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Find total surface area (in sq. cm) of a hollow globe with outer radius 18 cm and thickness 10 mm.1). 972 π2). 1552 π3). 2320 π4). 2452 π |
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Answer» Total surface area of hollow sphere = 4πr12 + 4πr22 Where, r1 = RADIUS of outer surface r2 = radius of inner surface Here, r1 = 18 cm, thickness = 10 mm = 1 cm ⇒ r2 = 17 cm ∴ Total surface area = [4 × (182 + 172)] π = 2452 π |
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