InterviewSolution
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1). 12 litres2). 14 litres3). 10 litres4). 13 litres |
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Answer» Given, TWO vessels CONTAIN mixtures of milk and water in the ratio of 8 : 1 and 1 : 5 respectively. Amount of water in 1st vessel = 1/9 Amount of water in 2nd vessel = 5/6 Final mixture has half milk and half water Amount of water in 3rd vessel = ½ Let the volume taken from 1st vessel be x, then the volume of mixture is taken from 2nd vessel = 26 – x $(\begin{array}{l} \therefore \;\frac{1}{9}\; \times \;x\; + \;\frac{5}{6}\left( {26 - x} \right)\; = \;\frac{1}{2}\; \times \;26\\ \Rightarrow \;\frac{{5\; \times \;26}}{6}\; + \;\frac{x}{9} - \frac{{5x}}{6}\; = \;\frac{{26}}{2}\\ \Rightarrow \;\frac{{13x}}{{18}}\; = \;\frac{{26}}{3} \end{array})$ ⇒ x = 12 LITRES Volume drawn from 2nd vessel = 26 – 12 = 14 litres |
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