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0.984 gm of the chloroplatinate of a diacid base gave 0.39 gm of platinum. Calculate the molecular mass of the base. |
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Answer» Mass of platinichloride taken `=0.984gm` Mass of platinum left `=0.39gm` Step 1. To calculate the equivalent mass of the base. Let the equivalent mass of the base be B. Molecular mass of the platininchloride `(B_2H_2PtCL_6)` `=2B+410`. Now, `("molecular mass of chloroplatinichloride")/("atomic mass of platinum")` `=("mass of platinichloride taken")/("mass of platinum left")` or `(2B+410)/(195)=(0.984)/(0.39)` or `B=(1)/(2)((0.984)/(0.39)xx195-410)=41` Thus, the equivalent mass of the base be `41` Step 2: to calculate the molecular mass of the base. Acidity of the base `=2` Molecular mass of base `=`equivalent mass of base`xx`acidity `=41xx2=82` Thus, the molecular mass of base is `82`. |
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