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    				| 1. | `0.15`g of a subatance dissolved in `15`g of solvent boiled at a temperature higher at `0.216^(@)`than that of the pure solvent. Calculate the molecular weight of the substance. Molal elecation constant for the solvent is `2.16^(@)C`A. 216B. 100C. 178D. None of these | 
| Answer» Correct Answer - B Here it is given that `"w"=0.15"g, " Delta"T"_("b")=0.216^(@)"C"` `"W"=15"g""K"_("b")=2.16^(@)"C ""m"?` Substituting values in the expression, `"m"=(1000xx"K"_("b")xx"w")/(Delta"T"_("b")xx"")" m"=(1000xx2.16xx0.15)/(0.216xx15)=100` | |