InterviewSolution
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1). 1/22). 1/33). 1/44). 1/5 |
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Answer» As we know, a cone with RADIUS ‘R’ and height ‘h’, has a volume = 1/3 πr2h Total volume of liquid = volume of FIRST conical vessel = (1/3) × (22/7) × (7)2 × 30 = 1540 cm3 Volume of liquid poured in one vessel = volume of second conical vessel = (1/3) × (22/7) × (5)2 × 21 = 550 cm3 Total number of vessels filled = 1540/550 = 2.8 Hence, the third vessel is only filled = 0.8 = 80% ∴ The LAST vessel remained empty by = 100 – 80 = 20% = 1/5 |
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