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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
Match the following columns. A. `{:(A,B,C,D),(2,3,4,1):}`B. `{:(A,B,C,D),(3,4,2,1):}`C. `{:(A,B,C,D),(2,1,3,4):}`D. `{:(A,B,C,D),(4,3,1,2):}` |
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Answer» (a) Molecular oxygen ultimately combines with hydrogen to form water at the end of Electron Transport Chain (ETC). Cytochrome-c is an electron acceptor in ETS. Pyuvate dehydrogenase catalyses reaction convrting pyruvic acid into acetyl Co-A. Decarboxylation oxalosuccinate forms `alpha-"ketoglutaric"` acid in a decarboxylation reaction. |
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| 202. |
The end product of oxidative phosphorylation isA. NADHB. oxygenC. ADPD. `ATP+H_(2)O` |
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Answer» Correct Answer - D Complete oxidation of glucose molecule produces 38 ATP molecules, water and carbon dioxide with the help of energy released during oxidation of reduced co-enzymes. This process is called oxidation phosphorylation. |
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| 203. |
Lactic acid fermentation does not produceA. ATPB. `CO_(2)" and "NADH+H^(+)`C. `CO_(2)`D. `NADH + H^(+)` |
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Answer» Correct Answer - B (B) Lactic acid fermentation does not produce `CO_(2)" and "NADH`. |
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| 204. |
The end product of glycolysis isA. pyruvic acidB. glycoseC. ethyl alcoholD. `CO_(2)` |
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Answer» Correct Answer - A Pyruvic acid is the end product of glycolysis. |
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| 205. |
What is true about the end products of glycolysis?A. 2 pyruvic acid `+2ATP + 2NADH_(2)`B. 2 pyruvic acid `+2NADH_(2)`C. 1 pyruvic acud `+2ATP + 2NADH_(2)`D. 2 pyruvic acid `+1ATP +1NADH_(2)` |
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Answer» Correct Answer - A In glycolysis, two molecules of ATP are consumed during two phosphorylation reactions to form fructose 1, 6-biphosphate. In return four molecules of ATP are produced by substrate level phosphorylation (conversion of 1, 3-biphosphoglycerate to 3-phosphoglycerate and phosphoenol pyruvate to pyruvate). Two molecules of `NADH_(2)` are formed at the time of oxidation of glyceraldehyde 3-phosphate to 1, 3-biphosphoglycerate. The net reaction of glycolysis is as follows : `"Glucose" + 2NAD^(+)+2ADP+2H_(3)PO_(4) rarr 2" Pyruvate" + 2NADH+2H^(+)+2ATP` Each NADH is equivalent to 2 ATP, so the net gain in glycolysis is 8 ATP. |
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| 206. |
End product of fermentation of sugars isA. Water and carbon dioxideB. Alcohol and carbon dioxideC. Carbon dioxideD. Alcohol |
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Answer» Correct Answer - B (B) End product of fermentation of sugars (alcoholic fer- mentation) is alcohol and carbon dioxide. |
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| 207. |
In germinating seed, R.Q. falls when there is shift fromA. Carbohydrate to fat as substrateB. Fat to carbohydrateC. Aerobic to anaerobic respirationD. Protein to carbohydrate |
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Answer» Correct Answer - A (A) In germinating seed, R.Q. falls when there is shift from carbohydrate to fat as substrate. |
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| 208. |
The number of carbon atom in citric acid isA. 8B. 6C. 10D. 2 |
| Answer» Correct Answer - B | |
| 209. |
In opuntia, in night the R.Q. will beA. OneB. Less than oneC. More than OneD. Zero |
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Answer» Correct Answer - D In some succulent or finely plants e.g., Opuritia, carbohydrates are incompletely oxidised to organic acids in dark without the evolution of `CO_(2)` `underset("glucose")2C_(6)H_(12)3O_(2)rarrunderset("mallic acid")3C_(4)H_(6)O_(5)+3H_(2)O` R.Q`=(CO_(2))/(O_(2))=(0)/(0)=0` (less than one) |
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| 210. |
R.Q. of malic acid isA. 0.7B. 1C. 1.33D. 4 |
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Answer» Correct Answer - C `C_(4)H_(6)O_(5)+3O_(2)rarr4CO_(2)+3H_(2)O` `R.Q.=(4)/(3)=1.3` (more than one). |
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| 211. |
Hydrogen of malate is accpeted byA. FADB. FMNC. COQD. NAD |
| Answer» Correct Answer - D | |
| 212. |
Cytochrome is a component of ETC in mitochendria/chloroplast, acting as electron acceptor. It is aA. glycoproteinB. lipidC. `Ca2^+` containing metallo flavoproteinD. `Fe^(+++)` containing prophyrin pigment protein |
| Answer» Correct Answer - D | |
| 213. |
In germinating castor seeds, the R.Q. is or A mixture containing equal quantity of germinating maize and groundnut seeds are taken. The RQ of this mixture would beA. OneB. More than oneC. Less than oneD. Zero |
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Answer» Correct Answer - C In germinating cator seeds, respiratory substrate is fat, Malize contains carbohydrats and grounded seed contains fatty acid. R.Q of these substance are respectively less than 1. Thus total R.Q. will be less than one. |
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| 214. |
Which of the following plant parts can respire even in the absence of oxygen ?A. SeedsB. RootsC. StemsD. Leaves |
| Answer» Correct Answer - A | |
| 215. |
Which can readily respire without oxygen ?A. AnabaenaB. SaccharomycesC. MushroomD. Fish |
| Answer» Correct Answer - B | |
| 216. |
Which of the following plant is widely accpeted to respire in absense of oxygen.A. yeastB. PotatoC. ChlorellaD. Grass |
| Answer» Correct Answer - A | |
| 217. |
R.Q. is less than one when the respiratory substrate isA. Organic acidsB. Fats and proteinsC. SucroseD. Glucose |
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Answer» Correct Answer - B (B) R.Q. is less than one if the respiratory substrate is fats and proteins. |
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| 218. |
Which one can respire in the absence of oxygen ?A. SeedsB. LeavesC. StenlD. Root |
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Answer» Correct Answer - A (A) Seeds can respire in the absence of oxygen (anaerobic respiration). |
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| 219. |
How much energy is conserved as ATP per mole of `O_2` reduced into `H_2O` ?A. 36B. 38C. 6D. 36 in eukaryotes and 38 in prokaryotes. |
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Answer» Correct Answer - C For `1/2O_2`,3ATP are formed. |
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| 220. |
The Nobel Prize for the discovery of TCA cycle and ATP biosynthesis was awarded toA. Hans KrebsB. LipmanC. Krebs and Lipman jointlyD. Vishniac and Ochoa |
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Answer» Correct Answer - C TCA cycle was discovered By Hans Krebs (1940). ATP formation system (ATP cycle) is,called Lipman system after the name of its discoverer. But ATP was discovered by Lohmann. |
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| 221. |
A business man of 70 kg weight requires 2800 kcal energy daily. How many glucose molecules and ATP molecules does he require to produce this much energy ?A. 20 molecules of glucose and 384 molecules of ATPB. 11 molecules of glucose and 380 molecules of ATPC. 1 Molecule of glucose and 38 molecules of ATPD. 6 molecules of glucose and 584 molecules of ATP |
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Answer» Correct Answer - B One molecule of glucose yields 686 Kcal of which only 262. 8 Kcal(= 36 ATP) is usable and rest is lost as heat. 1 ATP yields 7.3 Kcal and accordingly (1) number of glucose for 2800 Kcal energy will be`2800/262.8=11`(ii) number of ATP will be `2800/7.3=384`. |
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| 222. |
The commonest living, which can respire in the absence of `O_(2)` isA. FishB. YeastC. PotatoD. Chlorella |
| Answer» Correct Answer - B | |
| 223. |
Respiratory substrates are the organic substances which are _______during respiration to liberate energy.A. oxidisedB. reducedC. synthesisedD. both (a) and (b) |
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Answer» Correct Answer - A Respiration is an oxidative process in which repiratory substrates are oxidised to liberate energy inside the living cells. The common respiratory substrates are carbohydrates, proteins, fats and organic acids. The most common respiratory substrates are carbohydrates, proteins, fats and organic acids. The most common respiratory substrate is glucose. |
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| 224. |
The respiration in germinating seeds produces energy energy which can be detected in the form ofA. waterB. heatC. oxygenD. `CO_(2)` |
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Answer» Correct Answer - B In germinating seeds, imbibition takes place. Their kinetic energy is released in the form of heat (heat of wetting). |
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| 225. |
Which of the following is a direct oxidation pathway being performed without glycolysisA. TCA cycleB. HMP pathwayC. Both a and bD. None of these |
| Answer» Correct Answer - B | |
| 226. |
Why is glycolysis called an ancient pathway ? |
| Answer» Because it is presentin all organisms. | |
| 227. |
R.Q. of respiratory substrate `C_(99)H_(72)O_(6)` would beA. 0·718B. 1·34C. 2·71D. 3·250. |
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Answer» Correct Answer - A (A) R.Q. of respiratory substrate `C_(39)H_(72)O_(6)` would be 0·718. |
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| 228. |
The correct sequences of electron acceptor in ATP synthesis isA. Cyt a, `a_(3)`, b, cB. Cyt b, c, a, `a_(3)`C. Cyt c, b, a, `a_(3)`D. Cyt b, c, `a_(3)`, a |
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Answer» Correct Answer - B (B) Correct sequence in electron acceptors in ATP synthe- sis is Cyt b, c, a, `a_(3)`. |
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| 229. |
For each acetyl Co-A oxidized by the citric acid cycle, what is the energy gain?A. Two molecules of NADH, one `FADH_2` and one nucleoside triphosphateB. Three molecules of NADH, one `FADH_2` and one nucleoside triphosphateC. Two molecules of NADH, one `FADH_2` and two nucleoside triphosphateD. Three molecules of NADH, one `FADH_2` and two nucleoside triphosphate |
| Answer» Correct Answer - B | |
| 230. |
When examining the TCA cycle, alpha ketoglutarate dehydrogenase complex requires the set of cofactors as which of the following?A. Citrate synthaseB. Cis-aconitateC. Pyruvate dehydrogenaseD. Fumarate |
| Answer» Correct Answer - C | |
| 231. |
Synthesis of ATP in mitochondria requireA. OxygenB. NADPC. FMND. Pyruvic acid |
| Answer» Correct Answer - A | |
| 232. |
Identify A and B in the given diagram showing ATP synthesis in mitochondria. A. B. C. D. |
| Answer» Correct Answer - B | |
| 233. |
Identify A and B in the given diagram showing ATP synthesis in mitochondria. A. A = Mitochondrial matrix B = Outer mitochondrial membraneB. A= Mitochondrial matrix B = Inner mitochondrial membraneC. A = Cell cytoplasm B = Inner mitochondrial membraneD. A = Cell cytoplasm B = Outer mitochondrial membrane |
| Answer» Correct Answer - b | |
| 234. |
Net gain of ATP molecules, during aerobic respiration, in heart cells isA. 40 moleculesB. 48 moleculesC. 36 moleculesD. 38 molecules |
| Answer» Correct Answer - D | |
| 235. |
`alpha`-Ketoglutarate dehydrogenase brings aboutA. Oxidation and decarboxylationB. OxidationC. DecarboxylationD. Reduction |
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Answer» Correct Answer - A (A) `alpha`-Ketoglutarate dehydrogenase brings about oxidation and decarboxylation. |
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| 236. |
The energy yield of ATP is higher in aerobic respiration than during anaerobic respiration. Explain. |
| Answer» The energy yield in temrs of ATP is higher in aerobic respiration than during anaerobic respiration is as given `{:("Aerobic Respiration ","Anaerobic Respiration"),("In aerobic respiration, there is complete oxidation of substrate molecules producing ATP","In anaerobic respiration there is incomplete oxidation of substrate molecules so the ATP produced are less in number"),("Aerobic respiration of glucose produces 36 ATP molecules "+H_(2)O+CO_(2),"occurs in yeast, produces 2ATP molecules +ethy lalcohol+CO_(2)"):}` | |
| 237. |
A single turn of Krebs cycle yieldsA. `1 FADH_(2), 2 NADH_(2)` and 1 ATPB. `2 FADH_(2), 2 NADH_(2)` and 2 ATPC. `1 FADH_(2), 3 NADH_(2)`, and 1 ATPD. `1 FADH_(2), 1 NADH_(2)`, and 1 ATP |
| Answer» Correct Answer - A | |
| 238. |
In anaerobic respiration, the number of ATP molecules produced areA. 1B. 2C. 3D. 8 |
| Answer» Correct Answer - B | |
| 239. |
The number of ATP molecules produced by electron transport system from Krebs cycle intermediates in a single turn isA. 11B. 14C. 12D. 16 |
| Answer» Correct Answer - A | |
| 240. |
Glyceraldehyde-3-phosphate isA. produced from glucose during glycolysisB. part of PS-IC. produced from pyruvate before entering the mitochondriaD. an amino acid used for making protein |
| Answer» Correct Answer - A | |
| 241. |
Assertion :- 2,4 DNP is an uncoupling agent in ETS. Reason :- It is soluble in lipid.A. If both Assertion and Reason are true and the Reason is the correct explanation of the Assertion.B. If both Assertion and Reason are true, but the Reason is not the correct explanation of the Assertion.C. If Assertion is true, but Reason is flase.D. If both Assertion and Reason are false. |
| Answer» Correct Answer - B | |
| 242. |
Pyruvic acid is the end product ofA. Krebs cycleB. Electron transport systemC. PhotosynthesisD. Glycolysis |
| Answer» Correct Answer - D | |
| 243. |
Which of the following options does not hold good regarding anaerobic respiration or fermentation ?A. Occurs inside the mitochondriaB. Partial breakdown of glycose occursC. Net gain of only 2 ATP moleculesD. None of these |
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Answer» Correct Answer - A Fermentation is the incomplete oxidation of glucose under anaerobic conditions by sets of reactions where pyruvic acid is converted to `CO_(2)` and ethanol (alcoholic fermentation) or lactic acid (lactic acid fermentation). In fermentation, there is a net gain of only 2 ATP molecules for each molecule of glucose degraded to pyruvic acid. |
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| 244. |
A test tube containing molasses solution and yeast is kept in a warm place overnight. The gas collected from this mixtureA. extingusihes the flameB. bursts into flame when ignitedC. turns lime water milkyD. both (a) and (c) |
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Answer» Correct Answer - D The given process is an example of alcoholic fermentation, thus the gas produced is `CO_(2)` |
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| 245. |
Dough kept overnight in warm weather becomes soft and spongy due toA. Absorption of carbon dioxide from atmosphereB. FermentationC. CohesionD. Osmosis |
| Answer» Correct Answer - B | |
| 246. |
Enumerate the assumptions that we undertaker in making the respiratory balance Sheet . Are these assumptions valid for a living system? Compare fermentation and aerobic respiration in this context. |
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Answer» The Calculations of the net gain of ATP for every glucose molecules oxidised can be made on the following assumptions (i) There is sequential pathway that follows. i.e., glycolysis , TCA cycle and ETS in cytoplasm , mitochndrial matrix and inner mitochonodrial membrane respectively. (ii) NADH, synthesised in glycolysis enters in to ETC for phosphorylation. (iii) None of the intermediates in the pathway are utlised to synthesis any other compound (iv) Glucose forms respiatory substrate. These assumptions are not valid for a living system because of following neasons (i) These all pathways work simultaneously and do not take place one after the other. (ii) ATP is utilised when needed. (iii) Rate of enzyme actions is controlled by multiple means. Comparisan between fermentation and aerobic respiration are as follows `{:("Fermentation","Aerobic Respirartion"),("Fermentation is partial breakdown of glucose.","It is complete breakdown of glucose"),("Net gain of only "2ATP,38 ATP " are produced"),("Oxidation of NADH to " NAD^(+) " is slow proces","It is vigorous reaction in aerobic respiration"):}` |
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| 247. |
Oxidative phosphorylation involves simultaneous oxidation and phosphorylation to finally formA. pyruvateB. NADPC. DPND. ATP |
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Answer» Correct Answer - D In oxidative phophorylation ATP is formed as the electrons are transferred from NADH or `FADH_(2)` to `O_(2)` by a series of electron carries, located in the inner membrane of mitochondria. |
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| 248. |
Oxidative phosphorylation refers toA. Anaerobic production of ATPB. Citric acid cycle production of ATPC. Production of ATP by chemiosmosisD. Alcoholic fermentation |
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Answer» Correct Answer - B (B) Oxidative phosphorylation refers to citric acid cycle production of ATP. |
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| 249. |
Anaerobic respiration was first of all reported byA. MaguenneB. KostychevC. KleinD. Pfeffer |
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Answer» Correct Answer - B Anaerobic repiration first studies by Kostychev (1902). |
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| 250. |
What is the total gain of energy during anaerobic respirationA. One molecule of ATPB. Two molecules of ATPC. Four molecules of ATPD. Eight molecules of ATP |
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Answer» Correct Answer - B Number of ATP mol. Evolved in one complete cycle of anaerobic respiration is 2. |
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