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0.92 gm of an organic compound containing carbon, hydrogen, and oxygen was analysed by combustion method. The increase in the mass of the U-tube and the potash bulbs at the end of the operation was found to the 1.08 gm and 1.76 gm respectivley. Determine the percentage composition of the compound. |
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Answer» Increase in the mass of U-tube `=1.08gm` Mass of water formed `=1.08gm` since 18 gm of water contains 2 gm hydrogen 1.08 gm of water contains `(2)/(18)xx1.08gm` hydrogen mass of the compound taken for analysis `=0.92gm` Percentage of hydrogen `=(2)/(18)xx(1.08)/(0.92)xx100=13.04` Increase in the mass of potash bulbs `=1.76gm` mass of carbon dioxide formed `=1.76gm` Since 44 gm of carbon dioxide contains 12 gm carbon 1.76 gm of carbon dioxide contains 12 gm carbon 1.76 gm of carbon contains `=(12)/(44)xx1.76gm` carbon percentage of carbon `=(12)/(44)xx(1.76)/(0.92)xx100=52.17` percentage of oxygen`=100-`(percentage of `C+`percent of H) `=100-(52.17+13.04)` `100-65.21=34.79` Composition of the compound : `C=52.17%`, `H=13.04%`, `O=34.79%` |
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