InterviewSolution
| 1. |
1). 900 gm2). 800 gm3). 650 gm4). 100 gm |
|
Answer» Given, The AVERAGE WEIGHT of five different BOXES b1, b2, b3, b4 and b5 is 200 gm: Average weight = Total weight of items/number of items Total weight of five different boxes = 5 × 200 = 1000 m Total weight of five different boxes = 1000 gm Given, The average weight of b1 and b3 is 50 gm while average weight of b2 and b4 is 125 gm: Total weight of b1 and b3 = 50 × 2 = 100 gm Total weight of b1 and b3 = 100 gm Total weight of b2 and b4 = 125 × 2 = 250 gm Total weight of b2 and b4 = 250 gm Total weight of five different boxes ⇒ 1000 = Weight of b1 + weight of b2 + Weight of b3 + Weight of b4 + Weight of b5 ⇒ 1000 = (Total weight of b1 and b3) + (Total weight of b2 and b4) + weight of b5 ⇒ 1000 = 100 + 250 + weight of b5 ⇒ 1000 = 350 + weight of b5 Weight of b5 = 1000 - 350 Weight of b5 = 650 gm ∴ The weight of box b5 is 650 gm. |
|