1.

1). 152 cm2). 124 cm3). 140 cm4). 70 cm

Answer»

Solution :

Given:

Perimeter of five squares $P1 = 24cm , P2 = 32 cm, P3 = 40 cm , P4 = 80 cm, P5 = 100 cm$.

Perimeter of a square $= 4a$ units ,where $'a'$ is the side of the square. 

So, Side of the five squares are,

$a1 = 24/4 = 6$ cm 

$a2 = 32/4 = 8$ cm

$a3 = 40/4 = 10 $cm

$a4 = 80/4 = 20 $cm

$A5 = 100/4= 25$ cm

Area of a square $=a^2$ sq.units 

So,the area of five squares are

$A1 = 6^2 = 36$ sq.cm 

$A2 = 8^2 = 64$ sq.cm

$A3 = 10^2 = 100$ sq.cm

$A4 = 20^2 = 400$ sq.cm

$A5 = 25^2 = 625$ sq.cm

It is given that,

Area of the 6TH square = Sum of the area of five squares

$A6 = 36 + 64 + 100 + 400 + 625$

$A6 = 1225$ sq.cm.

$=> a6^2 = 1225$

$a6 = \sqrt{1225}$

$a6 = 35$

So, Perimeter of the $6th$ square $= 4a$ units

$P6 = 4 × 35$ cm

$P6 = 140$ cm

So, the perimeter of 6th square is $140$ cm .

The correct option is 3).140 cm

 

 



Discussion

No Comment Found

Related InterviewSolutions