InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 401. |
The symbol represents :- A. NOT gateB. OR gateC. AND gateD. NOR gate |
| Answer» Correct Answer - A | |
| 402. |
The following circuit represents:A. OR gateB. XOR gateC. AND gateD. NAND gate |
| Answer» Correct Answer - B | |
| 403. |
Which of the following will have an output of 1 :- A. aB. cC. bD. d |
| Answer» Correct Answer - B | |
| 404. |
In a `p-n` junction–A. new holes and conduction electrons are produced continuously throughout the materialB. new holes and conduction electrons are produced continiously throughout the material except in the depletion regionC. holes and conduction electrons recombine continuously throughout the materialD. holes and conduction electrons recombine continuosly throughout the material except in the depletion region. |
| Answer» Correct Answer - A::D | |
| 405. |
The combination of the gates shown will produce A. OR gateB. AND gateC. NOR gateD. NAND gate |
| Answer» Correct Answer - B | |
| 406. |
The combination of the gates shown will produce A. OR gateB. AND gateC. NOR gateD. NAND |
| Answer» Correct Answer - C | |
| 407. |
The width of the forbidden band will be small inA. metalsB. insulatorsC. semiconductorsD. good conductors |
| Answer» Correct Answer - C | |
| 408. |
Pick the correct statement the reverse current in p-n junction diodeA. can be maximum and constantB. remains constant even after the breakdown voltageC. becomes infinity at breakdownD. reverse current is controlled by external resistance. |
| Answer» Correct Answer - A::C::D | |
| 409. |
At ordinary temperature, an increase in temperature, increases the conductivity ofA. a semiconductorB. a conductorC. a super conductorD. an insulator |
| Answer» Correct Answer - A | |
| 410. |
Wires `P` and `Q` have the same resistance at ordinary (room) temperature. When heated, resistance of `P` increases and that of `Q` decreases. We conclude thatA. P and Q are conductors of different materialsB. P is n-type semiconductor and Q is p-type semiconductorC. P is semiconductor and Q is conductorD. P is conductor and Q is semiconductor |
| Answer» Correct Answer - D | |
| 411. |
Which of the following statements is correct-A. Resistance of semiconductor decreases with increase in temperatureB. In an electric field, displacement of holes is opposite to the displacement of electronsC. Resistance of a conductor decreases with the increase in temperatureD. n-type semiconductor are neutral. |
| Answer» Correct Answer - A::B::D | |
| 412. |
Which of the following statements is correct-A. Resistance of extrinsic semiconductors can be changed as requiredB. in n-type semiconductor the umber of electrons increases in valence bandC. In p-type semiconductors the number of holes increases in valence bandD. In pure semiconductor fermi band is situated in between the valence band and conduction band |
| Answer» Correct Answer - A::C::D | |
| 413. |
The output of `OR` gate is `1`A. if both inputs are zeroB. if either or both inputs are 1C. only if both input are 1D. if either input is zero |
| Answer» Correct Answer - B | |
| 414. |
Give the logic symbol of NAND gate.A. an OR gateB. a NOT gateC. an AND gateD. a NAND gate |
| Answer» Correct Answer - B | |
| 415. |
Give the logic symbol of NOR gate.A. an OR gateB. A NOR gateC. A NAND gateD. an AND gate |
| Answer» Correct Answer - B | |
| 416. |
What is a forward current in case of zero biased p-n junction diode? |
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Answer» When the diode terminals are shorted together, some holes (majority carriers) in the p-side have enough thermal energy to overcome the potential barrier. Such carriers cross the barrier potential and contribute to current. This current is known as the forward current. |
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| 417. |
What is knee voltage? |
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Answer» In forward bias mode, the voltage for which the current in a p-n junction diode rises sharply is called knee voltage. |
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| 418. |
State some important features of the depletion region. |
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Answer» 1. It is formed by diffusion of electrons from n-region to the p-region. This leaves positively charged ions in the n-region. 2. The p-region accumulates electrons (negative charges) and the n-region accumulates the holes (positive charges). 3. The accumulation of charges on either sides of the junction results in forming a potential barrier and prevents flow of charges. 4. There are no charges in this region. 5. The depletion region has higher potential on the n-side and lower potential on the p-side of the junction. |
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| 419. |
Avalanche breakdown is due toA. shift of fermi levelB. curmulative effect of conductor band electron collisionC. widening of forbidden gapD. Low impurity concentration |
| Answer» Correct Answer - B | |
| 420. |
Symbolic representation of four logic gates are shown as A. (iii), (ii) and (i)B. (iii), (ii) and (v)C. (ii), (iv) and (iii)D. (ii), (iii) and (iv) |
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Answer» Correct Answer - C The symbols given in problem represent (i) OR gate (ii) AND gate (iii) NOT gate and (iv) NAND gate |
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| 421. |
What is the forbidden energy gap (in joule) for a Germanium crystal ?A. `1.6xx10^(-19) `JB. `1.12xx10^(-19) `JC. `3.2xx10^(-19) `JD. `2.24xx10^(-19) `J |
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Answer» Correct Answer - B `E_g=0.7 eV = 0.7xx1.6xx10^(-19) J = 1.12xx10^(-19) J` |
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| 422. |
The band of maximum energy in which electrons are present is called theA. conduction bandB. valence bandC. forbidden bandD. none of these |
| Answer» Correct Answer - B | |
| 423. |
In a triode, `gm=2xx10^(-3)ohm^(-1) , mu=42`, resistance load, R = 50 kilo ohm. The voltage amplification obtained from this triode will beA. 30.42B. 29.57C. 28.18D. 27.15 |
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Answer» Correct Answer - B As, `A_(v)=(muR)/(r_(p)+R)=(muR)/((mu//g_(m))+R)` `=(42xx(50xx10^(3)))/(42//(2xx10^(-3))+50xx10^(3))=29.57` |
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| 424. |
When npn transistor is used as an ampliflerA. electrons move from base to collectorB. holes move from emitter to baseC. electrons move from collector to baseD. holes move from base to emitter |
| Answer» Correct Answer - D | |
| 425. |
The energy band gap is maximum inA. metalsB. superconductorsC. insulatorsD. semiconductors |
| Answer» Correct Answer - C | |
| 426. |
At absolute zero , Si acts asA. non-metalB. metalC. insulatorD. none of these |
| Answer» Correct Answer - C | |
| 427. |
Truth table for system of four `NAND` gates as shown in figure is : .A. `{:(A,B,Y),(0,0,1),(0,1,0),(1,0,0),(1,1,1):}`B. `{:(A,B,Y),(0,0,0),(0,1,1),(1,0,1),(1,1,0):}`C. `{:(A,B,Y),(0,0,0),(0,1,0),(1,0,1),(1,1,1):}`D. `{:(A,B,Y),(0,0,1),(0,1,1),(1,0,0),(1,1,0):}` |
| Answer» Correct Answer - B | |
| 428. |
If the Output of two NAND gates is given to input of a NAND gate. Then the truth table will be ofA. NOR gateB. OR gateC. AND gateD. XOR gate |
| Answer» Correct Answer - B | |
| 429. |
The relationship between `alpha` and `beta` is given byA. `alpha=b`B. `alpha=(1)/(beta)`C. `beta=(alpha)/(1-alpha)`D. `beta=(alpha)/(1+alpha)` |
| Answer» Correct Answer - C | |
| 430. |
In n-p-n transistor the emitter current will be equal toA. collector currentB. base currentC. sum of the collector and base currentD. difference of collector and base current |
| Answer» Correct Answer - C | |
| 431. |
In a p-n-p transistor, the n-type crystal works as aA. gateB. baseC. collectorD. emitter |
| Answer» Correct Answer - B | |
| 432. |
The current gain of a transistor is defined asA. the ratio of change in collector current to be change in emitter current for a constant value of collector voltage in a common base arrangementB. The ratio of charge in collector current to the change in base current for constant collector voltage in a common emitter arrangementC. the ratio of change in collector current to the change in base current for constant collector voltage in a common for constant arrangementD. The ratio of change in emitter current to the change in collector current for a constant emitter voltage in a common emitter arrangement |
| Answer» Correct Answer - A | |
| 433. |
In n-p-n transistor, the p-type crystal acts asA. base onlyB. collector onlyC. emitter onlyD. all of these |
| Answer» Correct Answer - A | |
| 434. |
Transistors may not replace vacuum tubes in all uses becauseA. transistors require longer warm-ups than vaccum tubesB. vacuum tubes are more resistance to shock and vibration tubes transistorsC. vacuum tubes can handle greater power than transistorsD. transistors use high voltage |
| Answer» Correct Answer - C | |
| 435. |
Three amplifier circuit are connected in series. The voltage gain of each is 5. What is the final voltage amplification?A. 15B. 125C. `5/3`D. 25 |
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Answer» Correct Answer - B `A=A_1 xx A_2 xx A_3 ` = 125 |
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| 436. |
The depletion layer in `P-N` junction region is caused byA. drift of holesB. drift of electronsC. diffusion of carriersD. migration a impurity ions |
| Answer» Correct Answer - C | |
| 437. |
Mark the correct statement(s)-A. Diode, LED and transistor are two leg devicesB. Diode, LED and resistor are two leg devicesC. Transistor and IC are 3 leg devicesD. IC and transistor are having same number of legs but not three |
| Answer» Correct Answer - B | |
| 438. |
Continuity test is made with multimeter by keeping the selector switch ON at-A. voltage positionB. current positionC. resistace positionD. None of these |
| Answer» Correct Answer - C | |
| 439. |
The frequency of oscillation in an oscillationA. `f=(1)/(sqrt(2pi LC)`B. `f=(1)/(2pi sqrt(LC))`C. `f=(sqrt(LC))/(2pi)`D. `f=(1)/(R)sqrt((L)/(C))` |
| Answer» Correct Answer - B | |
| 440. |
For sustained oscillation the product of gain of amplifier (A) and feedback factor (`beta`) isA. equal to 1B. less than 1C. greater than 1D. cannot be predicted |
| Answer» Correct Answer - A | |
| 441. |
In an oscillator when the signal from the output circuit is applied to input of the circuit then it calledA. feedbackB. ripple factorC. form factorD. refractive index |
| Answer» Correct Answer - A | |
| 442. |
Tank circuit of oscillator consists ofA. L and C in parallelB. RC in seriesC. L and C in seriesD. RC in parallel |
| Answer» Correct Answer - A | |
| 443. |
Which of the following is the part of oscillator ?A. Tank circuitB. AmplifierC. Feedback circuitD. All of these |
| Answer» Correct Answer - D | |
| 444. |
An electronic device that generates oscillations of desired frequency isA. oscillatorB. transformerC. voltage regulatorD. rectifier |
| Answer» Correct Answer - A | |
| 445. |
An electronic device which converts ac into dc is calledA. amplifierB. rectifierC. oscillatorD. induction coil |
| Answer» Correct Answer - B | |
| 446. |
The number of bonds formed in p-type and n-type semiconductors are respectively (A) 4,5 (B) 3,4 (C) 4,3 (D) 5,4 |
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Answer» Correct option is: (B) 3,4 |
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| 447. |
If the forward voltage in a semiconductor diode is chaged form 0.5 V to 2 V, then the forward current changed by 1.5 mA. The forward resistance of diode will be-A. 50 `Omega`B. 100 `Omega`C. 150 `Omega`D. 200 `Omega` |
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Answer» Correct Answer - D `R_f=(DeltaV)/(DeltaI)=0.3/(1.5xx10^(-3)) = 200 Omega` |
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| 448. |
If a `p-n` junction diode, a square input signal of `10 V` is applied as shown. Then the out put signal across `R_(L)` will be .A. B. C. D. |
| Answer» Correct Answer - A | |
| 449. |
If a `p-n` junction diode, a square input signal of `10 V` is applied as shown. Then the out put signal across `R_(L)` will be .A. B. C. D. |
| Answer» Correct Answer - D | |
| 450. |
The input characteristics of a transistor in CE mode is the graph obtained by plottingA. `I_(B)` against `I_(C)` at constant `V_(CE)`B. `I_(B)` against `V_(BE)` at constant `V_(CE)`C. `I_(B)` against `I_(C)` at constant `V_(BE)`D. `I_(B)` against `V_(CE)` at constant `V_(BE)` |
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Answer» Correct Answer - B The input characteristics of a transistor is a graph between `I_(B)` and `B_(BE)` at constant `V_(CE)`. |
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