1.

`0.15`g of a subatance dissolved in `15`g of solvent boiled at a temperature higher at `0.216^(@)`than that of the pure solvent. Calculate the molecular weight of the substance. Molal elecation constant for the solvent is `2.16^(@)C`A. 216B. 100C. 178D. None of these

Answer» Correct Answer - B
Here it is given that
`"w"=0.15"g, " Delta"T"_("b")=0.216^(@)"C"`
`"W"=15"g""K"_("b")=2.16^(@)"C ""m"?`
Substituting values in the expression,
`"m"=(1000xx"K"_("b")xx"w")/(Delta"T"_("b")xx"")" m"=(1000xx2.16xx0.15)/(0.216xx15)=100`


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