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51.

What is the basic law that has to be followed in order to analyze the circuit?(a) Newton’s laws(b) Faraday’s laws(c) Ampere’s laws(d) Kirchhoff’s lawThis question was posed to me in an online interview.I would like to ask this question from Kirchhoff’s Voltage Law in chapter Simple DC Networks of Basic Electrical Engineering

Answer»

Right answer is (d) KIRCHHOFF’s law

To EXPLAIN I would SAY: Kirchhoff’s laws, namely Kirchhoff’s CURRENT Law and Kirchhoff’s Voltage law are the basic laws in order to analyze a circuit.

52.

What is the value of current if a 50C charge flows in a conductor over a period of 5 seconds?(a) 5A(b) 10A(c) 15A(d) 20AI had been asked this question by my school principal while I was bunking the class.My query is from Kirchhoff’s Current Law in chapter Simple DC Networks of Basic Electrical Engineering

Answer»

The CORRECT option is (b) 10A

To explain: CURRENT=CHARGE/TIME. Here charge = 50c and time = 5seconds, so current = 50/5 = 10A.

53.

Which is the most cost efficient connection?(a) Series(b) Parallel(c) Either series or parallel(d) Neither series nor parallelThe question was asked in an online quiz.My doubt is from Series Circuits and Parallel Networks in chapter Simple DC Networks of Basic Electrical Engineering

Answer»

The CORRECT CHOICE is (a) Series

To elaborate: The ADVANTAGE of series-connections is that they share the supply voltage, hence cheap low voltage appliances MAY be used.

54.

In a _________ circuit, the total resistance is greater than the largest resistance in the circuit.(a) Series(b) Parallel(c) Either series or parallel(d) Neither series nor parallelThis question was posed to me in exam.Asked question is from Series Circuits and Parallel Networks topic in division Simple DC Networks of Basic Electrical Engineering

Answer»

The CORRECT CHOICE is (a) Series

Easy explanation: In series CIRCUITS, the total RESISTANCE is the SUM of all the resistance in the circuit, hence the total is greater than the largest resistance.

55.

The currents in the three branches of a parallel circuit are 3A, 4A and 5A. What is the current leaving it?(a) 0A(b) Insufficient data provided(c) The largest one among the three values(d) 12AI have been asked this question by my college director while I was bunking the class.My question is taken from Parallel Networks in portion Simple DC Networks of Basic Electrical Engineering

Answer»

Right answer is (d) 12A

For EXPLANATION I would SAY: The TOTAL CURRENT leaving a node is the same as the current that enters it. Total I=I1+I2+I3=3+4+5=12A.

56.

What is the value of the current I?(a) 8A(b) 7A(c) 6A(d) 5AI have been asked this question during an interview for a job.I need to ask this question from Kirchhoff’s Current Law in chapter Simple DC Networks of Basic Electrical Engineering

Answer» CORRECT CHOICE is (a) 8A

Easy EXPLANATION: At the JUNCTION, I-2+3-4-5=0. HENCE I=8A.
57.

Calculate the total current in the circuit.(a) 20 A(b) 10 A(c) 11.43 A(d) 15 AThis question was posed to me during an online exam.Origin of the question is Parallel Networks topic in division Simple DC Networks of Basic Electrical Engineering

Answer» CORRECT choice is (c) 11.43 A

The best I can explain: The 1 ohm and 2 ohm resistor are in SERIES which is in parallel to the 3 ohm resistor. The equivalent of these resistances (3/2 ohm) is in series with the 4 ohm and 5 ohm resistor. TOTAL R = 21/2 ohm. I=V/R=120/(21/2)=240/21=11.43 A.
58.

The rise or fall in resistance with the rise in temperature depends on ________(a) The property of the conductor material(b) The current in the metal(c) Property of material as well current in that material(d) Does not depend on any factorThis question was posed to me in exam.My query is from Temperature Coefficient of Resistance topic in portion Simple DC Networks of Basic Electrical Engineering

Answer»

Right option is (a) The property of the CONDUCTOR material

The best explanation: The rise or fall in RESISTANCE with a rise in temperature DEPENDS upon the property of the material. Hence it rises with temperature in metals and falls with temperature in insulators and semi-conductors.

59.

Calculate the work done in a resistor of 20 ohm carrying 5A of current in 3 hours.(a) 1.5J(b) 15J(c) 1.5kWh(d) 15kWhI got this question in exam.The above asked question is from Power in division Simple DC Networks of Basic Electrical Engineering

Answer» RIGHT CHOICE is (c) 1.5kWh

Explanation: To find POWER: P=I^2R=5^2*20=500W=0.5kW.

To find WORK done: W=Pt=0.5*3=1.5kWh.
60.

A copper coil has a resistance of 200 ohms when its mean temperature is 0 degree centigrade. Calculate the resistance of the coil when its mean temperature is 80 degree centigrade. Temperature coefficient of copper is 0.004041 centigrade^-1(a) 264.65 ohm(b) 264.65 kilo-ohm(c) 286.65 ohm(d) 286.65 kilo-ohmThis question was posed to me in unit test.I'm obligated to ask this question of Temperature Coefficient of Resistance topic in division Simple DC Networks of Basic Electrical Engineering

Answer» RIGHT CHOICE is (a) 264.65 ohm

Explanation: R=R0(1+α dT) = 200(1+ 0.004041*80) = 264.65 ohm.
61.

What is the resistivity of Copper?(a) 1.59*10^-8ohm-m(b) 2.7*10^-8ohm-m(c) 7.3*10^-8ohm-m(d) 5.35*10^-8ohm-mI got this question in my homework.My question is based upon Resistivity topic in division Simple DC Networks of Basic Electrical Engineering

Answer»

Right answer is (a) 1.59*10^-8ohm-m

The explanation is: RESISTIVITY is a MATERIAL property. Different MATERIALS have different resistivity. Resistivity of COPPER is 1.72*10^-8 ohm-m.

62.

A current of 2A flows in a wire offering a resistance of 10ohm. Calculate the energy dissipated by the wire in 0.5 hours.(a) 72Wh(b) 72kJ(c) 7200J(d) 72kJhI had been asked this question in exam.My enquiry is from Energy topic in division Simple DC Networks of Basic Electrical Engineering

Answer»

Correct choice is (b) 72kJ

Explanation: Here I (current) = 2A and RESISTANCE(R) = 10ohm. Power = I^2R = 2^2*10=40. Energy = Pt = 40*0.5*60*60 = 72000J=72kJ.

63.

Out of the following, which one is not a source of electrical energy?(a) Solar cell(b) Battery(c) Potentiometer(d) GeneratorThis question was posed to me by my college professor while I was bunking the class.Query is from Energy topic in division Simple DC Networks of Basic Electrical Engineering

Answer»

Right answer is (c) Potentiometer

Explanation: Solar CELL converts light energy to electrical energy. Battery converts chemical energy to electrical energy. GENERATOR generates electrical energy using ELECTROMAGNETIC induction. A potentiometer is an INSTRUMENT used for MEASURING voltage and consumes electrical energy instead of generating it.

64.

Calculate the power in the 20 ohm resistance.(a) 2000kW(b) 2kW(c) 200kW(d) 2WI had been asked this question during an interview for a job.My doubt stems from Power in portion Simple DC Networks of Basic Electrical Engineering

Answer»

Right choice is (B) 2kW

The BEST I can EXPLAIN: Here V = 200v and Resistance( R) = 20OHM. P=V^2/R= 200^2/20=2000W=2kW.

65.

Calculate the voltage across the 10 ohm resistor.(a) 12V(b) 4V(c) 10V(d) 0VI had been asked this question in an interview for job.I'm obligated to ask this question of Kirchhoff’s Voltage Law in chapter Simple DC Networks of Basic Electrical Engineering

Answer» RIGHT answer is (B) 4V

Explanation: TOTAL RESISTANCE = 5+10+15 = 30 OHM. Current in the circuit is 12/30 A.

Voltage across 10 ohm resistor is 10*(12/30) = 4V.
66.

KVL deals with the conservation of?(a) Mass(b) Momentum(c) Charge(d) EnergyThe question was asked in class test.I'm obligated to ask this question of Kirchhoff’s Voltage Law topic in chapter Simple DC Networks of Basic Electrical Engineering

Answer»

The correct answer is (d) ENERGY

Best explanation: KVL states that the sum of the POTENTIAL energy and taken with the right sign is equal to ZERO, hence it is the CONSERVATION of energy since energy doesn’t enter or leave the SYSTEM.

67.

Find the value of i2, i4 and i5 if i1=3A, i3=1A and i6=1A.(a) 2,-1,2(b) 4,-2,4(c) 2,1,2(d) 4,2,4The question was posed to me by my school teacher while I was bunking the class.I'd like to ask this question from Kirchhoff’s Current Law topic in division Simple DC Networks of Basic Electrical Engineering

Answer»

The correct option is (a) 2,-1,2

Best EXPLANATION: At junction a: i1-i3-i2=0. i2=2A.

At junction B: i4+i2-i6=0. i4=-1A.

At junction C: i3-i5-i4=0. i5=2A.

68.

Calculate the current A.(a) 5A(b) 10A(c) 15A(d) 20AI have been asked this question during an online interview.I would like to ask this question from Kirchhoff’s Current Law in section Simple DC Networks of Basic Electrical Engineering

Answer»

The correct ANSWER is (c) 15A

The best EXPLANATION: KCL states that the TOTAL CURRENT leaving the junction is equal to the current entering it. In this case, the current entering the junction is 5A+10A=15A.

69.

KCL can be applied for __________(a) Planar networks(b) Non-planar networks(c) Both planar and non-planar(d) Neither planar nor non-planarThe question was asked in an interview for internship.This intriguing question originated from Kirchhoff’s Current Law in portion Simple DC Networks of Basic Electrical Engineering

Answer»

Correct option is (c) Both planar and non-planar

For explanation I WOULD say: KCL is applied for different NODES of a NETWORK whether it is planar or non-planar.

70.

Calculate the equivalent resistance between A and B.(a) 60 ohm(b) 15 ohm(c) 12 ohm(d) 48 ohmThis question was posed to me during an online interview.My doubt is from Series Circuits and Parallel Networks in division Simple DC Networks of Basic Electrical Engineering

Answer»

Right option is (c) 12 ohm

Easiest EXPLANATION: 5 ohm and 15 ohm are connected in SERIES to give 20 ohm.10ohm and 20 ohm are connected in series to give 30 ohm. Now both equivalent resistances (20ohm and 30 ohm) are in parallel to give equivalent RESISTANCE 20*30/(20+30) = 12 ohm.

71.

The current in each branch of a parallel circuit is proportional to _________(a) The amount of time the circuit is on for(b) Proportional to the value of the resistors(c) Equal in all branches(d) Proportional to the power in the circuitThe question was posed to me in an online quiz.My doubt stems from Parallel Networks in portion Simple DC Networks of Basic Electrical Engineering

Answer»

The correct answer is (b) PROPORTIONAL to the value of the resistors

Explanation: I=V/R. In a parallel CIRCUIT, the VOLTAGE across each RESISTOR is equal, hence the value of the CURRENT is proportional (inversely) to the value of the resistance.

72.

The voltage across the short is?(a) 135V(b) Infinity(c) Zero(d) 11.25VThe question was asked in unit test.Asked question is from Parallel Networks topic in portion Simple DC Networks of Basic Electrical Engineering

Answer» CORRECT choice is (c) Zero

Explanation: The voltage across a SHORT is ALWAYS equal to zero whether it is CONNECTED in SERIES or parallel.
73.

Materials having resistance almost equal to zero is _______(a) Semi-conductor(b) Conductor(c) Superconductors(d) InsulatorsThis question was posed to me at a job interview.Question is from Temperature Coefficient of Resistance topic in chapter Simple DC Networks of Basic Electrical Engineering

Answer»

The correct choice is (C) Superconductors

For explanation I would say: When the temperature of the MATERIAL falls to absolute ZERO, the RESISTANCE falls to zero and hence there are no I^2R losses. Since resistance is zero, conductance is almost infinity and hence these MATERIALS are known as superconductors.

74.

A battery converts___________(a) Electrical energy to chemical energy(b) Chemical energy to electrical energy(c) Mechanical energy to electrical energy(d) Chemical energy to mechanical energyI got this question in class test.Asked question is from Energy topic in chapter Simple DC Networks of Basic Electrical Engineering

Answer» CORRECT option is (b) CHEMICAL energy to electrical energy

Explanation: A battery is a device in which the chemical ELEMENTS within the battery REACT with each other to produce electrical energy.
75.

A bulb has a power of 200W. What is the energy dissipated by it in 5 minutes?(a) 60J(b) 1000J(c) 60kJ(d) 1kJThe question was asked by my college director while I was bunking the class.My question comes from Energy in chapter Simple DC Networks of Basic Electrical Engineering

Answer»

Right answer is (c) 60kJ

For explanation: Here, POWER = 200w and TIME = 5min. E=Pt => E= 200*5= 1000Wmin=60000Ws= 60000J= 60kJ.

76.

Find the value of the currents I1 and I2.(a) 0.3, 0.1(b) -0.1, -0.3(c) -0.3, -0.1(d) 0.1, 0.2The question was asked in an interview for internship.I would like to ask this question from Kirchhoff’s Voltage Law in division Simple DC Networks of Basic Electrical Engineering

Answer» CORRECT choice is (d) 0.1, 0.2

To explain: Using KVL in LOOP 1, 10-100 i1=0. i1=0.1A

Using KVL in OUTER loop, -100i2+20=0i2=0.2A.
77.

Calculate the equivalent resistance between A and B.(a) 2 ohm(b) 4 ohm(c) 6 ohm(d) 8 ohmThe question was asked by my school teacher while I was bunking the class.Query is from Series Circuits and Parallel Networks topic in section Simple DC Networks of Basic Electrical Engineering

Answer»

Right answer is (b) 4 ohm

The BEST explanation: R=((2+3)||5)+1.5)||4. The 2 and the 3 ohm resistor are in SERIES. The equivalent of these TWO RESISTORS is in parallel with the 5 ohm resistor. The equivalent of these three resistances is in series with the 1.5 ohm resistor. Finally, the equivalent of these resistances is in parallel with the 4 ohm resistor.

78.

Which of the following statements are true about insulators?(a) Insulators have a positive temperature coefficient(b) Insulators have a negative temperature coefficient(c) Insulators have zero temperature coefficient(d) Insulators have infinite temperature coefficientI got this question in unit test.I would like to ask this question from Temperature Coefficient of Resistance in section Simple DC Networks of Basic Electrical Engineering

Answer» RIGHT choice is (B) Insulators have a negative TEMPERATURE coefficient

The BEST explanation: Insulators have a negative temperature coefficient because as temperature increases, the resistance of insulators decreases.
79.

Which of the following is not an expression power?(a) P=VI(b) P=I^2R(c) P=V^2/R(d) P=I/RThis question was addressed to me during an internship interview.This intriguing question originated from Power in division Simple DC Networks of Basic Electrical Engineering

Answer»

The CORRECT choice is (d) P=I/R

Explanation: Power is the PRODUCT of voltage and CURRENT. WRITING I in terms of V, we get P=V^2/R and writing V in terms of I, we get P=I^2r.

80.

Calculate the value of V1 and V2.(a) 4V, 6V(b) 5V, 6V(c) 6V, 7V(d) 7V, 8VThis question was addressed to me in an online interview.The doubt is from Kirchhoff’s Voltage Law topic in division Simple DC Networks of Basic Electrical Engineering

Answer»

Correct CHOICE is (a) 4V, 6V

The best I can EXPLAIN: USING KVL, 12-V1-8=0. V1= 4V.

8-V2-2=0. V2=6V.

81.

If the current through x ohm resistance in the circuit is 5A, find the value of x.(a) 27 ohm(b) 5 ohm(c) 12 ohm(d) 135 ohmI have been asked this question by my school principal while I was bunking the class.The query is from Parallel Networks topic in division Simple DC Networks of Basic Electrical Engineering

Answer» CORRECT ANSWER is (a) 27 ohm

The EXPLANATION: R=V/I. In this CIRCUIT I=5A and V=135V. THEREFORE, R=135/5=27 ohm.
82.

It is preferable to connect bulbs in series or in parallel?(a) Series(b) Parallel(c) Both series and parallel(d) Neither series nor parallelI have been asked this question by my college professor while I was bunking the class.My doubt is from Series Circuits and Parallel Networks in chapter Simple DC Networks of Basic Electrical Engineering

Answer»

Correct choice is (b) Parallel

The best I can EXPLAIN: BULBS are connected in parallel so that even if one of the bulbs blow out, the OTHERS continue to get a current supply.

83.

Which of the following statements are true with regard to resistance?(a) Resistance is directly proportional to a length of the wire(b) Resistance is directly proportional to an area of cross section of the wire(c) Resistance is inversely proportional to the length of the wire(d) Resistance is inversely proportional to the resistivity of the wireI got this question by my school principal while I was bunking the class.The above asked question is from Resistivity topic in portion Simple DC Networks of Basic Electrical Engineering

Answer»

Correct choice is (a) Resistance is directly PROPORTIONAL to a length of the WIRE

Easy EXPLANATION: The EXPRESSION for resistance is: Resistance=Resistivity*length of wire/ AREA of cross section of the wire. Hence resistance is directly proportional to length.

84.

The resistance of pure metals ___________(a) Increases with an increase in temperature(b) Decreases with an increase in temperature(c) Remains the same with an increase in temperature(d) Becomes zero with an increase in temperatureThis question was addressed to me in class test.My question is from Temperature Coefficient of Resistance topic in division Simple DC Networks of Basic Electrical Engineering

Answer»

Correct option is (a) INCREASES with an increase in temperature

Easiest explanation: In a conductor, the valence BAND and conduction band overlap each other, there is an excess of ELECTRONS in the conduction band. When the temperature increases, there is an overcrowding of electrons in the conduction band hence reducing the mobility and hence resistance increases.

85.

Calculate the power across each 20 ohm resistance.(a) 1000W, 1000W(b) 500W, 500W(c) 1000kW, 1000kW(d) 500kW, 500kWI have been asked this question in quiz.My question is based upon Power in section Simple DC Networks of Basic Electrical Engineering

Answer»

Correct choice is (B) 500W, 500W

The explanation is: This is a SERIES connected circuit HENCE the current across each resistance is the same. To FIND current: I=V/R=200/20=5A.

To find power: P=I^2R=5^2*20=500W. Since both the RESISTORS have a resistance of 20 ohms, the power across both is the same.

86.

A current of 5A flows in a resistor of 2 ohms. Calculate the energy dissipated in 300 seconds in the resistor.(a) 15kJ(b) 15000kJ(c) 1500J(d) 15JI got this question in an interview for internship.The query is from Power in portion Simple DC Networks of Basic Electrical Engineering

Answer» RIGHT OPTION is (a) 15kJ

For EXPLANATION I WOULD SAY: P=I^2R =5^2*2=50W.

E= Pt=50*300=15000J=15kJ.
87.

In a parallel circuit, with a number of resistors, the voltage across each resistor is ________(a) The same for all resistors(b) Is divided equally among all resistors(c) Is divided proportionally across all resistors(d) Is zero for all resistorsThe question was posed to me in homework.My doubt is from Parallel Networks in portion Simple DC Networks of Basic Electrical Engineering

Answer»

The correct CHOICE is (a) The same for all resistors

Easy EXPLANATION: In parallel circuits, the current across the circuits VARY whereas the VOLTAGE remains the same.

88.

Kilowatt-hour(kWh) is a unit of?(a) Current(b) Power(c) Energy(d) ResistanceThis question was addressed to me in an online quiz.Enquiry is from Power in division Simple DC Networks of Basic Electrical Engineering

Answer» CORRECT choice is (c) Energy

Easiest explanation: POWER is the energy per UNIT TIME. That is, P=E/t. If the unit of power in kW and the unit of time is an HOUR, then the unit of energy=unit of power*unit of time=kWh.