1/3) × (11x/20) = 66 ⇒ x = 360 Hence, book contain 360 pages. |
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| 127. |
In a exam Santosh attended 72 questions which is 75% of total questions. How many questions were asked in the exam?1). 902). 963). 244). 100 |
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Answer» ⇒ NUMBER of questions ATTEMPTED by SANTOSH = 72 ⇒ Given, ⇒ 75% = 72 ∴ 100% = (72/75) × 100 = 96 |
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| 128. |
1). 3002). 3503). 3604). 380 |
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Answer» LET the ELECTRIC BILL paid be Rs. X. According to question, 30X/100 = 108 ∴ X = 360 Hence, the electric bill is Rs. 360. |
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| 129. |
A number is multiplied by (7/11) instead of (2/3). New value is what percent of desired value?1). 95.452). 90.93). 86.294). 83.45 |
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Answer» Let the number be x. When this number is multiplied by 2/3, then we GET = 2x/3 And when this number is multiplied by 7/11, then we get = 7x/11 Required PERCENTAGE $(= \FRAC{{7x/11}}{{2x/3}} \times 100 = 95.45\%)$ |
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| 130. |
What is the value of 20% of 500% of 50?1). 0.52). 50003). 5004). 50 |
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Answer» It can be GIVEN as ⇒ (20/100) × (500/100) × 50 ⇒ 50 ∴ the VALUE of given EXPRESSION is 50 |
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| 131. |
All students can speak at least one of the two languages.Find the number of students who can speak only Tamil.1). 82). 103). 124). 14 |
| Answer» ⇒ Students who can speak only Tamil = 28 - 18 = 10 | |
| 132. |
If wages of X and Y are in the ratio of \(3\frac{1}{2}:3\frac{1}{4}\), how much percent X’s wages is greater than that of Y?1). \(10\frac{1}{{13}}\% \)2). \(8\frac{1}{{11}}\%\)3). \(7\frac{9}{{13}}\%\)4). \(6\frac{{12}}{{13}}\%\) |
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Answer» Wages of X and Y are in the ratio of Let the wages of X and Y be 7a/2 and 13A/4 respectively. X wage is greater than Y’s wage by a amount $(= \frac{{7a}}{2} - \frac{{13a}}{4} = \frac{a}{4})$ % by which X’s wage is greater than Y’s wage $(= \frac{{\frac{a}{4}}}{{\frac{{13a}}{4}}} \TIMES 100\%= \frac{{100}}{{13}}\%= 7\frac{9}{{13}}\% )$ |
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| 133. |
A box has 100 blue balls, 50 red balls, 50 black balls, 25% of blue balls and 50% of red balls are taken away. Percentage of black balls at present is 1). 50%2). 25%3). \(33\frac{1}{3}\%\)4). 40% |
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Answer» The box has 100 blue BALLS, 50 RED balls, 50 black balls. 25% of blue balls are taken away. Now, number of blue balls present in the box: = 100 – [25% of 100] = 100 – 25 = 75 50% of red balls are taken away. Now, number of red balls present in the box: = 50 – [50% of 50] = 50 – 25 = 25 Total number of balls present in the box now: = number of blue balls + number of black balls + number of red balls = 75 + 50 + 25 = 150 ∴ PERCENTAGE of black balls at present is: $(\frac{{{\rm{number\;of\;black\;balls\;present}}}}{{{\rm{Total\;number\;of\;balls\;present\;}}}} \TIMES 100)$ $(= \left[ {\frac{{50}}{{150}} \times 100} \right]\%)$ $(= \;\frac{{100}}{3}\%)$ $(= 33\frac{1}{3}\%)$ |
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| 134. |
The income of P is 50% more than Q’s income and the income of Q is 50% more than R’s income. P’s income is how much percentage more than R’s income?1). 2252). 1503). 1254). 100 |
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Answer» Income of the Q = 100 × 150/100 = 150 Income of the R = 150 × 150/100 = 225 So, Income of R is more than R’s income by = (225 - 100)/100 × 100 = 125% |
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| 135. |
A man’s working hours per day were increased by 20% and his wages per hour were increased by 15%. By how much percent were his daily earnings increased?1). 38%2). 35%3). 5%4). 40% |
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Answer» LET the NUMBER of working hours be x Let the wages PER hours be y Initial daily earnings = Number of working hours × Wages per hour = xy New number of working hours = x + (20/100) × x = 1.2x New wages per hour = y + (15/100) × y = 1.15y New daily earnings = Number of working hours × Wages per hour = (1.2x) × (1.15y) = 1.38xy %Change in daily earnings = (Change in daily earnings)/(Initial daily earnings) × 100 %Increase in daily earnings = (1.38xy -xy)/xy × 100 = 38% |
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| 136. |
A number is multiplied by 2/7 instead of 3/8. New value is what percent of expected value?1). 62.662). 76.193). 57.214). 68.76 |
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Answer» Let, the number = x After multiplying with 3/8, value = 3x/8 After wrongly multiplying it with 2/7, value= 2x/7 $( \Rightarrow \frac{{\frac{{2x}}{7}}}{{\frac{{3x}}{8}}} \times 100\% )$ ⇒ 16/21 × 100% ⇒ 76.19% |
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