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1). 352). 303). 364). 40 |
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Answer» Let, vertical distance between parallel lines = H cm. ∴ HEIGHT of the TRIANGLE = H cm. Base of PARALLELOGRAM = base of the triangle = 35 cm. ∴ Area of triangle, ⇒ ½ × base × height ⇒ ½ × 35 × H ⇒ 35H/2 According to PROBLEM, ⇒ 35H/2 = 630 ⇒ H = 630 × (2/35) ⇒ H = 36 ∴ Vertical distance between the parallel lines = 36 cm. |
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