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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
An amorphous solid (X) burns in air to form a gas ( Y) which turns lime water milky. This gas decolourises aqueous solution of acidified `KMnO_(4).` Gas (Y) reacts with oxygen to give another gas (Z) which is responsible for acid rain. X, Y and Z areA. `{:("X","Y","Z"),(C, CO,CO_(2)):}`B. `{:("X","Y","Z"),(S, SO_(2),SO_(3)):}`C. `{:("X","Y","Z"),(P, P_(2)O_(3),P_(2)O_(5)):}`D. `{:("X","Y","Z"),(S, SO_(3),H_(2)SO_(4)):}` |
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Answer» Correct Answer - B `underset((X))S+O_(2)rarrunderset((Y))(SO_(2))` `underset((Y))(SO_(2))+Ca(OH)_(2)rarrunderset("white ppt.")(CaSO_(3))darr+H_(2)O` `underset("Puple")(2KMnO_(4))+underset((Y))(5SO_(2))+2H_(2)OrarrK_(2)SO_(4)+underset("Colourless")(2MnSO_(4))+2H_(2)SO_(4)` `underset((Y))(2SO_(2))+O_(2)rarrunderset((Z))(2SO_(3))` `underset((Z))(SO_(3))+H_(2)OrarrH_(2)SO_(4)` (responsible for acid rain) |
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| 2. |
vii. The stability of dihalides of ` Si, Ge , Sn` and Pb increases steadily in the sequence :A. `PbX_(2) lt lt SnX_(2) lt lt GeX_(2) lt lt SiX_(2)`B. `GeX_(2) lt lt SiX_(2) lt lt SnX_(2) lt lt PbX_(2)`C. `SiX_(2) lt lt GeX_(2) lt lt PbX_(2) lt lt SnX_(2)`D. `SiX_(2) lt lt GeX_(2) lt lt SnX_(2) lt lt PbX_(2)` |
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Answer» Correct Answer - D Due to the inert pair effect (the reluctance of `ns^(2)` electrons of outermost shell to participate in bonding) the stability of `M^(3+)` ions (of group 14 elements ) increases as we down the group. |
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| 3. |
`NO_(2)`,a red -brown poisonous gas is prepared in the laboratory by heatingA. `NaNO_(3)`B. `NH_(4)NO_(3)`C. `Pb(NO_(3))_(2)`D. `KNO_(3)` |
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Answer» Correct Answer - 3 Nitrogen dioxde is prepared in the laboratory either by heating nitrates of heavy metals `2Pb(NO_(3))_(2)overset(Delta)rarr2PbO+4NO_(2)+O2` `Cu(NO_(3))_(2)(s)overset(Delta)rarrCuO(s)+2NO_(2)(g)+(1)/(2)O_(2)(g)` or by action of concentrated nitric acid on metals like copper, silve, lead etc `Cu+4NHO_(3)rarrCu(NO_(3))_(2)+2NO_(2)+2H_(2)O` In the previous case the mixture of nitrogen dioxide and oxygen is passed through a U- table cooled by freezing mixture. `NO_(2)` condenses to a pale yellow liquid while oxygen escapes. `NO_(2)` is produced on a large scale by oxidizing `NO` in the Ostwald process for the manufacture of nitric acid. `NH_(4)NO_(3) overset(Delta)rarr N_(2)O+2H_(2)O` `MNO_(3)rarrMNO_(2)+O_(2)` `(M=Na, K" etc")` `LiNO_(3)rarr Li_(2)O+NO_(2)+O_(2)` |
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| 4. |
Why has it been difficult to study the chemistry of radon?A. it is radioactive with short half lifeB. it is chemically inertC. its compound is not isolatedD. it has low boiling point |
| Answer» Correct Answer - A | |
| 5. |
`SF_(6)` is not easily hydrolysed whereas `SF_(4)` can be. Assign reason. |
| Answer» In `SF_(4)`, the sulphur atom has `+4` oxidation state and can extend the same to `+6` by accepting electron pairs from `H_(2)O` molecules. Therefore, it can be hydrolysed. But in `SF_(6)`, the oxidation state of sulphur is already `+6` and cannot increase the same any more. Therefore, it cannot be easily hydrolysed. For chemical reaction, consult section 15 (Chemical properties of oxygen family). | |
| 6. |
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power. A. `ClO_(4)^(-)gt IO_(4)^(-) gt BrO_(4)^(-)`B. `IO_(4)^(-) gt BrO_(4)^(-) gt ClO_(4)^(-)`C. `BrO_(4)^(-) gt IO_(4)^(-) gt ClO_(4)^(-)`D. `BrO_(4)^(-) gt ClO_(4)^(-) gt IO_(4)^(-)` |
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Answer» Correct Answer - C Higher the reduction potential value, greater is the tendency to undergo reduction and stronger is the oxidising power. `underset(E^(@)//V" "1.74)(BrO_(4)^(-))gtunderset(1.65)(IO_(4)^(-))gtunderset(1.19)(ClO_(4)^(-))` |
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| 7. |
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power. Ion `" " CiO_(4)^(-) " " IO_(4)^(-) " " BrO_(4)^(-)` Reduction `" " E^(Theta)=1.19 V " " E^(Theta)=1.65 V " " E^(Theta)=1.74` potential `E^(Theta)//V`A. `ClO_(4)^(-) gt IO_(4)^(-) gt BrO_(4)^(-)`B. `IO_(4)^(-) gt BrO_(4)^(-) gt ClO_(4)^(-)`C. `BrO_(4)^(-) gt IO_(4)^(-) gt ClO_(4)^(-)`D. `BrO_(4)^(-) gt ClO_(4)^(-)IO_(4)^(-)` |
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Answer» Correct Answer - C It is the correct decreasing order of oxidising power. |
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| 8. |
`SO_(2)+NaClO_(3) overset(H^(+))to` |
| Answer» `SO_(2)+2NaClO_(3) overset(H^(+))to underset("Chlorine dioxide")(2ClO_(2))+Na_(2)SO_(4)` | |
| 9. |
Aluminium exhibits +3 oxidation state. As we move down the group, +1 oxidation state gets more stable. This is a consequence ofA. increaseing size of the atomB. inert pair effectC. electron deficient natureD. `p pi - p pi` bonding |
| Answer» Correct Answer - B | |
| 10. |
Which of the following Lewis acids exhibits maximum acidic strength?A. `BI_(3)`B. `BBr_(3)`C. `BCl_(3)`D. `BF_(3)` |
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Answer» Correct Answer - A `BI_(3)` is the most electron deficient on account of the weakest `p_(pi) - p_(pi)` back bonding. The overall order of acidic strength is `BI_(3) lt BBr_(3) lt BCl_(3) lt BF_(3)` |
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| 11. |
Which of the following oxides are amphoteric? `(i) Tl_(2)O` `(ii) Al_(2)O_(3)` `(iii) Ga_(2)O_(3)` `(iv) In_(2)O_(3)`A. `(i), (ii), (iii)`B. `(ii), (iii), (iv)`C. `(i), (ii), (iii), (iv)`D. `(ii), (iii)` |
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Answer» Correct Answer - D `Tl_(2)O` is strongly basic, `In_(2)O_(3)` is basic, while `Al_(2)O_(3)` and `Ga_(3)O_(3)` are amphoteric. They dissolve in acids as well alkalies to form the corresponding salts. |
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| 12. |
Why is `SF_(6)` kinetically inert ? |
| Answer» Since sulphur atom has all filled orbitals in `SF_(6)` molecule. | |
| 13. |
Which of the following statements are correct for `SO_(2)` gas ?A. It acts as bleaching agent in moist conditions.B. Its molecule has linear geometry.C. Its dilute solution is used as disinfectant.D. It can be prepared by the reaction of dilute `H_(2)SO_(4)` with metal sulphide. |
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Answer» Correct Answer - A::C are both correct statements `SO_(2)+2H_(2)O to H_(2)SO_(4)+2H` Bleaching action is due to reduction. Dilute solution of `SO_(2)` is used as disinfectant. |
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| 14. |
Which of the following statements are correct ?A. All the three N-O bond length in `HNO_(3)` are equal.B. All P-Cl bond lengths in `PCl_(5)` molecule in gaseous state are equal.C. `P_(4)` molecules in white phosporus have angular strain therefore white phosphorus is very reactive.D. `PCl_(5)` is ionic in solid state in which cation is tetrahedral and anion is octahedral. |
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Answer» Correct Answer - C::D are both correct answers. |
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| 15. |
`KF` combination with `HF` to form `KHF_(2)`. The compound contains the speciesA. `K^(+), F^(-) " and " H^(+)`B. `K^(+), F^(-) " and " HF`C. `K^(+) " and " [HF_(2)]^(-)`D. `[KHF]^(+) " and " F^(-)` |
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Answer» Correct Answer - C The compound exists as : `K^(+)[H-F___H]^(-)` |
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| 16. |
Aluminium chloride exists as a dimer, `Al_(2)Cl_(6)` in solid state as well as in solution of non-polar solvents such as benzene. When dissolved in water, it gives :A. `Al_(2)O_(3)+6HCl`B. `Al^(3)+3Cl^(-)`C. `[Al(H_(2)O)_(6)]^(3+)`D. `[Al(OH)_(6)]^(3-) + 3HCl` |
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Answer» Correct Answer - C When dissolved in water, aluminium chloride changes into hydrated aluminium chloride which is ionic in nature. `Al_(2)Cl_(6) + 12H_(2)O rarr 2AlCl_(3) . 6H_(2)O` or `[Al(H_(2)O)_(6)]^(3+) (Cl^(-))_(3)` |
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| 17. |
Fullerenes constitute a family of crystalline allotropes of carbon consisting of spherical or ellipsoidal molecules of composition `C_(2n)` when `n` is ` gt =` ____.A. `20`B. `30`C. `40`D. `15` |
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Answer» Correct Answer - B Fullerenes were first prepared by the evaporation of graphite using a powerful laser. The sooty material formed by the condensation of vaporized graphite consists of `C_(2n)` molecules. |
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| 18. |
What is the basicity of `H_(3)PO_(4)` ? |
| Answer» The acid is tribasic since it has three P-OH bonds which can release `H^(+)` ions. For details, consult Section 12. | |
| 19. |
What happen when `Cl_(2)` is passed through a hot concentrated solution of a base like `Ba(OH)_(2)`? |
| Answer» `6Cl_(2)+6Ba(OH)_(2) to underset("Xenon trioxide")(Ba (ClO_(3))_(2))+5BaCl_(2)+6H_(2)O` | |
| 20. |
`XeF_(4)` on partial hydrolysis produces |
| Answer» `6XeF_(4)+12H_(2)O to 4Xe +underset("Xenon trioxide")(2XeO_(3)+24HF+#O_(2))` | |
| 21. |
Give the decreasing order of dipole moments of `HF,HCI,HBr`, and `HI`. |
| Answer» This is on account of inter molecular hydrogen bonding present in the molecules of HF. They get associated and acid exists as a liquid at room tremperature. Since this is absent in the other hydra acids, they remain in the gaseous state. | |
| 22. |
`CIF_(3)` exists but `FCl_(3)` does not. Why ? |
| Answer» Chlorine has vacant 3d-orbitals and an electron can be promoted from 3p filled orbital to 3d orbital. Thus, chlorine can show a cavalency of 3 in its compunds and a molecule of `ClF_(3)` can exist. But fluroine has no vacant 2d orbitals and can exhibit only cavalency of one in its compounds. Thus, a molecule of `FCl_(3)` fails to exist. | |
| 23. |
Interhalogen compounds are more reactive than halogens. Why ? |
| Answer» Bonds in the interhalogen compounds (X-Y) are generally weaker and also more polar than the bonds in the pure halogens (X-Y). Therefore, interhalogen compounds are more reactive than halogens. | |
| 24. |
When chloride is passed over dry slaked lime at room temperature the main reaction product isA. `CaCl_(2)`B. `Ca(CIO_(2))_(3)`C. `CaOCl_(2)`D. `Ca(OCl)_(2)` |
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Answer» Correct Answer - 4 chloride reacts with dry slaked lime to form bleaching power. `2Ca(OH)_(2)+2Cl_(2)rarrunderset("Cal. Hypochloride")(Ca(OCl)_(2))+CaCl_(2)+H_(2)O` the actual composition of bleaching power is `Ca(OCl)_(2).CaCl_(2).Ca(OH)_(2).2H_(2)O` |
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| 25. |
In the clathrates of xenon with water the nature of bonding in Xe and `H_(2)O` molecule isA. covalentB. hydrogen bondingC. coordinateD. dipole-induced dipole. |
| Answer» Correct Answer - D | |
| 26. |
Discuss the general characteristics of Group 15 elements with reference to their electronic configuration, oxidation state, atomic size, ionisation enthalpy and electronegativity. |
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Answer» General trends in group 15 elements (i) Electronic configuration: All the elements in group 15 have 5 valence electrons. Their general electronic configuration is `ns^(2)` `np^(3)`. (ii) Oxidation states: All these elements have 5 valence electrons and require three more electrons to complete their octets. However, gaining electrons is very difficult as the nucleus will have to attract three more electrons. This can take place only with nitrogen as it is the smallest in size and the distance between the nucleus and the valence shell is relatively small. The remaining elements of this group show a formal oxidation state of `−3` in their covalent compounds. In addition to the `−3` state, N and P also show `−1` and `−2` oxidation states. All the elements present in this group show `+3` and `+5` oxidation states. However, the stability of `+5` oxidation state decreases down a group, whereas the stability of `+3` oxidation state increases. This happens because of the inert pair effect. (iii) Ionization energy and electronegativity First ionization decreases on moving down a group. This is because of increasing atomic sizes. As we move down a group, electronegativity decreases, owing to an increase in size. (iv) Atomic size: On moving down a group, the atomic size increases. This increase in the atomic size is attributed to an increase in the number of shells. |
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| 27. |
The general valence shell electronic configuration of `p`-block elements isA. `np^(1 - 6)`B. `ns^(2)np^(1 - 6)`C. `ns^(2)np^(6)`D. `ns^(2)np^(2)` |
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Answer» Correct Answer - B As we move across a period of `p`-block, the electrons enter one by one in the `p`-subshell of the last shell, and the maximum capacity of `p`-subshell is of six electrons. |
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| 28. |
Catenation i.e., linking of similar atoms depends on size and electronic configuration of atoms. The tendency of catenation in group 14 elements follows the order.A. C `gt` Si `gt` Ge `gt` SnB. C `gt gt` Si `gt` Ge `~~` SnC. Si `gt` C `gt` Sn `gt` GeD. Ge `gt` Sn `gt` Si `gt` C |
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Answer» Correct Answer - B The tendency to form long open or closed atom chains by combination of some atoms in themselves is known as catenation. The catenation is maximum in carbon and decreases down the group C `gt gt` Si `gt` Ge `~~` Sn `gt` Pb This is due to high bond energy of C-C bonds. Down the group, size increases and electronegativity decreases, thereby, tendency to show catenation decreases. |
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| 29. |
What is the general valence shell electronic configuration of group `14` elements?A. `ns^(2)`B. `ns^(2)np^(4)`C. `ns^(2)np^(6)`D. `ns^(2)np^(2)` |
| Answer» Correct Answer - D | |
| 30. |
The electronic configuration of four different elements is given below. Identify the group `14` elements among these.A. `[He]2s^(1)`B. `[Ne]3s^(2)`C. `[Ne]3s^(2)3p^(2)`D. `[Ne]3s^(2)3p^(5)` |
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Answer» Correct Answer - C The general valence shell electron configuration of group `14` elements if `ns^(2)np^(2)`. |
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| 31. |
Give two examples to show the anomalous behavious of fluorine. |
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Answer» Anomalous behaviour of fluorine (i) It forms only one oxoacid as compared to other halogens that form a number of oxoacids. (ii) Ionisation enthalpy, electronegativity, and electrode potential of fluorine are much higher than expected. |
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| 32. |
Acidity of diprotic acids in aqueous solutions increases in the orderA. `H_(2)S lt H_(2)Se lt H_(2)Te`B. `H_(2)Se lg H_(2)S lt H_(2)Te`C. `H_(2)Te lt H_(2)S lt H_(2)Se`D. `H_(2)Se lt H_(2)Te lt H_(2)S`. |
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Answer» Correct Answer - A It is the correct answer since bond length increases from `H_(2)S " to " H_(2)` Te and bond dissociation enthalpy decreases. |
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| 33. |
Assertion : Acidity of hydrides of group 16 elements increases down the group. Reason : Electronegativity of these elements increases down the group.A. If both assertion and reason are correct and reason is correct explanation for assertion.B. If both assertion and reason are correct but reason is not correct explanation for assertion.C. If assertion is correct but reason is incorrect.D. If both assertion and reason are incorrect. |
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Answer» Correct Answer - C Correct reason : Electronegativity of these elements decreases down the group. |
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| 34. |
For the hydrides of nitrogen family, in going down the group :A. stability decreasesB. reducing activity increasesC. bond angle HEH decreasesD. b.p increases. |
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Answer» Correct Answer - A::B::C All the three options are correct. Option (d) is not correct because `NH_(3)` is an exception. |
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| 35. |
Assertion: Helium and beryllium have similar outer electronic configuration of the type `ns^(2)`. Reason: Both are chemically inert.A. If both assertion and reason are correct and reason is correct explanation for assertion.B. If both assertion and reason are correct but reason is not correct explanation for assertion.C. If assertion is correct but reason is incorrect.D. If both assertion and reason are incorrect. |
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Answer» Correct Answer - C Correct reason : Helium is a noble gas while beryllium is a member of alkaline earth family |
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| 36. |
Assertion : All F - S - F angle in `SF_(4)` are greater than `90^(@)` but less than `180^(@)`. Reason :The lone pair -bond pair repulsion is weaker than bond pair -bond pair repulsionA. If both assertion and reason are correct and reason is correct explanation for assertion.B. If both assertion and reason are correct but reason is not correct explanation for assertion.C. If assertion is correct but reason is incorrect.D. If both assertion and reason are incorrect. |
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Answer» Correct Answer - C Correct reason. The lone pair : lone pair repulsion is stronger than bond pair : bond pair repulsion. |
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| 37. |
Assertion (A) : `EA` of `O` is less than that of `F` but greater than that of `N`. Reason (R ): `IE` is as follows: `N gt O gt F`.A. If both assertion and reason are correct and reason is correct explanation for assertion.B. If both assertion and reason are correct but reason is not correct explanation for assertion.C. If assertion is correct but reason is incorrect.D. If both assertion and reason are incorrect. |
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Answer» Correct Answer - C Correct reason : Since the atomic sizes decrease from N to F, the electron gain enthalpies of the elements tend to increase. |
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| 38. |
Assertion :Sulphuric acid is more visous than water. Reason :Concentrated Sulphuric acid has a greater effinity for water.A. If both assertion and reason are correct and reason is correct explanation for assertion.B. If both assertion and reason are correct but reason is not correct explanation for assertion.C. If assertion is correct but reason is incorrect.D. If both assertion and reason are incorrect. |
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Answer» Correct Answer - B Correct explanation : Sulphuric acid is more viscous because of the presence of greater extent of hydrogen bonding in the molecules. |
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| 39. |
The electronegaivity difference between `N` and `F` is greater than that between ` N` and `H` yet the dipole moment of `NH_2` ( 1 .5 D) is larger than that of ` NF_3 ( 0. 2 D)`. This is because :A. In `NH_(3)`, the atomic dipoles and bond dipoles are in the opposite directions while in `NF_(3)` these are in the same directionB. in `NH_(3)` and in `NF_(3)`, the atomic dipole and bond dipoles are in the same directionC. in `NH_(3)`, the atomic dipoles and bond dipole are in the same direction whereass in `NF_(3)` these are in opposite directionD. in `NH_(3)` as well as in `NF_(3)`, the atomic dipoles and bond dipoles are in opposite direction. |
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Answer» Correct Answer - C is the correct answer. For explanation, consult text part. |
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| 40. |
The compound present in greater proportion in water gas isA. `CH_(4)`B. `CO_(2)`C. `CO`D. `H_(2)` |
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Answer» Correct Answer - D Water gas is made by passing steam over white-hot coke. It contains about `45% CO` and `50% H_(2)` (by volume), with small amounts of `CO_(2)` and `N_(2)`. |
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| 41. |
Which of the following structure is smaller to graphite?A. Boron nitrideB. Boron carbideC. Aluminium oxideD. Aluminium carbide |
| Answer» Correct Answer - A | |
| 42. |
Which of the following allotropes of P has a graphite like layer structure and is an electrical conductor?A. Black `P`B. White `P`C. Red `P`D. Violet `P` |
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Answer» Correct Answer - 1 Black P has two forms `alpha`-black phosphorus and `beta`-black phosphorus. `alpha`-Black `P` is formed when red `P` is heated in a sealed tube at `803 K`. It can be sublimed in air and has opaque monoclinic or rhombohedral crystals. It does not oxidize in air. `Beta`-Black`P` is prepared by heating white `P` at `473K` under high presure .It has a layer structure and does not burm in air upto `673K`. |
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| 43. |
What is the type of graphite structure? |
| Answer» Correct Answer - Layered structure. | |
| 44. |
What happens when sulphur dioxide is passed through an aqueous solution of Fe(III) salt? |
| Answer» Fe(III) gets converted to Fe(II) | |
| 45. |
`Al_(2)O_(3)` can be converted to anhydrous `AlCl_(3)` by heatingA. `Al_(2)O_(3)`with gas `Cl_(2)` gasB. `Al_(2)O_(3)` with `HCl` gasC. `Al_(2)O_(3)` with `NaCl` in solid gasD. a mixture of `Al_(2)O_(3)` and `C` in dry `Cl_(2)` gas |
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Answer» Correct Answer - D By passing a stream of dry chlorine over a mixture of aluminium oxide and charcoal heated to about `1000^(@)C`: `Al_(2)O_(3)(s) + 3C(s) + 3Cl_(2)(g) rarr Al_(2)Cl_(6)(s) + 3CO(g)` |
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| 46. |
Which of the following reactions describes the decomposition of potassium chlorate?A. `KCIO_(3)rarrKCl+O_(2)`B. `KCIO_(3)rarrK_(2)O+Cl_(2)`C. `KCIO_(3)rarrKCIO_(4)+KCl`D. Both (1) and (3) |
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Answer» Correct Answer - 4 Chlorates decompose on heating `KCIO_(3)` may decompose in two different ways .Depending on the temperature. Heating `KCIO_(3)` to `400-500^(@)C` is well known laboratery experiment to produce dioxygen .It also gives a trace to `CI_(2)` or `CIO_(2)`. Decomposition occurs at `150^(@)C` if a catalyst such as `MnO_(2)` or powdered glass is present to provide a surface from which `O_(2)` can escape. `2KCIO_(3) overset(Delta)rarr2KCI+3O_(2)` In the absence of a cataysist ,especially at a lower temperature `KCIO_(3)` tends to disproportionate to perchlorate and chloride: `4KCIO_(3)rarr3KCIO_(4)+KCI` When `Zn(CIO_(3))_(2)` is heated it decomposes to `O_(2)` and `CI_(2)`: `2Zn(CIO_(3))_(2)rarr2ZnO+2CI_(2)+5O_(2)` |
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| 47. |
Which of the following oxides of chlorine is obtained by passing dry chlorine over silver chlorate at `90^(@)C`.A. `CIO_(2)`B. `CIO_(4)`C. `CIO_(3)`D. `Cl_(2)O` |
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Answer» Correct Answer - 1 Pure `ClO_(2)` is obtained by passing dry `Cl_(2)` over silver chlorate heated to `990^(@)C` `2AgClO_(3)+CI_(2)("dry")rarr2AgCl+2ClO_(2)+O_(2)` it can also be obtained by the action of `Cl_(2)` on sodium chlorite. `2NaClO_(2)+Cl_(2)rarr2NaCl+2ClO_(2)` |
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| 48. |
Write the balanced chemical equations for the following. (i)Hypophosphorous acid is heated. (ii) Sodium chlorate reacts with sulphur dioxide in dilute sulphuric acid medium. |
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Answer» (i) `underset("Phosphorus acid") (4H_(3)PO_(3)) overset("heat") to underset("Phosphoric acid")(3H_(3)PO_(4))+ underset("Phosphine")(PH_(3))` (ii)` Xe + PtF_(6) overset("hot") to Xe^(+) [PtF_(6)]^(-)` |
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| 49. |
Which one of the following does not exist ? `(i) XeOF_(4) (ii) NeF_(2) (iii) XeF_(2) (iv) XeF_(6)`. |
| Answer» `NeF_(2)` does not exist because the element Ne(Z=10) with `1s^(2)2s^(2)2p^(6)` does not have vacant 2d orbitals. As such there is no scope of any electron promotion even by a highly electronegative element. | |
| 50. |
Which of the follwing is the most basic oxide?A. `SeO_(2)`B. `Al_(2)O_(3)`C. `Sb_(2)O_(3)`D. `Bi_(2)O_(3)` |
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Answer» Correct Answer - 4 Nonmetals usually form acidic oxides metals usually form basic oxides and metalloids (semimetals) usually form ampoteric oxides. `SeO_(2)` is an acidic oxide as it dissolves in water to give selenious acid `(H_(2)SeO_(3))`. `Al_(2)O_(3)` and `Sb_(2)O_(3)` are amphoteric oxides `Bi_(2)O_(3)` is a basic oxide |
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