1.

0.92 gm of an organic compound containing carbon, hydrogen, and oxygen was analysed by combustion method. The increase in the mass of the U-tube and the potash bulbs at the end of the operation was found to the 1.08 gm and 1.76 gm respectivley. Determine the percentage composition of the compound.

Answer» Increase in the mass of U-tube `=1.08gm`
Mass of water formed `=1.08gm`
since 18 gm of water contains 2 gm hydrogen
1.08 gm of water contains `(2)/(18)xx1.08gm` hydrogen
mass of the compound taken for analysis `=0.92gm`
Percentage of hydrogen `=(2)/(18)xx(1.08)/(0.92)xx100=13.04`
Increase in the mass of potash bulbs `=1.76gm`
mass of carbon dioxide formed `=1.76gm`
Since 44 gm of carbon dioxide contains 12 gm carbon
1.76 gm of carbon dioxide contains 12 gm carbon
1.76 gm of carbon contains `=(12)/(44)xx1.76gm` carbon
percentage of carbon `=(12)/(44)xx(1.76)/(0.92)xx100=52.17`
percentage of oxygen`=100-`(percentage of `C+`percent of H)
`=100-(52.17+13.04)`
`100-65.21=34.79`
Composition of the compound : `C=52.17%`,
`H=13.04%`,
`O=34.79%`


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