InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 351. |
What is thermistor? |
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Answer» Thermistor is a temperature sensitive resistor. Its resistance changes with change in its temperature. |
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| 352. |
In given diagram which p-n junction in reverse biasedA. B. C. D. |
| Answer» Correct Answer - B | |
| 353. |
The current obtained from a simple filterless reactifier isA. varying direct currentB. constant direct currentC. direct current mixed with alternating currentD. eddy current |
| Answer» Correct Answer - C | |
| 354. |
When out put current is in one direction only, but is continuously varying in value, then it is calledA. anode currentB. direction currentC. alternating currentD. pulsating direct current |
| Answer» Correct Answer - D | |
| 355. |
Enlist any two features of thermistor. |
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Answer» 1. A small change in surrounding temperature causes a large change in their resistance. 2. They can measure temperature variations of a small area due to their small size. |
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| 356. |
Write a note on: i. Electric devices ii. Electronic devices |
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Answer» i. Electric devices: 1. These devices convert electrical energy into some other form. 2. Examples: Fan, refrigerator, geyser etc. Fan converts electrical energy into mechanical energy. A geyser converts it into heat energy. 3. They use good conductors (mostly metals) for conduction of electricity. 4. Common working range of currents for electric circuits is milliampere (mA) to ampere. 5. Their energy consumption is also moderate to high. A typical geyser consumes about 2.0 to 2.50 kW of power. 6. They are moderate to large in size and are costly. ii. Electronic devices: 1. Electronic circuits work with control or sequential changes in current through a cell. 2. A calculator, a cell phone, a smart watch or the remote control of a TV set are some of the electronic devices. 3. Semiconductors are used to fabricate such devices. 4. Common working range of currents for electronic circuits it is nano-ampere to µA. 5. They consume very low energy. They are very compact, and cost effective. |
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| 357. |
Current through a reverse biased p-n junction, increases abruptly at : (A) Breakdown voltage (B) 0.0 V (C) 0.3 V (D) 0.7 V |
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Answer» Correct answer is (A) Breakdown voltage |
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| 358. |
The energy levels of holes are : (A) in the valence band (B) in the conduction band(C) in the band gap but close to valence band (D) in the band gap but close to conduction band |
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Answer» Correct answer is (C) in the band gap but close to valence band |
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| 359. |
When the resistance between p and n regions is very high then the p-n junction diode acts asA. an inductorB. a transistorC. a capacitorD. zener diode |
| Answer» Correct Answer - C | |
| 360. |
Electric conduction through a semiconductor is due to : (A) Electrons (B) holes (C) none of these (D) both electrons and holes |
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Answer» Correct answer is (D) both electrons and holes |
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| 361. |
In a p - n junction, electric conduction takes place due toA. driftB. diffusionC. drift and diffusionD. barrier potential |
| Answer» Correct Answer - C | |
| 362. |
In the circuit shown infigure, voltage `V_(0)` is,A. 11.7 voltB. 11.3 voltC. 0D. None of these |
| Answer» Correct Answer - A | |
| 363. |
In the given circuit `V_(O_(1))&V_(O_(2))` areA. 11.3 V 0.3 VB. 0.3 V & 11.3 VC. 11.3 V & 11.3 VD. 0.3 V & 0.3 V |
| Answer» Correct Answer - A | |
| 364. |
The current obtained from a simple filterless reactifier isA. an eddy currentB. sinusoidal currentC. varying direct currentD. constant direct current |
| Answer» Correct Answer - C | |
| 365. |
Can we take one slab of p-type semiconductor and physically join it to another n-type semiconductor to get p-n junction? |
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Answer» 1. No. Any slab, howsoever flat, will have roughness much larger than the inter-atomic crystal spacing (~2 to 3 Å). 2. Hence, continuous contact at the atomic level will not be possible. The junction will behave as a discontinuity for the flowing charge carriers. |
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| 366. |
Which is the correct diagram of a half- wave reactifier?A. B. C. D. |
| Answer» Correct Answer - B | |
| 367. |
In the diagram, the input is across the terminals `A` and `C` and the output is across the terminals `B` and `D`, then the outputs is A. ZeroB. same as inputC. full wave rectifierD. half wave rectifier |
| Answer» Correct Answer - C | |
| 368. |
In the half-wave rectifier circuit shown. Which one of the following wave forms in true for `V_(CD)`, if the input is as shown?A. B. C. D. |
| Answer» Correct Answer - B | |
| 369. |
In a half wave rectifier, the r.m.s value of the A.C. component of the wave isA. less than zeroB. less than D.C. ValueC. equal to D.C. valueD. greater than D.C. value |
| Answer» Correct Answer - D | |
| 370. |
Can we take one slab of p - type semiconductor and physically join it to another n - type semiconductor to get p - n junction? |
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Answer» Correct Answer - A No. Any slab will have some roughness . Hence continous contact at the atomic level will not be possible. For the charge carries , the junction will behave as a discontinuity . |
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| 371. |
The diode is also used asA. an amplifierB. a modulatorC. a rectifierD. an oscillator |
| Answer» Correct Answer - C | |
| 372. |
When two semiconductor of p and n type are brought in to contact, they from a p-n junction which acts like a :-A. rectifierB. amplifierC. oscillatorD. conductor |
| Answer» Correct Answer - A | |
| 373. |
A rectifier is used to convertA. high current into low currentB. low current into high currentC. D.C. current into A.C. currentD. A.C. current into D.C. current |
| Answer» Correct Answer - D | |
| 374. |
Which of the statements given in above example is true for p - type semiconductors ? |
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Answer» Correct Answer - A (d) Holes are majority carries and trivalent atoms are the dopants in an p - type semiconductors |
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| 375. |
In an n- type silicon, which of the following statements is true ? (a) Electrons are majority carries and trivalent atoms are the dopants. (b) Electrons are majority carries and pentavalent atoms are the dopants. (c ) Holes are minority carries and paentavalent atoms are the dopants. (d) Holes are minority carries and trivalent atoms are the dopants. |
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Answer» Correct Answer - A ( c) Holes are minority charge carries and pentavalent atoms are the dopants in an n- type silicon. |
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| 376. |
When two semiconductor of p and n type are brought in to contact, they from a p-n junction which acts like a :-A. conductorB. oscillatorC. amplifierD. rectifier |
| Answer» Correct Answer - D | |
| 377. |
In a crystal, the permitted energy states of electrons are presentA. in the conduction band and the forbidden gapB. only in the forbidden gapC. in the valence band and conduction bandD. in the forbidden gap and the valence band |
| Answer» Correct Answer - C | |
| 378. |
In N-Type semiconductors, which extra energy level is added?(a) Conduction level(b) Donor Energy Level(c) Acceptor energy level(d) Valence level |
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Answer» Correct option is (b) Donor Energy Level Best explanation: In N-Type semiconductor level, a new energy level below the conduction band is formed. The energy difference between the two is about 0.045 eV. |
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| 379. |
What are the current carriers in semiconductors?(a) Electrons and Protons(b) Electrons and Nucleons(c) Electrons and Photons(d) Electrons and Holes |
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Answer» Right choice is (d) Electrons and Holes To explain I would say: Electrons and holes are the two current carriers in semiconductors. Electrons are negatively charged while holes are positively charged. Their movement gives rise to a current in the semiconductor. |
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| 380. |
The electrons in the atoms of an element, which determine its chemical and electricalproperties are calledA. valence electronsB. conduction electronsC. free electronsD. bound electrons |
| Answer» Correct Answer - A | |
| 381. |
The concentration of doping is kept below ______________(a) 1 %(b) 5 %(c) 10 %(d) 50 % |
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Answer» The correct choice is (a) 1 % Easiest explanation: The concentration of doping in semiconductors is generally kept below 1 %. However, it is enough to bring a huge drop in the energy gap. |
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| 382. |
In a semi conductor diode , the barrier potential offers opposition to only -A. majority carrier in both regionsB. minority carrier in both regionsC. free electrons in the n-regionD. holes in the p-region |
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Answer» Correct Answer - C In a semiconductor diode, the barrier potential offers opposition to only free electrons in the n-region. |
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| 383. |
What is the order of forbidden energy gap in `eV` in the energy bands of silicon ?A. 0.5 eVB. 1.1 eVC. 2.1 eVD. 3.5 eV |
| Answer» Correct Answer - B | |
| 384. |
Which one of the following is not an intrinsic semiconductor?(a) Carbon(b) Silicon(c) Germanium(d) Lead |
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Answer» Right answer is (a) Carbon Easiest explanation: There are 4 bonding electrons in all the above materials. However, the energy required to take out an electron will be maximum for carbon as the valence electrons are in the second orbit. Hence, the number of free electrons for conduction is negligibly small in C. |
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| 385. |
Pure Si at 300 K has equal electron (ni) and hole concentration (p) of 1.5 X 10^16 m^-3. Doping by indium increases p to 4.5 X 10^22 m^-3. What is n in the doped silicon?(a) 4.5 X 10^9 m^-3(b) 4.5 X 10^22 m^-3(c) 5 X 10^9 m^-3(d) 5 X 10^22 m^-3 |
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Answer» The correct choice is (c) 5 X 10^9 m^-3 Best explanation: Here, ni = 1.5 X 10^16 m^-3, p = 4.5 X 10^22 m^-3 We know, np = ni^2 n = ni^2/p = 5 X 10^9 m^-3. |
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| 386. |
The following graph depicts the I-V characteristics of which instrument?(a) Photodiode(b) Light Emitting Diode(c) Solar Cell(d) Zener diode |
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Answer» Right answer is (c) Solar Cell Easiest explanation: The generation of EMF by a solar cell is due to three basic processes: generation of electron-hole pair, separation of electrons and holes and collection of electrons by the front contact. The p-side becomes positive and the n-side becomes negative giving rise to photo voltage. The I-V characteristics of the solar cell are drawn in the fourth quadrant of the coordinate axis because a solar cell does not draw current but supplies the same to the load. |
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| 387. |
Identify the type of material.(a) Intrinsic Semiconductor(b) N-Type semiconductor(c) P-Type semiconductor(d) Conductor |
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Answer» Correct choice is (c) P-Type semiconductor The explanation is: In the figure, as we can see there is an acceptor energy level just above the valence band. This happens in the case of P-Type semiconductors. |
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| 388. |
Which of the following can be used to create a P-Type Semiconductor?(a) P(b) Sb(c) Ga(d) As |
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Answer» The correct choice is (c) Ga To explain: For a P-Type semiconductor, a material with 3 valence electrons is chosen. Out of the given choices, Ga can be used to create a P-Type Semiconductor. |
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| 389. |
Which of the following is n-type semiconductor?(a) CaO(b) MgO(c) ZnO(d) BaO |
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Answer» Right answer is (c) ZnO The explanation: II-VI semiconductors are generally p-type semiconductors except for ZnO and ZnTe. II-VI semiconductors are those which contain atoms of materials that have 2 valence electrons and 6 valence electrons. |
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| 390. |
The Hall coefficient of a specimen is 3.66 x 10^-4 m^3C^-1. If it’s resistivity is 8.93 x 10^-3 Ωm, what will be its mobility?(a) 0.01 m^2V^-1s^-1(b) 0.02 m^2V^-1s^-1(c) 0.03 m^2V^-1s^-1(d) 0.04 m^2V^-1s^-1 |
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Answer» The correct choice is (d) 0.04 m^2V^-1s^-1 Easy explanation: We know, Mobility = Hall coefficient/resistivity Therefore, Mobility = 3.66 x 10^-4/8.93 x 10^-3 = 0.04 m^2V^-1s^-1. |
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| 391. |
Resistivity of a semiconductor depends onA. sizeB. type of atomsC. lengthD. size and type of atom |
| Answer» Correct Answer - B | |
| 392. |
In common base circuit of a transistor , current amplification factor is `0.95`. Calculate the emitter current , if base current is `0.2` mAA. 2 mAB. 4 mAC. 6 mAD. 8 mA |
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Answer» Correct Answer - B `alpha=0.95 = I_C/I_E` and `I_E=I_C-I_B " " therefore I_C=I_E+I_B` `therefore I_C=0.95 I_E` Thus `I_E+I_B=0.95I_E` `therefore I_E(1-0.95) = -I_B` `therefore I_E(5/100)=2/10 mA ` (-ve sign neglected) `50I_E=200 " " therefore I_E=4mA` |
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| 393. |
The current through the diode in the given circuit is A. 1 mAB. 10 mAC. 5 mAD. zero |
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Answer» Correct Answer - D Current is zero as the junction diode is reverse biased. |
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| 394. |
Distinguish between p-type and n-type semiconductor. |
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| 395. |
What is the charge on a p-type and n-type semiconductor? |
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Answer» n-type as well as p-type semiconductors are electrically neutral. |
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| 396. |
What is a p-n junction? |
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Answer» When n-type and p-type semiconductor materials are fused together, the junction formed is called as p-n junction. |
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| 397. |
In a PNP transistor, N-type semiconductor is used as theA. collector onlyB. base onlyC. emitter onlyD. collector or emitter |
| Answer» Correct Answer - B | |
| 398. |
In p-type semiconductor, the major charge carriers are:A. neutronsB. protonsC. electronsD. holes |
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Answer» Correct Answer - D The trivalent impurities provide holes to create positive charge carriers. It is known that in a p-type semiconductor trivalent impurity (having 3 valance electrons) is added. Hence, current carriers in p-type semiconductors are holes. |
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| 399. |
GaAs is-A. an elemental semiconductorB. alloy semiconductorC. bad conductorD. metallic semiconductor |
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Answer» Correct Answer - B Holes behave as positive charge carriers, electrons have negative charge. Thus, gallium Arsenide is an alloy semiconductor where Ga contributes holes and as contributes electrons. |
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| 400. |
The current (I) in the circuit will be:-A. `(5)/(40)A`B. `(5)/(50)A`C. `(5)/(10)A`D. `(5)/(20)A` |
| Answer» Correct Answer - B | |