InterviewSolution
Saved Bookmarks
InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
Halogen atoms haveA. High ionisation energy, high electron affinity and low electronegativityB. High Ionisation energy, high electronegativity and high electron affinityC. High Ionisation energy, low electron affinity and high electronegativityD. Low Ionisation energy, high electron affinity and high electronegativity. |
| Answer» Correct Answer - B | |
| 152. |
The highest oxidation state is shown by chlorine in which of the following oxide ?A. `ClO_2`B. `ClO_3`C. `Cl_2O_5`D. `Cl_2O_7` |
| Answer» Correct Answer - D | |
| 153. |
The common positive oxidation states exhibited by the halogens areA. +2, +4, +6B. -1, +1, +3, +5C. +1, +2, +3D. +1 to +7. |
| Answer» Correct Answer - B | |
| 154. |
The halogens which show positive oxidation states areA. FB. ClC. BrD. I |
|
Answer» Correct Answer - B,C,D Fluorine shows only -1 oxidation state, because it is the most electronegative element and there is no d-subshell in the valence shell of F. |
|
| 155. |
Halogens combine among themselves to form covalent compounds which are calledA. PseudohalidesB. Interhalogen compoundsC. PolyhalidesD. None of these |
| Answer» Correct Answer - B | |
| 156. |
Assertion (A): The halogens absorb visible light. Reason (R ): All halogens are coloured.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. A is false but R is true |
|
Answer» Correct Answer - A Both assertion and reason are true and R is the correct explanation of A. |
|
| 157. |
Which of the following halogens has metallic character ?A. `F_2`B. `Cl_2`C. `I_2`D. `Br_2` |
|
Answer» Correct Answer - D Electropositive or metallic character of elements increases down the group. Thus, out of `F_2, Cl_2 ,Br_2 and I_2, I_2` is most metallic. |
|
| 158. |
Bleaching powder is obtained by the action of chlorine gas andA. Dilute solution of `Ca(OH)_2`B. Concentrated solution of `Ca(OH)_2`C. Dry CaOD. Dry slaked lime |
|
Answer» Correct Answer - D `underset("Dry slaked lime")(Ca(OH)_2) + Cl_2 to underset(" Bleaching Powder")(CaOCl_2) + H_2O` |
|
| 159. |
the bleaching action of chlorine is due toA. ReductionB. HydrogenationC. ChlorinationD. Oxidation. |
|
Answer» Correct Answer - D Bleaching action of `Cl_2` is due to oxidation `Cl_2+H_2O to 2HCl +[O]` Colour +[O]` to`Oxidised colour (colourless) |
|
| 160. |
Chlorine acts as a bleaching agent only in the presence ofA. Dry airB. MoistureC. SunlightD. Pure oxygen. |
|
Answer» Correct Answer - B `Cl_2` can act as a bleaching agent only in the presence of moisture `Cl_2 + H_2O to 2HCl + O` Colour +O `to` Oxidised product (Colourless) |
|
| 161. |
The correct order of increasing oxidising powerA. `F_2 lt Cl_2 lt Br_2 lt I_2`B. `F_2 lt Br_2 lt Cl_2 lt I_2`C. `Cl_2 lt Br_2 lt F_2 lt I_2`D. `I_2 lt Br_2 lt Cl_2 lt F_2` |
|
Answer» Correct Answer - D Fluorine in the strongest oxidising agent due to its highest reduction potential value (+2.87V). |
|
| 162. |
The difference between the value of `DeltaH` (hydration) of `X^-` ion is maximum for which of the following pairs of ions?A. `Cl^(-), Br^(-)`B. `Br^(-), I^(-)`C. `I^(-), Cl^-`D. `F^(-), Cl^(-)` |
|
Answer» Correct Answer - D Due to very large value of `DeltaH_(hyd.)` of `F^-`, the difference between the values of `F^-` and `Cl^-` ion is the highest |
|
| 163. |
Which of the following pairs is not correctly matched ?A. A halogen which is liquid at room temperature-BromineB. The most electronegative element-FluorineC. The most reactive halogen-FluorineD. The strongest oxidising halogen-Iodine |
|
Answer» Correct Answer - D The strongest oxidising halogen is fluorine and not iodine |
|
| 164. |
Here each question contains statements given in two columns which have to be matched. Statements in Column I are labelled as A, B, C and D whereas the statements in Column II are labelled as p, q, r and s. The answers to these questions are to be appropriately bubbled as illustrated below in the following example. If the correct matches are A-p, A-s, B-q, B-r, C-p, C-q and D-p, their correctly labelled `4 xx 4` matrix should look like : |
| Answer» `F_2` is a gas and shows variable oxidation state. `Br_2` is a liquid at room temperature and `I_2` is a solid at room temperature. Both these halogens show variable oxidation states. | |
| 165. |
Which of the following statements is incorrect?A. ICl is a good conductor of electricity in fused stateB. `Cl_2O_7` is an anhydride of perchloric acidC. Melting point and boiling point of HB less than HClD. `F_2` does not form oxyacids. |
|
Answer» Correct Answer - C Melting point and boiling point of HBr are greater than HCl |
|
| 166. |
Identify the incorrect statement amongst the followingA. `Br_2` reacts with hot NaOH solution to give NaBr, `NaBrO_3` and waterB. Ozone reacts with `SO_2` to form `SO_3`C. Silicon reacts with aq NaOH in the presence of air to give `Na_2SiO_3 and H_2O `D. `Cl_2` reacts with excess of `NH_3` to give `N_2` and HCl |
|
Answer» Correct Answer - D `Cl_2` reacts with excess of ammonia to form `N_2 + NH_4 Cl` ` 8NH_3 +3Cl_2 to N_2 +6NH_4 Cl` |
|
| 167. |
In which of the following compounds the halogen is `sp^3d` hybridised ?A. `CIF_5`B. `IC l_3`C. `CIO_3^(-)`D. IC l |
|
Answer» Correct Answer - B `IC l_3` has `sp^3d` hybridised halogen. `ClF_5` has `sp^3d^2` hybridised halogen. `ClO_3^(-)` has `sp^3` hybridised halogen. |
|
| 168. |
The stability of interhalogen compounds follows the orderA. `IF_3 gt BrF_3 gt CIF_3`B. `BrF_3 gt IF_3 gt CIF_3`C. `CIF_3gt BrF_3 gt IF_3`D. `CIF_3gt IF_3gt BrF_3` |
|
Answer» Correct Answer - A The stability of interhalogens increases as the size of difference and polarity of bond increases. Thus the correct order of stability is `IF_3 gt BrF_3 gt CIF_3` |
|
| 169. |
Which of the following is not the characteristic of interhalogen compounds?A. They are more reactive than halogensB. They are quite unstable but none of them is explosiveC. They are covalent in natureD. They have low boiling points and are highly volatile. |
|
Answer» Correct Answer - D Interhalogen compounds are mostly liquid or solid at room temperature and are not highly volatile. |
|
| 170. |
Which of the following interhalogen compounds does not exist ?A. `IC l`B. `IC l_2`C. `IC l_3`D. `IF_5` |
|
Answer» Correct Answer - B Interhalogen compound of type `AB_2` does not exist. Interhalogen compounds are of AB, `AB_3` , `AB_5` and `AB_7` types |
|
| 171. |
Ammonia , on reaction with hypochlorite anion, can formA. NOB. `NH_2Cl`C. `NH_4`D. `HNO_2` |
|
Answer» Correct Answer - B,C `NH_3 + NaOCl to + underset("Chloramine")(NH_4Cl) + NaOH` `NH_2Cl + NH_3 + OH^(-) overset("Gum or gelatin")to H_2N-NH_2 + Cl^(-) + H_2O` |
|
| 172. |
Total sum of oxidation states of Cl in the compounds obtained in disproportionation of sodium hypochlorite is ….. |
|
Answer» Correct Answer - 4 `underset("Sodium hypochloride")(3NaOCl)tooverset(-1)(3NaCl)+overset(+5)(NaClO_3)` `therefore` of oxidation state in NaCl and `NaClO_3` = - 1 +5 =+4 |
|
| 173. |
Highest oxidation state shown by Cl in its compounds is … |
|
Answer» Correct Answer - 7 Chlorine exhibits highest oxidation of +7. |
|
| 174. |
Fluorine oxidizes `HSO_4^(-)` to ……A. `S_2O_3^(2-)`B. `S_2O_8^(2-)`C. `S_4O_6^(2-)`D. `SO_2` |
|
Answer» Correct Answer - B `F_2` oxidises warm solution of potassium hydrogen sulphate to peroxydisulfate. `2HSO_4^(-) +F_2 to S_2O_8^(2-) + 2HF` `F_2` also oxidises chlorates to perchlorates and `Cr^(3+)` salts to dichromates |
|
| 175. |
In which of the following, hydrogen bond is the strongest ?A. F-H..OB. F-H...NC. F-H.....FD. All are equally strong. |
|
Answer» Correct Answer - C F being most electronegative and smallest forms the strongest H-bond. Thus H-bonding is strongest in F-H......F. |
|
| 176. |
Increasing order of ionic size : `N^(3-),Na^(+),F^(-),O^(2-),Mg^(2+)`A. `Mg^(2+ )lt Na^(+) ltF^(-) lt O^(2-) lt N^(3-)`B. `Na^(+) lt Mg^(2+) lt F^(-) lt O^(2-) lt N^(3-)`C. `N^(3-) lt O^(2-) ltF^(-) lt Na^(+) lt Mg^(2+)`D. `F^(-)ltN^(3-) lt O^(2-) lt Mg^(2+) lt Na^(+)` |
|
Answer» Correct Answer - A `N^(3+), Na^(+), F^(-) , O^(2-) and Mg^(2+)` are all isoelectronic ions. In such ions more the nuclear charge (or atomic number) smaller is the ion. Thus, the correct order of ionic radii of `N^(3-)` (Z= 7 ), `Na^+` (Z=11), `F^-` (Z = 19), `O^(2-)` (Z =8) and `Mg^(2+)` (Z= 12) is `Mg^(2+) lt Na^(+) lt F^(-) lt O^(2-) lt N^(3-)` |
|
| 177. |
Among the fluorides given below which will further react with `F_2`A. NaFB. `CaF_2`C. `IF_5`D. `SF_6` |
|
Answer» Correct Answer - C `IF_5 + F_2 to IF_7` |
|
| 178. |
Among the fluorides given below which will further react with `F_2`A. `CaF_2`B. `IF_5`C. `SF_6`D. NaF |
|
Answer» Correct Answer - B `IF_5 + F_2toIF_7` |
|
| 179. |
`F_2` on reaction with `H_2O` producesA. HFB. `O_2`C. `O_3`D. None of these. |
|
Answer» Correct Answer - A,B,C `2F_2 +2H_2O to 4HF +O_2` `3F_2 +3H_2O to 6HF +O_3` |
|
| 180. |
Arrange the following in the decreasing order of their acidic strength HClO, HBrO, HIOA. HBrO gt HClO gt HIOB. HClO gt HBrO gt HIOC. HIO gt HBrO gt HClOD. HClO gt HIO gt HBrO. |
|
Answer» Correct Answer - B HClO gt HBrO gt HIO on the basis of electronegativity of halogen. |
|
| 181. |
When chlorine is passed over dry slaked lime at room tempreture, the main reaction product isA. `Ca(ClO_2)_2`B. `CaCl_2`C. `CaOCl_2`D. `Ca(OCl)_2 ` |
|
Answer» Correct Answer - C `Cl_2(g)+underset("Slaked lime")(Ca(OH)_2)(s) to underset("Bleaching powder")(CaOCl_2(s))+H_2O(g)` |
|
| 182. |
HBr and HI can reduce sulphurie acid, HCI can reduced `KMnO_(4)` and HF can reduce…………….A. `H_2SO_4`B. `KMnO_4`C. `K_2Cr_2O_7`D. None of the above |
|
Answer» Correct Answer - D Conc. `H_2SO_4` can oxidise HBr (or HI) to `Br_2` (or `I_2`). `KMnO_4//H^(+)` can oxidise HCl to `Cl_2`. However chemical oxidation of HF to `F_2` is not possible. This is because, fluorine has the highest reduction potential. |
|
| 183. |
Assertion :HBr is a stronger acid than HI. Reason :HBr is more polar than HI.A. Both A and R true and R is the correct explanation of AB. Both A and R true and R is not a correct explanation of AC. A is true but R is falseD. Both A and R is false |
|
Answer» Correct Answer - D HI is a stronger acid than HBr. It is due to low bond energy of H-I bond. |
|
| 184. |
Which is the weakest out of HF, HCl, HBr and HI?A. HFB. HClC. HBrD. HI |
|
Answer» Correct Answer - A Acidic strength of hydrogen halides is in the order `HF lt HCl lt HBr lt HI` |
|
| 185. |
`HI` can be prepared by all the following methods exceptA. `PI_3 +H_2O`B. `KI + H_2SO_4`C. `H_2 + I_2 overset(Pt)to`D. `I_2 + H_2S` |
|
Answer» Correct Answer - B `H_2 + I_2 overset(Pt)to2HI` `I_2 + H_2S to 2HI +S` `PI_3 + 3H_2O to H_3PO_3 + 3HI` HI cannot be prepared from KI and `H_2SO_4` because conc. `H_2SO_4` oxidises the HI produce to `I_2`. `({:(KI+H_2SO_4 to, KHSO_4 +HI"]"xx2),(H_2SO_4 to, H_2O +SO_2 +O),(2HI+O to,H_2O + I_2):})/ul(2KI +3H_2SO_4 to 2KHSO_4 +2H_2O +SO_2 +I_2)` |
|
| 186. |
Chlorine gas is dried overA. CaOB. NaOHC. KOHD. Conc. `H_2SO_4` |
|
Answer» Correct Answer - D `Cl_2` gas is dried by passing it through conc `H_2SO_4`. All others will react with `Cl_2`. |
|
| 187. |
HI cannot be prepared by the action of conc. `H_(2)SO_(4)` on KI becauseA. HI is stronger than `H_2SO_4`B. HI is more volatile than `H_2SO_4`C. `H_2SO_4` also oxidises HI so formed, to `I_2`D. `H_2SO_4` forms complex with HI |
|
Answer» Correct Answer - C `2HI + H_2SO_4 to 2H_2O+ I_2+SO_2` |
|
| 188. |
Which of the following gases can be dried by conc. `H_2SO_4` ?A. HClB. HBrC. HID. `H_2S` |
|
Answer» Correct Answer - A HCl is dried over conc. `H_2SO_4`. Because HBr, HI and `H_2S` are oxidised by `H_2SO_4` |
|
| 189. |
Which of the halogen exists as liquid at ordinary temperature ?A. `F_2`B. `Cl_2`C. `I_2`D. `Br_2` |
|
Answer» Correct Answer - D `F_2` and `Cl_2` are gases. `Br_2` is liquid while `I_2` is solid at ordinary temperature. |
|
| 190. |
Which halogen acid exists in dimeric form even in the gaseous state ?A. Hydrogen chlorideB. Hydrogen fluorideC. Hydrogen bromideD. Hydrogen iodide |
|
Answer» Correct Answer - B HF remains associated to form dimers (H F.....H-F) even in gaseous state. In solid and liquid states the extent of association is much more. |
|
| 191. |
The element belonging to Group 17 which sublimes isA. FluorineB. ChlorineC. IodineD. Bromine |
|
Answer» Correct Answer - C Iodine undergoes sublimation i.e., directly changes into gaseous state without melting |
|
| 192. |
The elements which exists in the liquid state is/ areA. BromineB. MercuryC. GalliumD. All |
|
Answer» Correct Answer - D Bromine and mercury are liquids at room temperature (`25^@C` or 298 K) while gallium has a melting point of only `30^@C` or 303 K (gallium easily melts on the palm of your hand as normal human temperature `~~37^@C`) |
|
| 193. |
Which of the elements of group 17 is radioactive ?A. ChlorineB. BromineC. IodineD. Astatine |
|
Answer» Correct Answer - D Astatine (At) is radioactive. |
|
| 194. |
Fluorine differs from rest of the halogens due toA. Its high electronegativityB. Smallest size and lack of d-orbitalsC. Low bond dissociation energyD. All the above A, B and C. |
|
Answer» Correct Answer - C Due to these reasons fluorine shows anomalous behaviour and differs from rest of the halogens in many properties |
|
| 195. |
Among the halogens, fluorine differs considerably form the other members. The hydrides of halogens also differ in their properties. Which of the following halogens do not form polyhalide ?A. FluorineB. ChlorineC. BromineD. Iodine. |
|
Answer» Correct Answer - A Fluorine does not form polyhalide ion. |
|
| 196. |
1.0 M solution of which of the following salts is most basic ?A. NaClOB. `NaClO_4`C. `NaClO_2`D. `NaClO_3` |
|
Answer» Correct Answer - A Acidic strength of oxy-acids of chlorine is in order `HClO lt HClO_2 lt HClO_3 lt HClO_4` Therefore, salts of these acids with a strong base (say NaOH), will be most basic, when the acid involved is weak. Thus NaClO will be most basic. |
|
| 197. |
Which one of the following elements shou different oxidation states?A. SodiumB. FluorineC. ChlorineD. Potassium |
|
Answer» Correct Answer - C Chlorine easily show a number of oxidation states (-1, 0, +1. +3, +5 and + 7). |
|
| 198. |
Dilute solution of HF cannot be concentrated beyond 36% by distilling only because :A. HF is non volatileB. HF forms a constant boiling mixtureC. HF is least acidicD. It is bad conductor. |
|
Answer» Correct Answer - B HF forms a constant boiling mixture having 36% acid and boiling point of `120^@` |
|
| 199. |
At room temperature, HCl is a gas while HF is low boiling liquid. This is becauseA. H-F bond is covalentB. H-F bond is ionicC. HF has metallic bondD. HF has hydrogen bond |
|
Answer» Correct Answer - D H-F is a liquid at room temperature while HCl is a gas. This is due to extensive H-bonding in H-F which increases its b.p. |
|
| 200. |
which of the following halogen is solid at room tempreture?A. ChlorineB. BromineC. FluorineD. Iodine. |
|
Answer» Correct Answer - D Iodine is solid at room temperature. Fluorine and chlorine are gases at room temperature Bromine is a liquid at room temperature. |
|