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`0.5M` of `H_(2)SO_(4)` is diluted from 1 litre to 10 litre, normality of resulting solution isA. 1NB. 0.1NC. 10ND. 11N |
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Answer» Correct Answer - B `0.5M H_(2)SO_(4)=1N H_(2)SO_(4)` `underset(("conc"))(N_(1)V_(1)) = underset(("dil"))(N_(2)V_(2))` ` 1Nxx1L = N_(2)xx10L` `N_(2)=1//10N = 0.1N` |
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