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A mixture is said to be symmetrical if it contains liquids P and Q in ratio 1 ∶ 2. 40 liters of a mixture of P and Q is taken in which P and Q are in the ratio 2 ∶ 3. What should be the ratio of P and Q in 20 liters of mixture that when mixed with first mixture results in a symmetrical mixture?1). 1 ∶ 22). 1 ∶ 33). 1 ∶ 44). 1 ∶ 5 |
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Answer» 40 LITERS of a MIXTURE of P and Q is TAKEN in which P and Q are in the ratio 2 ? 3. Amount of P in this mixture = (2/(2+3)) × 40 = 16 liters Amount of Q in this mixture = (3/(2+3)) × 40 = 24 liters Let amounts of P and Q in second mixture be T liters and (20 – T) liters, respectively. To form a symmetrical mixture, ratio of P and Q in resultant mixture should be 1 ? 2. ⇒ (16 + T)/(24 + 20 – T) = ½ ⇒ T = 12/3 = 4 ∴ ratio of P and Q = T/(20 – T) = 4/16 = 1 ? 4 |
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