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0.1 formal soluton of NaCl is found to be isotonic with 1.10% solution of urea. Calculate the apparent degree of ionization of NaCl. |
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Answer» Correct Answer - 0.83 `pi_(NaCl)=pi_(urea)` `=nxx(1)/(V)RT` `ixx0.1xxRT=(1.1)/(60xx0.1)xxRT" "(pi=(n)/(V)RT)` `i=83` `alpha=(i-1)/(n-1)=(1.83-1)/(2-1)=0.83`] |
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