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1). 100 cm22). 200 cm23). 250 cm24). 300 cm2 |
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Answer» Solution; Given : ABCD is a parallelogram. AB = CD = 20 cm AD = BC = 10 cm It is ALSO given that Let us take DM with M on the AB line as the perpendicular with height 'h'. Now in the triangle DAM, SINE teta = DM / AD sine 30 degree = h / 10 1/2 = h / 10 By cross multiplication we get 2h = 10 h = 5 cm Area of the parallelogram = perpendicular height × perpendicular base (AB) sq.units. = 5 × 20 = 100 sq.cm. The correct option is 1). 100 sq.cm. |
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