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If a cone, a hemisphere and a right circular cylinder stand on equal base and have the same height then their volumes are in the ratio1). 2: 3: 22). 2: 3: 13). 1: 2: 34). 3: 2: 2 |
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Answer» Let r be the radius of cone, cylinder and hemisphere And h be the height of cone, cylinder and hemisphere As we know, That height of a hemisphere is equal to radius of the hemisphere ∴ h = r Now, Volume of cone = $(\FRAC{1}{3}\;\PI {r^2}\;h = \;\frac{1}{3}\;\pi {r^3})$ Volume of cylinder = π r2 h = π r3 Volume of hemisphere $(= \;\frac{2}{3}\;\pi \;{r^3})$ Now, required ratio= Volume of cone: volume of hemisphere: volume of cylinder ⇒ Required ratio $(= \;\frac{1}{3}\;\pi {r^3}:\;\frac{2}{3}\;\pi \;{r^3}:\;\pi \;{r^3}\; = \;\frac{1}{3}:\frac{2}{3}:1 = 1\;:2\;:3)$ Thus, the required ratio is 1: 2: 3 |
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