1.

A mixture is said to be symmetrical if it contains liquids P and Q in ratio 1 ∶ 2. 40 liters of a mixture of P and Q is taken in which P and Q are in the ratio 2 ∶ 3. What should be the ratio of P and Q in 20 liters of mixture that when mixed with first mixture results in a symmetrical mixture?1). 1 ∶ 22). 1 ∶ 33). 1 ∶ 44). 1 ∶ 5

Answer»

40 LITERS of a MIXTURE of P and Q is TAKEN in which P and Q are in the ratio 2 ? 3.

Amount of P in this mixture = (2/(2+3)) × 40 = 16 liters

Amount of Q in this mixture = (3/(2+3)) × 40 = 24 liters

Let amounts of P and Q in second mixture be T liters and (20 – T) liters, respectively.

To form a symmetrical mixture, ratio of P and Q in resultant mixture should be 1 ? 2.

⇒ (16 + T)/(24 + 20 – T) = ½

32 + 2T = 44 – T

⇒ T = 12/3 = 4

∴ ratio of P and Q = T/(20 – T) = 4/16 = 1 ? 4


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