1.

Quantity B: In a 100 L mixture of petrol and spirit, the spirit is only 2% then find amount of spirit to be added to make spirit concentration 30%.1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B

Answer»

QUANTITY A:

Let AMOUNT of water mixed be ‘x’ L.

⇒ So amount of water before mixing = 10 × 40/100 = 4 L

⇒ Amount of water after mixing = 4 + x

⇒ Amount % = 50 = (4 + x) × 100/ (40 + x)

⇒ x = 32 L

Quantity B:

Let amount of spirit mixed is ‘x’ L.

⇒ So amount of spirit before mixing = 2 × 100/100 = 2 L

⇒ Amount of spirit after mixing = 2 + x

⇒ Amount % = 30 = (2 + x) × 100/ (100 + x)

⇒ x = 40 L

∴ Quantity A < Quantity B



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