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`0.002 molar` solutiion of `NaCl` having degree of dissociation of `90%` at `27^(@)C` has osmotic pressure equal to a.0.94 bar , b.9.4 bar , c.0.094 bar , d.`9.4xx10^(-4)` barA. 0.94 barB. 9.4 barC. 0.094 barD. `9.4 xx 10^(-4)` bar |
Answer» Correct Answer - C `alpha = (i-1)/(n-1)` `0.9=(i-1)/(2-1),i=1.9` `pi=iCRT` `=1.9xx0.002xx0.082xx300` `=0.094` bar] |
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