1.

`1.355 g` of a substance dissolved in `55 g`of `CH_(3)COOH` produced a depression in the freezing point of `0.618^(@)C`. Calculate the molecular weight of the substance `(K_(f)=3.85)`

Answer» `DeltaT=K_(f)xx(w_(B)xx1000)/(m_(B)xxw_(A))`
where, `w_(B)=` mass of solute, `m_(B)=` molar mass of solute, `w_(A) =` mass of solvent
`0.618=3.85xx(1.355xx1000)/(m_(B)xx55)`
`m_(B)=153.47`.


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