1.

The empirical formula of anorganic compound is `CH_2`.The mass of 1 mol of it is 42 gm.The molecular formula of the compound is:A. `C_4H_8`B. `C_2H_4`C. `C_3H_6`D. `CH_2`

Answer» Correct Answer - C
E.F.W.`=CH_2=12+2=14`
`n=(Mw)/(E.F.W.)=(42)/(14)=3`
`MF=C_3H_6`


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