1.

1). 172). 183). 254). 13

Answer»

LET, the radius of the RESULTANT CIRCLE = R cm.

∴ Area of the resultant circle = πR2 cm2

Radius of the 1st circle = 7cm.

∴ Area of the 1st circle = π × 72 = 49π cm2

Radius of the 2nd circle = 8 cm.

∴ Area of the 2nd circle = π × 82 = 64π cm2

Radius of the 3rd circle = 11cm.

∴ Area of the 3rd circle = π × 112 = 121π cm2

According to problem,

⇒ πR2 = 49π + 64π + 121π

⇒ R2 = 234

⇒ R ≈ 15

∴ Radius of the circle = 15 cm.



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