InterviewSolution
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1). 152 cm2). 124 cm3). 140 cm4). 70 cm |
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Answer» Solution : Given: Perimeter of five squares $P1 = 24cm , P2 = 32 cm, P3 = 40 cm , P4 = 80 cm, P5 = 100 cm$. Perimeter of a square $= 4a$ units ,where $'a'$ is the side of the square. So, Side of the five squares are, $a1 = 24/4 = 6$ cm $a2 = 32/4 = 8$ cm $a3 = 40/4 = 10 $cm $a4 = 80/4 = 20 $cm $A5 = 100/4= 25$ cm Area of a square $=a^2$ sq.units So,the area of five squares are $A1 = 6^2 = 36$ sq.cm $A2 = 8^2 = 64$ sq.cm $A3 = 10^2 = 100$ sq.cm $A4 = 20^2 = 400$ sq.cm $A5 = 25^2 = 625$ sq.cm It is given that, Area of the 6TH square = Sum of the area of five squares $A6 = 36 + 64 + 100 + 400 + 625$ $A6 = 1225$ sq.cm. $=> a6^2 = 1225$ $a6 = \sqrt{1225}$ $a6 = 35$ So, Perimeter of the $6th$ square $= 4a$ units $P6 = 4 × 35$ cm $P6 = 140$ cm So, the perimeter of 6th square is $140$ cm . The correct option is 3).140 cm
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