63 + Interview Questions in Resonance In Ac Circuits in Basic Electrical Engineering Page 1 InterviewSolution

1.	The current in the inductor ___________ the voltage in a series RLC circuit above the resonant frequency.(a) Leads(b) Lags(c) Equal to(d) Depends on the circuitThis question was addressed to me during an online interview.Question is taken from Voltages in a Series RLC Circuit in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» CORRECT OPTION is (b) Lags To elaborate: ω > ω0 => ω > 1/√LC => ωL > 1/ωC=>XL > XC The circuit is inductive dominant so, the CURRENT in the inductor lags the VOLTAGE in a series RLC circuit above the resonant frequency.

Discussion

2.	In a series RLC circuit, the phase difference between the voltage across the capacitor and the current in the circuit is?(a) 0^0(b) 90^0(c) 180^0(d) 360^0This question was addressed to me in an online interview.The query is from Voltages in a Series RLC Circuit in section Resonance in AC Circuits of Basic Electrical Engineering
Answer» Right OPTION is (b) 90^0 To elaborate: In a series RLC CIRCUIT, voltage across capacitor LAG the current by 90^0 so, the phase difference between the voltage across the capacitor and current is 90^0.

Discussion

3.	The current lags the supply voltage in a series RLC circuit has its frequency _________ the resonant frequency.(a) Above(b) Below(c) Equal to(d) Cannot be determinedThe question was asked in homework.My question is based upon Frequency Variation in a Series RLC Circuit in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct CHOICE is (a) Above For explanation I WOULD say: Current is lagging the voltage indicates INDUCTOR dominating circuit.XC < XL => 1/(ωC) < ωL=> ω > 1/√LC So, frequency more than RESONANT frequency.

Discussion

4.	What is the power factor of a series RLC circuit under resonance condition?(a) 0(b) 1(c) Infinity(d) 100The question was asked in an internship interview.My question is based upon Frequency Variation in a Series RLC Circuit in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» Right choice is (b) 1 For EXPLANATION: The power factor for a SERIES RLC circuit in resonance condition is always UNITY because the current is in PHASE with the voltage under resonance condition. Φ=0^0 => cos ϕ = 1i.e.power factor = 1.

Discussion

5.	In a series RLC circuit, the phase difference between the voltage across the capacitor and the voltage across the inductor is?(a) 0^0(b) 90^0(c) 180^0(d) 360^0I have been asked this question during a job interview.This interesting question is from Voltages in a Series RLC Circuit topic in section Resonance in AC Circuits of Basic Electrical Engineering
Answer» Right OPTION is (c) 180^0 Easy explanation: In a series RLC CIRCUIT, voltage across inductor lead the CURRENT by 90^0 and voltage across capacitor lag the current by 900 so, the PHASE difference between the voltage across the inductor and the voltage across the capacitor is 180^0.

Discussion

6.	Q is the ratio of?(a) Active power to reactive power(b) Reactive power to active power(c) Reactive power to average power(d) Reactive power to capacitive powerI have been asked this question during a job interview.The above asked question is from Oscillation of Energy at Resonance topic in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct choice is (c) REACTIVE power to AVERAGE power The BEST explanation: Q is the ratio of the reactive power to the average power. The reactive power is due to the inductance or capacitance and the average power is due to the RESISTANCE.

Discussion

7.	The maximum electrostatic energy stored in a capacitor at any instance is?(a) CVm^2(b) 1/2*CVm^2(c) CVm(d) CVm/2The question was asked in a national level competition.I'd like to ask this question from Oscillation of Energy at Resonance in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» RIGHT answer is (B) 1/2CVm^2 To explain I would say: The maximum electrostatic energy STORED in a capacitor at any instance is 1/2CVm^2, where C is the capacitance value and VM is the peak voltage.

Discussion

8.	The energy stored in the capacitor is of _________ nature.(a) Electrostatic(b) Magnetic(c) Neither electrostatic nor magnetic(d) Either electrostatic or magneticThe question was asked in an interview for internship.Asked question is from Oscillation of Energy at Resonance topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» The CORRECT OPTION is (a) Electrostatic To explain: Since capacitor STORES charge in between the plates and ENERGY ASSOCIATED with static charge is of electrostatic nature, so we can say energy stored in the capacitor is of electrostatic nature.

Discussion

9.	At resonance, the circuit appears __________(a) Inductive(b) Capacitive(c) Either inductive or capacitive(d) ResistiveI have been asked this question in a national level competition.My doubt stems from Oscillation of Energy at Resonance topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» The CORRECT choice is (d) RESISTIVE For explanation: At resonance, the CIRCUIT appears resistive because the capacitive and INDUCTIVE energies are EQUAL to each other.

Discussion

10.	What is the voltage across the inductor when the source voltage is 200V and the Q factor is 10?(a) 100V(b) 20V(c) 2000V(d) 0VThe question was asked in final exam.This is a very interesting question from Quality Factor topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» Right OPTION is (c) 2000V The explanation is: We know that voltage across the capacitor in RESONANCE condition is equal to Q times the source voltage. Q=VL/VSwhere VL is inductive voltage and VS is source voltage.10=VL/200=>VL = 2000 V.

Discussion

11.	_________ the resonant frequency, the current in the capacitor leads the voltage in a series RLC circuit.(a) Above(b) Below(c) Equal to(d) Depends on the circuitI had been asked this question in quiz.My enquiry is from The Current in a Series RLC Circuit topic in section Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct option is (b) Below For explanation I would say: The current in the capacitor leads the VOLTAGE in a series RLC circuit if circuit is capacitive DOMINANT i.e.i.e. if XL < XC ωL < 1/ωC=> ω < 1/√LC=> ω < ω0. So, the current in the capacitor leads the voltage in a series RLC circuit below the resonant frequency.

Discussion

12.	At resonance, the capacitive energy is ___________ inductive energy.(a) Greater than(b) Less than(c) Equal to(d) Depends on the circuitI had been asked this question by my college professor while I was bunking the class.Enquiry is from Oscillation of Energy at Resonance topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct option is (c) EQUAL to Easiest EXPLANATION: At RESONANCE, energy stored in the capacitor is equal to energy stored in the inductor because capacitive reactance and inductive reactance are equal at resonance.So, at resonance, capacitive energy is equal to inductive energy.

Discussion

13.	Find the Q factor when the voltage across the inductor is 2000V and the source voltage is 100V.(a) 10(b) 20(c) 30(d) 40I have been asked this question during an internship interview.The doubt is from Quality Factor in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» The CORRECT answer is (b) 20 To EXPLAIN I would say: We KNOW that voltage across the CAPACITOR in resonance CONDITION is equal to Q times the source voltage. Q=VL/VSwhere VL is inductive voltage and VS is source voltage. Q=2000/100=20.

Discussion

14.	In a series RLC circuit, the phase difference between the current in the circuit and the voltage across the resistor is?(a) 0^0(b) 90^0(c) 180^0(d) 360^0This question was posed to me during an online interview.My enquiry is from The Current in a Series RLC Circuit topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct ANSWER is (a) 0^0 The EXPLANATION: In a SERIES RLC circuit, the phase difference between the voltage ACROSS the resistor and the current in the circuit is 0^0 because they are in phase.

Discussion

15.	In a series RLC circuit, the phase difference between the voltage across the resistor and the current in the circuit is?(a) 0^0(b) 90^0(c) 180^0(d) 360^0I had been asked this question in class test.My question is from Voltages in a Series RLC Circuit topic in section Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct CHOICE is (a) 0^0 The explanation is: In a SERIES RLC CIRCUIT, the phase difference between the voltage across the resistor and the current in the circuit is 0 degrees because they are in phase.

Discussion

16.	In selective circuits, higher the Q factor _________ the peak.(a) Sharper(b) Blunter(c) Neither sharper nor blunter(d) Either sharper or blunterI got this question by my college director while I was bunking the class.My doubt is from Selectivity topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» CORRECT answer is (a) SHARPER To ELABORATE: Q=RESONANCE frequency / Bandwidth. Higher the quality factor, sharper the peak of resonance CURVE.

Discussion

17.	Find the Q factor when the voltage across the capacitor is 1000V and the source voltage is 100V.(a) 10(b) 20(c) 30(d) 40I got this question in unit test.I want to ask this question from Quality Factor topic in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct option is (a) 10 The explanation is: We know that VOLTAGE ACROSS the CAPACITOR in resonance condition is equal to Q times the source voltage. Q=VC/VSwhere VC is capacitive voltage and VS is source voltage.Q=1000/100 = 10 V.

Discussion

18.	What is the voltage across the capacitor when the source voltage is 100V and the Q factor is 10?(a) 100V(b) 10V(c) 1000V(d) 0VI had been asked this question in an interview for job.My doubt is from Quality Factor topic in section Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct option is (c) 1000V Easy explanation: We know that voltage ACROSS the capacitor in resonance CONDITION is EQUAL to Q TIMES the source voltage. Q=VC/VSwhere VC is CAPACITIVE voltage and VS is source voltage. 10=VC/100 VC=1000 V.

Discussion

19.	What is the SI unit for quality factor?(a) Hz(b) kHz(c) MHz(d) No unitThis question was posed to me in semester exam.I want to ask this question from Frequency Variation in a Series RLC Circuit topic in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct option is (d) No unit To EXPLAIN I would say: We know that QUALITY factor is equal to the resonant frequency DIVIDED by the bandwidth. It is one frequency divided by another hence it has no unit.

Discussion

20.	The current in the capacitor leads the voltage in a series RLC circuit ___________ resonant frequency.(a) Above(b) Below(c) Equal to(d) Depends on the circuitThe question was asked in quiz.The question is from Voltages in a Series RLC Circuit topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct choice is (B) Below The explanation: The current in the capacitor leads the voltage in a series RLC CIRCUIT if circuit is capacitive dominant i.e. if XL < XC ωL < 1/ωC=> ω < 1/√LC=> ω < ω0.So, the current in the capacitor leads the voltage in a series RLC circuit below the resonant FREQUENCY.

Discussion

21.	Q is a measure of _________(a) Resonance(b) Bandwidth(c) Selectivity(d) Either resonance or bandwidthI had been asked this question during an internship interview.The query is from Selectivity in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct CHOICE is (c) Selectivity The best explanation: For a circuit to be selective, it should have a high QUALITY FACTOR. It should have a SHARP peak with narrow BANDWIDTH.

Discussion

22.	At resonance, bandwidth includes the frequency range that allows _____ percent of the maximum voltage to flow.(a) 33.33(b) 66.67(c) 50(d) 70.7The question was posed to me in homework.I'm obligated to ask this question of Bandwidth topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» The CORRECT choice is (d) 70.7 To explain: At resonance, bandwidth includes the FREQUENCY range that allows 70.2 PERCENT of the maximum voltage to flow. This is because in the bandwidth frequency range, the VALUE of the voltage is equal to the maximum value of voltage DIVIDED by √2.

Discussion

23.	Find the value of current in the bandwidth range when the maximum value of current is 50A.(a) 56.65A(b) 35.36A(c) 45.34A(d) 78.76AThe question was asked in unit test.This interesting question is from Bandwidth topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct ANSWER is (B) 35.36A For explanation I would SAY: At the bandwidth frequency range, the value of the current is equal to the MAXIMUM value of current divided by √2. HENCE I =50/√2= 35.36A.

Discussion

24.	Find the reactive power when the average power is 5W and Q=2.(a) 10W(b) 5W(c) 2W(d) 1WI have been asked this question in an international level competition.The above asked question is from Oscillation of Energy at Resonance topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» The CORRECT answer is (a) 10W For EXPLANATION I would say: Q is the ratio of the REACTIVE power to the average power. Q = Reactive power / Average power 2 = Reactive power / 5 Reactive Power = 2*5 = 10W.

Discussion

25.	The SI unit for bandwidth is?(a) Hz(b) Watt(c) kHz(d) kWThe question was asked during an interview for a job.This intriguing question comes from Bandwidth in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct answer is (a) Hz Best explanation: The SI unit for BANDWIDTH is Hz. HERTZ is the SI unit because bandwidth is BASICALLY frequency and the unit for frequency is Hz.

Discussion

26.	Find the source voltage when the voltage across the inductor is 2000V and the Q factor is 20.(a) 10V(b) 200V(c) 100V(d) 90VI have been asked this question in my homework.The query is from Quality Factor topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct answer is (c) 100V The best I can explain: We know that voltage across the capacitor in resonance CONDITION is EQUAL to Q TIMES the source voltage. Q=VL/VSwhere VL is INDUCTIVE voltage and VS is source voltage. 20=2000/VS VS=100 V.

Discussion

27.	In a series RLC circuit, the phase difference between the current in the capacitor and the current in the resistor is?(a) 0^0(b) 90^0(c) 180^0(d) 360^0This question was addressed to me during an interview for a job.This intriguing question originated from The Current in a Series RLC Circuit in section Resonance in AC Circuits of Basic Electrical Engineering
Answer» Right option is (a) 0^0 Best EXPLANATION: In a series RLC circuit, the phase difference between the current in the CAPACITOR and the current in the RESISTOR is 0^0 because same current FLOWS in the capacitor as well as the resistor.

Discussion

28.	In order for high selectivity, the resistance must be?(a) Small(b) Large(c) Negative(d) PositiveI have been asked this question in an internship interview.This is a very interesting question from Selectivity topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct CHOICE is (a) Small To explain: For high SELECTIVITY, the Q FACTOR should be large and for Q factor to be large, the resistance WOULD be small because Q is inversely proportional to the resistance.

Discussion

29.	Shape of the resonance curve depends upon the?(a) Q-factor(b) Voltage(c) Current(d) Either voltage or currentThis question was addressed to me in an international level competition.This intriguing question originated from Selectivity in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» CORRECT choice is (a) Q-factor The EXPLANATION: The shape of the resonance curve depends on the Q factor because of the equation: Q=Resonance FREQUENCY / Bandwidth.Sharp resonance MEANS high quality factor.

Discussion

30.	Find the value of voltage in the bandwidth range when the maximum value of voltage is 100 V.(a) 56.65 V(b) 35.36 V(c) 45.34 V(d) 70.72 VI had been asked this question during an internship interview.My question comes from Bandwidth in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct choice is (d) 70.72 V To ELABORATE: At the bandwidth FREQUENCY range, the value of the voltage is equal to the maximum value of voltage divided by √2. Hence V =100/√2= 70.72V.

Discussion

31.	At bandwidth frequency range, the value of the current I is?(a) I=Im/2(b) I=Im^2(c) I=Im(d) I=Im/√2The question was asked in class test.This interesting question is from Bandwidth topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct choice is (d) I=Im/√2 Explanation: At the BANDWIDTH FREQUENCY range, the value of the current is EQUAL to the MAXIMUM value of current divided by √2.

Discussion

32.	What happens to the voltage across the capacitor when the Q factor increases?(a) Increases(b) Decreases(c) Remains the same(d) Becomes zeroThe question was asked in an interview for internship.This interesting question is from Quality Factor topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» Right choice is (a) Increases Explanation: We know that voltage across the CAPACITOR in resonance CONDITION is equal to Q TIMES the source voltage. Hence as the Q FACTOR increases, the voltage across the capacitor also increases.

Discussion

33.	If the resonant frequency in a series RLC circuit is 50kHz along with a bandwidth of 1kHz, find the quality factor.(a) 5(b) 50(c) 100(d) 500The question was posed to me by my school teacher while I was bunking the class.The query is from Frequency Variation in a Series RLC Circuit in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct ANSWER is (b) 50 Explanation: We KNOW that QUALITY factor is equal to the resonant FREQUENCY divided by the bandwidth. Q=fres/Bandwidth = 50/1 = 50.

Discussion

34.	_________ the resonant frequency, the current in the inductor lags the voltage in a series RLC circuit.(a) Above(b) Below(c) Equal to(d) Depends on the circuitThe question was asked in my homework.My question is based upon The Current in a Series RLC Circuit in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» RIGHT option is (a) Above For explanation: The current in the inductor lags the voltage in a series RLC CIRCUIT if a circuit is inductive dominant i.e. if XL > XC ωL > 1/ωC=> ω > 1/√LC=> ω > ω0. So, the current in the inductor lags the voltage in a series RLC circuit above the resonant FREQUENCY.

Discussion

35.	What is the Q factor of a selective circuit?(a) Very low(b) Very high(c) Zero(d) InfinityI had been asked this question in examination.This key question is from Selectivity topic in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» Right answer is (B) Very HIGH Explanation: For a circuit to be selective, it should have high quality FACTOR. It should have a sharp PEAK with narrow bandwidth.

Discussion

36.	At resonance, bandwidth includes the frequency range that allows _____ percent of the maximum current to flow.(a) 33.33(b) 66.67(c) 50(d) 70.7The question was asked in semester exam.Question is taken from Bandwidth in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» RIGHT choice is (d) 70.7 Best explanation: At resonance, bandwidth includes the frequency range that allows 70.2 PERCENT of the maximum current to FLOW. This is because in the bandwidth frequency range, the value of the current is equal to the maximum value of current DIVIDED by √2.

Discussion

37.	The energy stored in the inductor is of _________ nature.(a) Electrostatic(b) Magnetic(c) Neither electrostatic nor magnetic(d) Either electrostatic or magneticThe question was asked during an interview.My doubt is from Oscillation of Energy at Resonance topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» Right choice is (b) Magnetic Easy explanation: Since inductor stores CURRENT which involves MOVING CHARGE and energy associated with moving charge is of magnetic NATURE so we can say energy STORED in the inductor is of magnetic nature.

Discussion

38.	Resonance frequency occurs when __________________(a) XL=XC(b) XL>XC(c) XL
Answer» Right option is (a) XL=XC Explanation: The frequency of a SYSTEM is SAID to be RESONATING when the VALUE of the capacitive reactance and the INDUCTIVE reactance is the same.

Discussion

39.	In a series RLC circuit, the phase difference between the current in the capacitor and the current in the inductor is?(a) 0^0(b) 90^0(c) 180^0(d) 360^0I got this question in an interview for internship.My doubt is from The Current in a Series RLC Circuit in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct answer is (a) 0^0 Easiest EXPLANATION: In a SERIES RLC circuit, the phase DIFFERENCE between the current in the INDUCTOR and the current in the capacitor is 0^0 because same current flows in the inductor as well as the capacitor.

Discussion

40.	In selective circuits, the resonant frequency lies in the ________ of the bandwidth frequency range.(a) Beginning(b) End(c) Midpoint(d) Cannot be determinedThis question was posed to me in my homework.Query is from Selectivity in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» RIGHT CHOICE is (c) Midpoint To explain I would say: In selective CIRCUITS, the RESONANT frequency lies in the midpoint of the bandwidth frequency RANGE.

Discussion

41.	A circuit is said to be selective if it has a _____ peak and ____ bandwidth.(a) Blunt, narrow(b) Sharp, narrow(c) Sharp, broad(d) Blunt, broadThe question was asked in an online interview.This interesting question is from Selectivity topic in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct choice is (b) SHARP, narrow For explanation: For a circuit to be selective, it should have high QUALITY factor. And we KNOW that for high quality factor, resonance frequency should be high(PEAK should be sharp) and BANDWIDTH should be narrow.

Discussion

42.	Bandwidth is the difference of_____________________ frequencies.(a) half power(b) full power(c) double power(d) wattlessThe question was asked in final exam.I'm obligated to ask this question of Bandwidth topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct answer is (a) half power The explanation: Current for the END frequencies of BANDWIDTH is 1/√2 times the MAXIMUM current. So, power at the end frequencies of bandwidth is half the maximum power. So, bandwidth is the difference of half power frequencies.

Discussion

43.	Find the value of Q if the reactive power is 10W and the average power is 5W.(a) 10(b) 5(c) 2(d) 1I have been asked this question in class test.My question is from Oscillation of Energy at Resonance topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» The CORRECT answer is (c) 2 To explain I would say: Q is the ratio of the reactive POWER to the AVERAGE power. Q = Reactive power / Average power = 10/5 = 2.

Discussion

44.	In a series RLC circuit, the phase difference between the voltage across the inductor and the voltage across the resistor is?(a) 0^0(b) 90^0(c) 180^0(d) 360^0I had been asked this question during an internship interview.I want to ask this question from Voltages in a Series RLC Circuit topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct OPTION is (B) 90^0 For explanation I would say: In a series RLC circuit, voltage ACROSS inductor lead the CURRENT by 90^0 and voltage across resistor is in phase with current so, the phase difference between the voltage across the inductor and the voltage across the resistor is 90^0.

Discussion

45.	The maximum magnetic energy stored in an inductor at any instance is?(a) E=LIm^2/2(b) E=LIm/2(c) E=LIm^2(d) E=LIm^2*2The question was asked during a job interview.This intriguing question originated from Oscillation of Energy at Resonance topic in chapter Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct ANSWER is (a) E=LIm^2/2 To explain: At any instant, the magnetic energy STORED in an inductor is E=LIm^2/2, where IM is the maximum CURRENT and L is the value of the inductor.

Discussion

46.	What happens to the quality factor when the bandwidth increases?(a) Increases(b) Decreases(c) Remains the same(d) Becomes zeroI got this question during an interview for a job.The origin of the question is Frequency Variation in a Series RLC Circuit topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct answer is (b) Decreases The BEST explanation: Q=fres/Bandwidth QUALITY factor is inversely proportional to bandwidth. So, if bandwidth INCREASES quality factor decreases.

Discussion

47.	Quality factor is also known as _________(a) Voltage magnification(b) Current magnification(c) Resistance magnification(d) Impedance magnificationI have been asked this question in examination.My enquiry is from Quality Factor in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» Correct answer is (a) Voltage magnification Best explanation: QUALITY factor is also known as voltage magnification because the voltage across the capacitor or INDUCTOR in RESONANCE condition is EQUAL to Q times the SOURCE voltage.

Discussion

48.	In a series RLC circuit, the phase difference between the current in the circuit and the voltage across the capacitor is?(a) 0^0(b) 90^0(c) 180^0(d) 360^0I had been asked this question in my homework.My doubt stems from The Current in a Series RLC Circuit topic in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct choice is (b) 90^0 The BEST I can explain: In a SERIES RLC CIRCUIT, VOLTAGE across capacitor LAGS the current in the circuit by 90^0 so, the phase difference between the voltage across the capacitor and the current in the circuit is 90^0.

Discussion

49.	For a sharp resonance, bandwidth is ______________(a) low(b) high(c) zero(d) infinityThis question was addressed to me during an interview.The doubt is from Bandwidth topic in division Resonance in AC Circuits of Basic Electrical Engineering
Answer» The correct OPTION is (a) low To ELABORATE: For SHARP resonance QUALITY factor is high and the quality factor is inversely proportional to bandwidth so bandwidth is low for sharp resonance.

Discussion

50.	At bandwidth frequency range, the value of the voltage V is?(a) V=Vm/2(b) V=Vm^2(c) V=Vm(d) V=Vm/√2This question was posed to me in an online quiz.Query is from Bandwidth topic in portion Resonance in AC Circuits of Basic Electrical Engineering
Answer» Right option is (d) V=Vm/√2 The best I can explain: At the bandwidth frequency range, the VALUE of the VOLTAGE is equal to the MAXIMUM value of voltage divided by √2.

Discussion

Explore topic-wise InterviewSolutions in .

What is the power factor of a series RLC circuit under resonance condition?(a) 0(b) 1(c) Infinity(d) 100The question was asked in an internship interview.My question is based upon Frequency Variation in a Series RLC Circuit in chapter Resonance in AC Circuits of Basic Electrical Engineering

What is the voltage across the inductor when the source voltage is 200V and the Q factor is 10?(a) 100V(b) 20V(c) 2000V(d) 0VThe question was asked in final exam.This is a very interesting question from Quality Factor topic in chapter Resonance in AC Circuits of Basic Electrical Engineering

Find the Q factor when the voltage across the inductor is 2000V and the source voltage is 100V.(a) 10(b) 20(c) 30(d) 40I have been asked this question during an internship interview.The doubt is from Quality Factor in division Resonance in AC Circuits of Basic Electrical Engineering

Find the Q factor when the voltage across the capacitor is 1000V and the source voltage is 100V.(a) 10(b) 20(c) 30(d) 40I got this question in unit test.I want to ask this question from Quality Factor topic in portion Resonance in AC Circuits of Basic Electrical Engineering

What is the voltage across the capacitor when the source voltage is 100V and the Q factor is 10?(a) 100V(b) 10V(c) 1000V(d) 0VI had been asked this question in an interview for job.My doubt is from Quality Factor topic in section Resonance in AC Circuits of Basic Electrical Engineering

What is the SI unit for quality factor?(a) Hz(b) kHz(c) MHz(d) No unitThis question was posed to me in semester exam.I want to ask this question from Frequency Variation in a Series RLC Circuit topic in portion Resonance in AC Circuits of Basic Electrical Engineering

Q is a measure of _________(a) Resonance(b) Bandwidth(c) Selectivity(d) Either resonance or bandwidthI had been asked this question during an internship interview.The query is from Selectivity in portion Resonance in AC Circuits of Basic Electrical Engineering

Find the value of current in the bandwidth range when the maximum value of current is 50A.(a) 56.65A(b) 35.36A(c) 45.34A(d) 78.76AThe question was asked in unit test.This interesting question is from Bandwidth topic in chapter Resonance in AC Circuits of Basic Electrical Engineering

Find the reactive power when the average power is 5W and Q=2.(a) 10W(b) 5W(c) 2W(d) 1WI have been asked this question in an international level competition.The above asked question is from Oscillation of Energy at Resonance topic in division Resonance in AC Circuits of Basic Electrical Engineering

The SI unit for bandwidth is?(a) Hz(b) Watt(c) kHz(d) kWThe question was asked during an interview for a job.This intriguing question comes from Bandwidth in division Resonance in AC Circuits of Basic Electrical Engineering

Find the source voltage when the voltage across the inductor is 2000V and the Q factor is 20.(a) 10V(b) 200V(c) 100V(d) 90VI have been asked this question in my homework.The query is from Quality Factor topic in chapter Resonance in AC Circuits of Basic Electrical Engineering

In order for high selectivity, the resistance must be?(a) Small(b) Large(c) Negative(d) PositiveI have been asked this question in an internship interview.This is a very interesting question from Selectivity topic in chapter Resonance in AC Circuits of Basic Electrical Engineering

Find the value of voltage in the bandwidth range when the maximum value of voltage is 100 V.(a) 56.65 V(b) 35.36 V(c) 45.34 V(d) 70.72 VI had been asked this question during an internship interview.My question comes from Bandwidth in division Resonance in AC Circuits of Basic Electrical Engineering

At bandwidth frequency range, the value of the current I is?(a) I=Im/2(b) I=Im^2(c) I=Im(d) I=Im/√2The question was asked in class test.This interesting question is from Bandwidth topic in division Resonance in AC Circuits of Basic Electrical Engineering

What is the Q factor of a selective circuit?(a) Very low(b) Very high(c) Zero(d) InfinityI had been asked this question in examination.This key question is from Selectivity topic in portion Resonance in AC Circuits of Basic Electrical Engineering

At resonance, bandwidth includes the frequency range that allows _____ percent of the maximum current to flow.(a) 33.33(b) 66.67(c) 50(d) 70.7The question was asked in semester exam.Question is taken from Bandwidth in portion Resonance in AC Circuits of Basic Electrical Engineering

Resonance frequency occurs when __________________(a) XL=XC(b) XL>XC(c) XL

In selective circuits, the resonant frequency lies in the ________ of the bandwidth frequency range.(a) Beginning(b) End(c) Midpoint(d) Cannot be determinedThis question was posed to me in my homework.Query is from Selectivity in chapter Resonance in AC Circuits of Basic Electrical Engineering

A circuit is said to be selective if it has a _ peak and bandwidth.(a) Blunt, narrow(b) Sharp, narrow(c) Sharp, broad(d) Blunt, broadThe question was asked in an online interview.This interesting question is from Selectivity topic in portion Resonance in AC Circuits of Basic Electrical Engineering

Bandwidth is the difference of_____________________ frequencies.(a) half power(b) full power(c) double power(d) wattlessThe question was asked in final exam.I'm obligated to ask this question of Bandwidth topic in chapter Resonance in AC Circuits of Basic Electrical Engineering

Find the value of Q if the reactive power is 10W and the average power is 5W.(a) 10(b) 5(c) 2(d) 1I have been asked this question in class test.My question is from Oscillation of Energy at Resonance topic in division Resonance in AC Circuits of Basic Electrical Engineering

Quality factor is also known as _________(a) Voltage magnification(b) Current magnification(c) Resistance magnification(d) Impedance magnificationI have been asked this question in examination.My enquiry is from Quality Factor in portion Resonance in AC Circuits of Basic Electrical Engineering

For a sharp resonance, bandwidth is ______________(a) low(b) high(c) zero(d) infinityThis question was addressed to me during an interview.The doubt is from Bandwidth topic in division Resonance in AC Circuits of Basic Electrical Engineering

At bandwidth frequency range, the value of the voltage V is?(a) V=Vm/2(b) V=Vm^2(c) V=Vm(d) V=Vm/√2This question was posed to me in an online quiz.Query is from Bandwidth topic in portion Resonance in AC Circuits of Basic Electrical Engineering