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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 301. |
Ultrasonic, infrasonic and audio waves travel though a medium with speeds `V_(u), V_(i)` and `V_(a)` respectively then :-A. `V_(u),V_(i)" and "V_(a)` are equalB. `V_(u)gtV_(a)gtV_(i)`C. `V_(u)ltV_(a)ltV_(i)`D. `V_(a)ltV_(u)" and "V_(u)~~V_(i)` |
| Answer» Correct Answer - A | |
| 302. |
Due to global warming, ice on polar caps is likely to melt in large quantity. Due to this effect :A. Moment of inertia of earth shall decreaseB. Length of the day shall decreaseC. Angular velocity of earth shall decreaseD. Angular momentum of earth shall decrease |
| Answer» Correct Answer - C | |
| 303. |
If source and observer both are relatively at rest and if speed of sound is increased then frequency heard by observer willA. IncreasesB. DecreasesC. Can not be predictedD. Will not change |
| Answer» Correct Answer - D | |
| 304. |
A small source of sound moves on a circle as shown in figure and an observer is sitting at O. Let `v_1,v_2,v_3` be the frequencies heard when the source is at A,B and C respectively. .A. `n_(1)gtn_(2)gtn_(3)`B. `n_(2)gtn_(3)gtn_(1)`C. `n_(1)=n_(2)gtn_(3)`D. `n_(2)gtn_(1)gtn_(3)` |
| Answer» Correct Answer - B | |
| 305. |
A diatomic ideal gas is heated at constant at constant volume until the pressure is doubled and again heated of constant pressure until the volume is doubled. The average molar heat capacity for the whole process isA. `(13R)/(6)`B. `(19R)/(6)`C. `(23R)/(6)`D. `(17R)/(6)` |
| Answer» Correct Answer - B | |
| 306. |
A gas undergoes following process :- `Abto`Compressed to half of the initial volume `(PpropV)` `Bcto`Isothermal expansion to intial volume `CDto`Adiabatic process such that `P_(D)=P_(A)` Select incorrect statementA. Net heat is releasedB. `DeltaU_(AB)lt0`C. `DeltaU_(CD)gt0`D. `DeltaU_(AC)gt0` |
| Answer» Correct Answer - D | |
| 307. |
Consider two vectors `vecF_(1)=2hati+5hatk` and `vecF_(2)=3hatj+4hatk`. The magnitude to thhe scalar product of these vectors isA. 20B. 23C. `5sqrt(33)`D. 26 |
| Answer» Correct Answer - A | |
| 308. |
The torpue of force `vecF=-2hati+2hatj+3hatk` acting on a point `vecr=hati-2hatj+hatk` about origin will be :A. `8hati+5hatj+2hatk`B. `-8hati-5hatj-2hatk`C. `8hati-5hatj+2hatk`D. `-8hati+5hatj-2hatk` |
| Answer» Correct Answer - B | |
| 309. |
Two vectors `vecA=4hati+alphahatj+2hatk" and "vecB=2hati+hatj+hatk` are parallel if :-A. `alpha=0`B. `alpha=1`C. `alpha=2`D. `alpha=4` |
| Answer» Correct Answer - C | |
| 310. |
`(vecA+2vecB).(2vecA-3vecB)`:- |
| Answer» Correct Answer - D | |
| 311. |
If vector `hati+hatj-hatk" and "2hati+2hatj+lambdahatk` are parallel than find out the value of `lambda` :-A. -1B. 1C. -2D. 2 |
| Answer» Correct Answer - C | |
| 312. |
The angle between the vectors `(hati+hatj)` and `(hatj+hatk)` isA. `90^(@)`B. `180^(@)`C. `0^(@)`D. `60^(@)` |
| Answer» Correct Answer - D | |
| 313. |
If the vectors `(hati+ hatj + hatk)` and `3 hati` from two sides of a triangle, then area of triangle is :A. `sqrt(3)` unitB. `2sqrt(3)` unitC. `(3)/(sqrt(2))` unitD. `3sqrt(2)` unit |
| Answer» Correct Answer - C | |
| 314. |
The component of vector `A=a_(x)hati+a_(y)hatj+a_(z)hatk` and the directioin of `hati-hatj` isA. `a_(x)-a_(y)+a_(z)`B. `a_(x)-a_(y)`C. `(a_(X)-a_(y))/(sqrt(2))`D. `a_(x)+a_(y)+a_(z)` |
| Answer» Correct Answer - C | |
| 315. |
Two vertical glass plates 1 mm apart are dipped into water. How high will the water rise between the plates. If the surface tension of water is 70 dyne `cm^(-1)`A. 1.43 cmB. 1.63 cmC. 2.86 cmD. 3.86 cm |
| Answer» Correct Answer - A | |
| 316. |
A long cylindrical vessel has a small hole of diameter D at its bottom. This vessel can be lowered vertically in water to a depth h without any water entering the vessel. Given : A=surface tension, B=density of liquid, C=acceleration due to gravity. The value of h isA. `(A)/(DBC)`B. `(2A)/(DBC)`C. `(3A)/(DBC)`D. `(4A)/(DBC)` |
| Answer» Correct Answer - D | |
| 317. |
The change in the value of `g` at a height `h` above the surface of the earth is the same as at a depth d below the surface of earth. When both `d` and `h` are much smaller than the radius of earth, then which one of the following is correct?A. `d=(h)/(2)`B. `d=(3h)/(2)`C. `d=2h`D. `d=h` |
| Answer» Correct Answer - C | |
| 318. |
A body weigh `50 g` in air and `40 g` in water. How much would it weigh in a liquid of specific gravity `1.5`A. 30 gB. 35 gC. 65 gD. 45 g |
| Answer» Correct Answer - B | |
| 319. |
The height at which the acceleration due to gravity becomes `(g)/(9)` (where g =the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is :A. `(R)/(2)`B. `sqrt(2)R`C. 2RD. `(R)/(sqrt(2))` |
| Answer» Correct Answer - C | |
| 320. |
At a place where the acceleration due to gravity is `10"m sec"^(-2)` a force of 5 kg - wt acts on a body of mass 10 kg initially at rest. The velocity of the body after 4 second isA. 5 m/sB. 20 m/sC. 10 m/sD. 50 m/s |
| Answer» Correct Answer - B | |
| 321. |
If suddenly the gravitational force of attraction between earth and satellite revolving around it becomes zero, then the satellite willA. continue to move in its orbit with same velocityB. move tangentially to the original orbit with same velocityC. become stationary in its orbitD. move towards the earth |
| Answer» Correct Answer - B | |
| 322. |
A drunked person is 10 step away from a manhole. Suddenly he begins to walk towards the manhole. Suddenly he begins to walk towards the manhole. He walks two steps forward and one step beckward in one second. Find out (i) The time after which the person will fall into the manhole? |
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Answer» Correct Answer - (i) at `(1)/(3)sec("during"9^(th)"see), (ii) 26 steps |
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| 323. |
The values of `sintheta_(1), cos^(2)theta_(2)` and `tan theta_(3)` are given as `0.5, -0.5` and `3` (not in order), for some angles `theta_(1), theta_(2)` and `theta_(3)`. Choose incorrect statement. |
| Answer» Correct Answer - 4 | |
| 324. |
A uniform string resonates with a tuning fork, at a maximum tension of 32 N. If it is divided into two segments by placing a wedge at a distance one fourth of length from one end, then resonance frequency will occur at a maximum value of tension :-A. 2 NB. 4 NC. 8 ND. 16 N |
| Answer» Correct Answer - A | |
| 325. |
If T is the surface tension of a liquid, the energy needed to break a liquid drop of radius R into 64 drops is :-A. `6piR^(2)T`B. `piR^(2)T`C. `12piR^(2)T`D. `8piR^(2)T` |
| Answer» Correct Answer - C | |
| 326. |
Find the difference of air pressure (in `N-m^(-2)`) between the inside and outside of a soap bubble 5 mm in diameter, if the surface tension is `1.6 N-m^(-1)` :-A. 2560B. 3720C. 1208D. 10132 |
| Answer» Correct Answer - A | |
| 327. |
Work done in increasing the size of a soap bubble from a radius of `3 cm` to `5 cm` is nearly. (surface tension of soap solution `= 0.3 Nm^(-1))`A. `4pi` mJB. `0.2pi` mJC. `2pi` mJD. `0.4pi` mJ |
| Answer» Correct Answer - D | |
| 328. |
Find the value of following :- `{:((a)sin 150^(@)"", (b)sin 135^(@)), ((c)cos 120^(@)"", (d)tan 225^(@)), ((e)cos 240^(@)"", (f)sin 210^(@)), ((g)sin 315^(@)"", (h)sin 300^(@)):}` |
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Answer» Correct Answer - (a) `(1)/(2)` (b) `(1)/(sqrt(2))` (c )`-(1)/(2)` (d) 1 (e ) `-(1)/(2)` (f) `-(2)/(sqrt(3))` `(g) -(1)/(sqrt(2))` (h) `-(sqrt(3))/(2)` |
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| 329. |
Convert the following angle from radian to degree `{:((a)(pi)/(4)"red",(b)(pi)/(6)"rad"),((c)(pi)/(3)"rad",(d)(3pi)/(4)"rad"),((e)(7pi)/(6)"rad",(f)(5pi)/(4)"rad"),((g)(5pi)/(2)"rad",(h)(7pi)/(4)"rad"),((i)(5pi)/(6),):}` |
| Answer» Correct Answer - `{:((a)45^(@),(b)30^(@),(c)60^(@)),((d)135^(@),(e)210^(@),(f)225^(@)),((g)450^(@),(h)315^(@),(i)300^(@)):}` | |
| 330. |
Convert the angle from degree to radian : `{:((a)" "30^(@),(b)" "45^(@)),((c)" "60^(@),(d)" "90^(@)),((e)" "120^(@),(f)" "135^(@)),((g)" "210^(@),(h)" "270^(@)),((i)" "315^(@),):}` |
| Answer» Correct Answer - `{:((a)(pi)/(6),(b)(pi)/(4),(c)(pi)/(3)),((d)(pi)/(2),(e)(2pi)/(3),(f)(3pi)/(4)),((g)(7pi)/(6),(h)(3pi)/(2),(i)(7pi)/(4)):}` | |
| 331. |
If body having initial velocity zero is moving with uniform acceleration `8m//sec^(2)` the distance travelled by it in fifth second will beA. 1.25 mB. 2.25 mC. 6.25 mD. 30.25 m |
| Answer» Correct Answer - B | |
| 332. |
A body rotating with uniform angular acceleration covers `100 pi` (radian) in the first 5 s after the start. Its angular speed at the end of 5 s (in rad/s) isA. 40 `pi`B. 30 `pi`C. 20 `pi`D. 10 `pi` |
| Answer» Correct Answer - A | |
| 333. |
A body is projected vertically upward with speed 40m/s. The distance travelled by body in the last second of upward journey is [take `g=9.8m/s^(2)` and neglect eggect of air rresistance]:-A. 4.9 mB. 9.8 mC. 12.4 mD. 19.6 m |
| Answer» Correct Answer - A | |
| 334. |
A body is thrown vertically upwards and takes 5 seconds to reach maximum height. The distance travelled by the body will be same in :-A. `1^(st)" and "10^(th)" second "`B. `2^(nd)" and "8^(th)` secondC. `4^(st)" and "6^(th)` secondD. Both (2) & (3) |
| Answer» Correct Answer - A | |
| 335. |
A man travels half time of its journey with speed of 5m/s and for remaining half time he moves half of its total distance travelled, with speed of 3 m/s and remaining half distance with speed of 6 m/s. Find out the average speed of the man? |
| Answer» Correct Answer - 4.5 m/s | |
| 336. |
A body moving with uniform acceleration covers a distance of 14 m in first 2 second and 88 m in next 4 second. How much distance is travelled by it in `5^(th)` second? |
| Answer» Correct Answer - 5m | |
| 337. |
A man drives his car uniformly at 30 km/h for three hour After it he covered next 90 km distance with uniform speed of 45 km/hr. Find the average speed of car. |
| Answer» Correct Answer - 36 km/h | |
| 338. |
Which of the following relation cannot be deduced using dimensional analysis ? [the symbols have their usual meanings]A. `y=Asin(omegat+kx)`B. v=u+atC. `k=(1)/(2)mv^(2)`D. All of these |
| Answer» Correct Answer - D | |
| 339. |
The wave function of a pulse is given by `y=(5)/((4x+6t)^(2))` where x and y are in metre and t is in second :- (i) Identify the direction of propagation (ii) Determine the wave velocity of the pulse |
| Answer» Correct Answer - (i) `-xaxis` (ii) `-1.5` m/s | |
| 340. |
The potential energy of a particle varies with distance `x` from a fixed origin as `U = (A sqrt(x))/( x^(2) + B)`, where `A and B` are dimensional constants , then find the dimensional formula for `AB`.A. `[ML^(7//2)T^(-2)]`B. `[ML^(11//2)T^(-2)]`C. `[M^(2)L^(9//2)T^(-2)]`D. `[ML^(13//2)T^(-3)]` |
| Answer» Correct Answer - B | |
| 341. |
The intial velocity of a particle is u (at t=0) and the acceleration is given by f=at. Which of the following relations is valid ?A. `v=u+at^(2)`B. `v=u+(at^(2))/(2)`C. `v=u+"at"`D. v=u |
| Answer» Correct Answer - B | |
| 342. |
If `v=(t+2)(t+3)` then acceleration`(i.e(dv)/(dt))` at t=1 sec.A. `5 m//s^(2)`B. `7 m//s^(2)`C. `2 m//s^(2)`D. None of these |
| Answer» Correct Answer - B | |
| 343. |
Area bounded by curve `y=sinx`, whit x-axis, when x varies from 0 to `(pi)/(2)` is :-A. 1 unitB. 2 unitsC. 3 unitD. 0 |
| Answer» Correct Answer - A | |
| 344. |
If `y=sinx+cosx" then "(d^(2)y)/(dx^(2))` is :-A. `sinx-cosx`B. `cosx-sinx`C. `-(sinx+cosx)`D. None of these |
| Answer» Correct Answer - C | |
| 345. |
The slope of the tangent to the curve `y=ln(cosx)" at "x=(3pi)/(4)" is "`A. 1B. -1C. `l nsqrt(2)`D. `(1)/(sqrt(2))` |
| Answer» Correct Answer - A | |
| 346. |
If `x=sqrt(2+sqrt(2+sqrt(2+........oo)))` and `y=sqrt(2sqrt(2sqrt(2........oo)))` find `x-y`A. `2x = y`B. `3x lt y`C. `4x = 5y`D. `x = y` |
| Answer» Correct Answer - A | |
| 347. |
If radius of a spherical bubble starts to increase with time t as `r=0.5t`. What is the rate of change of volume of the bubble with time `t=4s`?A. `8pi` units/sB. `4pi` units/sC. `2pi` units/sD. `pi` units/s |
| Answer» Correct Answer - A | |
| 348. |
Starting from rest, the acceleration of a particle is `a=2(t-1)`. The velocity (i.e.`v=int" a dt "`) of the particle at t=10 s is :-A. 15 m/sB. 25 m/sC. 5 m/sD. 80 m/s |
| Answer» Correct Answer - D | |
| 349. |
The work done in increasing the size film with dimensions `8cm xx3.75cm` to `10cmxx6cm` is `2xx10^(-4)J`. The surface tension of the film in `(N)/(m)` isA. `1.65xx10^(-2)`B. `3.3xx10^(-2)`C. `6.6xx10^(-2)`D. `8.25xx10^(-2)` |
| Answer» Correct Answer - B | |
| 350. |
Given a function `y=x^(2)-2sqrt(x)`. What is rate of change in y with respect to x when x=I?A. ZeroB. 1C. 1.5D. -1.5 |
| Answer» Correct Answer - B | |