1). $1\frac{5}{6}$2). $2\frac{1}{6}$3). $3\frac{1}{2}$4). \(2\fr

1.	1). \(1\frac{5}{6}\)2). \(2\frac{1}{6}\)3). \(3\frac{1}{2}\)4). \(2\frac{1}{2}\)
Answer» Follow BODMAS rule to solve this question, as per the order given below, Step - 1 - Parts of an equation ENCLOSED in the ‘BRACKETS’ MUST be solved first Step - 2 - Any mathematical ‘OF’ or ‘EXPONEMTS’ must be solved next Step - 3 - Next the part of the equation that contains ‘DIVISION; and ‘MULTIPLICATION’ are calculated Step - 4 - Last but not LEAST, the parts of the equation that contains ‘ADDITION’ and ‘SUBTRACTION’ should be calculated Now, the given expression: ⇒ $(2\frac{1}{9} \times 2\frac{2}{{19}} \DIV 6\frac{2}{3} = ? -1\frac{1}{2})$ ⇒ $(\frac{{19}}{9} \times \frac{{40}}{{19}} \div \frac{{20}}{3} = ? -\frac{3}{2})$ ⇒ $(\frac{{19}}{9} \times \frac{{40}}{{19}} \times \frac{3}{{20}} = ? -\frac{3}{2})$ ⇒ $(\frac{2}{3} = ? - \frac{3}{2})$ ⇒ $(\frac{2}{3} + \frac{3}{2} = ?)$ ⇒ $(? = \frac{{13}}{6} = 2\frac{1}{6})$ Hence, the required answer is $(2\frac{1}{6})$.

1). $1\frac{5}{6}$2). $2\frac{1}{6}$3). $3\frac{1}{2}$4). $2\frac{1}{2}$

Answer»

Follow BODMAS rule to solve this question, as per the order given below,

Step - 1 - Parts of an equation ENCLOSED in the ‘BRACKETS’ MUST be solved first

Step - 2 - Any mathematical ‘OF’ or ‘EXPONEMTS’ must be solved next

Step - 3 - Next the part of the equation that contains ‘DIVISION; and ‘MULTIPLICATION’ are calculated

Step - 4 - Last but not LEAST, the parts of the equation that contains ‘ADDITION’ and ‘SUBTRACTION’ should be calculated

Now, the given expression:

⇒ $(2\frac{1}{9} \times 2\frac{2}{{19}} \DIV 6\frac{2}{3} = ? -1\frac{1}{2})$

⇒ $(\frac{{19}}{9} \times \frac{{40}}{{19}} \div \frac{{20}}{3} = ? -\frac{3}{2})$

⇒ $(\frac{{19}}{9} \times \frac{{40}}{{19}} \times \frac{3}{{20}} = ? -\frac{3}{2})$

⇒ $(\frac{2}{3} = ? - \frac{3}{2})$

⇒ $(\frac{2}{3} + \frac{3}{2} = ?)$

⇒ $(? = \frac{{13}}{6} = 2\frac{1}{6})$

Hence, the required answer is $(2\frac{1}{6})$.