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0.90g of a non-electolyte was dissolved in 87.9 g of benzene. This reised the boiling point of benzene by `0.25^(@)C`. If the molecular mass of the non-electrolyte is 103.0 g `mol^(-1)` , calculate the molal elecation constant for benzene. |
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Answer» `K_(B)=(DeltaT_(b)xxM_(B)xxW_(A))/W_(B)` `W_(B)=0.90g,W_(A)=87.9g=0.0879 kg, M_(B)=103.0 g mol^(-1),` `DeltaT_(b)=0.25 K` `K_(b)=((0.25K)xx(103.0gmol^(-1))xx(0.0879kg))/((0.90g))=2.52 K kg mol^(-1)` |
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