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One litre of a mixture of CO and `CO_2` is passed through red-hot charcoal. The volume now becomes 1.6 litre. Find the composition of the mixture by volume. |
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Answer» Let `CO_2=x`litre `CO=(1-x)` litre `underset(xlitre)CO_2overset(C)tounderset(2xlitre)2CO` `underset(x)CO_2+underset(1-x)Co overset(C)tounderset(2x)2CO+underset(1-x litre)(CO)` `2x+(1-x)=1.6` `x=0.6litre` volume of `CO_2=0.6` litre Volume of `CO=(1-0.6)=0.4litre` |
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