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The volume of the metal of a cylindrical pipe is 1496 cm3. The length of the pipe is 28 cm and its external radius is 18 cm. its thickness is approximately: (Take π = 22/7)1). 0.5 cm2). 10.4 cm3). 4.6 cm4). 7.4 cm |
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Answer» Volume of a hollow CYLINDER = πh (R2 – r2) ∴ 1496 = (22/7) × 28 × (R2 – r2) ⇒ (R2 – r2) = 17 As R = 18 cm, 324 – r2 = 17 ⇒ r = √307 cm ∴ Thickness = R – r = (18 - √307) cm Thus, the thickness is around 0.5 cm |
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