InterviewSolution
Saved Bookmarks
| 1. |
0.1m solution of KCI and `BaCI_(2)` are preparred. The freezing point of KCI solution is found to be- `4.0^(@)C`. What will be the freezing point of `BaCI_(2)` solution assuming that both KCI and `BaCI_(2)` solution are sompletely ionised in solution ?A. `-3^(@)C`B. `-4^(@)C`C. `-5^(@)C`D. `-6^(@)C` |
|
Answer» Correct Answer - a `"For" KCI,DeltaT_(f)=iK_(f)xxm` `DeltaT_(f)=(0.0.4^(@)C)=4^(@)C` `4K=2xxK_(f)xxm` `"For " BaCI_(2),DeltaT_(f)=iK_(f)xxm` `=3xxK_(f)xxm` Both `K_(f)` and m are same for the solute, `DeltaT_(f)=(BaCI_(2))=3` Freezing point of `BaCI_(2)=0-3=-3^(@)C` |
|