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Quantity B: In a 100 L mixture of petrol and spirit, the spirit is only 2% then find amount of spirit to be added to make spirit concentration 30%.1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
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Answer» QUANTITY A: Let AMOUNT of water mixed be ‘x’ L. ⇒ So amount of water before mixing = 10 × 40/100 = 4 L ⇒ Amount of water after mixing = 4 + x ⇒ Amount % = 50 = (4 + x) × 100/ (40 + x) ⇒ x = 32 L Quantity B: Let amount of spirit mixed is ‘x’ L. ⇒ So amount of spirit before mixing = 2 × 100/100 = 2 L ⇒ Amount of spirit after mixing = 2 + x ⇒ Amount % = 30 = (2 + x) × 100/ (100 + x) ⇒ x = 40 L ∴ Quantity A < Quantity B |
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