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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
Position of a body with acceleration `a` is given by `x=Ka^mt^n`, here t is time Find demension of m and n.A. `m=1, n=1`B. `m=1, n=2`C. `m=2, n=1`D. `m=2, n=2` |
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Answer» Correct Answer - B |
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| 52. |
Which physical quantities have the same dimensionA. Couple of force and workB. Force and powerC. Latent heat and specific heatD. Work and power |
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Answer» Correct Answer - A |
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| 53. |
The frequency of vibration of string is given by `v = (p)/(2 l) [(F)/(m)]^(1//2)`. Here `p` is number of segment is the string and `l` is the length. The dimension formula for `m` will beA. `[M^(0) LT^(-1)]`B. `[M L^(0) T^(-1)]`C. `[ML^(-1) T^(0)]`D. `[M^(0) L^(0) T^(0)]` |
| Answer» Correct Answer - C | |
| 54. |
The equation of a state of a real gas is given by `(P + (a)/(V^(2))) (V - b) = RT`, where `T` is absolute temperature, `P` is pressure, `V` is volume and `R` is universal gas constant. What are the dimensions of constant `a` and `b` ? |
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Answer» The terms in addition or subtraction have same `unit//dimension`. Dimension of `(a)/(V^(2))`= dimensions of `P` `(a)/([L^(6)]) = [ML^(-1) T^(-2)]` Dimensions of `a = [ML^(5) T^(-2)]` Dimensions of b = dimensions of `V` Dimension of `b = [L^(3)]` |
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| 55. |
Find the value of a and b in the following cases : (a) The velocity `v` of the ball falling freely under gravity is proportional to `g^(a) h^(b)`, where `g` is the acceleration due to gravity, `h` is the height from which the ball is dropped. (b) The kinetic energy `K` of a rotating body is proportional to `I^(a) omega^(b)` where `I` is the moment if inertia and `omega` is the angular speed. (c ) The time-period `T` of spring pendulum is proportiona to `m^(a) k^(b)`, where `m` is the mass of block attached to the spring and `k` is the spring constant. The speed of sound `v` in a gaseous medium is proportional to `P^(a) rho^(b)`, where `P` is the pressure and `rho` is the density of medium. |
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Answer» (a) `v prop g^(a) h^(b)` `[LT^(-1)] prop [LT^(-2)]^(a) [L]^(b)` `L^(1) T^(-1) prop L(a + b) T^(-2a)` Comparing powers of `L` and `T` `a + b = 1` `-2 a = - 1` `a = (1)/(2), b = (1)/(2)` `K prop I^(a) omega^(b)` `[ML^(2) T^(-2)] prop [ML^(2)]^(a) [T^(-1)]^(b)` `M^(1) L^(2) T^(-2) prop M^(a) L^(2a) T^(-b)` Comparing powers of `M` and `T` `a = 1` `-b = - 2` `a = 1, b= 2` (c ) `T prop m^(a) k^(b)` `[T] prop [M]^(a) [MT^(-2)]^(b)` `M^(0) T^(-1) prop M^(a + b) T^(-2b)` Comparing power of `M` and `T` `a + b = 0` `-2 b = 1` `a = (1)/(2), b = - (1)/(2)` (d) `v prop P^(a) rho^(b)` `[LT^(-1)] prop [ML^(-1) T^(-2)]^(a) [ML^(-3)]^(b)` `M^(0) L^(1) T^(-1) prop M^(a + b) L^(-a - 3b) T^(-2a)` Comparing powers of `M` and `T` `a + b = 0` `- 2a = - 1` `a = (1)/(2), b = - (1)/(2)` |
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| 56. |
If energy `(E )` , velocity `(V)` and time `(T)` are chosen as the fundamental quantities , the dimensions formula of surface tension will beA. `["Ev"^(-2)"T"^(-1)]`B. `["Ev"^(-1)"T"^(-2)]`C. `["Ev"^(-2)"T"^(-2)]`D. `["E"^(-2)"v"^(-1)"T"^(-3)]` |
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Answer» Correct Answer - C we know that surface tension `(S)=("Force"["F"])/("Length"["L"])` So, `" "["S"]=(["MLT"^(-2)])/(["L"])=["ML"^(0)"T"^(-2)]` Energy `(E)` = Force`xx`displacement `rArr["E"]=["ML"^(2)"T"^(-2)]` Velocity `(v)` = `("displacement")/("time")rArr["v"]["LT"^(-1)]` As, `" "SpropE^(a)v^(b)T^(c)` where, a, b, c are constants. From the principle of homogeneity, `" "["LHS"]=["RHS"]" "` `rArr["ML"^(0)"T"^(-2)]=["ML"^(2)"T"^(-2)]^(a)["LT"^(-1)]^(b)["T"]^(c)` `rArr["ML"^(0)"T"^(-2)]=["M"^(a)"L"^(2a+b)"T"^(-2a-b+c)]` Equating the power on both sides, we get a=1, 2a+b=0, b=-2 `rArr" "-2a-b+c=-2` `rArr" "c=(2a+b)-2=0-2=-2` So, `" "["S"]=["Ev"^(-2)"T"^(-2)]=["Ev"^(-2)"T"^(-2)]` |
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| 57. |
The dimensions of coefficient of thermal conductivity isA. `ML^(2) T^(-1) K^(-1)`B. `MLT^(-3) K^(-1)`C. `MLT^(-2) K^(-1)`D. `MLT^(-3) K` |
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Answer» Correct Answer - B (2) `(Delta Q)/(Delta t) = (K (theta_(2) - theta_(1)) A)/(L), K :` thermal conductivity `K = (Delta Q)/(Delta t) (L)/((theta_(2) - theta_(2)) A)` Unit : `(j o u l e . M)/(s. k e l vi n . M^(2)) = (j o u l e)/(s. k e l vi n. m)` `[K] = (ML^(2) T^(-2))/(T. K.L) = [MLT^(-3) k^(-1)]` |
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| 58. |
The frequency of vibration of string is given by `v=p/(2l)[F/m]^(1//2)`. Here `p` is number of segments in the string and `l` is the length. The dimensional formula for `m` will beA. `["M"^(0)"LT"^(-1)]`B. `["ML"^(0)"T"^(-1)]`C. `["ML"^(-1)"T"^(0)]`D. `["M"^(0)"L"^(0)"T"^(0)]` |
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Answer» Correct Answer - C `m` is mass per unit length. |
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| 59. |
The equation of a wave is given by `Y = A sin omega ((x)/(v) - k)`, where `omega` is the angular velocity and `v` is the linear velocity. Find the dimension of `k`.A. `LT`B. `T`C. `T^(-1)`D. `T^(2)` |
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Answer» Correct Answer - B |
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| 60. |
The unit of e.m.f isA. JouleB. Joule-CoulombC. Volt-CoulombD. Joule/Coulomb |
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Answer» Correct Answer - D |
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| 61. |
Which of the following is not the unit of timeA. Micro secondB. Leap yearC. Solar dayD. Parallactic second |
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Answer» Correct Answer - D |
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| 62. |
Dimensions of potential energy areA. `MLT^(-1)`B. `ML^(2)T^(-2)`C. `ML^(-1)T^(-2)`D. `ML^(-1)T^(-1)` |
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Answer» Correct Answer - B |
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| 63. |
Assertion : Light year and year, both measure time. Reason : Because light year is the time light takes to reach the earth from the sun.A. If both assertion and reason are true and the reason is the correctexplanation of the assertion.B. If both assertion and reason are true but reason is not the correctexplanation of the assertion.C. If assertion is true but reason is false.D. If the assertion and reason both are false. |
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Answer» Correct Answer - D |
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| 64. |
Light year is a unit ofA. TimeB. MassC. DistanceD. Energy |
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Answer» Correct Answer - C |
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| 65. |
Length cannot be measured byA. FermiB. DebyeC. MicronD. Light year |
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Answer» Correct Answer - B |
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| 66. |
If the unit of length and force be increased four times, then the unitof energy isA. Increased 4 timesB. Increased 8 timesC. Increased 16 timesD. Decreased 16 times |
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Answer» Correct Answer - C |
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| 67. |
The nuclear cross-section is measured in barn, it is equal toA. `10^(-20)m^(2)`B. `10^(-30)m^(2)`C. `10^(-28)m^(2)`D. `10^(-14)m^(2)` |
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Answer» Correct Answer - C |
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| 68. |
Which is the correct unit for measuring nuclear radiiA. MicronB. MillimetreC. AngstromD. Fermi |
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Answer» Correct Answer - D |
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| 69. |
In which of the following systems of unit, Weber is the unit ofmagnetic fluxA. CGSB. MKSC. SID. None of these |
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Answer» Correct Answer - C |
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| 70. |
Tesla is a unit for measuringA. Magnetic momentB. Magnetic inductionC. Magnetic intensityD. Magnetic pole strength |
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Answer» Correct Answer - B::C |
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| 71. |
SI unit of pressure isA. PascalB. Dynes`//cm^(2)`C. cm of HgD. Atmosphere |
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Answer» Correct Answer - A |
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| 72. |
The unit of angular acceleration in the SI system isA. `Nkg^(-1)`B. `ms^(-2)`C. `rads^(-2)`D. `m kg^(-1)K` |
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Answer» Correct Answer - C |
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| 73. |
Which of the following is not a unit of energyA. `W-s`B. `kg-m//sec`C. `N-m`D. Joule |
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Answer» Correct Answer - B |
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| 74. |
The dimensional formula fo resistivity in terms of `M,L,T` and `Q` where `Q` stands for the dimensions of charge isA. `ML^(3)T^(-1)Q^(-2)`B. `ML^(3)T^(-2)Q^(-1)`C. `ML^(2)T^(-1)Q^(-1)`D. `MLT^(-1)Q^(-1)` |
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Answer» Correct Answer - A |
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| 75. |
The dimensional formula fo resistivity in terms of `M,L,T` and `Q` where `Q` stands for the dimensions of charge isA. `[ML^(3)T^(-1)Q^(-2)]`B. `[ML^(2)T^(-2)Q^(2)]`C. `[MLT^(-2)Q^(-2)]`D. `[ML^(2)T^(-2)Q^(-1)]` |
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Answer» Correct Answer - A Since, `R=(rhol)/(A)` , where `rho` is specific resistance. `therefore" "[rho]=[(RA)/(l)],R=(V)/(i),V=(W)/(Q)` `" "[rho]=["ML"^(3)"T"^(-1)theta^(-2)]` |
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| 76. |
The dimensions of `a/b` in the equation `P=(a-t^(2))/(bx)` where `P` is pressure, `x` is distance and `t` is time areA. `[M^(2)L^T^(-3)]`B. `[MT^(-2)]`C. `[LT^(-3)]`D. `[ML^(3)T^(-1)]` |
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Answer» Correct Answer - B `p=(a-t^(2))/(bx)` , where ,o`p` -pressure, `t` - time `" "[pbx]=[a]=[t^(2)]` Hence, `" "[b]=([T^(2)])/([px])` Dimensions of `(a)/(b)=[px]=["MT"^(-2)]` |
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| 77. |
The equation of a wave is given by `y = a sin omega [(x)/v -k]` where ` omega ` is angular velocity and v is the linear velocity . The dimensions of k will beA. `[T^(-2)]`B. `[T^(-)]`C. [T]D. [LT] |
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Answer» Correct Answer - C `omegak` is dimensionless. |
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| 78. |
Dimensional formula for latent heat is________A. `M^(0)L^(2)T^(-2)`B. `MLT^(-2)`C. `ML^(2)T^(-2)`D. `ML^(2)T^(-1)` |
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Answer» Correct Answer - A |
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| 79. |
Candela is the unit ofA. Electric intensityB. Luminous intensityC. Sound intensityD. None of these |
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Answer» Correct Answer - B |
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| 80. |
One femtometer is equivalent toA. `10^(15)m`B. `10^(-15)m`C. `10^(-12)m`D. `10^(12)m` |
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Answer» Correct Answer - B |
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| 81. |
The dimension of magnetic field in `M,L,T and C` (coulomb) is given asA. `MT^(2) C^(-2)`B. `MT^(-1) C^(-1)`C. `MT^(-2) C^(-1)`D. `MLT^(-1) C^(-1)` |
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Answer» Correct Answer - B (2) `F = Bqv implies V = (F)/(qv) = (MLT^(-2))/(Q.LT^(-1))` `[B] = MT^(-1) C^(-1)` |
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| 82. |
Dimensional formula of heat energy isA. `ML^(2)T^(-2)`B. `MLT^(-1)`C. `M^(0)L^(0)T^(-2)`D. None of these |
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Answer» Correct Answer - A |
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| 83. |
The dimensions of `CV^(2)` matches with the dimensions ofA. `L^(2)I`B. `L^(2)I^(2)`C. `LI^(2)`D. `1/(LI)` |
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Answer» Correct Answer - C |
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| 84. |
The equation `(P+a/(V^(2)))(V-b)` constant. The units of `a` areA. `"Dyne"xxcm^(5)`B. `"Dyne"xxcm^(4)`C. `"Dyne"//cm^(3)`D. `"Dyne"//cm^(2)` |
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Answer» Correct Answer - B |
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| 85. |
In `S=a+bt+ct^(2).S` is measured in metres and `t` in seconds. The unit of `c` isA. NoneB. `m`C. `ms^(-1)`D. `ms^(-2)` |
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Answer» Correct Answer - D |
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| 86. |
If `L=2.331cm`,`B=2.1cm`, then `L+B=A. `4.431cm`B. `4.43cm`C. `4.4cm`D. `4cm` |
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Answer» Correct Answer - C |
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| 87. |
What is the number of significant figures in `0.0310xx10^(3)`?A. 2B. 3C. 4D. 6 |
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Answer» Correct Answer - B We shall count number of significant digit only in 0.0310 which is 3. |
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| 88. |
In which of the following numerical values, all zeros are significant?A. `0.2020`B. 20.2C. 2020D. None of these |
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Answer» Correct Answer - B Only in 20.2 all zero are significant because in the digit zero lies between two digits. |
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| 89. |
The volumes of two bodies are measured to be `V_1 = (10.2+-0.02) cm^3 and V_2 = (6.4 +- 0.01)cm^3`. Calculate sum and difference in volumes with error limits. |
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Answer» given, `V_(1)=(10.2pm0.02)cm^(3)` and `V_(2)=(6.4pm0.01)m^(3)` `DeltaV=pm(DeltaV_(1)+DeltaV_(2))` `=pm(0.02+0.01)cm^(3)=pm0.03 cm^(3)` `V_(1)+V_(2)=(10.2+6.4)cm^(3)=16.6 cm^(3)` and `V_(1)+V_(2)=(10.2-6.4)cm^(3)=3.8 cm^(3)` Hence, sum of volumes= `(16.6pm0.03)cm^(3)` and difference of volumes= `(3.8pm0.03)cm^(3)` |
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| 90. |
The length of a rod as measured in an experiment was found to be 2.48m, 2.46 m, 2.49 m, 2.50 m and 2.48m. Find the average length, absolute arror in each observation and the percentage error. |
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Answer» Average length=Arithmetic mean of the measured values `x_(mean)=(2.48+2.46+2.49+2.49+2.46)/(5)=(12.38)/(5)=2.476 m` `therefore` True value, `x_(mean)=2.48m` Absolute errors in various measurements, `|Deltax_(1)|=|x_(1)=x_(mean)|=2.48-2.48=0.00m` `|Deltax_(2)|=|2.46-2.48|=0.02m` `|Deltax_(3)|=|2.49-2.48|=0.01m` `|Deltax_(4)|=|2.49-2.48|=0.01m` `|Deltax_(5)|=|2.46-2.48|=+0.02m` Mean absolute error =`(|Deltax_(1)|+|Deltax_(2)|+|Deltax_(3)|+...+|Deltax_(5)|)/(5)` `((0.00+0.02+0.01+0.01+0.02))/(5)=(0.06)/(5)` `Deltax_(mean)=0.01 m` Thus, `x=2.48pm0.01m` Percentage error, `deltax=(Deltax_(mean))/(x)xx100` `(0.01)/(2.48)xx100=0.40%` |
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| 91. |
The resistance of a conductor `R = V//I`, where `V = (50 +- 2) V` and `I = (9 +- 0.3) A`. Find the percentage error in `R`. |
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Answer» `(Delta R)/(R ) = (Delta V)/(V) + (Delta I)/(I)` `= (2)/(50) + (0.3)/(9)` `(Delta R)/(R ) xx 100 = ((2)/(50) + (0.3)/(9)) xx 100` `= 4 + 3.3` `= 7.3%` |
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| 92. |
What is the maximum percentage error? (a) In measurement of kinetic energy if the percentage error in mass and speed are `1%` and `2%`, respectively. (b) In measurement of pressure if maximum errors in the measurement of force and length of square plate are `3%` and `2%`, respectively. In measurement of time period of simple pendulum if the percentage error in measurement of length and acceleraton due to gravity are respectively `2%` and `3%` |
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Answer» `K = (1)/(2) mv^(2)` `(Delta K)/(K) = (Delta m)/(m) + 2 (Delta v)/(v)` `(Delta K)/(K) xx 100 = (Delta m)/(m) xx 100 + 2 (Delta v)/(v) xx 100` `= 1 + 2 xx 2 = 5%` (b) `P = (F)/(l^(2))` `(Delta P)/(P) xx 100 = (Delta F)/(F) xx 100 + 2 (Delta l)/(l)` `= 3 + 2 xx 2 = 7%` (c ) `T = 2 pi sqrt(l//g)` `(Delta T)/(T) xx 100 = (1)/(2) (Delta l)/(l) xx 100 + (1)/(2) (Delta g)/(g) xx 100` `= (1)/(2) xx 2 + (1)/(2) xx 3 = 2.5 %` |
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| 93. |
The velocity of a freely falling body changes as `g^ph^q`where g is acceleration due to gravity and h is the height. The values of p and q areA. `1,1/2`B. `1/2,1/2`C. `1/2,1`D. `1,1` |
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Answer» Correct Answer - B |
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| 94. |
If `V` denotes te potential difference across the plate of a capacitor of capacitance `C`, the dimensions of `CV^(2)` areA. Not expressible in `MLT`B. `MLT^(-2)`C. `M^(2)LT^(-1)`D. `ML^(2)T^(-2)` |
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Answer» Correct Answer - D |
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| 95. |
In the relation `P = (alpha)/(beta) e^((alpha Z)/(k theta))`, `P` is pressure, `Z` is height, `k` is Boltzmann constant and `theta` is the temperature. Find the dimensions of `alpha` and `beta` |
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Answer» Power of exponential is dimesnionless. `(alpha Z)/(k theta)` is dimensionless. `(alpha [L])/([ML^(2) T^(-2) K ^(-1)] [K])` is dimensionless. `[alpha] = [MLT^(-2)]` Dimensions of `(alpha)/(beta)` = Dimensions of `P` `([MLT^(-2)])/(beta) = [ML^(01) T^(-2)]` `[beta] = [L^(2)]` |
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| 96. |
(a) The displacement `s` of a particale in time `t` related as `s = alpha + beta t + gamma t^(2) + delta t^(2)` (b) The veloctiy `v` of particle varies with time as `v = alpha t + beta t^(2) + (gamma )/(t + s)` Findk the dimension fo `alpha, beta, gamma` and `delta`. |
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Answer» (a) Dimensions of each term on the right-hand side have same dimension as that fo `s`, i.e., `[L]` `[alpha] = L` `[beta t] = L implies [beta] = LT^(-1)` `[gamma t^(2)] = L implies [gamma] = LT^(-2)` `[delta t^(2)] = L implies [delta] = LT^(-3)` (b) Dimension of each term on the right-hand side have same dimensions as that of `v`, i.e., `[Lt^(-1)]` `[alphat] = Lt^(-1) implies [alpha] = LT^(-2)` `[beta t^(2)] = LT^(-1) implies [beta] = LT^(-3)` `[delta] = L` `[(gamma)/(t + S)] = LT^(-1) implies [gamma] = L` |
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| 97. |
The function `f` is given by `f = A sin alpha x + B cos beta t`, where `x` is displacement and `t` is the time. The dimensions of `alpha//beta` isA. `[M^(0) L^(0) T^(0)]`B. `[MLT^(-1)]`C. `[M^(0) L^(-1) T]`D. `[M^(0) LT^(-1)]` |
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Answer» Correct Answer - C (3) Angles have no dimension. `alpha x` is dimensionless : `[alpha] = L^(-1)` `beta t` is dimensionless : `[beta] = T^(-1)` `(alpha)/(beta) = (L^(-1))/(T^(-1)) = L^(-1) T` |
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| 98. |
A sperical body of mass `m` and radius `r` is allowed to fall in a medium of viscosity `eta`. The time in which the velocity of the body increases from zero to `0.63 ` times the terminal velocity `(v)` is called constant `(tau)`. Dimensionally , `tau` can be represented byA. `(mr^(2))/(6pi eta)`B. `sqrt(((6 pi mr eta)/(g^(2))))`C. `m/(6pi eta rv)`D. None of the above |
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Answer» Correct Answer - D |
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| 99. |
Which one of the following is not correct?A. Dimension formula of thermal conductivity `(K)` is `["M"^(1)"L"^(1)"T"^(-3)"K"^(-1)]`B. Dimension formula of potential `(V)` is `["M"^(1)"L"^(2)"T"^(3)"A"^(-1)]`C. Dimension formula of permeability of free space `(mu_(0))` is `["M"^(1)"L"^(1)"T"^(-2)"A"^(-2)]`D. Dimensional formula of `RC` is `["M"^(0)"L"^(0)"T"^(-1)]` |
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Answer» Correct Answer - B Dimensional formula of potential `[V]=["M"" L"^(2)"T"^(-3)"A"^(-1)]` Dimensional formula of `[RC]=["M"^(0)"L"^(0)"T"]` |
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| 100. |
In the equation `((1)/(pbeta))=(y)/(k_(B)T)`, where `p` is the pressure, `y` is the distance, `k_(B)` is Boltzmann constant and `T` is the tempreture. Dimensions of `beta` areA. `["M"^(-1)"L"^(1)"T"^(2)]`B. `["M"^(0)"L"^(2)"T"^(0)]`C. `["M"^(1)"L"^(-1)"T"^(-2)]`D. `["M"^(0)"L"^(0)"T"^(0)]` |
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Answer» Correct Answer - B Given equation, `(1)/(pbeta)=(y)/(k_(B)T)` where, `p` = pressure, `y` = distance, `k_(B)` = Boltzmann constant and `T` = temperature Dimension of `[beta]=(["Dimensions of "k_(B)]["Dimensions of "T])/(["Dimensions of "p]["Dim en sions of "y])` `" "=(["ML"^(2)"T"^(-3)]["T"])/(["ML"^(-1)"T"^(-2)]["L"])=["M"^(0)"L"^(2)"T"^(0)]` |
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