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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

Equation of horizontal line below x-axis at 5 units from x-axis is _______(a) x=5(b) x=-5(c) y=5(d) y=-5The question was asked in examination.The above asked question is from General Equation of a Line in chapter Straight Lines of Mathematics – Class 11

Answer»

The CORRECT choice is (d) y=-5

To explain: EQUATION of x-axis is y=0. Horizontal line is parallel to x-axis and below it by 5 UNITS so, equation of line is y=-5.

2.

The points A (1, 2), B (3, 5), C (7, 8) are collinear.(a) True(b) FalseI had been asked this question at a job interview.Query is from Various Forms of the Equation of a Line topic in chapter Straight Lines of Mathematics – Class 11

Answer»

Correct choice is (b) False

To explain: We KNOW, SLOPE of LINE joining TWO points (x1, y1) and (x2, y2) is GIVEN by(y2-y1)/(x2-x1).

Slope of line AB = (5-2)/(3-1) = 3/2

Slope of line BC = (8-5)/(7-3) = 3/4

Since slope of AB is not equal to BC so, points are not collinear.

3.

If the two lines with slope m1 and m2 are perpendicular then their slopes has relation ______(a) m1 + m2 = 1(b) m1 * m2 = 1(c) m1 * m2 = -1(d) m1 + m2 = -1This question was addressed to me in homework.My query is from Various Forms of the Equation of a Line topic in section Straight Lines of Mathematics – Class 11

Answer»

The CORRECT answer is (c) M1 * m2 = -1

To explain: If the two lines are perpendicular then if one line form ANGLE α with positive x-axis then the other line form angle 90° + α.

If m1 = TAN α then m2 will be tan (90°+ α) = – cot α = -1/tan α

=> m1 * m2 = – 1.

4.

What is the slope of a line which is parallel to y-axis?(a) -1(b) 0(c) 1(d) Not definedI have been asked this question in an online interview.The above asked question is from Slope of a Line topic in chapter Straight Lines of Mathematics – Class 11

Answer»

Right answer is (d) Not DEFINED

Best EXPLANATION: If a line is parallel to y-axis then angle formed by it with x-axis is zero. So, its inclination is 90°. Hence SLOPE = tan 90° which is not defined.

5.

What is the area of triangle whose vertices are (-4, -4), (-3, 2), (3, -16)?(a) 24 sq. units(b) 27 sq. units(c) 32 sq. units(d) 37 sq. unitsI have been asked this question during an interview for a job.Enquiry is from Slope of a Line in division Straight Lines of Mathematics – Class 11

Answer»

Right answer is (b) 27 sq. units

To EXPLAIN I would say: We know, area of TRIANGLE joining vertices (x1, y1), (x2, y2) and (x3, y3) is (1/2)* determinant \(\begin{pmatrix}-4 & -4 &1 \\-3& 2 & 1\\ 3& -16 & 1\end{pmatrix}\) is \(\frac{1}{2}\){(-4)(2+16) – (-4)(-3-3) + (1)(48-6)} = \(\frac{1}{2}\)|(-72)+(-24)+42| = 27 square units.

6.

If two lines are parallel then their slopes must be equal.(a) True(b) FalseThis question was posed to me in my homework.My query is from Various Forms of the Equation of a Line in section Straight Lines of Mathematics – Class 11

Answer»

Right choice is (a) True

To EXPLAIN: Let the inclination of the two lines be α and β. SINCE they are parallel so, α = β.

=>TAN α = tan β. Hence their SLOPES are equal.

7.

Angle made by line with ____________ measured anticlockwise is called inclination of the line.(a) positive x-axis(b) negative x-axis(c) positive y-axis(d) negative y-axisI have been asked this question in an internship interview.This question is from Slope of a Line in portion Straight Lines of Mathematics – Class 11

Answer» RIGHT CHOICE is (a) positive x-axis

The best I can explain: We know, inclination of line is always measured with positive x-axis in ANTICLOCKWISE DIRECTION.
8.

What is the inclination of a line which is parallel to x-axis?(a) 0°(b) 180°(c) 45°(d) 90°I got this question in my homework.The query is from Slope of a Line in section Straight Lines of Mathematics – Class 11

Answer»

The CORRECT option is (a) 0°

To explain I would SAY: If a line is parallel to x-axis then angle FORMED by it with x-axis is ZERO. So, its inclination is zero.

9.

Find the equation of line parallel to y-axis and passing through (3, 4).(a) x=3(b) x=4(c) y=4(d) y=3I had been asked this question in semester exam.I would like to ask this question from General Equation of a Line in portion Straight Lines of Mathematics – Class 11

Answer» CORRECT answer is (a) x=3

Best explanation: LET general equation of LINE be y=m (x-d) => x = y/m +d

Since line is parallel to y-axis so, m=1/0 or 1/m =0

=>x=d => x=3 by SUBSTITUTING the POINT (3, 4).
10.

Equation of horizontal line above x-axis at 5 units from x-axis is _______(a) x=5(b) x=-5(c) y=5(d) y=-5The question was posed to me at a job interview.My question comes from General Equation of a Line in chapter Straight Lines of Mathematics – Class 11

Answer»

The CORRECT choice is (C) y=5

Best EXPLANATION: Equation of x-axis is y=0. HORIZONTAL line is parallel to x-axis and above it by 5 units so, equation of line is y=5.

11.

Find slope of line passing through origin and (3, 6).(a) 2(b) 3(c) 1/3(d) 1/2This question was addressed to me in my homework.My query is from Various Forms of the Equation of a Line topic in section Straight Lines of Mathematics – Class 11

Answer»

The CORRECT choice is (a) 2

For explanation: We know, slope of line joining two points (x1, Y1) and (X2, y2) is GIVEN by (y2-y1)/(x2-x1).

So, slope of line joining (0, 0) and (3, 6) is (6-0)/(3-0) = 6/3 = 2.

12.

Slope of a line is given by _________ if inclination of line is α.(a) sinα(b) cosα(c) tanα(d) cotαI have been asked this question by my school principal while I was bunking the class.This is a very interesting question from Slope of a Line topic in division Straight Lines of Mathematics – Class 11

Answer»

The CORRECT ANSWER is (c) tanα

For explanation I would say: Slope of a line is given by tanα if inclination of line is α. Slope is DENOTED by tangent of the inclination ANGLE.

13.

Find slope of line if inclination made by the line is 60°.(a) 1/2(b) 1/√3(c) √3(d) 1The question was posed to me at a job interview.This question is from Slope of a Line in division Straight Lines of Mathematics – Class 11

Answer»

The correct CHOICE is (C) √3

To elaborate: Slope of a line is given by tanα if INCLINATION of line is α. If inclination is 60° the slope is TAN 60° = √3.

14.

What is the distance of (5, 12) from origin?(a) 6 units(b) 8 units(c) 10 units(d) 13 unitsI got this question during an internship interview.I'd like to ask this question from Slope of a Line in chapter Straight Lines of Mathematics – Class 11

Answer»

The correct choice is (d) 13 UNITS

The EXPLANATION is: We KNOW, distance between two points (x1, Y1) and (x2, y2) is\(\SQRT{(x_1-x_2)^2+(y_1-y_2)^2}\).

So, distance between (5, 12) from origin (0, 0) is \(\sqrt{(5-0)^2+(12-0)^2} = \sqrt{(5)^2+(12)^2}\) = 13 units.

15.

If equation of line is y=5x+10 then find the value of x-intercept made by the line.(a) 2(b) 1/2(c) -1/2(d) -2The question was asked in class test.My enquiry is from Distance of a Point from a Line topic in portion Straight Lines of Mathematics – Class 11

Answer»

Correct choice is (d) -2

Easy explanation: GIVEN equation is y=5x+10. X-intercept MEANS value of x when y is zero

0=5x+10 => x=-2

16.

In which ratio (3, 4) divides the line segment joining (1, 2) and (4, 5) internally?(a) 1:2(b) 2:1(c) 3:4(d) 4:3I had been asked this question in unit test.Origin of the question is Slope of a Line in section Straight Lines of Mathematics – Class 11

Answer»

Right option is (b) 2:1

The best explanation: The coordinates of a POINT dividing the line segment joining (x1, Y1) and (X2, y2) internally in the ratio m: n is \((\FRAC{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})\).

Let the ratio be k: 1.So, the coordinates of a point dividing the line segment joining (1, 2) and (4, 5) internally in the ratio k: 1 is \((\frac{k*4+1*1}{k+1},\frac{k*5+1*2}{k+1})\)

=> \((\frac{k*4+1*1}{k+1},\frac{k*5+1*2}{k+1})\) is same as (3, 4).

=> (4k+1)/(k+1) = 3

=> 4k+1 = 3k+3

=> k = 2

So, ratio is 2:1.

17.

Line perpendicular to line joining (1, 3) and (4, 5) and pass through (2, 4) has equation ____________(a) 3x+2y-14=0(b) 3x-2y-14=0(c) 2x-3y-14=0(d) 2x+3y-14=0The question was posed to me during an online interview.The query is from General Equation of a Line topic in chapter Straight Lines of Mathematics – Class 11

Answer» CORRECT answer is (a) 3x+2y-14=0

Best EXPLANATION: Slope of line JOINING (1, 3) and (4, 5) is (5-3) / (4-1) = 2/3

So, slope of line PERPENDICULAR to it is -3/2.

Line has slope -3/2 and pass through (2, 4)

So, EQUATION is y-4 = (-3/2)(x-2) => 2y-8 = -3x+6 => 3x+2y-14=0.
18.

If angle between the two lines is 45° and slope of one line is 1/4 then which of the following is possible value of the slope of other line.(a) 3/5(b) -3/5(c) -5/3(d) 4/5This question was posed to me during an online exam.My query is from Various Forms of the Equation of a Line topic in division Straight Lines of Mathematics – Class 11

Answer» CORRECT answer is (b) -3/5

Easy explanation: If angle between two LINES with slopes m1 and M2 is α then tan α = |(m1-m2)/(1+m1*m2)|

tan 45° = \(|\frac{m-1/4}{1+m/4}|\)

=> \(\frac{4m-1}{m+4}\) = -1

=>- m-4 = 4m-1 => 5M = -3

=> m = -3/5.
19.

Find the distance between 2x+y+4=0 and 2x+y+8=0.(a) \(\frac{4}{\sqrt{5}}\)(b) \(\frac{3}{\sqrt{5}}\)(c) \(\frac{9}{\sqrt{5}}\)(d) \(\frac{3}{\sqrt{2}}\)I had been asked this question in final exam.My question is from Distance of a Point from a Line in chapter Straight Lines of Mathematics – Class 11

Answer» RIGHT OPTION is (a) \(\frac{4}{\sqrt{5}}\)

For EXPLANATION: Distance between PARALLEL lines ax +by +c1=0 and ax+by+c2=0 is \(|\frac{c1-c2}{\sqrt{a^2+b^2}}|\).

So, distance 2x + y+4=0 and 2x+y+8=0 is \(|\frac{8-4}{\sqrt{2^2+1^2}}|=\frac{4}{\sqrt{5}}\).
20.

Find the equation of line parallel to x-axis and passing through (3, 4).(a) x=3(b) x=4(c) y=4(d) y=3I have been asked this question in a job interview.This intriguing question comes from General Equation of a Line topic in division Straight Lines of Mathematics – Class 11

Answer»

The correct CHOICE is (c) y=4

For explanation: LET general equation of LINE be y=m*x + c.

Since line is PARALLEL to x-axis so, m=0.

=>y=c=>y=4 by substituting the point (3, 4).

21.

If area of triangle formed by three points is zero then the three points must be collinear.(a) True(b) FalseI had been asked this question during an online interview.This is a very interesting question from Slope of a Line topic in section Straight Lines of Mathematics – Class 11

Answer»

The correct choice is (a) True

Easiest explanation: AREA of TRIANGLE FORMED by THREE points is zero then the three points must be collinear i.e. they must lie on the same line.

22.

Find the equation of line joining (3, 4) and (5, 8).(a) y = 2x-1(b) y = 2x+2(c) y = 2x+1(d) y = 2x-2I got this question in semester exam.My question is based upon General Equation of a Line in chapter Straight Lines of Mathematics – Class 11

Answer»

Right CHOICE is (d) y = 2x-2

The best I can explain: We know, equation of LINE joining two POINTS (x1, y1) and (x2, y2) is given by

\(\FRAC{y-y1}{y2-y1} = \frac{x-x1}{x2-x1}\)

So, equation will be \(\frac{y-4}{8-4} = \frac{x-3}{5-3}\)

=>\(\frac{y-4}{4} = \frac{x-3}{2}\)

=>y-4 = 2x-6

=>y = 2x-2

23.

The coordinates of a point dividing the line segment joining (1, 2) and (4, 5) internally in the ratio 2:1 is ____________________(a) (3, 4)(b) (4, 3)(c) (5, 4)(d) (5, 3)The question was posed to me in final exam.This question is from Slope of a Line topic in section Straight Lines of Mathematics – Class 11

Answer»

The correct option is (a) (3, 4)

EXPLANATION: The coordinates of a point DIVIDING the line segment JOINING (x1, y1) internally in the ratio m: N is \((\FRAC{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n})\).

So, the coordinates of a point dividing the line segment joining (1, 2) and (4, 5) internally in the ratio 2:1 is \((\frac{2*4+1*1}{2+1}, \frac{2*5+1*2}{2+1})\) = (3, 4).

24.

What is the slope of a line which is parallel to x-axis?(a) -1(b) 0(c) 1(d) Not definedThis question was addressed to me in an interview for internship.My doubt is from Slope of a Line topic in section Straight Lines of Mathematics – Class 11

Answer» RIGHT answer is (b) 0

Explanation: If a line is parallel to x-axis then angle FORMED by it with x-axis is zero. So, its INCLINATION is zero. Hence SLOPE = tan 0° = 0.
25.

Find the perpendicular distance of point (2, 4) from line 2x+y-5=0.(a) \(\frac{6}{\sqrt{5}}\)(b) \(\frac{3}{\sqrt{5}}\)(c) \(\frac{9}{\sqrt{5}}\)(d) \(\frac{3}{\sqrt{2}}\)I got this question during an interview for a job.Question is from Distance of a Point from a Line topic in chapter Straight Lines of Mathematics – Class 11

Answer»

Right answer is (b) \(\frac{3}{\SQRT{5}}\)

For EXPLANATION: Distance of point (x1, y1) from LINE ax +by +c=0 is \(|\frac{ax1+by1+c}{\sqrt{a^2+b^2}}|\).

So, distance of point (2, 4) from line 2x+y-5=0 is \(|\frac{2*2+4*1-5}{\sqrt{2^2+1^2}}| = \frac{3}{\sqrt{5}}\).

26.

If equation of line is x + y=2 then find the perpendicular distance of line from origin.(a) √2(b) √3(c) 1/√2(d) 1/√3This question was addressed to me in semester exam.I'm obligated to ask this question of Distance of a Point from a Line in division Straight Lines of Mathematics – Class 11

Answer»

Correct choice is (a) √2

To elaborate: Given EQUATION is x + y=2. REDUCING the above equation to NORMAL form

(x + y)/√2 =√2.

x cos⁡45° + y SIN 45° = √2

Perpendicular distance from ORIGIN is √2.

27.

If perpendicular distance of a line from origin is 4 units and angle which the normal makes with positive x-axis is 45°, then the equation will be ______________(a) x + y = 4√2(b) x – y = 4√2(c) y – x = 4√2(d) x + y = -4√2The question was posed to me in unit test.My question is based upon General Equation of a Line topic in portion Straight Lines of Mathematics – Class 11

Answer»

Right choice is (a) x + y = 4√2

Best EXPLANATION: If p is perpendicular DISTANCE of line from ORIGIN and ω be the angle FORMED by normal with positive x-axis then equation of line is x cos⁡ω + y sin⁡ω = p.

So, equation of given line will be x cos⁡45° + y sin⁡45° = 4

=>(x + y)/√2 = 4

=>x + y = 4√2.

28.

What is the distance between (1, 3) and (5, 6)?(a) 3 units(b) 4 units(c) 5 units(d) 25 unitsThis question was posed to me during an interview.My enquiry is from Slope of a Line in section Straight Lines of Mathematics – Class 11

Answer»

Right OPTION is (c) 5 units

The explanation: We know, distance between two points (x1, y1) and (x2, y2) is\(\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\).

So, distance between (1, 3) and (5, 6) is \(\sqrt{(1-5)^2+(3-6)^2}=\sqrt{(4)^2+(3)^2}\) = 5 units.

29.

If slope of a line is 4 and x-intercept made by the line is 2 then the equation of line will be __________(a) y = 4x-8(b) y = 4x+8(c) y = 2x+4(d) y = 2x-4This question was posed to me in class test.My doubt stems from General Equation of a Line topic in chapter Straight Lines of Mathematics – Class 11

Answer»

The correct option is (a) y = 4x-8

The BEST EXPLANATION: Let general equation of line be y=m*x + c.

Given m=4 and VALUE of x when y=0 is 2.

C= – m*2 = -4*2 = -8.

=>y=4x-8.

30.

If equation of a line is y=3x-4 then find the slope of line.(a) 3(b) -3(c) 4(d) -4I got this question in final exam.I'd like to ask this question from Distance of a Point from a Line topic in chapter Straight Lines of Mathematics – Class 11

Answer»

Right choice is (a) 3

To explain I would SAY: Comparing the above EQUATION with general equation y=m*X + C,

m=3 which is the slope of line.

31.

Find the equation perpendicular to 2x – y=4 and pass through (2, 4).(a) 2x+y-10 = 0(b) x+2y+10 = 0(c) x+2y-10 = 0(d) x+y-10 = 0I got this question in quiz.Question is taken from Distance of a Point from a Line in section Straight Lines of Mathematics – Class 11

Answer»

The correct option is (c) X+2y-10 = 0

To explain: LINE 2x – y=4 has SLOPE 2. Line PERPENDICULAR to given line has slope -1/2.

Equation is (y-4) = (-1/2) (x-2)

2y-8 = -x + 2 => x+2y -10 = 0.

32.

If line joining (1, 2) and (5, 7) is parallel to line joining (3, 4) and (11, x).(a) 10(b) 11(c) 12(d) 14This question was addressed to me in an online quiz.This intriguing question comes from Various Forms of the Equation of a Line topic in section Straight Lines of Mathematics – Class 11

Answer»

Right OPTION is (d) 14

The explanation is: We know, slope of line JOINING two POINTS (x1, y1) and (x2, y2) is given by(y2-y1)/(x2-x1).

Lines are parallel means slope is equal.

=>(x-4)/(11-3) = (7-2)/(5-1) => x-4 = 5*8/4 = 10 => x=14.

33.

What is the inclination of a line which is parallel to y-axis?(a) 0°(b) 180°(c) 45°(d) 90°This question was addressed to me at a job interview.This intriguing question comes from Slope of a Line in division Straight Lines of Mathematics – Class 11

Answer»

Right CHOICE is (d) 90°

Explanation: If a LINE is parallel to y-axis then ANGLE FORMED by it with x-axis is 90°. So, its inclination is 90°.

34.

If equation of line is x + y=2 then find the angle made by line with x-axis.(a) 45°(b) 60°(c) 30°(d) 75°I had been asked this question during an online exam.Asked question is from Distance of a Point from a Line in division Straight Lines of Mathematics – Class 11

Answer» RIGHT answer is (a) 45°

The best explanation: Given equation is X + y=2. REDUCING the above equation to normal FORM

(x + y)/√2 =√2.

x cos⁡45° + y SIN 45° = √2

Angle made with x-axis is 45°.
35.

If -40°F is equal to -40°C and 0°C is equal to 32°F then find the value of 40°C.(a) 104°F(b) 112°F(c) 86°F(d) 92°FThis question was posed to me in a job interview.Question is from General Equation of a Line topic in chapter Straight Lines of Mathematics – Class 11

Answer»

The CORRECT answer is (a) 104°F

The explanation is: LET GENERAL equation be F=m*C +k

-40 = -40m + k

and 32 = 0 + k

=>-40 = -40m + 32 => m=72/40 = 18/10

F=18/10 * 40 + 32 = 72+32 = 104.

36.

Find slope of line joining (1, 2) and (4, 11).(a) 1/3(b) 3(c) 9(d) 1/9The question was asked in a national level competition.I'm obligated to ask this question of Various Forms of the Equation of a Line in portion Straight Lines of Mathematics – Class 11

Answer»

The correct choice is (b) 3

The explanation: We know, SLOPE of line joining two points (x1, Y1) and (X2, y2) is GIVEN by \(\frac{y_2-y_1}{x_2-x_1}\).

So, slope of line joining (1, 2) and (4, 11) is \(\frac{11-2}{4-1} = \frac{9}{3}\) = 3.

37.

If slope of a line is 4 and y-intercept made by the line is 2 then the equation of line will be __________(a) y=4x-2(b) y=4x+2(c) y=2x+4(d) y=2x-4This question was addressed to me in my homework.Query is from General Equation of a Line topic in chapter Straight Lines of Mathematics – Class 11

Answer» RIGHT answer is (b) y=4x+2

To EXPLAIN: LET general equation of LINE be y=m*x + c.

Given, m=4 and c=2.

=>y=4x+2
38.

If a line has slope 3 and pass through point (1, 2) then the equation of line is _________(a) x=3y-1(b) x=3y+1(c) y=3x+1(d) y=3x-1I had been asked this question during an interview for a job.This question is from General Equation of a Line in section Straight Lines of Mathematics – Class 11

Answer»

Right option is (d) y=3x-1

To EXPLAIN I would say: LET general EQUATION of line be y=m*x + c.

Given m=3 => y=3x+c

Substituting the point (1, 2) in above equation we get 2=3*1 + c => c = -1

So, equation of line will be y = 3x-1.

39.

Equation of vertical line to the right of y-axis at 5 units from y-axis is _______(a) x=5(b) x=-5(c) y=5(d) y=-5I had been asked this question by my school teacher while I was bunking the class.Query is from General Equation of a Line topic in division Straight Lines of Mathematics – Class 11

Answer»

Right choice is (a) x=5

Easiest EXPLANATION: EQUATION of y-axis is x=0. Vertical line is PARALLEL to y-axis and to the right by 5 UNITS so, equation of line is x=5.

40.

If line joining (1, 2) and (7, 6) is perpendicular to line joining (3, 4) and (11, x).(a) 12(b) 16(c) -16(d) -12I have been asked this question in an online interview.My doubt stems from Various Forms of the Equation of a Line topic in portion Straight Lines of Mathematics – Class 11

Answer»

Right option is (c) -16

Easy EXPLANATION: We know, slope of line JOINING two points (x1, y1) and (x2, y2) is given by(y2-y1)/(x2-x1).

Lines are perpendicular means m1*m2 = -1

=> \((\FRAC{X-4}{11-3})(\frac{6-2}{7-1})\) = -1

=> (x-4)(4) = (-1)(8)(6)

=> x-4 = -12 => x= -16.

41.

If x-intercept of a line is 4 and its y-intercept is 2 then find the equation of line.(a) 2x+y-4=0(b) x+2y-4=0(c) 2x+y+4=0(d) x+2y+4=0This question was posed to me in a national level competition.The query is from General Equation of a Line in division Straight Lines of Mathematics – Class 11

Answer»

Correct answer is (B) x+2y-4=0

For explanation I WOULD say: If x-intercept of a line is a and y-intercept of line is b so, equation of line is \(\FRAC{x}{a} + \frac{y}{b}\) = 1.

Equation of line is \(\frac{x}{4} + \frac{y}{2}\) = 1 => x+2y-4=0.

42.

If slope of one line is 1/4 and other is 5/3 then find the angle between two lines.(a) 30°(b) 45°(c) 90°(d) 180°The question was asked in unit test.My question is based upon Various Forms of the Equation of a Line in section Straight Lines of Mathematics – Class 11

Answer» RIGHT ANSWER is (b) 45°

For explanation: If angle between two lines with slopes m1 and M2 is α then TAN α = |(m1-m2)/(1+m1*m2)|

tan α = \(|\FRAC{5/3-1/4}{1+5/3*1/4}| = |\frac{20-3}{12+5}|\) = 17/17 =1 => α = 45°
43.

If slope of a line is 2/3 then find the slope of line perpendicular to it.(a) -3/2(b) 3/2(c) 2/3(d) -2/3I got this question in semester exam.My question is based upon Various Forms of the Equation of a Line in division Straight Lines of Mathematics – Class 11

Answer»

The correct answer is (a) -3/2

Best explanation: If LINES with slopes m1 and M2 are PERPENDICULAR then m1 * m2 = – 1.

If m1 = 2/3 then m2 = -1 / (2/3) = -3/2.

44.

If the two lines are perpendicular then difference of their inclination angle is ________(a) 45°(b) 60°(c) 90°(d) 180°The question was posed to me in unit test.This key question is from Various Forms of the Equation of a Line in chapter Straight Lines of Mathematics – Class 11

Answer»

Right ANSWER is (C) 90°

Explanation: If the two LINES are perpendicular then if one line form ANGLE α with positive x-axis then the other line form angle 90°+ α.

45.

_____________ is the midpoint of (1, 2) and (5, 8).(a) (2, 5)(b) (3, 5)(c) (5, 2)(d) (5, 3)I got this question by my school teacher while I was bunking the class.Query is from Slope of a Line topic in chapter Straight Lines of Mathematics – Class 11

Answer»

The CORRECT answer is (b) (3, 5)

For EXPLANATION I would say: We know, midpoint of (x1, y1) and (x2, y2) is \((\FRAC{x1+x2}{ 2}, \frac{y1+y2}{2})\).

So, midpoint of (1, 2) and (5, 8) is ((1+5)/2, (2+8)/2) is (3, 5).

46.

Find the equation of line parallel to 4x+y=2 and pass through (2, 5).(a) 4x+y-13=0(b) 4x+y+13=0(c) 4x-y-13=0(d) 4x-y+13=0I got this question during an interview.I'd like to ask this question from Distance of a Point from a Line in division Straight Lines of Mathematics – Class 11

Answer»

The correct CHOICE is (a) 4x+y-13=0

For EXPLANATION I would say: Line 4x+y=2 has SLOPE -4. Line parallel to it has slope -4 and pass through (2, 5) so equation will be y-5 = (-4) (x-2) => 4x+y-13=0

47.

If P (1, 2), Q (3, 5), R (7, 9) form a triangle then find the equation of median through P.(a) 5x-4y+3 = 0(b) 5x+4y+3 = 0(c) 5x-4y-3 = 0(d) 5x+4y-3 = 0The question was posed to me by my college director while I was bunking the class.I would like to ask this question from General Equation of a Line in division Straight Lines of Mathematics – Class 11

Answer»

Correct option is (a) 5x-4y+3 = 0

The best I can explain: MIDPOINT of QR line is \((\frac{3+7}{2}, \frac{5+9}{2})\) = (5, 7).

Equation of line joining (1, 2) and (5, 7) is \(\frac{y-2}{7-2} = \frac{x-1}{5-1}\)

=>\(\frac{y-2}{5} = \frac{x-1}{4}\) => 4y-8 = 5x-5 => 5x-4y+3 =0.

48.

If slope of a line is negative then its inclination is ___________(a) right angle(b) acute angle(c) obtuse angle(d) zeroThis question was addressed to me in an interview for internship.The query is from Various Forms of the Equation of a Line in chapter Straight Lines of Mathematics – Class 11

Answer»

Correct choice is (C) obtuse angle

To ELABORATE: If inclination is α SLOPE is given by TAN α. Given that slope of line is negative which MEANS tan α is negative. We know, tan α is negative in 2^nd quadrant i.e. α should be obtuse angle.

49.

If slope of a line is positive then its inclination is ___________(a) right angle(b) acute angle(c) obtuse angle(d) zeroI have been asked this question in a job interview.I need to ask this question from Various Forms of the Equation of a Line topic in section Straight Lines of Mathematics – Class 11

Answer» CORRECT answer is (b) acute angle

Explanation: If INCLINATION is α SLOPE is GIVEN by tan α. Given that slope of line is positive which means tan α is positive. We know, tan α is positive in 1^st quadrant i.e. α should be acute angle.
50.

If two lines are parallel their inclination angle may be different.(a) True(b) FalseI got this question during a job interview.Enquiry is from Various Forms of the Equation of a Line in chapter Straight Lines of Mathematics – Class 11

Answer»

Correct CHOICE is (b) False

Best explanation: If two LINES are parallel then they form same ANGLE with POSITIVE direction of x-axis in anticlockwise direction i.e. their inclinations are equal.