1). 182). 193). $19\frac{1}{2}$4). Data insufficient

1.	1). 182). 193). \(19\frac{1}{2}\)4). Data insufficient
Answer» (A + B)’s 2 day’s work $( = \frac{1}{{12}} + \frac{1}{{48}} = \frac{5}{{48}})$ Work done in 9 pairs of days $( = \LEFT\{ {\frac{5}{{48}} \times 9} \right\} = \frac{{15}}{{16}})$ Remaining work $( = \left\{ {1 - \frac{{15}}{{16}}} \right\} = \frac{1}{{16}})$ Work done by B on 19^th day $(= \frac{1}{{48}})$ Remaining work $( = \left\{ {\frac{1}{{16}} - \frac{1}{{48}}} \right\} = \frac{1}{{24}})$ Now, $(\frac{1}{{12}})$ work is done by A in 1 day. $(\frac{1}{{24}})$ work is done by A in $( = \left\{ {12 \times \frac{1}{{24}}} \right\} = \frac{1}{2})$ Total time TAKEN $( = 19\frac{1}{2})$

Answer»

(A + B)’s 2 day’s work $( = \frac{1}{{12}} + \frac{1}{{48}} = \frac{5}{{48}})$

Work done in 9 pairs of days $( = \LEFT\{ {\frac{5}{{48}} \times 9} \right\} = \frac{{15}}{{16}})$

Remaining work $( = \left\{ {1 - \frac{{15}}{{16}}} \right\} = \frac{1}{{16}})$

Work done by B on 19^th day $(= \frac{1}{{48}})$

Remaining work $( = \left\{ {\frac{1}{{16}} - \frac{1}{{48}}} \right\} = \frac{1}{{24}})$

Now, $(\frac{1}{{12}})$ work is done by A in 1 day.

$(\frac{1}{{24}})$ work is done by A in $( = \left\{ {12 \times \frac{1}{{24}}} \right\} = \frac{1}{2})$

Total time TAKEN $( = 19\frac{1}{2})$

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