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151.

Velocity of sound increases on a cloudy day. Why?

Answer»

Since on a cloudy day, the air is wet i.e. it contains a lot of moisture, As a result of which the density of air is less and since velocity is inversely proportioned to density, hence velocity increases. 

152.

Two loudspeakers installed at a particular place. A person at another point, receive very weak sound. What can be the reason of it? What will happen if one loudspeaker is kept off?

Answer»

If the difference in the distances of the loudspeakers from the listener is an odd multiple of λ/2, then due to destructive interference very feeble sound will be heard. If one loudspeaker is put off, the no interference will take place and the full sound of the other speaker will be heard.

153.

Establish a relation between wave speed and particle speed.

Answer»

Equation of the wave is represented by:

y = A sin (ωt - kx)

Differentiating it with respect to t, we get

O = A cos (ωt - kx) [ω - k.dx/dt]

And the velocity of wave,

dx/dy = ω/k

Similarly the velocity of the particle

dx/dy = ωA cos (ωt - kx)

And the acceleration of a point particle is given by

d2y/dt2 = ω2 A sin (ωt - kx)    ....(i)

Differentiating the y with respect to x

dx/dy = -Ak cos (ωt - kx)

and d2y/dx2 = -Ak2 sin (ωt - kx)   ...(ii)

From eqn. (i) and eqn. (ii) we get

d2y/dx2 = v2 d2y/dx2

154.

The diagram shows the profile of a wave, which of the following pairs of points are in phase? (a) A, B (b) B, C (c) B, D (d) B, E

Answer»

Correct answer is (d) B, E

155.

With the rise of temperature, the speed of sound in a gas …….. (a) increases (b) decreases (c) remain the same (d) may increase or decrease depending on the corresponding change in pressure.

Answer»

Correct answer is (a) increases

156.

Show that the fundamental frequency of an open organ pipe is twice that of a closed organ pipe of the same length.

Answer»

Fundamental frequency of an open organ pipe

v0 = v/2L

Fundamental frequency of a closed organ pipe is,

vc = v/4L

Hence, v0/vc = 2

or, v0 = 2vc

157.

What would a person hear, if he moves away from a source of sound with a speed of sound?

Answer»

The person would be hearing nothing if he is moving away from the source with the speed of sound. It is so, because the relative velocity of sound waves with respect to the person is zero.

Therefore, the sound waves cannot strike the drum of the person's ears and no sensation of hearing is produced.

158.

Use the formula v = √{γp/ρ} to explain why the speed of sound in air(i) is independent of pressure,(ii) increases with temperature,(iii) increases with humidity.

Answer»

We are given that,

v = √{γp/ρ}

We know that pV = nRT

⇒ pV = m/M RT

where m is the total mass and M is the molecular mass of the gas.

p = m/M.RT/V = ρRT/M

⇒ p/ρ = RT/M

(a) For gas at constant temperature,

p/ρ = constant

As p increases, ρ also increases and vice versa. This implies that

v = √{γp/ρ} = const.

i.e., velocity is independent of pressure of the gas.

(a) Since p/ρ = RT/M

Therefore, v = √{γp/ρ} = √{γRT/M}

Clearly v α √T, i.e., Speed of sound in air increases with increase in temperature.

(c) Increase in humidity decreases the effective density of air.

Therefore, the velocity (v x 1/√ρ) increases.

159.

A steel wire has a length of 12.0 m and a mass of 2.10 kg. What should be the tension In the wire so that the speed of a transverse wave on the wire equals the speed of sound in dry air at 20°C = 343 m s-1?

Answer»

Mass per unit length of the wire,

µ = \(\frac{2.10kg}{12.0m}\) = 0.175 kg m-1

The speed of wave on a string is

given by, v = \(\sqrt \frac{T}μ \)

Given v = 343 ms-1

∴ T = µv2 =0.175 × 3432

= 20588.575 = 2.06×104 N.

160.

What are beats? 

Answer»

The periodic variations in the intensity of sound due to the superposition of two sound waves of slightly different frequencies are called beats. One rise and one fall of intensity constitute one beat. The number of beats produced per second is called beat frequency.

161.

What is Zero level or threshold of hearing ?

Answer»

The lowest intensity of sound that can be perceived by the human ear is called threshold of hearing. 

162.

Define the term Intensity of sound.

Answer»

The intensity of sound at any point may be defined as the amount of sound energy passing per unit time per unit area around that point in a perpendicular direction.

163.

Define the term Reflection of a wave.

Answer»

When a wave is reflected from a rigid boundary or a closed end, it is reflected back with a phase reversal or phase difference of radians but reflection at an open boundary takes place without any phase change.

164.

The displacement `y` of a particle executing periodic motion is given by `y = 4 cos^(2) ((1)/(2)t) sin(1000t)` This expression may be considereed to be a result of the superposition ofA. (a) twoB. ( b ) threeC. ( c ) fourD. (d) five

Answer» Correct Answer - B
(b) `y = 4cos^(2) ((t)/(2)) sin(1000t) = 2(2cos^(2)(t)/(2)sin1000t)`
`= 2[cos t + 1]sin 1000t`
`= 2cos t sin 1000t + 2 sin 1000t`
`= sin 1000t + sin 999t + 2 sin 1000t`
165.

Why do the stages of large auditoriums gave curved backs?

Answer»

The stages of large auditorium have curved backs because when speaker stands at or near the focus of curved surface his voice is rendered parallel after reflection from the concave or parabolic seer face. Hence the voice can be heard at larger distances.

166.

The phenomenon of echo is an example ofA. reflectionB. refractionC. beatD. resonance

Answer» Correct Answer - A
The phenomenon of echo is an example of reflection by a rigid boundary
167.

Why are all stringed instruments provided with hollow boxes?

Answer»

The stringed instruments are provided with a hollow box called sound box. When the strings are set into vibration, forced vibrations are produced in the sound box. Since sound box has a large area, it sets a large volume of air into vibration. This produces a loud sound of the same frequency of that of the string. 

168.

Stringed instruments are provided with hollow boxes. Why?

Answer»

The hollow boxes in the instruments are set into forced vibrations along with the strings. The loudness is higher if area of the vibrating body is move. So, the hollow boxes attached increase the loudness of sound.

169.

Can mechanical waves travel through vacuum?

Answer»

No, mechanical waves can not travel through vacuum.

170.

What do mechanical waves transfer : energy; matter; both or neither?

Answer»

Mechanical waves transfer only energy from one point to another.

171.

How does velocity of sound in air change when temperature rises by 1°C.

Answer»

Velocity of sound in air increases by 0.61 ms-1, when temperature rises by 1°C

172.

In travelling waves, the relation between particle velocity `V_(p)`, wave velocity V wave shape slope m is given byA. `V_(p)=-vxxm`B. `V_(p)=Vxxm`C. `V=-V_(p)xxm`D. `V=V_(p)xxm`

Answer» Correct Answer - A
173.

In standing waves, select incorrectA. All particle between two consecutive nodes vibrate in same phaseB. particles on opposite side of a node vibrate in same phaseC. frequency of oscillation of all particles (except nodes) is sameD. formation of standing waves is a special type of interference phenomana.

Answer» Correct Answer - B
174.

In standing waves, select incorrectA. If both assertion and reason are true and reason is the correct explanation of assertion.B. If both assertion and reason are true but reason is not the correct explanation of assertion.C. If assertion is true but reason is false.D. If both assertion and reason are false.

Answer» Correct Answer - D
The interference of two identical waves moving in opposite directions produces standing waves. Various elements of standing waves remain in constant phase.
175.

A stretched wireof length 0.6m is observed to vibrate with a frequency of 30 Hz in the fundamental mode. If the string has a linear massof 0.05 `kg //m`. Find (a) the velocity of propagation of transverse wave in the string (b) the tension in the string.

Answer» `v= 20 Hz , 1= 0.6m, mu = 0.05 kg m^(-1) ,v= ? , T= ? `
(a) `v= 2vl= 2xx30xx0.6=36 m//s `
`T = v^(2) mu = 36 xx 36 xx0.05 = 64.8 N `
176.

The propagation constant of a wave is also calle itsA. wavelengthB. frequencyC. wave numberD. angular wave number

Answer» Correct Answer - D
The propagation constant of a wave is also called its angular wave number.
177.

A pipe of length `l_(1)`, closed at one end is kept in a chamber of gas of density `rho_(1)`. A second pipe open at both ends is placed in a second chamber of gas of density `rho_(2)`. The compressibility of both the gases is equal. Calculate the length of the second pipe if frquency of first overtone in both the cases is equalA. (a) `(4)/(3)l_(1)sqrt((rho_(2))/(rho_(1))`B. (b) `(4)/(3)l_(1)sqrt((rho_(1))/(rho_(2))`C. ( c ) `l_(1)sqrt((rho_(2))/(rho_(1))`D. (d) `l_(1)sqrt((rho_(1))/(rho_(2))`

Answer» Correct Answer - B
(b) Frequency of first overtone in closed pipe,
`v = (3v)/(4l_(1))sqrt((P)/(rho_(1))` ….(i)
Frequency of first overtone in open pipe,
`v = (1)/(4l_(2))sqrt((P)/(rho_(2))` …(ii)
From equation (i) and (ii)
rArr `l_(2) = (4)/(3)l_(1)sqrt((rho_(1))/(rho_(2))`
178.

Give the relation between the fundamental note and overtone in an open pipe.

Answer»

f' = (n +1)f

f – fundamental frequency, n = 1,2, 3….

for 1st and 2nd …. overtones.

179.

The fundamental frequency produced in a dosed pipe is 500 Hz. What Is the frequency of the first overtone?

Answer»

[Frequency of the first over tone in a closed pipe is = 3f = 3 × 500 = 1500 Hz].

180.

The fundamental frequency produced in a dosed pipe is 500 Hz. What Is the frequency of the first overtone?

Answer»

[Frequency of the first over tone in a closed pipe is f' = 3f = 3 × 500 = 1500 Hz].

181.

The length of the vibrating portion of a sonometer wire Is doubled. How does its frequency change?

Answer»

[Reason: Frequency f ∝ 1/. As / is doubled f is halved].

182.

In the above problem, if some of the sound reaching the target ges reflected back to the rocket as an echo, then what frequency of the echo is detected by the rocket?

Answer» Correct Answer - 2500 Hz
183.

What are harmonics?

Answer»

Overtones, which are an integral multiple of the fundamental frequency, are called harmonics.

184.

A rocket is moving at a speed of 220 `ms^(-1)` towards a stationary target. While moving, it emits a wave of frequency 500 Hz. What is the frequency of the sound as detected by the target?

Answer» Correct Answer - 1500 Hz
185.

By how much does the frequencies of 2 sound sources differ, if they produce 10 beats in 2 seconds.

Answer»

Number of beats per second

\(\frac{10}{2} = 5\) 

∴ ∆ f = f1 ~ f2 = 5 Hz.

186.

What are overtones?

Answer»

Frequencies greater than fundamental frequency are called overtones.

187.

What Is fundamental frequency?

Answer»

The vibration of a body with the lowest frequency is called the fundamental frequency.

188.

A train moving at a speed of 220 m/s towards a stationary object, emits a sound of frequency 1000 Hz. Some of the sound reaching the object gets reflected back to the train as echo. The frequency of the echo as detected by the driver of the train is (a) 3000 Hz(b) 3500 Hz(c) 4000 Hz(d) 5000 Hz 

Answer»

(d) 5000 Hz

\(f' = (\frac{330 + 220}{330 -220})\) x 1000 = 5000 Hz

189.

What is a stationary wave?

Answer»

The wave formed due to the superposition of two identical waves travelling with the same speed in opposite directions is called a stationary wave or standing wave.

190.

Define reverberation.

Answer»

Reverberation is defined as the persistence of audible sound even after the source has ceased to produce the sound.

191.

Define the beat period.

Answer»

The time interval between two consecutive maxima or minima is called beat period. It is also equal to the reciprocal of beat frequency.

192.

which one of following is a simple harmonic motoin?A. Ball bouning between two rigid vertical wallsB. particle moving in a circle with unifrom speedC. Wave moving through a string a string fixed at both endsD. Earth spinnig about its own axis

Answer» Correct Answer - c
193.

A listener and a source of sound are moving with the same speed in the same direction. The ratio of the frequency of the source and the frequency which is heard by the listerner isA. `1:2`B. `2:1`C. `1:1`D. `1:4`

Answer» Correct Answer - C
194.

The frequency of the whistle of a train is observed to drop from 280 Hz to 260 Hz as the train moves away from a stationary listerner on the platform. Calculate the speed of the train, if speed of sound in air is 340 m/s.

Answer» Correct Answer - 26.15 m/s
195.

A source and an observer approach each other with same velocity 50m/s.  If the apparent frequency is 435sec-1, then the real frequency isA) 320 sec-1B) 360 sec-1C) 390 sec-1D) 420 sec-1

Answer»

A) 320 sec-1

n' = n(v+vo/v-vs) n

⇒ 400 = n(360 + 40/360 - 40)

⇒ n = 320cps

196.

What is Wave motion ? What are the types of Wave motion ?

Answer»

It is a kind of disturbance which travels through a medium due to the repeated vibrations of the particles of the medium about their mean positions, the disturbance being handed over from one particle to the next. In a wave both information and energy propagate from one point to another but there is no motion of matter as a whole through medium. 

Three types of waves: 

(i) Mechanical waves: The waves which requires a mechanical medium for their propagation are called mechanical waves or elastic waves. For their propagation, the medium must possess the properties of inertia and elasticity. For example, water waves, sound waves, etc. 

(ii) Electromagnetic waves: The waves which travel n in the form of oscillating electric and magnetic fields are called electromagnetic waves. Such waves do not require any material medium for their propagation. For example, visible light, radio waves, etc. 

(iii) Matter waves: The waves associated with microscopic particles, such as electrons, protons, neutrons, atoms, molecules, etc.

197.

Define Progressive wave.

Answer»

A wave that moves from one point of medium to another is called a progressive wave.

198.

Give the Characteristic of a musical sound.

Answer»

Characteristic of a musical sound: 

These are 

(i) Pitch: It is the characteristic of musical sound that helps the listener in distinguishing a shrill note from a grave (flat or dull) one. It depends on frequency. 

(ii) Quality: It is the characteristic of the musical sound that distinguishes between two sound of same pitch and loudness from one another. It depends on the number or intensity of overtones. 

(iii) Loudness: The sensation of hearing which enables us to distinguish between a loud and a faint sound is called loudness. It depends on intensity.

199.

What are Units f loudness ?

Answer»

The unit of loudness of a sound is bel. The loudness of a sound is said to be 1 bel, if its intensity is 10 times that of the threshold of hearing.  

200.

Define Musical scale.

Answer»

A series of notes arranged such that their fundamental frequencies have definite ratios is called a musical scale.