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1). 172). 183). 254). 13 |
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Answer» LET, the radius of the RESULTANT CIRCLE = R cm. ∴ Area of the resultant circle = πR2 cm2 Radius of the 1st circle = 7cm. ∴ Area of the 1st circle = π × 72 = 49π cm2 Radius of the 2nd circle = 8 cm. ∴ Area of the 2nd circle = π × 82 = 64π cm2 Radius of the 3rd circle = 11cm. ∴ Area of the 3rd circle = π × 112 = 121π cm2 According to problem, ⇒ πR2 = 49π + 64π + 121π ⇒ R2 = 234 ⇒ R ≈ 15 ∴ Radius of the circle = 15 cm. |
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