1). 102). 153). 204). 23

1.	1). 102). 153). 204). 23
Answer» First of all we round the decimals to nearest whole NUMBERS and Non-perfect Square to the nearest perfect squared NUMBER. After that we APPLY BODMAS rule. Also we know that √2 = 1.414 and √3 = 1.732 $(\begin{array}{l} {\left\{ {{{\left( {1.732} \RIGHT)}^2} + {{\left( {1.414} \right)}^2}} \right\}^2} = \left( {\SQRT {2024} \div 2.999} \right) + ?\\ \Rightarrow {\left\{ {{{\left( {\sqrt 3 } \right)}^2} + {{\left( {\sqrt 2 } \right)}^2}} \right\}^2} = \left( {\sqrt {2025} \div 3} \right) + ? \end{array})$ ⇒ (3 + 2)² = (45 ÷ 3) + ? ⇒ ? = 25 - 15 = 10

Answer»

First of all we round the decimals to nearest whole NUMBERS and Non-perfect Square to the nearest perfect squared NUMBER. After that we APPLY BODMAS rule.

Also we know that √2 = 1.414 and √3 = 1.732

$(\begin{array}{l} {\left\{ {{{\left( {1.732} \RIGHT)}^2} + {{\left( {1.414} \right)}^2}} \right\}^2} = \left( {\SQRT {2024} \div 2.999} \right) + ?\\ \Rightarrow {\left\{ {{{\left( {\sqrt 3 } \right)}^2} + {{\left( {\sqrt 2 } \right)}^2}} \right\}^2} = \left( {\sqrt {2025} \div 3} \right) + ? \end{array})$

⇒ (3 + 2)² = (45 ÷ 3) + ?

⇒ ? = 25 - 15 = 10

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1). 102). 153). 204). 23

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