1.

1). 100 cm22). 200 cm23). 250 cm24). 300 cm2

Answer»

Solution;

Given : ABCD is a parallelogram.

AB = CD = 20 cm 

AD = BC = 10 cm 

It is ALSO given that

Let us take DM with M on the AB line as the perpendicular with height 'h'.

Now in the triangle DAM,

SINE teta = DM / AD

sine 30 degree = h / 10

1/2 = h / 10

By cross multiplication we get 

2h = 10

h = 5 cm

Area of the parallelogram

= perpendicular height × perpendicular base (AB) sq.units.

= 5 × 20

= 100 sq.cm.

The correct option is 1). 100 sq.cm.



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